Cpu costing is off (consider enabling it)

Hi,
I am using Oracle 10.2.0.3.
Whenever I generate explain plan for any query, the very last line of explain plan is as below.
cpu costing is off (consider enabling it)_
It seems that optimizer didn't considerd CPU stats while generating plan for this.
How to enable CPU statistics here?
The parameter optimizer_mode value is "CHOOSE", and stats are being gathered at an interval of one week.
When I use CPU_COSTING hint in the SQL, then this line went away, and the query plan also started giving CPU % in PLAN output. But how can I make this a default behaviour of optimizer ( Any parameter etc to be set in oracle 10g for this)?
Thanks in advance.
Best Regards,
oratest

oratest wrote:
Hi,
I am using Oracle 10.2.0.3.
Whenever I generate explain plan for any query, the very last line of explain plan is as below.
cpu costing is off (consider enabling it)_
It seems that optimizer didn't considerd CPU stats while generating plan for this.
How to enable CPU statistics here?
The parameter optimizer_mode value is "CHOOSE", and stats are being gathered at an interval of one week.In your version of the database, the default value of optimizer_mode is ALL_ROWS. Is there any reason why you have changed it? You may want to post the output of following executed in SQL*Plus
show parameter optimizer

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    USB Device: Bluetooth USB Host Controller, apple_vendor_id, 0x8281, 0xfa113000 / 5
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    hi,
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    refer to his link.. http://hoopercharles.wordpress.com/2010/02/19/what-is-the-meaning-of-the-cpu-column-in-an-explain-plan/
    I like the most.
    HTH
    - Pavan Kumar N

  • How to find the cpu cost and i/o cost  by a query

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    Sounds like you want to use TRACE.
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    902181 wrote:
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      5 
      6          DBMS_SQL.parse(
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      9                  DBMS_SQL.native
    10          );
    11 
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    13  end;
    14  /
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    SQL> var childNumber number
    SQL> var sqlText varchar2(4000)
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      4          select
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      8  end;
      9  /
    PL/SQL procedure successfully completed.
    SQL>
    SQL> col PLAN_TABLE_OUTPUT format a50
    SQL> select
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             1 EXPLAINED SQL STATEMENT:
             2 ------------------------
             3 select /* TEST1 */  * from emp
             4
             5 Plan hash value: 3956160932
             6
             7 -----------------------------------------------
             8 | Id  | Operation         | Name | Cost (%CPU)|
             9 -----------------------------------------------
            10 |   0 | SELECT STATEMENT  |      |     3 (100)|
            11 |   1 |  TABLE ACCESS FULL| EMP  |     3   (0)|
            12 -----------------------------------------------
            13
    13 rows selected.
    SQL> The problem is extracting intelligence from the output as it is raw text. Perhaps not that complex as a where clause can be added to only display line id 0 and then extract the cost value from that line. Regular expressions (not my forte) will likely do this easily.

  • HT201209 Have redeemed a $20 iTunes gift card and at top shows $20 but when I go to purchase anything it is asking to use credut card? CAn anybody tell me what I need to do to make the cost come off my gift card redeemtion and not my credit card??

