Count first two columns

Hello,
I have a count requirement that i havent been able to solve by searching sdn. Maybe someone can help.
I have a query built on a multiprovider that points to two basic cubes. The basic cubes do not contain a count key figure. The first two columns of my query are characteristics. My requirement is to count the occurences of the combination of the first two column (characteristics). I am looking for a way to do this in the query so i do not have to reload the cubes as they have large volumes of data. All the suggestions i have been able to find on sdn seem to be only for counting a single characteristic. Is there a way to count the combination of two?
Regards,
TMS

Hi Create a count using the formula or calculated ket figure for the count unique id like client id for your infocube.
so you will have a count for each row now. place this count object in your column.
now select the two char or the group whatever you want a count in your row.
select query properties and select the display tab and make sure the option - hide repeated key values is selected (normally by default it is selected). Then select each of the char in rows and in free char and set the option under display tab result rows - always suppress.
Execute the query now. you will get the list of char and their count. sort the count by descending to get the most duplicate entries by their highest number on top in the count coulmn.
you can also ignore the rows which donot have a duplicate i.e count more than 1 by creating a new condintion on the count key figure > 1 and restricting the condition by only the group of char you have given in the column. so that you can also do a drill down by free char in your query and it will only show the duplicates group.
Hope it helps.
regards,
Siva

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Hi
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Hi,
MinValue     MaxValue   Desc
-1                -1
-1                 1
-1                 2
0                  0
0                  1
0                  2
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I need to update like,
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declare @T table ( MinValue int,MaxValue int, [Desc] nvarchar(100) );
insert @T ( MinValue, MaxValue )
values ( -1, 1 ) , ( -1, 1 ) , ( -1, 2), ( 0, 0), ( 0, 1), ( 0, 2)
select *
from @T
update @T
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when MinValue=-1 and MaxValue=-1 then 'NotSpecified'
when MinValue=-1 and MaxValue=1 then 'Up to 1'
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when MinValue=0 and MaxValue=1 then 'At lest 1'
when MinValue=0 and MaxValue=2 then 'At least 2'
when MinValue=0 and MaxValue=3 then 'At least 3'
end
select *
from @T
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Concatenate two Columns in OAF

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Fully Declarative Way
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Fully Programmatic Way
1. Add transient variable to your VO.
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3. Loop thru VO using an iterator.
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How do I count the unique value pairs in two columns of a table?

I have a table (Table 2) that is populated with data from an imported .csv file. On table 1 I need to count the unique value pairs in two columns of Table 2.
Here's what I have:
Date                                        Person
7/10/2011                         A
7/12/2011                         W
7/12/2011                         X
7/12/2011                         X
7/12/2011                         X
7/12/2011                         Z
7/14/2011                         Z
7/15/2011                 X
7/16/2011                         Z
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Here's the result I'm looking for (Person "X" shows up on 2 different days - 3 times on 7/12/2011 and once on 7/15/2011):
X                    2
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Hi John,
Not being allowed to modify Table 2 is a minor inconvenience. Just copy (using a formula) the necessary two columns onto Table 1.
Yellow columns may be hidden. The procedure progresses from left to right. All formulas are entered into row 2 then filled down that column to the end of the table. The table must be as long as the list in column A of Table 2.
A2: =Table 2::A
Fill right to column B.
Fill both columns down as far as needed.
I've used actual Date and Time values in column A, formatted to show only the Date part, but the technique will work with text in these cells, provided all cells representing the same 'date' have exactly the same content.
C2: =A&B
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D2: =COUNTIF($C$2:C2,C)
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E2: =IF(COUNTIF($B$2:B2,B)=1,MAX($E$1:E1)+1,"")
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Regards,
Barry

Compare two columns and match ALL recurring values, not just the first instance

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I was looking for a way to compare values in two columns, identifying every duplicate value instance on a third column.
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For example:
The first value on column A is 'Apple'. On column B there are three instances for the value 'Apple', the formula identifies the first of these values, but not the remaining two.
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Thanks in advance,
Pablo

