Count the total number of licenses of any product of my environmen
Good afternoon,
First of all thanks for the help.
I have sccm 2007 R2, I have enabled and running the asset intelligence and Reporting Services.
I need to find out what the total licenses used in any program for example, any version of Adobe or Oracle. It is possible or only asset intelligence can perform from the Reporting Services?.
The idea is to have an overview of all of Adobe licenses used on all servers of my corporation. It would be interesting to have a list of all Adobe products installed on all servers, it is possible?
Thanks again it is very urgent to me:>
Sopitas.
Do you want to know installed or actually used? This is most definitely possible with AI however what are asking for is not so easy out of the box. I personally use a
third party add-in
to accomplish this task by cleaning up and consolidating the data in the database.
John Marcum | http://myitforum.com/myitforumwp/author/johnmarcum/
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Please help !!!!Your approach is correct.
You can use a standard Query or create your own Query to run through Datainstances.
Documentation with examples for Queries in ABSL see here: https://my020062.sapbydesign.com/sap/ap/ui/repository/SAP_BYD_WEKTRA/CP/sapLSUIContentPlayerTestPage.html?manifest=067D03A7602B1D490899DF46B5082089&COMPONENT=A1S_PDI&RELEASE=260&LANGUAGE=en®ION=&INDUSTRY=&TASK=CR_VIEW&sap-language=EN
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I have parameter and data-set i.e consists of SharePoint List items,Data-set get's filters and I need to count the total rows of the data-set i.e I get after filtration.
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Hello All:
I am very new to Power Shell and need some help:
I have 224 GAL's on our Exchange System (Ex 2007) where, I need to count the total number of email addresses/display names assigned to each GAL. I am not sure how to set up a for-next loop in PowerShell. I am not sure how to set a input
file/variable, with the names of each GAL. (GAL is Global Address List)
I think it's $GALLIST = 'NameofGal1, NameofGal2, etc thru to NameofGaln' where n is the last GAL in the list.
So I need to now a command which would get all the gal names (Get-AddressList(?) for all the GAL's in the Exchange System and then pipe them into a function to count the number of email addresses.
In making a start with the following code and got stuck:
Get-Mailbox | Where {$_.GlobalAddressList -eq “GAL” -and $_.} | Select-Object Displayname, EmailAddresses, count
Missing or invalid property reference or expression.
At line:1 char:71
+ Get-Mailbox | Where {$_.GlobalAddressList -eq "GAL" -and $_.} <<<< | Select-Object Displayname, EmailAddresses, count
I think I know how to pipe the results to a csv file - with - Export-Csv -path c:\filename.csv - NoTypeInformation.
Please can someone advise. Please help.
Thanks in advance
PS - is there a way to access, read and display variable name and value which stores the number of email addresses/per GAL in exchange 2007 database so you don't have carry out a count exercise. Because this metadata will be in the Exchange DB?
Would this be easier to get?
Started building conditional statement:
Get-Mailbox | Where {$_.GlobalAddressList -eq "GAL" AND {{HiddenFromAddressListsEnabled -eq $True} OR {HiddenFromAddressListsEnabled -eq $False}} |
If {{HiddenFromAddressListsEnabled -eq $True} | Select-Object Displayname, EmailAddresses, count ELSE {HiddenFromAddressListsEnabled -eq $False}} | Select-Object Displayname, EmailAddresses, count
ENDIF
Export-Csv -path c:\test.csv -NoTypeInformation
Will this work? Checking to see how to do a for-next loop.
