Coordinates of rotated textframe

With the help of itemtransform horizontal, vertical distance and path point arrays, I can find out the coordinates of text frame (x1,y1), (x2,y2), (x3,y3), (x4,y4). If the textframe is rotated then item transform values are getting changed, but the path point array values are same. I can find rotation angle by the matrix [cos(θ) sin(θ) -sin(θ) cos(θ) 0 0], But I could not get the exact coordinates of rotated textframe. The textframes are given below.
Normal Text frame
<TextFrame Self="u136" ParentStory="u124" ItemTransform="1 0 0 1 101.72727272727272 -349.41818181818184">
            <Properties>
                <PathGeometry>
                    <GeometryPathType PathOpen="false">
                        <PathPointArray>
                            <PathPointType Anchor="-101.72727272727272 -46.581818181818164" LeftDirection="-101.72727272727272 -46.581818181818164" RightDirection="-101.72727272727272 -46.581818181818164"/>
                            <PathPointType Anchor="-101.72727272727272 -0.3272727272727103" LeftDirection="-101.72727272727272 -0.3272727272727103" RightDirection="-101.72727272727272 -0.3272727272727103"/>
                            <PathPointType Anchor="115.9090909090909 -0.3272727272727103" LeftDirection="115.9090909090909 -0.3272727272727103" RightDirection="115.9090909090909 -0.3272727272727103"/>
                            <PathPointType Anchor="115.9090909090909 -46.581818181818164" LeftDirection="115.9090909090909 -46.581818181818164" RightDirection="115.9090909090909 -46.581818181818164"/>
                        </PathPointArray>
                    </GeometryPathType>
                </PathGeometry>
            </Properties>
</TextFrame>
Rotated textframe
<TextFrame Self="u136" ParentStory="u124" ItemTransform="0 1 -1 0 320.3805483338268 -125.07900895050204">
            <Properties>
                <PathGeometry>
                    <GeometryPathType PathOpen="false">
                        <PathPointArray>
                            <PathPointType Anchor="-101.72727272727272 -46.581818181818164" LeftDirection="-101.72727272727272 -46.581818181818164" RightDirection="-101.72727272727272 -46.581818181818164"/>
                            <PathPointType Anchor="-101.72727272727272 -0.3272727272727103" LeftDirection="-101.72727272727272 -0.3272727272727103" RightDirection="-101.72727272727272 -0.3272727272727103"/>
                            <PathPointType Anchor="115.9090909090909 -0.3272727272727103" LeftDirection="115.9090909090909 -0.3272727272727103" RightDirection="115.9090909090909 -0.3272727272727103"/>
                            <PathPointType Anchor="115.9090909090909 -46.581818181818164" LeftDirection="115.9090909090909 -46.581818181818164" RightDirection="115.9090909090909 -46.581818181818164"/>
                        </PathPointArray>
                    </GeometryPathType>
                </PathGeometry>
            </Properties>
</TextFrame>
Can anyone help me to find out the cordinates of rotated textframe.
Thanks in advance.

I suspect you'll do better asking here: http://forums.adobe.com/community/indesign/indesign_sdk

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How to find out the coordinates of rotated textframe

Hi All,
With the help of (idml) itemtransform horizontal / vertical distances and path point arrays, I can find out the coordinates of text frame (x1,y1), (x2,y2), (x3,y3), (x4,y4). If the textframe is rotated then item transform values are getting changed, but the path point array values are same. I can find rotation angle by the matrix [cos(θ) sin(θ) -sin(θ) cos(θ) 0 0], But I could not get the exact coordinates of rotated textframe. The textframes are given below.
Normal Text frame
<TextFrame Self="u136" ParentStory="u124" ItemTransform="1 0 0 1 101.72727272727272 -349.41818181818184">
            <Properties>
                <PathGeometry>
                    <GeometryPathType PathOpen="false">
                        <PathPointArray>
                            <PathPointType Anchor="-101.72727272727272 -46.581818181818164" LeftDirection="-101.72727272727272 -46.581818181818164" RightDirection="-101.72727272727272 -46.581818181818164"/>
                            <PathPointType Anchor="-101.72727272727272 -0.3272727272727103" LeftDirection="-101.72727272727272 -0.3272727272727103" RightDirection="-101.72727272727272 -0.3272727272727103"/>
                            <PathPointType Anchor="115.9090909090909 -0.3272727272727103" LeftDirection="115.9090909090909 -0.3272727272727103" RightDirection="115.9090909090909 -0.3272727272727103"/>
                            <PathPointType Anchor="115.9090909090909 -46.581818181818164" LeftDirection="115.9090909090909 -46.581818181818164" RightDirection="115.9090909090909 -46.581818181818164"/>
                        </PathPointArray>
                    </GeometryPathType>
                </PathGeometry>
            </Properties>
</TextFrame>
Rotated textframe
<TextFrame Self="u136" ParentStory="u124" ItemTransform="0 1 -1 0 320.3805483338268 -125.07900895050204">
            <Properties>
                <PathGeometry>
                    <GeometryPathType PathOpen="false">
                        <PathPointArray>
                            <PathPointType Anchor="-101.72727272727272 -46.581818181818164" LeftDirection="-101.72727272727272 -46.581818181818164" RightDirection="-101.72727272727272 -46.581818181818164"/>
                            <PathPointType Anchor="-101.72727272727272 -0.3272727272727103" LeftDirection="-101.72727272727272 -0.3272727272727103" RightDirection="-101.72727272727272 -0.3272727272727103"/>
                            <PathPointType Anchor="115.9090909090909 -0.3272727272727103" LeftDirection="115.9090909090909 -0.3272727272727103" RightDirection="115.9090909090909 -0.3272727272727103"/>
                            <PathPointType Anchor="115.9090909090909 -46.581818181818164" LeftDirection="115.9090909090909 -46.581818181818164" RightDirection="115.9090909090909 -46.581818181818164"/>
                        </PathPointArray>
                    </GeometryPathType>
                </PathGeometry>
            </Properties>
</TextFrame>
When I converted the values of rotated textframe in to coordinates and drawn in a screen then I am not getting the exact position where it drawn in the original.
Can anyone help me to find out the cordinates of rotated textframe.
Thanks in advance.

