Count the occurence of a character in a string
Post Author: halfpat
CA Forum: Formula
Hello to everyone,
I use CR 8,0. Is anyone can tell me if this is possible:
I have a string "12345-C-1 23456-C-2 34567-C-4", how can I count the occurence of the "C" character in this string ?Is the InStr function can help me to do this ?
I appreciate any suggestion,
Thanks.
Post Author: bettername
CA Forum: Formula
How about measuring the length of the string, and subtracting the length of the same string where C is replaced with <nothing>?
len("12345-C-1 23456-C-2 34567-C-4") - len(replace("12345-C-1 23456-C-2 34567-C-4" , "C", ""))
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s=what.replaceAll(regexp,"");
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t:1
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b exists 4 time(s) in the word.
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b exists 9 time(s) in the word.
r exists 10 time(s) in the word.
t exists 11 time(s) in the word.
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public class tests {
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final char[] chars = new char[] {'a', 'b', 'c', 'd', 'e', 'f', 'g', 'h',
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int[] alphaCount = new int[26];
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for(int i=0; i<alphaCount.length; i++){
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