How count the total number of instances ?

I have 2 scenarios :-
1. How to get the total number of instances of the node in a BO?
eg :
businessobject BO1   {
element BO_ID;
                   node NODE1 [0..n]
                     element Node_ID;
                     element Status ;
                     element value:
I want to get total number of the NODES instances in the particular instance of the BO1.   !!!?????
2. I want to make some calculations based on the attributes of the NODE1 , in the   BeforeSave .absl of the Business Object BO1.
eg:
something like this :-
In BeforeSave of BO1.absl -
for ( all the instances in NODE1 )
{   if (NODE1.status == true)
             sum = sum + NODE1.value
Please help !!!!

Your approach is correct.
You can use a standard Query or create your own Query to run through Datainstances.
Documentation with examples for Queries in ABSL see here: https://my020062.sapbydesign.com/sap/ap/ui/repository/SAP_BYD_WEKTRA/CP/sapLSUIContentPlayerTestPage.html?manifest=067D03A7602B1D490899DF46B5082089&COMPONENT=A1S_PDI&RELEASE=260&LANGUAGE=en&REGION=&INDUSTRY=&TASK=CR_VIEW&sap-language=EN
Looking / Clincking for "SAP Business ByDesign Scripting Language" and "Syntax for Implementation of Actions and Events" and "Query"

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Thanks for the question and Destin Joy’s reply. Please try to add the filter in the dataset level rather than the data region
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How to find the total number of pair under particular parent according to pattern 1:2or2:1,1:1 day to day maximum up to 5 pair caping daily

Dear friends,
I provide full details here ,my database table structure ,data and stored procedure and my problem ,
please review it and provide the solution or any idea to solve my problem.
I am working on a project in which members are added in a tree pattern, and get the payment accordingly.
below is my table structure ,data and stored procedure
CREATE TABLE Associate_Income
ID varchar(30) NOT NULL,
ParentID varchar(30) NULL,
IsLeft tinyint NULL,
IsRight tinyint NULL,
joingdate datetime NOT NULL
go
INSERT Associate_Income
(ID, ParentID, IsLeft, IsRight, joingdate)
SELECT 'Ramesh123', NULL, NULL, NULL '2014-01-03 16:31:15.000' UNION ALL
SELECT 'Sonu', 'Ramesh123', 1, NULL, '2014-01-03 16:45:21.000' UNION ALL
SELECT 'Pawan kumar', 'Ramesh123', NULL, 1, '2014-01-04 16:50:23.000' UNION ALL
SELECT 'Ravi123', 'Sonu', 1, NULL, '2014-01-04 17:03:22.000' UNION ALL
SELECT 'Vineet123', 'Sonu', NULL, 1, '2014-01-04 17:26:01.000' UNION ALL
SELECT 'dev123', 'Ravi123', 1, NULL, '2014-01-05 19:35:16.000' UNION ALL
SELECT 'Mukesh123', 'Ravi123', NULL, 1, '2014-01-05 19:40:41.000' UNION ALL
SELECT 'poonam123', 'Vineet123', 1, NULL, '2014-01-05 19:49:49.000' UNION ALL
SELECT 'monu', 'Pawan kumar', 1, NULL, '2014-01-05 17:32:58.000' UNION ALL
SELECT 'Arti123', 'Pawan kumar', NULL, 1, '2014-01-05 19:54:35.000' UNION ALL
My database table Associate_Income structure and data is as follow:
ID ParentID IsLeft IsRight joingdate
Ramesh123 NULL NULL NULL 2014-01-03 16:31:15.000
Sonu Ramesh123 1 NULL 2014-01-03 16:45:21.000
Pawan kumar Ramesh123 NULL 1 2014-01-04 16:50:23.000
Ravi123 Sonu 1 NULL 2014-01-04 17:03:22.000
Vineet123 Sonu NULL 1 2014-01-04 17:26:01.000
dev123 Ravi123 1 NULL 2014-01-05 19:35:16.000
Mukesh123 Ravi123 NULL 1 2014-01-05 19:40:41.000
poonam123 Vineet123 1 NULL 2014-01-05 19:49:49.000
monu Pawan kumar 1 NULL 2014-01-05 17:32:58.000
Arti123 Pawan kumar NULL 1 2014-01-05 19:54:35.000
by using below stored procedure i can count the total number of pairs under particular node in 2:1,1:1 ratio means first pair is completed when two node added to the left side of given parent node and one node added
right side of given parent node after that all pairs are completed when one node added left side and one node added right side of parent node (1:1 ratio)
example if i execute my stored procedure as follows it would return following.
EXEC count_pairs 'Ramesh123'
3
so there is 3 pairs as shown in my figure.
when we execute my stored procedure for ParentID 'sonu' it would return following.
EXEC count_pairs 'sonu'
2
so there is 2 pairs as shown in my figure.
My problem is to find the query which can return the total number of pair under particular node any given parent node. day to
day maximum 5 pairs in a day please any one can suggest us
CREATE proc [dbo].[count_pairs]
@ParentID nvarchar(50)
as
begin
Declare @ParentSUM SMALLINT = 0
Declare @SubLeftID nvarchar(50)
Declare @SubRightID nvarchar(50)
SELECT @SubLeftID = CASE WHEN [IsLeft] = 1 THEN [ID] ELSE @SubLeftID END
,@SubRightID = CASE WHEN [IsRight] = 1 THEN [ID] ELSE @SubRightID END
FROM Associate_Income
WHERE ParentID = @ParentID
IF @SubLeftID IS NOT NULL AND @SubRightID IS NOT NULL AND EXISTS(SELECT 1 FROM Associate_Income WHERE [IsLeft] = 1 AND ParentID = @SubLeftID)
BEGIN
SET @ParentSUM = 1
;WITH Associate_Income_CTE AS
SELECT [ID], [ParentID], [IsLeft], [IsRight], 0 AS [Level]
FROM Associate_Income
WHERE [ParentID] = @ParentID
UNION ALL
SELECT RecursiveMember.[ID], RecursiveMember.[ParentID], RecursiveMember.[IsLeft], RecursiveMember.[IsRight], Level + 1
FROM Associate_Income RecursiveMember
INNER JOIN Associate_Income_CTE AnchorMember
ON RecursiveMember.[ParentID] = AnchorMember.[ID]
SELECT @ParentSUM = @ParentSUM + COUNT([ParentID])
FROM
SELECT [ParentID]
,'IsLeft' AS [Direction]
,1 AS [Value]
FROM Associate_Income
WHERE [IsLeft] = 1
AND [ID] <> @ParentID --AND [ID] NOT IN (@SubLeftID, @ParentID)
AND [ParentID] NOT IN (@ParentID, @SubLeftID)
UNION ALL
SELECT [ParentID]
,'IsRight' AS [Direction]
,1 AS [Value]
FROM Associate_Income
WHERE [IsRight] = 1
AND [ParentID] <> @ParentID
) AS Associate_Income
PIVOT
MAX([Value]) FOR [Direction] IN ([IsLeft], [IsRight])
) PVT
WHERE [IsLeft] IS NOT NULL AND [IsRight] IS NOT NULL
END
SELECT @ParentSUM
Jitendra Kumar Sr. Software Developer at Ruvixo Technologies 7895253402

