Converting XML file to DTD or XSD file

Hi everyone,
We're currently doing an IDOC to File. The file should be in XML format. Right now, we have a sample XML file. We need to convert the file to DTD or XSD and then upload this in XI to be able to get it structure. We've tried different conversion tools to do this, however, the converted DTD/XSD file still has errors when we load it to XI. What we're thinking is to create a data type to achieve this. These are some of the fields in the file.
<messageHeader creationDate>
<catellae:gTTSDataDelivery creationDate="X" (...)>
*/<catellae:()>/<txnId>
*/<catellae:()>/<items>/<item>/<quantity>
*/<catellae:()>/<items>/<item>/<unitOfMea>
*/<catellae:()>/<items>/<item>/<prodDesc>/<matType>
*/<catellae:()>/<shipToAddress>/<nameAndAddress>/<city>
*/<catellae:()>/<shipToAddress>/<contactInformation>/<communicationChannel ()
It seems that there are more than 3 nodes. And in XI, only three nodes are allowed. Could you tell us how should we create the data type for this? Thanks in advance!

Hi Mariel,
Refer to the below link for conversion of XML to Xsd using Altova XML Spy.
Re: data type for xml file
For altova free trial Download:
http://www.altova.com/download.html
Please let me know if u need furthur information.
Thanks,
Bhargav.
Note:Award points if found useful

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External dependency on remote dtd and xsd files

The question bugs me for years, please help.
Should we download external dtd and xsd files declared for web.xml and faces-config.xml and pack them in the war files to eliminate the external dependency.
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Hi Srikanth,
Have you done this?
SAP HELP
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Hi,
I'd like to create an XML document with java. BUT How can we "bind" this creation with a XSD file. Hence, the creation may fail if the XSD binded file is not respected.
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Hi,
I'd like to create an XML document with java. BUT How can we "bind" this creation with a XSD file. Hence, the creation may fail if the XSD binded file is not respected.
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Problem with import tag in xsl files and include in xsd files

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yes, thats not the value returned of
URL url = this.getClass().
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java.io.FileNotFoundException: C:\cpqd\isp\tools\third-party\jboss\server\jbossISP1\deploy\cpqd-ispeng-EngEJB-3.3.0.0.ear\cpqd-ispinv-ServiceEJB.jar\xsl\isp_transformer_manufacturer.xsl
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Register XSD-Files which includes Other XSD-Files

Hallo
i have two XML-Schemata. One is included by the other.
Here is an example:
This is the XSD, which is included by the other (metadata.xsd):
<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema" elementFormDefault="qualified">
     
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     <xs:complexType name="metadataType">
          <xs:sequence>
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               <xs:element ref="category"/>
               <xs:element ref="creator"/>
               <xs:element ref="creation_date"/>
               <xs:element ref="publisher"/>
               <xs:element ref="language"/>
               <xs:element ref="title"/>
               <xs:element ref="basic_year"/>
               <xs:element ref="statistic"/>
This is the XSD, which include the other XSD (lexikon.xsd):
<?xml version="1.0" encoding="UTF-8"?>
<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:xdb="http://xmlns.oracle.com/xdb" elementFormDefault="unqualified" attributeFormDefault="unqualified">
     
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     <xs:complexType name="lexikonType">
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               <xs:element ref="lexikonEntries"/>
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          <xs:attribute name="lexikonKat" type="xs:integer">
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               </xs:annotation>
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     <xs:element name="explicationTxt" type="explicationType"/>
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Both documents have i copied to a webdav-folder. Now i want register the documents.
BEGIN
DBMS_XMLSchema.registerSchema(
schemaurl=>'http://190.1.1.148:8080/home/DEV/xsd/lexikon.xsd',
schemadoc=>sys.UriFactory.getUri('/home/DEV/xsd/lexikon.xsd'));
END;
The following error-message is displayed:
ERROR at line 1:
ORA-31000: Resource 'metadata.xsd' is not an XDB schema document
ORA-06512: at "XDB.DBMS_XMLSCHEMA_INT", line 0
ORA-06512: at "XDB.DBMS_XMLSCHEMA", line 166
ORA-06512: at line 2
I made the XSD-Files by XMLSpy. The Documents are well-formated and valid.
When i make a new XML-File based ONLY (of course) on lexikon.xsd everything works fine with XMLSpy.
How must i register these documents? Is it possible? Or can´t i register XSD-Files which includes others?
Thank you very much
cu
Heidi

Heidi,
register the metadata.xsd first inthe same way and then register the lixikon.xsd.
it should work.

How to import a XSD schema files hierarchy (=mulitple dependent XSD files)?

