Converting year(date in bpel)

Hello
I will get input year as 10/11. I need to convert it as *2010-2011*.
Below is xpath is converting as 2010-11
translate(concat('20',bpws:getVariableData('year')),"/","-20")
Any help is appreciated.

concat('20',substring(bpws:getVariableData('year'),1,2),'-','20',substring(bpws:getVariableData('year'),4,2))

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Routine to convert the date into month/year

Hi friends,
I have requirement like I have 0billdate, but i want only month and year in that. So i have created a z object for that taking reference as 0calmonth. I think the format is yyyymm.
So now I want to write a routine which converts the date to month/year. If anybody know this please let me know.
Regards
San Reddy

Hi
in the trnasfer rule or in the update rule select the Zinfo object to which you need to do conversion
in details select formula and create.
Select all functions and follow the steps below.
use the conversion function DATE_MONTH( )
Short Text
Function: Date -> Month
Functionality
Calculates the month from a specified date.
Requirements
The date must appear in the format yyyymmdd.
Parameters
DATE_MONTH (date)
Result
The result is calculated in the format yyyymm.
Regards
RaM

Convert two dates difference to number of years, months and days

Post Author: gigimonu
CA Forum: Formula
I wanted to write a formula (if there is a function I can use) that can convert a date difference to total number of years, months and days example
adate = 10/22/2006
?xdate = current date - adate (answer should be 1 years, 0 months and 0 days)
Please help
Thanks

Post Author: V361
CA Forum: Formula
[Years, Months, Days]
DATEVAR FROMDATE := DATE(2000,01,01); // FROM DATE
DATEVAR TODATE := CURRENTDATE; // TO DATE
NUMBERVAR YEARS;
NUMBERVAR MONTHS;
NUMBERVAR DAYS;
STRINGVAR DIFF;
DATEVAR TEMP;
IF TODATE < FROMDATE THEN
(TEMP := TODATE;
TODATE := FROMDATE;
FROMDATE := TEMP);
YEARS := DATEDIFF('YYYY',FROMDATE,TODATE);
IF YEARS > 2 THEN
(YEARS := YEARS - 2;
TEMP := DATE(DATEADD("M",YEARS * 12,FROMDATE));)
ELSE
(YEARS := 0;
TEMP := FROMDATE);
WHILE TRUE DO
(TEMP := DATE(DATEADD('M',1,TEMP));
IF TEMP > TODATE THEN
EXIT WHILE;
MONTHS := MONTHS + 1);
DAYS := DATEDIFF('D',DATE(DATEADD('M',-1,TEMP)),TODATE);
IF MONTHS > 12 THEN
(YEARS := YEARS + INT(MONTHS/12);
MONTHS := MONTHS MOD 12);
DIFF := IIF(YEARS>0 ,TRIM(TOTEXT(YEARS,0)) & " YEARS " ,"0 YEARS ") &
IIF(MONTHS>0,TRIM(TOTEXT(MONTHS,0))& " MONTHS ","0 MONTHS ")&
IIF(DAYS>0 ,TRIM(TOTEXT(DAYS,0)) & " DAYS" ,"0 DAYS");

Adding 1 day to a date in BPEL

Hi,
Im trying to add 1 day to a date in a BPEL proces. I saw that there was a xp20:add-dayTimeDuration-to-dateTime so I tried using this in several ways. I didnt expect the input variable to be a string. I tried converting my date to a string and adding 1 day like this:
xp20:add-dayTimeDuration-to-dateTime(xp20:format-dateTime(string(bpws:getVariableData('inputVariable','payload','/ns1:GereedMeldenRoosterRequest/StartDatum')), 'YYYY-MM-DD'), 'P1D')
But the variables which I try to fill stays empty. The element which I try to fill is of type dateTime. Is this maybe the error that add-dayTimeDuration-to-dateTime returns a string and it cannot cast it to dateTime?
Can anyone tell me how to solve this properly?
Thanks in advance!

Hi,
I refactored my expression to look like this:
xp20:format-dateTime(xp20:add-dayTimeDuration-to-dateTime(bpws:getVariableData('inputVariable','payload','/ns1:GereedMeldenRoosterRequest/StartDatum'), 'P1D'), '[Y]-[M]-[D]')
But the I receive an error: XMLElement cannot be cast to java.lang.String
Then I tried:
xp20:format-dateTime(string(xp20:add-dayTimeDuration-to-dateTime(bpws:getVariableData('inputVariable','payload','/ns1:GereedMeldenRoosterRequest/StartDatum')), 'P1D'), '[Y]-[M]-[D]')
Because xp20:add-dayTimeDuration-to-dateTime needs a String as input and I dont know how getVariableData returned it but with this I get the error:Parse Error in string function
Any ideas?