I don't think this is homework, I am not sure how helpful it was by Kalman to merge the two threads. It appears that two different persons posted the questions. It could be though, that it is the same problem and Jitendra has taken over Chandra's
task.
However, I was not able to understand the problem nor the figure. And nor the definition of pairs in this context. My assumption is that what Jitendra posted is an abstraction of the actual problem in order to not reveal intellecutal property. Possibly this
makes the problem more difficult to understand for us outsiders.
I've come so far that I worked out a table definition and INSERT statements with sample data, as well as a call to the procedure which returns 3 and this appears to map to the figure, but I don't know what it means. Since I don't know what this
is about, I have not made any attepmts to understand the code, but I would appreciate clarification about the underlying business rules as well as the expected results for various test cases.
CREATE TABLE Associate_Income(ID varchar(30) NOT NULL,
ParentID varchar(30) NULL,
IsLeft tinyint NULL,
IsRight tinyint NULL,
joingdate datetime NOT NULL)
go
INSERT Associate_Income (ID, ParentID, IsLeft, IsRight, joingdate)
SELECT 'Ramesh123', NULL, NULL, NULL, '2014-01-03 16:31:15.000' UNION ALL
SELECT 'Sonu', 'Ramesh123', 1, NULL, '2014-01-03 16:45:21.000' UNION ALL
SELECT 'Pawan kumar', 'Ramesh123', NULL, 1, '2014-01-04 16:50:23.000' UNION ALL
SELECT 'Ravi123', 'Sonu', 1, NULL, '2014-01-04 17:03:22.000' UNION ALL
SELECT 'Vineet123', 'Sonu', NULL, 1, '2014-01-04 17:26:01.000' UNION ALL
SELECT 'dev123', 'Ravi123', 1, NULL, '2014-01-05 19:35:16.000' UNION ALL
SELECT 'Mukesh123', 'Ravi123', NULL, 1, '2014-01-05 19:40:41.000' UNION ALL
SELECT 'poonam123', 'Vineet123', 1, NULL, '2014-01-05 19:49:49.000' UNION ALL
SELECT 'monu', 'Pawan kumar', 1, NULL, '2014-01-05 17:32:58.000' UNION ALL
SELECT 'Arti123', 'Pawan kumar', NULL, 1, '2014-01-05 19:54:35.000'
go
CREATE proc [dbo].[count_pairs]
@ParentID nvarchar(50)
as
begin
Declare @ParentSUM SMALLINT = 0
Declare @SubLeftID nvarchar(50)
Declare @SubRightID nvarchar(50)
SELECT @SubLeftID = CASE WHEN [IsLeft] = 1 THEN [ID] ELSE @SubLeftID END
,@SubRightID = CASE WHEN [IsRight] = 1 THEN [ID] ELSE @SubRightID END
FROM Associate_Income
WHERE ParentID = @ParentID
IF @SubLeftID IS NOT NULL AND @SubRightID IS NOT NULL AND EXISTS(SELECT 1 FROM Associate_Income WHERE [IsLeft] = 1 AND ParentID = @SubLeftID)
BEGIN
SET @ParentSUM = 1
;WITH Associate_Income_CTE AS
SELECT [ID], [ParentID], [IsLeft], [IsRight], 0 AS [Level]
FROM Associate_Income
WHERE [ParentID] = @ParentID
UNION ALL
SELECT RecursiveMember.[ID], RecursiveMember.[ParentID], RecursiveMember.[IsLeft], RecursiveMember.[IsRight], Level + 1
FROM Associate_Income RecursiveMember
INNER JOIN Associate_Income_CTE AnchorMember
ON RecursiveMember.[ParentID] = AnchorMember.[ID]
SELECT @ParentSUM = @ParentSUM + COUNT([ParentID])
FROM
SELECT [ParentID]
,'IsLeft' AS [Direction]
,1 AS [Value]
FROM Associate_Income
WHERE [IsLeft] = 1
AND [ID] <> @ParentID --AND [ID] NOT IN (@SubLeftID, @ParentID)
AND [ParentID] NOT IN (@ParentID, @SubLeftID)
UNION ALL
SELECT [ParentID]
,'IsRight' AS [Direction]
,1 AS [Value]
FROM Associate_Income
WHERE [IsRight] = 1
AND [ParentID] <> @ParentID
) AS Associate_Income
PIVOT
MAX([Value]) FOR [Direction] IN ([IsLeft], [IsRight])
) PVT
WHERE [IsLeft] IS NOT NULL AND [IsRight] IS NOT NULL
END
SELECT @ParentSUM
END
go
EXEC count_pairs 'Ramesh123'
go
DROP PROCEDURE count_pairs
DROP TABLE Associate_Income
Erland Sommarskog, SQL Server MVP, [email protected]

