Count(*) with group by and a join

Question

I've the below tables:
Tables:
EMPLOYEE
EMP_ID         LNAME             FNAME
1000                 SLITT              JOHN
1001                 SLITHER              STEVE
1002                 JACOB              MARLYN
1003                 STUFFEY     NOSE
1004                 SLIPPY              MOUTH-----
ACCESS_TYPE
ACCESS_TYPE_ID     ACCESS_DESCRIPTION
1                         EMPLOYEE
2                         EMPLOYEE_ADMIN
3                         CONTRACTOR-----
EMPLOYEE_ACCESS
ACCESS_ID      ACCESS_TYPE_ID     EMP_ID     ACCESS_EFF_DATE     
1               1               1000              01-JAN-13
2               1               1001              10-FEB-13
3               1               1002              18-FEB-13
4               2               1003              10-OCT-12
5               3               1004              10-MAR-08-----
I'm trying to figure out the count of employees group by their type and whose last name does not start with SL
I've written the query below and I'm getting a 00936 Missing Expression. What am I doing wrong? Thanks
SELECT EA.COUNT(*) , ACCESS_TYPE_ID
FROM EMPLOYEE_ACCESS EA, EMPLOYEE E
WHERE ACCESS_EFF_DATE >= '31-DEC-12' AND E.LNAME NOT LIKE 'SL%'
GROUP BY ACCESS_TYPE_ID;
Edited by: parsar on Mar 25, 2013 3:54 PM

Answer 1

thanks for the response.
If I don't use the alias prefix, which table rows will the query count because I've two tables in the from clause.
I've modified the query as below but it doesn't return any data:
SELECT COUNT(*) AS ACCESS_COUNT, ACCESS_TYPE_ID
FROM EMPLOYEE_ACCESS EA , EMPLOYEE E
WHERE EA.EMP_ID=E.EMP_ID AND
ACCESS_EFF_DATE >= TO_DATE('2012-12-31', 'YYYY-MM-DD') AND
E.LNAME NOT LIKE 'SL%'
GROUP BY ACCESS_TYPE_ID;Please let me know which part of the query I screwed up.