It seems pretty straightforward to me.
Your center point is (42.375 mm, 27.458 mm) and your box is 58.417 mm x 28.417mm.
IDML defines the rectangle by its corners, not its center, so let's find the upper-left corner. Divide the width by two and subtract from the x, same for the height and the y. You get (13.665 mm, 13.2495 mm).
That is in page coordinates relative to the upper-left corner of the page, we can see from your rulers.
But IDML coordinates are spread-relative from the center of the spread. Your spread is a single page that is 85 mm x 55 mm.
So if we translate your upper-left corner, it is (13.665, 13.2495) mm - (85/2, 55/2) => (29.3335 mm, 14.2505mm) in spread-relative coordinates.
But IDML coordinates are in points, not in mm. So we convert (multiply by 2.835). And we get (83.150 pt, 40.395 pt).
But that doesn't match up with your IDML file, which has (-82.650 pt, -39.890pt).
But look at the difference: (0.500 pt, 0.505 pt). That's really 1/2 point, because your box has a 1-pt border and that gets split evenly across all 4 sides. And there's 0.005 of round-off error, bceause floating point math sucks.
Any questions?

Multiplying image to coordinates and rotation

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I was wondering if anyone could help me write a Adobe Illustrator script.
The script must be able to:
1. Read a file containing several coordinates (X,Y) and angles.
2. Select an image (or load an image).
3. Copy and paste an image to the coordinates and rotate the images by the given angles.
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Can this be possible with an illustrator script?
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Could you recommend any online references on programming an illustrator script?
I don't always have access to Illustrator.
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Hi Carlos,
I have a bit of programming background. I'm familiar with VB, C, C++. I'm a novice on illustrator.
I attempted at writing quick "copy, paste & rotate" script in javascript, see below. But I need to somehow get the coordinates from another file (a text file).
Can I use something like this on the Illustrator script?
http://www.javapractices.com/topic/TopicAction.do?Id=42
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var msgType = "";
if (app.documents.length>0)
     myselection = app.activeDocument.selection;
     if (myselection.length>0)
for (var i=0; i<myselection.length; i++) {
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     myselection[i].duplicate()
     myselection[i].translate(300,50)
     myselection[i].rotate(50)
     myselection[i].duplicate()
     myselection[i].translate(600,10)
     myselection[i].rotate(45)

Coordinates of rotated rectangle

I have a rectangle that is rotated by a script.
When outputting the geometric bounds of the rectangle, I get the coordinates of the outside rectangle that is aligned horizontally.
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Here's a basic example of using resolve()
Note: This will only work if your object is (directly) on a page. Generalizing it to work whether it's on a page or a spread is very hard, and I don't have the time right now to break my head over this...
var coord = getPointCoordinates(app.selection[0],AnchorPoint.TOP_LEFT_ANCHOR);
alert(coord);
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    var page = obj.parentPage;
    var pC = page.resolve(anchorPoint,CoordinateSpaces.SPREAD_COORDINATES);
    return [oC[0][0]-pC[0][0],oC[0][1]-pC[0][1]];
HTH
Harbs

How do you find out the angle degree of type that has been rotated?