PowerShell Exchange 2007 Question To count up the total number of email addresses (view/hidden) per GAL

Hello All:
I am very new to Power Shell and need some help:
I have 224 GAL's on our Exchange System (Ex 2007) where, I need to count the total number of email addresses/display names assigned to each GAL. I am not sure how to set up a for-next loop in PowerShell. I am not sure how to set a input
file/variable, with the names of each GAL. (GAL is Global Address List)
I think it's $GALLIST = 'NameofGal1, NameofGal2, etc thru to NameofGaln' where n is the last GAL in the list.
So I need to now a command which would get all the gal names (Get-AddressList(?) for all the GAL's in the Exchange System and then pipe them into a function to count the number of email addresses.
In making a start with the following code and got stuck:
Get-Mailbox | Where {$_.GlobalAddressList -eq “GAL” -and $_.} | Select-Object Displayname, EmailAddresses, count
Missing or invalid property reference or expression.
At line:1 char:71
+ Get-Mailbox | Where {$_.GlobalAddressList -eq "GAL" -and $_.} <<<< | Select-Object Displayname, EmailAddresses, count
I think I know how to pipe the results to a csv file - with - Export-Csv -path c:\filename.csv - NoTypeInformation.
Please can someone advise. Please help.
Thanks in advance
PS - is there a way to access, read and display variable name and value which stores the number of email addresses/per GAL in exchange 2007 database so you don't have carry out a count exercise. Because this metadata will be in the Exchange DB?
Would this be easier to get?
Started building conditional statement:
Get-Mailbox | Where {$_.GlobalAddressList -eq "GAL" AND {{HiddenFromAddressListsEnabled -eq $True} OR {HiddenFromAddressListsEnabled -eq $False}} |
If {{HiddenFromAddressListsEnabled -eq $True} | Select-Object Displayname, EmailAddresses, count ELSE {HiddenFromAddressListsEnabled -eq $False}} | Select-Object Displayname, EmailAddresses, count
ENDIF
Export-Csv -path c:\test.csv -NoTypeInformation
Will this work? Checking to see how to do a for-next loop.
$GAL = Get-GlobalAddressList
foreach($GAL IN $GAL)
Get-Mailbox | Where {$_.GlobalAddressList -eq $GAL AND {{HiddenFromAddressListsEnabled -eq $True} OR {HiddenFromAddressListsEnabled -eq $False}} |
If {{HiddenFromAddressListsEnabled -eq $True} | Select-Object Displayname, EmailAddresses, count AS "Count of Hidden Addresses" ELSE {HiddenFromAddressListsEnabled -eq $False}} | Select-Object Displayname, EmailAddresses, count AS "Count of
Visible Addresses" |
Export-Csv -path c:\test.csv -NoTypeInformation |
not sure if this works and looks spaghetti -like!