How to convert the date time from MM-DD-YYYThh:mm:ss to YYYY-MM-DDThh:mm:ss format

Hi All,
I have a requirement in my project like to convert the date time from one format to another.my situation is like to convert the date time from MM-DD-YYYThh:mm:ss to YYYY-MM-DDThh:mm:ss format. I am using the soa suite 11.1.1.6.
Can any one suggest me how to convert in the BPEL transformation.
Thanks,
Sanju.

Hi Sanju,
Store the date to be converted into a variable viz. dateVar. Now, process an expression in assign as: xp20:format-dateTime($dateVar,'[Y0001]-[M01]-[D01] [h]:[m01]:[s01]').
Regards

Conversion from YYYYMMDD to Julian Date in BPEL

Hi,
My requirement is to convert date format from YYYYMMDD to Julian Date (CYYDDD) in BPEL.
C - Stands for Century
Would like to know a way to achieve this conversion in BPEL. Please suggest.
Appreciate your quick help.
Thanks
Priyanka G

Hi,
I suggest you use a java activity for that... There are many examples in java on how to convert a date to julian...
Cheers,
Vlad

I need a formula to convert a date into an integer (for use in Lookout)

I have a DATA logger with the following:
40001 = 4 (2004)
40002 = 2 (February)
40003 = 5 (5th)
40004 = 13 (1:00pm)
40005 = 12 (12 minutes)
Lookout requires a date that it understands (eg. January 1, 1900).
All I need is a basic formula to convert the date and time.
This formula does not need to be specifically written for Lookout. Just a basic formula that I can do on paper or a calculator.
I can integrate that formula into the Lookout software myself.

Hello Smigman,
First of all, I apologize in advance for not giving you "just the formula." And for the lengthy explanation (had to wait till after work hours), which you are very likely aware of already. I am writing this response in much detail so that it may benefit others.. hopefully And so that we understand the underlying principle involved, which will hopefully help us in building the formula the best way that suits us.
As you have figured out, the data and time in Lookout is represented as a real number. This real number's integer portion represents days, and the decimal portion denotes time. The integer portion is basically the number of days since 01/01/1900. And the decimal portion is the number of seconds since midnight.
So, for instance, if you insert the today() Expression in Lookout, you'll get a integer 38022 (which corresponds to today, Feb. 5th, 2004). In other words, today is the 38022nd day since 01/01/1900. Tomorrow, Feb. 6th 2004, will be 38023 and so on.
The decimal part denotes time. A day has 24*60*60 = 86400 seconds, obviously. So, 1/86400 = 1.15741E-5 roughly represents one second. For instance, 38022.00001157 will give 02/05/2004 00:00:01.
Coming to the formula now, for Time, first convert it to total seconds from midnight. E.g., 5:15:07pm would be (17*60*60) + (15*60) + 7 = 62107 seconds total since midnight. To get the Lookout's decimal part, divide this by 86400.
62107/86400 = 0.71883102
Therefore, 38022.71883102 would now give 02/05/2004 17:15:07. Computing Time is relatively easy.
For the Date -- which is more complicated-- you could keep track of the total number of days either from 01/01/1900, or better still, a more recent day, like say 12/31/2003, which corresponds to 37986. To this reference you will keep adding 1 for each additional day to get the number for the current day. Note, you will have to accomodate leap years (Feb. 29th of this year, for instance).
It's very helpful to have the reference day as the last day of the past year. That can be derived by counting the number of days since 01/01/1900 as follows:
104 years * 365 days = 37960;
+ 1 day for each leap year
A leap year is a year divisible by 4 (and 400 if the year ends with two zeros). There were 26 leap years from 1900 till 2003.
So, 37960 + 26 = 37986. 12/31/2003 is thus represented by 37986.
To get the integer for the Current Date we would first find what day of the year it is. Then add it to the reference day. Feb 5th, is the 36th day of the year. Adding this to 37986, gets us 38022.
In your case you will have to come up with the correct day of the year using registers 40002 and 40003. Not sure if this helped or confused you more.
I tried
Khalid

Function module to convert calender date to Julian date format

Hi,
Is there any FM which can convert Calendaer Date to <b>Julian Date</b> format?
Thanks.
Regards,
Madhu

It is not a func mod... but it is pretty straight forward.
data: julian_day(3) type n,
date_aux type d,
date_I_need type d.
first day of the year
concatenate date_I_need(4) '0101' into date_aux.
julian_day = date_I_need - date_aux.
julian_day = julian_day + 1.