I have manually rotated some type. It's not rotated a standard number of degrees and I'd like to find out what that number is. Do you know if there is a place in Illustrator that gives this informatiion because I sure as heck can't find it.

You are supposed to be able to measure angles using the Measure Tool. I find this completely unreliable, because it fails to abide by Snaps. (Absolutely hideous.)
This page describes an AI Javascript you can download and try, for un-rotating textframe objects.
JET

3D rotationX/Y/Z with local coordinate?

Hi,
When I use 3D rotation tool, there is an option called global transform, if it turned off, the object would rotate by its own axes, this is exactly what I want. How can I do rotatation like that with AS3 code?
Is there any property if changed then rotationX/Y/Z would rotate object by its axes?
Thanks

Thanks,
I have found an easier way to do local rotation, so write here for someone needs it in the future:
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+ If you want to rotate it by global coordinate, then rotate its container, just: cont1.rotationZ +=1;
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Just to be clear, I know how to move the anchor point visually on the stage, but I want accuracy. I want to be able to give two symbols the exact same coordinates to rotate around.
Thanks for your help.

Thank you! That's exactly what I was looking for.
I also found a work around to what I was trying to do. You can select multiple symbols and rotate them around one axis, but that's not as accurate. BTW if you have any links to using 3D in CS4 that are beyond basic, I would love to see them.
Thanks again,
-Red-Mike

Animation

heloo
i did put this animation in my Japplet and when the game state change i want it to show different image
i tried every thing i know but it change to fast or it do not work i have 4 different state in my game and i want to call this class and tell the class to change picture how can i slow it down with out interupting its move.
i will be thank full if some one give different way to do it or tell
me how to solve my error
Thanks in advance
class DemoAnimation extends JPanel implements Runnable {
Thread thread;
JApplet Demm;
Image image;
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int picture;
double x, y, xi, yi;
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double scale; int UP = 0; int DOWN = 1;
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// 7. DemoAnimationCanvas constructor ...
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setBackground(Color.black); // For canvas background color
Demm=De;
MediaTracker mt = new MediaTracker(this);
          // Construct URL for image icon ....
butterflyURL[0] = Toolkit.getDefaultToolkit().createImage( "wpawn.gif");
butterflyURL[1] = Toolkit.getDefaultToolkit().createImage( "ac516.gif");
butterflyURL[2] = Toolkit.getDefaultToolkit().createImage( "wpawn.gif");
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butterflyURL[6] = Toolkit.getDefaultToolkit().createImage( "wpawn.gif");
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// but i can not tell to call just one image
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public int changeAnimation()
     { int l=picture;
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public void step( int w, int h ) {
// upgrade the translation coordinates
x += xi; y += yi;
// the x and y exceed the dimensions of canvas
if (x > w) {
x = w - 1;
xi = Math.random() * -w/32;
if (x < 0) {
x = 2;
xi = Math.random() * w/32;
if (y > h) {
y = h - 2;
yi = Math.random() * -h/32;
if (y < 0) {
y = 2;
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if (scaleDirection == UP) {
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scaleDirection = DOWN;
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if ((scale -= .05) < 0.5) {
scaleDirection = UP;
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super.paintComponent(g);
// | i call the method here
// it change to fast and i can get fix image{how can i slow it down}
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Dimension d = getSize();
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thread.setPriority(Thread.MIN_PRIORITY);
thread.start();
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public void run() {
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You've been pasting bits of your game all over the place and I also KNOW YOU'VE ALSO BEEN TOLD THIS;-
USE THE FLAMING [code] ... [/code] tags and use [j] instead of [i], or write it like this;- [ i ]
Noone will bother to read you code otherwise ... GRRRRR!

Editing Polaroid Image Viewer

So, not sure if this is the right section to put this in, so if not I'm sorry!
Anyways, I'm currently making a polaroid image viewer working off of this tutorial: http://active.tutsplus.com/tutorials/design/create-a-nifty-polaroid-photo-viewer-with-flas h-and-photoshop/comment-page-1/#comment-47571. It's my first time working in Flash, so I'm kind-of on the verge of a mental breakdown. Anyways, to my own surprise I've actually gotten it to work and look great. My issue? I'm making the overall project larger and with more images (800 x 600 with seven images). Anyways, when I publish preview the flash document it shows up 800 x 600 but all of the polaroids are squished together as though it's still 600 x 600. Is there a way that I can space them out a bit? Or, even better, is there a way that I can have each of the polaroids sit in a specific spot on the flash document?
Thanks for any help you can give, sorry if this is a really basic question. I'm just so lost, haha.