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    Hi Kim ...
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    Number of blocks allocated             4.205.760
    Number of empty blocks                         0
    Average space                                  0
    Chain count                                    0
    Average row length                           680
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    MBLNR                                    483.630
    MJAHR                                          3
    ZEILE                                        476
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    Number of distinct keys               38.657.400
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    Average data blocks per key                    1
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    MATNR                                     16.601
    WERKS                                         29
    LGORT                                         38
    BWART                                         52
    SOBKZ                                          5
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    Number of leaf blocks                    379.900
    Number of distinct keys                   16.601
    Average leaf blocks per key                   70
    Average data blocks per key                6.681
    Clustering factor                     35.901.000
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    MANDT                                          1
    RSNUM                                    192.208
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    Levels of B-Tree                               3
    Number of leaf blocks                    139.100
    Number of distinct keys                  404.600
    Average leaf blocks per key                    1
    Average data blocks per key                   15
    Clustering factor                      6.151.600
    NONUNIQUE  Index   MSEG~S
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    SMBLN                                        528
    SJAHR                                          4
    SMBLP                                        150
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    Levels of B-Tree                               3
    Number of leaf blocks                    182.300
    Number of distinct keys                      582
    Average leaf blocks per key                  313
    Average data blocks per key                7.110
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    Number of blocks allocated                70.524
    Number of empty blocks                         0
    Average space                                  0
    Chain count                                    0
    Average row length                           142
    Partitioned                                   NO
    NONUNIQUE  Index   MKPF~BUD
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    MANDT                                          1
    BUDAT                                        539
    MBLNR                                  2.465.167
    Last statistics date                  05.03.2012
    Analyze Method               Sample 219.184 Rows
    Levels of B-Tree                               2
    Number of leaf blocks                     12.750
    Number of distinct keys                2.499.699
    Average leaf blocks per key                    1
    Average data blocks per key                    1
    Clustering factor                      1.306.222
    NONUNIQUE  Index   MKPF~Z01
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    MANDT                                          1
    XBLNR                                     43.025
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    Analyze Method               Sample 169.933 Rows
    Levels of B-Tree                               2
    Number of leaf blocks                     15.780
    Number of distinct keys                  462.223
    Average leaf blocks per key                    1
    Average data blocks per key                    1
    Clustering factor                        587.177
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    MANDT                                          1
    MBLNR                                  2.465.167
    MJAHR                                          3
    Last statistics date                  05.03.2012
    Analyze Method               Sample 225.313 Rows
    Levels of B-Tree                               2
    Number of leaf blocks                     10.044
    Number of distinct keys                2.274.411
    Average leaf blocks per key                    1
    Average data blocks per key                    1
    Clustering factor                      1.149.849
    *And here is the standard abap coding responsible
    *SAP include
    *RM07DOCS_GENERATED
    *FORM DATA_SELECTION .     "#EC CALLED
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    * process SELECT command depending on the
    * required material selection
      if  g_cnt_matnr_total  > 0                 and
          g_cnt_matnr_total  = g_cnt_matnr_i_eq.
    *   work with .. for all entries ...
        select (g_t_fields)
        into corresponding fields of table itab
        from mkpf inner join mseg
        on    mkpf~mandt = mseg~mandt
          and mkpf~mblnr = mseg~mblnr
          and mkpf~mjahr = mseg~mjahr
        for all entries in matnr
        where matnr = matnr-low
          and MKPF~BUDAT in BUDAT
          and MSEG~BWART in BWART
          and MSEG~CHARG in CHARG
          and MSEG~KUNNR in KUNNR
          and MSEG~LFBNR in LFBNR
          and MSEG~LGORT in LGORT
          and MSEG~LIFNR in LIFNR
          and MSEG~SOBKZ in SOBKZ
          and MKPF~USNAM in USNAM
          and MKPF~VGART in VGART
          and MSEG~WERKS in WERKS
          and MKPF~XBLNR in XBLNR
    %_HINTS
    ORACLE '&SUBSTITUTE VALUES&'
      else.
    *   wor

  • What is the difference between est. cost, CPU cost, and IO cost

    When looking at and execution plan there is est. cost, CPU cost, and IO cost.
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    I have seen many program hit 10,000 cost and 1 Mio CPU cost and I need to get that down to improve performance.
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    Mikie

    Hi Olivier,
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    The amount of work to do for the database to get the job done (that is to deliver the requested results) may vary A LOT!
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    Usually there's not much you can do to the CPU costs - the database has it's internal rating concerning how "expensive" a sort-merge-join will be or a hash-distinct function.
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  • High CPU usage with double buffering enabled

    Hello all,
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  • [SOLVED] [KDE4.1] Mucho cpu use with desktop effects enabled

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    Following a suggestion by Pierre, I disabled vsync, which helped dramatically. CPU usage -- with desktop effects enabled -- has dropped from 40-60 percent to < 10 percent, usually around 2-3 percent.
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