Converting palm data to outlook

I have a treo 650 with palm os; need to know if I can convert palm data to outlook data and then sync with outlook. Help.
f100
Post relates to: Treo 650 (Sprint)

I used Chapura to convert my Palm data to Outlook. it created duplicate files for over half of the entries, merged telephone numbers and ignored notes all together- it is a mess.
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thanks for any help and leads on how to accomplish.

Problem in converting legacy date format

Hello all,
I am having a legacy file in which the date format is yyddd ( e.g 07129 ).
Can any of you experts suggest me how can i convert these date format in SAP date format i.e YYYYMMDD.
Please suggest.
Arun

Hi, Arun
May be the following code will help you in this way,
data: date like sy-datum,
      year(4),
      month(2),
      day(2).
year = '2006'.
month = '12'.
day = '01'.
date+0(4) = year.
date+4(2) = month.
date+6(2) = day.
Replay if any problem,
Kind Regards,
Faisal
Edited by: Faisal Altaf on Jan 6, 2009 11:00 PM

How to convert DateField date to String ?

Hi,
I'm trying to convert DateField date to String.
How can I do it because Data class does not have String converting
methods...
Thanks
Krzysztof

Hello,
you can get an instance of Calendar and use it with the date as a long integer.
public Calendar cal=Calendar.getInstance();
myDate=dateField.getDate();
cal.setTime(myDate);
myDateString=cal.get(Calendar.DATE)+"."+cal.get(Calendar.MONTH)+"."+cal.get(Calendar.YEAR));
Try it.
Unfortunately I have found that the MIDlet get a day less when I use the same long integer that I got from an application on PC. I don't realy understand why but I' still searching.
I hope it is usefull for you.
ValeriuS

Convert the date

Hi Experts,
        Is there any FM to Convert the date from 04/01/2009 to 4/1/2009?
i want to remove the zero before the date and month.
Regards.

Hi,
Test the following Sample Code it will solve out your problem,
PARAMETERS: date like sy-datum.
data: day(2),
      month(2),
      year(4),
      cdate(10).
day = date+6(2).
month = date+4(2).
year = date+0(4).
CALL FUNCTION 'CONVERSION_EXIT_ALPHA_OUTPUT'
EXPORTING
    input         = day
IMPORTING
   OUTPUT        = day
CALL FUNCTION 'CONVERSION_EXIT_ALPHA_OUTPUT'
EXPORTING
    input         = month
IMPORTING
   OUTPUT        = month
CONCATENATE: day '/' month '/' year into cdate.
WRITE: cdate.
Best Regards,
Faisal

How to extract month from given date in bpel??

Hi friends hi need some information regarding dates in BPEL.. Here in these I taking date as input which type is also date type.Then required output is month in number format.. Here I used Assign activity and in assign activity,I took month-from-date and passed argument to this function.But it raised an error "internal Xpath error" Any one can you give me ideas please....

First convert you date into datetime and then use the month-from-datetime function.
Regards,
Anshul

Loading leap year date using SQL*Loader

Hello,
I have a problem loading a date '29/02/2000' using SQL*Loader. This date is on a leap year. I'm getting an error message from SQL*Loader as 'ORA-01839: date not valid for month specified'. My colleague and I have tried using various date functions to convert the data into date, but no luck.
I would appreciate any helps,
Bruce

Thanks for your help, I found the bug on my control file. I was using the RTRIM function to remove bad timestamp such as '29/02/2000 0:00:00'. So instead of using this statement:
LOG_DATE DATE "DD/MM/RRRR" "RTRIM(:LOG_DATE,'0:00:00')"
I was using the statement below with a space before the '0:00:00' string literal, with the intention to remove a space also:
LOG_DATE DATE "DD/MM/RRRR" "RTRIM(:LOG_DATE,' 0:00:00')"
Well, it turned out that if there was a space before the string literal, RTRIM function would trim the matching string plus any '0' characters from the right, including the '000' that belongs to '2000'. Thus, the error.
Thanks again,
Bruce