$GAL = Get-GlobalAddressList
foreach($GAL IN $GAL)
Get-Mailbox | Where {$_.GlobalAddressList -eq $GAL AND {{HiddenFromAddressListsEnabled -eq $True} OR {HiddenFromAddressListsEnabled -eq $False}} |
If {{HiddenFromAddressListsEnabled -eq $True} | Select-Object Displayname, EmailAddresses, count AS "Count of Hidden Addresses" ELSE {HiddenFromAddressListsEnabled -eq $False}} | Select-Object Displayname, EmailAddresses, count AS "Count of
Visible Addresses" |
Export-Csv -path c:\test.csv -NoTypeInformation |
not sure if this works and looks spaghetti -like!Hi Everton,
In addition, If you want to export GlobalAddressList, please refer to the script below:
$filter = (Get-GlobalAddressList 'Default Global Address List').RecipientFilter
#filter HiddenFromAddressListsEnabled is ture
Get-Recipient -RecipientPreviewFilter $filter | Where-Object {$_.HiddenFromAddressListsEnabled -eq $ture} | Select-Object Name,PrimarySmtpAddress
#filter HiddenFromAddressListsEnabled is false
Get-Recipient -RecipientPreviewFilter $filter | Where-Object {$_.HiddenFromAddressListsEnabled -eq $false} | Select-Object Name,PrimarySmtpAddress
Refer to:
How to Export the Exchange 2010 Default Global Address List (GAL)
If there is anything else regarding this issue, please feel free to post back.
Best Regards,
Anna Wang
Please remember to mark the replies as answers if they help and unmark them if they provide no help. If you have feedback for TechNet Support, contact [email protected] -
Dear friends,
I provide full details here ,my database table structure ,data and stored procedure and my problem ,
please review it and provide the solution or any idea to solve my problem.
I am working on a project in which members are added in a tree pattern, and get the payment accordingly.
below is my table structure ,data and stored procedure
CREATE TABLE Associate_Income
ID varchar(30) NOT NULL,
ParentID varchar(30) NULL,
IsLeft tinyint NULL,
IsRight tinyint NULL,
joingdate datetime NOT NULL
go
INSERT Associate_Income
(ID, ParentID, IsLeft, IsRight, joingdate)
SELECT 'Ramesh123', NULL, NULL, NULL '2014-01-03 16:31:15.000' UNION ALL
SELECT 'Sonu', 'Ramesh123', 1, NULL, '2014-01-03 16:45:21.000' UNION ALL
SELECT 'Pawan kumar', 'Ramesh123', NULL, 1, '2014-01-04 16:50:23.000' UNION ALL
SELECT 'Ravi123', 'Sonu', 1, NULL, '2014-01-04 17:03:22.000' UNION ALL
SELECT 'Vineet123', 'Sonu', NULL, 1, '2014-01-04 17:26:01.000' UNION ALL
SELECT 'dev123', 'Ravi123', 1, NULL, '2014-01-05 19:35:16.000' UNION ALL
SELECT 'Mukesh123', 'Ravi123', NULL, 1, '2014-01-05 19:40:41.000' UNION ALL
SELECT 'poonam123', 'Vineet123', 1, NULL, '2014-01-05 19:49:49.000' UNION ALL
SELECT 'monu', 'Pawan kumar', 1, NULL, '2014-01-05 17:32:58.000' UNION ALL
SELECT 'Arti123', 'Pawan kumar', NULL, 1, '2014-01-05 19:54:35.000' UNION ALL
My database table Associate_Income structure and data is as follow:
ID ParentID IsLeft IsRight joingdate
Ramesh123 NULL NULL NULL 2014-01-03 16:31:15.000
Sonu Ramesh123 1 NULL 2014-01-03 16:45:21.000
Pawan kumar Ramesh123 NULL 1 2014-01-04 16:50:23.000
Ravi123 Sonu 1 NULL 2014-01-04 17:03:22.000
Vineet123 Sonu NULL 1 2014-01-04 17:26:01.000
dev123 Ravi123 1 NULL 2014-01-05 19:35:16.000
Mukesh123 Ravi123 NULL 1 2014-01-05 19:40:41.000
poonam123 Vineet123 1 NULL 2014-01-05 19:49:49.000
monu Pawan kumar 1 NULL 2014-01-05 17:32:58.000
Arti123 Pawan kumar NULL 1 2014-01-05 19:54:35.000
by using below stored procedure i can count the total number of pairs under particular node in 2:1,1:1 ratio means first pair is completed when two node added to the left side of given parent node and one node added
right side of given parent node after that all pairs are completed when one node added left side and one node added right side of parent node (1:1 ratio)
example if i execute my stored procedure as follows it would return following.