Unfortunately I can't see your screenshot, but supposing you have a table like this:
Col1
Col2
1
3
Dupe
2
4
Dupe
3
5
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4
6
5
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Getting DISTINCT count from two different columns

Hi all,
I have following query which gives currency code from two different tables. I would like to get the distinct count of currency codes from these two different columns.
SELECT eb.person_seq_id, eb.bonus_amount, eb.currency_cd, ed.currency_cd_host
FROM fr_emp_bonuses eb, fr_emp_details ed, fr_periods p
WHERE eb.person_seq_id = ed.person_seq_id AND ed.period_seq_id = eb.period_seq_id
AND ed.period_seq_id = p.period_seq_id AND p.period_status = 'CURRENT'
AND eb.bonus_amount >= 0 AND eb.person_seq_id = 3525125;
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3525125     350000 2
Thanks in advance

Hi,
Here's one way:
WITH     original_query     AS
     SELECT eb.person_seq_id
     ,     eb.bonus_amount
     ,     eb.currency_cd
     ,     ed.currency_cd_host
     FROM     fr_emp_bonuses         eb
     ,     fr_emp_details          ed
     ,     fr_periods          p
     WHERE      eb.person_seq_id    = ed.person_seq_id
     AND      ed.period_seq_id    = eb.period_seq_id
     AND      ed.period_seq_id    = p.period_seq_id
     AND      p.period_status         = 'CURRENT'
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     AND     eb.person_seq_id    = 3525125
,     unpivoted_data     AS
     SELECT     person_seq_id
     ,     bonus_amount
     ,     currency_cd
     FROM     original_query
    UNION ALL
        SELECT person_seq_id
     ,     0               AS bonus_amount
     ,     currency_cd_host     AS currency_cd
     FROM     original_query
SELECT       person_seq_id
,       SUM (bonus_amount)          AS total_bonus_amount
,       COUNT (DISTINCT currency_cd)     AS distinct_currency_cds
FROM       unpivoted_data
GROUP BY person_seq_id
;There may be a shorter, more efficient way to get the same results, but without knowing more about your tables, I can't tell.
The tricky thing is getting two columns (currency_cd and currencuy_cd_host in this case) counted together. You can't simply say
COUNT (DISTINCT eb.currency_cd) +
COUNT (DISTINCT ed.currency_code_host)That happens to get the correct result with the sample data you posted, but what if you had data like thEe following?
currency_cd     currency_cd_host
INR          USD
USD          INRHere, the count of distinct currency_cds is 2, and the count of distinct currency_cd_hsots is also 2. Does that mean the grand total is 2 + 2 = 4? No, the 2 codes in one column arte the same 2 codes as in the other column. We need to get both currency_cd and currency_cd_hsot into the same column, and then do COUNT (DISTINCT ...) on that combined column. A UNION, as shown above, will certainly do that, starting with your query as you posted it. The query you posted isn't necessarily the best frist step towards this result, however, so there may be a much better approach, depending on your tables.
Edited by: Frank Kulash on Feb 1, 2012 6:21 PM
Here's a slightly shorter, and probably more efficient way to get the same results:
WITH     cntr     AS
     SELECT     LEVEL     AS n
     FROM     dual
     CONNECT BY     LEVEL     <= 2
SELECT       eb.person_seq_id
,       SUM (eb.bonus_amount)          AS total-amount
,       COUNT ( DISTINCT CASE
                    WHEN c.n = 1
                    THEN eb.currency_cd
                    ELSE ed.currency_cd_host
                  END
          )               AS distinct_currency_cds
FROM       fr_emp_bonuses    eb
,       fr_emp_details    ed
,       fr_periods          p
,       cntr              c
WHERE        eb.person_seq_id = ed.person_seq_id
AND        ed.period_seq_id = eb.period_seq_id
AND        ed.period_seq_id = p.period_seq_id
AND        p.period_status   = 'CURRENT'
AND        eb.bonus_amount   >= 0
AND       eb.person_seq_i   = 3525125
--       NOTE: no join condition involving c; we really do want a cross-join
GROUP BY eb.person_seq_id
;

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When you mean "incorrect results" is that associated with only Grand Totals or entire result set?
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