Count distinct  from a master table and sum from a detail

Hello to all,
I have  a query like as:
         select a,b,c,     SUM(fa.ip1) S1, SUM(fa.ip2)   S2
         FROM tab1 FI, tab2 FA
         where fi.x1 = fa.x1
         and fi.x2 = fa.x2
         group by    a,b,c;
tab1's table is master table for tab2's table (one tab1 records there are   many tab2 records), (one to many relation)
My question is, how can I get to sum of columns: ip1 and ip2 from tab2 Fa, with only count(how many) of rows of tab1? 
Somethings similar to;
Select a,b,c, count(distinct fi.x1, fi.x2 ) nrec_of_FI,   SUM(fa.ip1)S1, SUM(fa.ip2)   S2
Thanks in advance

Hi,
Sorry, I can't tell what you want just by looking at code that does not do it.
Whenever you have a problem, please post a little sample data (CREATE TABLE and INSERT statements, relevant columns only) from all tables involved, so that the people who want to help you can re-create the problem and test their ideas.
Also post the results you want from that data, and an explanation of how you get those results from that data, with specific examples.
Always say which version of Oracle you're using (for example, 11.2.0.2.0).
See the forum FAQ: https://forums.oracle.com/message/9362002
Perhaps you want to get the totals in 2 stages, like this:
WITH  five_column_totals  AS
    select    a, b, c
    ,         fi.x1, fi.x2       -- For debugging only
    ,         SUM (fa.ip1)   AS prelim_S1
    ,         SUM (fa.ip2)   AS prelim_S2
    FROM      tab1 FI
    ,         tab2 FA
    where     fi.x1 = fa.x1
    and       fi.x2 = fa.x2
    group by  a, b, c
    ,         f1.x1, f2.x2
SELECT    a, b, c
,         COUNT (*)             AS nrec_of_f1
,         SUM (prelim_s1)       AS s1
,         SUM (prelim_s2)       AS s2
FROM      five_column_totals
GROUP BY  a, b, c
Notice that the sub-query called five_column_totals is essentially what you posted, except that there fi.x1 and fi.x2 are included in the GROUP BY clause.  That means the sub-query will hve a separate row for each distinct combination of x1 and x2, which you can COUNT in the main query, GROUPing only BY a, b and c.

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