EXEC count_pairs 'Ramesh123'
3
so there is 3 pairs as shown in my figure.
when we execute my stored procedure for ParentID 'sonu' it would return following.
EXEC count_pairs 'sonu'
2
so there is 2 pairs as shown in my figure.
My problem is to find the query which can return the total number of pair under particular node any given parent node. day to
day maximum 5 pairs in a day please any one can suggest us
CREATE proc [dbo].[count_pairs]
@ParentID nvarchar(50)
as
begin
Declare @ParentSUM SMALLINT = 0
Declare @SubLeftID nvarchar(50)
Declare @SubRightID nvarchar(50)
SELECT @SubLeftID = CASE WHEN [IsLeft] = 1 THEN [ID] ELSE @SubLeftID END
,@SubRightID = CASE WHEN [IsRight] = 1 THEN [ID] ELSE @SubRightID END
FROM Associate_Income
WHERE ParentID = @ParentID
IF @SubLeftID IS NOT NULL AND @SubRightID IS NOT NULL AND EXISTS(SELECT 1 FROM Associate_Income WHERE [IsLeft] = 1 AND ParentID = @SubLeftID)
BEGIN
SET @ParentSUM = 1
;WITH Associate_Income_CTE AS
SELECT [ID], [ParentID], [IsLeft], [IsRight], 0 AS [Level]
FROM Associate_Income
WHERE [ParentID] = @ParentID
UNION ALL
SELECT RecursiveMember.[ID], RecursiveMember.[ParentID], RecursiveMember.[IsLeft], RecursiveMember.[IsRight], Level + 1
FROM Associate_Income RecursiveMember
INNER JOIN Associate_Income_CTE AnchorMember
ON RecursiveMember.[ParentID] = AnchorMember.[ID]
SELECT @ParentSUM = @ParentSUM + COUNT([ParentID])
FROM
SELECT [ParentID]
,'IsLeft' AS [Direction]
,1 AS [Value]
FROM Associate_Income
WHERE [IsLeft] = 1
AND [ID] <> @ParentID --AND [ID] NOT IN (@SubLeftID, @ParentID)
AND [ParentID] NOT IN (@ParentID, @SubLeftID)
UNION ALL
SELECT [ParentID]
,'IsRight' AS [Direction]
,1 AS [Value]
FROM Associate_Income
WHERE [IsRight] = 1
AND [ParentID] <> @ParentID
) AS Associate_Income
PIVOT
MAX([Value]) FOR [Direction] IN ([IsLeft], [IsRight])
) PVT
WHERE [IsLeft] IS NOT NULL AND [IsRight] IS NOT NULL
END
SELECT @ParentSUM
Jitendra Kumar Sr. Software Developer at Ruvixo Technologies 7895253402I don't think this is homework, I am not sure how helpful it was by Kalman to merge the two threads. It appears that two different persons posted the questions. It could be though, that it is the same problem and Jitendra has taken over Chandra's
task.
However, I was not able to understand the problem nor the figure. And nor the definition of pairs in this context. My assumption is that what Jitendra posted is an abstraction of the actual problem in order to not reveal intellecutal property. Possibly this
makes the problem more difficult to understand for us outsiders.
I've come so far that I worked out a table definition and INSERT statements with sample data, as well as a call to the procedure which returns 3 and this appears to map to the figure, but I don't know what it means. Since I don't know what this
is about, I have not made any attepmts to understand the code, but I would appreciate clarification about the underlying business rules as well as the expected results for various test cases.