Converting UTC dates to local time

Hello all. I have some data I imported that has a date column containing dates spanning a number of years. The dates are in the UTC timezone.
I need to display the dates in the local time zone that was in effect at the time. I've seen many fine examples of converting from one time zone to another. But I need it to be smarter than that. For example, date/times (this year) prior to 03/09/2008 2AM should display in EST (my zone in effect then), while date/times on/after then should display in EDT.
Are there any Oracle built-in functions to do this, or will I need to gather the data of when daylight savings time begins/ends for the years I have dates and write my own function? I don't need help for the latter; I just don't want to reinvent the wheel. Also, I don't want to convert the data; I append to it regularly.
Thanks for your help and consideration.

Sergiusz, thanks again. When I added a very recent date, I saw the effect. But perhaps something is wrong with my local 10gR1 "play" database. It seems the DST start point is not correct. Should it not start showing -4 offset at row# 4? I didn't see a change until I added the last date. But I believe DST began on 3/9/2008 at 2am local, which is 7am UTC.
~Pete
SQL> DROP   TABLE imported_events;
Table dropped.
SQL> CREATE TABLE imported_events (event_date TIMESTAMP(0) WITH TIME ZONE);
Table created.
SQL> BEGIN
2 INSERT INTO imported_events VALUES ( '10-JAN-08 2:00:00 PM UTC');
3 INSERT INTO imported_events VALUES ( '08-MAR-08 2:00:00 PM UTC');
4 INSERT INTO imported_events VALUES ( '09-MAR-08 6:59:00 AM UTC');
5 INSERT INTO imported_events VALUES ( '09-MAR-08 7:01:00 AM UTC');
6 INSERT INTO imported_events VALUES ( '09-MAR-08 2:00:00 PM UTC');
7 INSERT INTO imported_events VALUES ( '10-MAR-08 2:00:00 PM UTC');
8 INSERT INTO imported_events VALUES ( '09-JUN-08 2:00:00 PM UTC');
9 COMMIT;
10 END;
11 /
PL/SQL procedure successfully completed.
SQL> COLUMN ROWNUM         FORMAT 99
SQL> COLUMN event_date_utc FORMAT A25
SQL> COLUMN offset_local   FORMAT 99
SQL> COLUMN offset_eastern FORMAT 99
SQL> SELECT ROWNUM
2        ,event_date event_date_utc
3        ,TO_CHAR(CAST((event_date AT LOCAL) AS DATE),'YYYY-MM-DD HH24:MI:SS') date_local
4        ,(CAST((event_date AT LOCAL) AS DATE) - CAST(event_date AS DATE))*24 offset_local
5        ,TO_CHAR(CAST((event_date AT TIME ZONE 'US/Eastern') AS DATE),'YYYY-MM-DD HH24:MI:SS') date_eastern
6        ,(CAST((event_date AT TIME ZONE 'US/Eastern') AS DATE) - CAST(event_date AS DATE))*24 offset_eastern
7    FROM imported_events
8   ORDER BY 1;
ROWNUM EVENT_DATE_UTC            DATE_LOCAL          OFFSET_LOCAL DATE_EASTERN        OFFSET_EASTERN
     1 10-JAN-08 02.00.00 PM UTC 2008-01-10 10:00:00           -4 2008-01-10 09:00:00             -5
     2 08-MAR-08 02.00.00 PM UTC 2008-03-08 10:00:00           -4 2008-03-08 09:00:00             -5
     3 09-MAR-08 06.59.00 AM UTC 2008-03-09 02:59:00           -4 2008-03-09 01:59:00             -5
     4 09-MAR-08 07.01.00 AM UTC 2008-03-09 03:01:00           -4 2008-03-09 02:01:00             -5
     5 09-MAR-08 02.00.00 PM UTC 2008-03-09 10:00:00           -4 2008-03-09 09:00:00             -5
     6 10-MAR-08 02.00.00 PM UTC 2008-03-10 10:00:00           -4 2008-03-10 09:00:00             -5
     7 09-JUN-08 02.00.00 PM UTC 2008-06-09 10:00:00           -4 2008-06-09 10:00:00             -4
7 rows selected.
SQL>

Converting year(date in bpel)

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