Assume I have a XSD schema file hierarchy in my local directory
D:\bpelprojects\projXSDs\proj123\*
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D:\bpelprojects\projXSDs\proj123\main.xsd
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Peter

HI,
Make sure that you use all the relative paths while referring those XSDs in the BPEL/XSD files. Otherwise you will see the problems ar runtime.
As a jeneral rule... if the schemas are public put them in system/xmllib directory and refer them using the localhost:7778/xmllib/...
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Hope this makes clear.
-- Khaleel

How to convert XML file into DTD or XSD

Hi Folks,
This is the output structure I need to get. My interface is file to file. Can u please let me know How do I create a data type or any XSD to get below Structure.
<?xml version="1.0" encoding="UTF-8" ?>
- <Command xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:noNamespaceSchemaLocation="Command.xsd">
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Please help me How would I create Data type for this. Your help is highly apreciated
Thanks,
Enivass

Hi Enivas,
>>>>>>>>>Please help me how would I delete ns0.
For remove ns0, you have to do use XMLAnonymizerBean module in adpater module (In Communication channel).
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Type: Local Enterprise Bean
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Add Parameters in the Module Configuration
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Xml file with DTD in jar file

Dear all,
I developed an application using NetBeans which lets you create XML files.
The process of creating the new XML file, set the attribute Doctype of these files to the DTD (fileXML.dtd) present in the build / classes / Dtd that is loaded during implementation through:
URL url=ClassLoader.getSystemClassLoader().getResource("Dtd/fileXML.dtd");so the attribute Doctype XML files created will have the location of the DTD fileXML.dtd:
<?xml version="1.0"?>
<!DOCTYPE AGSet SYSTEM "file:/F:/Documents%20and%20Settings/ioXp/Desktop/mioProgramma/build/classes/Dtd/fileXML.dtd">
Well. After completing the development of the program, I created the executable miaApplicazione.jar (in which he was pulled inside your full Buil, including build / dtd) by the option of NetBeans "Build Main Project."
Double-clicking the file miaApplicazione.jar the program runs properly.
The problem now is that when I create the XML file by mioProgramma.jar, they will refer to this DTD within miaApplicazione.jar and consequently when trying to open these files XML message appears:
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<?xml version="1.0"?>
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What is the solution for this problem?
Hi
ELVIO

Hi swanelvis ,
I have the same issue. Were you able to resolve this ?
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DTD and XSD Validation for xml file

hi kindly reply to this mail guru'ssss
i am facing a problem in parising a xml file against dtd and xsd.
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when DTD is present then it is throwing errors like the elements should be declared.
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what could be soln to this.

Hi
Venky_Ferrari.
Based on your description, your case related to XMLＸSD, SO I will move your thread to
Data Platform Development > XML, System.Xml, MSXML and XmlLite
forum for better support.
Best regards,
Kristin
We are trying to better understand customer views on social support experience, so your participation in this interview project would be greatly appreciated if you have time. Thanks for helping make community forums a great place.
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HERE to participate the survey.

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http://www.oracle.com/technology/oramag/oracle/07-may/o37sql.html
http://www.oracle.com/technology/obe/hol08/sqldev_srccodexmlext/xmlext_otn.htm
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Included XSD-File - defaulttable

Hello,
i have a xsd-file "metaddi.xsd" in which i have informations about the "main"-xsd-file. This metadata-xsd-file is included by other xsd-files:
<?xml version="1.0" encoding="UTF-8"?>
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</xs:schema>
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Thank you
Heidi

Hello Marco,
a view could be a solution. Defining a defaulttable is consequently not possible, isn´t it?
But how can i create a view based on several tables?
My metadata.xsd looks like:
<metadata>
<category1>country</category1>
<category2>state</category2>
<category3>city</category3>
</metadata>
The examples in the XDB Developer´s Guide are only with one table. Can you or someone else can give me please a little example how to do this?
I want a table with 3 columns:
category1 category2 category3
And the records of the different tables should be among each other. How can i do this?
Thank you very much
Heidi

Convert XML data to byte array...

Hello All,
In my application, i have an XML file and the corresponding XSD file. This XML file is having some date, which i want to convert into an byte[] and then save it in a file.
How i can convert the XML data in the byte[]? Here as an example of the xml file and the byte[] data which i want to save in a file.
<?xml version="1.0" encoding="utf-8"?>
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<header>
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string name = (string)header.Element("Name");
byte[] nameBytes = System.Text.Encoding.UTF8.GetBytes(name);
Console.WriteLine("id: {0}, Name: {1}", id, name);
// Write id
writer.Write(GetUIntBytes((uint)id));
// Write name NameLength (5) max, otherwise padded
if (nameBytes.Length > NameLength)
writer.Write(nameBytes, 0, NameLength);
else
writer.Write(nameBytes, 0, nameBytes.Length);
if (nameBytes.Length < NameLength)
writer.Write(zeroBytes, 0, NameLength - nameBytes.Length);
byte[] result = ms.ToArray();
// dump array
foreach (var value in result)
Console.Write("{0:X2} ", value);
Console.WriteLine();
return result;
public static byte[] GetUIntBytes(uint value)
if (BitConverter.IsLittleEndian)
// swap bytes
value = ((value & 0x00ff) << 24)
| ((value & 0xff00) << 8)
| ((value & 0x00ff0000) >> 8)
| ((value & 0xff000000) >> 24);
return BitConverter.GetBytes(value);
For a general purpose solution you should create a class and split the example into separate methods to extract the data and write the values (integers, strings).
Regards, Elmar

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