Count of unique values in 7 columns

Question

Hey there…
I have a Lookup table with 8 columns
ID = unique ID
U = Sunday,
M = Monday
T = Tues
W = Weds
R = Thur
F = Fri
S = Sat
Each of the ‘day’ columns can have a value between 1 and 1150, looks like this
ID U M T W R F S
1 15 15 16 15 17 345 17
What I am trying to find is a count of the deviation of each row… or how many of the days have different values
So for the above example
ID U M T W R F S COUNT
1 15 15 16 15 17 345 17 4
As there are 4 unique values in the week..
15,16,17,345
Any ideas on how that could be done in oracle? Stumped!

Answer 1

Yep, pre-11g:
CREATE TABLE temp (id INTEGER, col_1 INTEGER, col_2 INTEGER, col_3 INTEGER, col_4 INTEGER, col_5 INTEGER, col_6 INTEGER, col_7 INTEGER);
INSERT INTO temp VALUES (1000, 1, 2, 3, 4, 5, 6, 7);
INSERT INTO temp VALUES (1001, 7, 2, 3, 4, 5, 6, 7);
INSERT INTO temp VALUES (1002, 1, 1, 1, 1, 1, 1, 1);
SELECT * FROM temp
ORDER BY id;
SELECT id, COUNT (DISTINCT col)
  FROM (
SELECT id, col_1 col FROM temp UNION
SELECT id, col_2 FROM temp UNION
SELECT id, col_3 FROM temp UNION
SELECT id, col_4 FROM temp UNION
SELECT id, col_5 FROM temp UNION
SELECT id, col_6 FROM temp UNION
SELECT id, col_7 FROM temp
GROUP by id
ORDER BY 1;
Table dropped.
Table created.
1 row created.
1 row created.
1 row created.
        ID  COL_1  COL_2  COL_3  COL_4  COL_5  COL_6  COL_7
      1000      1      2      3      4      5      6      7
      1001      7      2      3      4      5      6      7
      1002      1      1      1      1      1      1      1
        ID COUNT(DISTINCTCOL)
      1000                  7
      1001                  6
      1002                  1