Thank you for your help! Yes, I found the following code in the Polaroid.as coding:
private function whenAdded(event:Event):void {
                              //store the Polaroid's original coordinates and rotation
                              origX = x;
                              origY = y;
                              origRotation = rotation;
And then in the PolaroidHolder.as file there's a chunk of coding that looks like this:
public function PolaroidHolder(images:Vector.<Bitmap>) {
                              // constructor code
                              for each (var image:Bitmap in images) {
                                        //create a new Polaroid
                                        var polaroid:Polaroid = new Polaroid(image);
                                        //position and rotate it
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                                        polaroids.push(polaroid);
My issue is that there are 7 polaroids on the image, not just one, so if I get rid of the random element and give it an exact location then they'll all be in the same spot. Even if there was a way to add padding to each image so that they wouldn't touch that would be amazing. I don't even know if that statment made sense, sorry, I'm so very lost with this project.

Request a .jpg image from Indesign server via script?

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I need to do something like this with InDesign Server. Is it possible to write a script specifying an Indesign Document and maybe a TextFrameID or PictureFrame ID and get a JPG rendering of it?
I know I can export the whole document as a PDF but I need to be able to get images of single textframes/pictureframes or grouped frames.
Does anyone know if this is possible or how to do this?
thanks in advance!!!
-Lloyd

Or maybe the only way to achieve this (hopefully not, though) is to export the whole document as a JPG, and then find a way to programmatically crop the part I need based on the coordinates of the textframe/pictureframe (or grouped framed) that I need?
thanks in advance,
Lloyd

How do I get the coordinates of the text block (TextFrame) help me please!

Dim myApp As New Illustrator.Application
Dim myDoc As Illustrator.Document
myDoc = myApp.ActiveDocument
Dim textRef = myDoc.TextFrames.Add
For Each ArtPageItems In myDoc.PageItems
If TypeName(ArtPageItems) = "TextFrame" Then
'========It is necessary to obtain the coordinates of the text block and move closer to the object (ie the text)============
Else
End If
Next

Hi Todd, you're welcome, please explain better, I don't understand the question.
are you trying to "move" a textframe (Dim textRef = myDoc.TextFrames.Add) closer to other text frames? or do you want to "zoom" to this textframe?

Rotated coordinates

when i rotate an image how do i get the new cordinates of the image.
This image is rotated around 0,0 but what is the coordinates of the other corners now it os rotated?
img1.rotation=_angle;

The new coordination after the rotation would be:
x' = x*cosθ - y*sinθ
y' = x*sinθ + y*cosθ
So the AS equivalent would be something like:
private function rotatedPoint(originalPoint:Point, rotation:Number):Point {
return new Point(originalPoint.x*Math.cos(rotation) - originalPoint.y*Math.sin(rotation), originalPoint.x*Math.sin(rotation) + originalPoint.y*Math.cos(rotation));
So Point(0, 20) after 10 degrees rotation would be:
trace(rotatedPoint(new Point(0, 20), 10*Math.PI/180));
// (x=-3.4729635533386065, y=19.69615506024416)
Sounds about right...?

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I am using "3D Cartesian Coordinate Rotation (Direction) (Array).vi" but this VI used Double Precision XYZ numbers.
Is there equivalent in Single Precision?
My reason is to save memory space and time. I am already using 64-bits LabVIEW with 16 GB or RAM.
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No, unfortunately LabVIEW provides very few Single Precision VIs (see my idea here). You might have success by reimplementing it yourself (it's just a matrix multiplication - look in the Help), and using the Multicore Analysis and Sparse Matrix Toolkit which does provide both SGL and DBL paralellized forms of most of the Linear Algebra VIs, among other things.

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hey, i wanna to make an animation of camera. the situation looks in this way:
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ok nevermind :]

Probleme rotation coordinate

Hi everybody,
I`m going to try to be clear, but I have juste one problem with the coordinate about a rotate rectangle.
So, first I have this data, and when I put in Excel I have a right rectangle.
SO now I know that I have to modify the data with the rotation, It`s what I did.
It worked very well, I tried with graph and to modify the degree of rotation it was perfect I had good rotated rectangle.
My next step and final step was just to put the coordinate on excel and reproduce the same rectangle on one graph in Excel.
And it`s there that I met the problem.
I have no Idea why, and I don`t see what to change to fix that......
I now that just one rotation of 90 degree it`s enough to correct the position but where can I change something?
If somenody know something about that or have the solution, you`re welcome.
Sorry about this big post but I think is more clear with picture than more text.
Thank you again for your answers (in advance)
Maxime
Solved!
Go to Solution.

Direction of rotation?
In Excel, it looks like a postive rotation causes it to rotate clockwise.
I didn't dig into your math, but in a lot of programs (like Autocad), a positive rotation angle is counter clockwise following the right hand rule. Where 0 is the + X axis and a line from there rotates towards the + Y axis with a + angle.

Coordinates of rotated textframe

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