CREATE TABLE Associate_Income(ID varchar(30) NOT NULL,
ParentID varchar(30) NULL,
IsLeft tinyint NULL,
IsRight tinyint NULL,
joingdate datetime NOT NULL)
go
INSERT Associate_Income (ID, ParentID, IsLeft, IsRight, joingdate)
SELECT 'Ramesh123', NULL, NULL, NULL, '2014-01-03 16:31:15.000' UNION ALL
SELECT 'Sonu', 'Ramesh123', 1, NULL, '2014-01-03 16:45:21.000' UNION ALL
SELECT 'Pawan kumar', 'Ramesh123', NULL, 1, '2014-01-04 16:50:23.000' UNION ALL
SELECT 'Ravi123', 'Sonu', 1, NULL, '2014-01-04 17:03:22.000' UNION ALL
SELECT 'Vineet123', 'Sonu', NULL, 1, '2014-01-04 17:26:01.000' UNION ALL
SELECT 'dev123', 'Ravi123', 1, NULL, '2014-01-05 19:35:16.000' UNION ALL
SELECT 'Mukesh123', 'Ravi123', NULL, 1, '2014-01-05 19:40:41.000' UNION ALL
SELECT 'poonam123', 'Vineet123', 1, NULL, '2014-01-05 19:49:49.000' UNION ALL
SELECT 'monu', 'Pawan kumar', 1, NULL, '2014-01-05 17:32:58.000' UNION ALL
SELECT 'Arti123', 'Pawan kumar', NULL, 1, '2014-01-05 19:54:35.000'
go
CREATE proc [dbo].[count_pairs]
@ParentID nvarchar(50)
as
begin
Declare @ParentSUM SMALLINT = 0
Declare @SubLeftID nvarchar(50)
Declare @SubRightID nvarchar(50)
SELECT @SubLeftID = CASE WHEN [IsLeft] = 1 THEN [ID] ELSE @SubLeftID END
,@SubRightID = CASE WHEN [IsRight] = 1 THEN [ID] ELSE @SubRightID END
FROM Associate_Income
WHERE ParentID = @ParentID
IF @SubLeftID IS NOT NULL AND @SubRightID IS NOT NULL AND EXISTS(SELECT 1 FROM Associate_Income WHERE [IsLeft] = 1 AND ParentID = @SubLeftID)
BEGIN
SET @ParentSUM = 1
;WITH Associate_Income_CTE AS
SELECT [ID], [ParentID], [IsLeft], [IsRight], 0 AS [Level]
FROM Associate_Income
WHERE [ParentID] = @ParentID
UNION ALL
SELECT RecursiveMember.[ID], RecursiveMember.[ParentID], RecursiveMember.[IsLeft], RecursiveMember.[IsRight], Level + 1
FROM Associate_Income RecursiveMember
INNER JOIN Associate_Income_CTE AnchorMember
ON RecursiveMember.[ParentID] = AnchorMember.[ID]
SELECT @ParentSUM = @ParentSUM + COUNT([ParentID])
FROM
SELECT [ParentID]
,'IsLeft' AS [Direction]
,1 AS [Value]
FROM Associate_Income
WHERE [IsLeft] = 1
AND [ID] <> @ParentID --AND [ID] NOT IN (@SubLeftID, @ParentID)
AND [ParentID] NOT IN (@ParentID, @SubLeftID)
UNION ALL
SELECT [ParentID]
,'IsRight' AS [Direction]
,1 AS [Value]
FROM Associate_Income
WHERE [IsRight] = 1
AND [ParentID] <> @ParentID
) AS Associate_Income
PIVOT
MAX([Value]) FOR [Direction] IN ([IsLeft], [IsRight])
) PVT
WHERE [IsLeft] IS NOT NULL AND [IsRight] IS NOT NULL
END
SELECT @ParentSUM
END
go
EXEC count_pairs 'Ramesh123'
go
DROP PROCEDURE count_pairs
DROP TABLE Associate_Income
Erland Sommarskog, SQL Server MVP, [email protected] -
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MAny Thank in advacneCheck this http://obiee100.blogspot.com/2011/07/display-total-number-of-records-in.html
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How do I print the total number of pages in report, like Page 1 of 5?
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Check for the below code:
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DATA L_PAGE_COUNT(5) TYPE C.
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WRITE SY-PAGNO TO L_PAGE_COUNT LEFT-JUSTIFIED.
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MODIFY CURRENT LINE.
ENDDO.
TOP-OF-PAGE.
WRITE: /(70) 'Heading' CENTERED, 70 SY-PAGNO,'of ', '-----'.
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Total Pages in Basic List
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