Hi Everton,
In addition, If you want to export GlobalAddressList, please refer to the script below:
$filter = (Get-GlobalAddressList 'Default Global Address List').RecipientFilter
#filter HiddenFromAddressListsEnabled is ture
Get-Recipient -RecipientPreviewFilter $filter | Where-Object {$_.HiddenFromAddressListsEnabled -eq $ture} | Select-Object Name,PrimarySmtpAddress
#filter HiddenFromAddressListsEnabled is false
Get-Recipient -RecipientPreviewFilter $filter | Where-Object {$_.HiddenFromAddressListsEnabled -eq $false} | Select-Object Name,PrimarySmtpAddress
Refer to:
How to Export the Exchange 2010 Default Global Address List (GAL)
If there is anything else regarding this issue, please feel free to post back.
Best Regards,
Anna Wang
Please remember to mark the replies as answers if they help and unmark them if they provide no help. If you have feedback for TechNet Support, contact [email protected]

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hi,
i can get all the parameter names of a http request using this statement:
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but how can i get the total number of parameters which are not null?
thanks in advance

but how can i get the total number of parameters
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Hi,
I am customizing the payables remittance RTF template, our requirement is to reset page number to 1 for each payment, i am able to achieve this using "@section"
also we have a requirement to have a summary page at the end, i am able to get this using "start@last-page:body".
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i.e. suppose if i am generating remittance for 2 payments which are printing details in two pages and one page respectively, my output will have total 4 pages and it's showing
Payment1 page-1 footer -> 1 of 2
Payment1 page-2 footer -> 2 of 3
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My application requirement is client side require only limited number of data for 'Search Key' form total records found in cluster. Also i need 'total number of result count' for that key present on the custer.
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user11100190 wrote:
Hi,
Thanks for suggesting a soultion, it works well.
But apart from the count (cardinality), the client also expects the actual results. In this case, it seems that the filter will be executed twice (once for counting, then once again for generating actual resultset)
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We assume that the aggregator will execute immediately after the filter on the same node, this way aggregator will always read the count set by the filter.
You can't assume this if you have multiple client threads doing the same kind of filtering operation and you have a thread-pool configured for the cache service.
Please tell us if our approach will always work, and whether it will be efficient as compared to using Count class which requires executing filter twice.
No it won't if you used a thread-pool. Also, it might happen that Coherence will execute the filtering and the aggregation from the same client thread multiple times on the same node if some partitions were newly moved to the node which already executed the filtering+aggregation once. I don't know anything which would even prevent this being executed on a separate thread concurrently.
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1. Ensure that a ConcurrentLinkedQueue object exists in a HashMap keyed by that unique key, and
2. Enqueue the total number count you want to pass to the aggregator into that queue.
The parallel aggregator should do the following two steps while being synchronized on the HashMap.
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Best regards,
Robert

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Hi
How do I print the total number of pages in report, like Page 1 of 5?
thanks,
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Hi,
Check for the below code:
*Declare a variable
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MODIFY CURRENT LINE.
ENDDO.
TOP-OF-PAGE.
WRITE: /(70) 'Heading' CENTERED, 70 SY-PAGNO,'of ', '-----'.
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Phil Hoop

Hi Phil,
Assumes SQL 2005 or higher
Let 's try simple one ....
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If you think my suggestion is useful, please rate it as helpful.
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