Create Zip File In Windows and Extract Zip File In Linux
I had created a zip file (together with directory) under Windows as follow (Code are picked from [http://www.exampledepot.com/egs/java.util.zip/CreateZip.html|http://www.exampledepot.com/egs/java.util.zip/CreateZip.html] ) :
package sandbox;
import java.io.File;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.io.IOException;
import java.util.zip.ZipEntry;
import java.util.zip.ZipOutputStream;
* @author yan-cheng.cheok
public class Main {
* @param args the command line arguments
public static void main(String[] args) {
// These are the files to include in the ZIP file
String[] filenames = new String[]{"MyDirectory" + File.separator + "MyFile.txt"};
// Create a buffer for reading the files
byte[] buf = new byte[1024];
try {
// Create the ZIP file
String outFilename = "outfile.zip";
ZipOutputStream out = new ZipOutputStream(new FileOutputStream(outFilename));
// Compress the files
for (int i=0; i<filenames.length; i++) {
FileInputStream in = new FileInputStream(filenames);
// Add ZIP entry to output stream.
out.putNextEntry(new ZipEntry(filenames[i]));
// Transfer bytes from the file to the ZIP file
int len;
while ((len = in.read(buf)) > 0) {
out.write(buf, 0, len);
// Complete the entry
out.closeEntry();
in.close();
// Complete the ZIP file
out.close();
} catch (IOException e) {
e.printStackTrace();
The newly created zip file can be extracted without problem under Windows, by using [http://www.exampledepot.com/egs/java.util.zip/GetZip.html|http://www.exampledepot.com/egs/java.util.zip/GetZip.html]
However, I realize if I extract the newly created zip file under Linux, using modified version of [http://www.exampledepot.com/egs/java.util.zip/GetZip.html|http://www.exampledepot.com/egs/java.util.zip/GetZip.html] . The original version doesn't check for directory using zipEntry.isDirectory()).public static boolean extractZipFile(File zipFilePath, boolean overwrite) {
InputStream inputStream = null;
ZipInputStream zipInputStream = null;
boolean status = true;
try {
inputStream = new FileInputStream(zipFilePath);
zipInputStream = new ZipInputStream(inputStream);
final byte[] data = new byte[1024];
while (true) {
ZipEntry zipEntry = null;
FileOutputStream outputStream = null;
try {
zipEntry = zipInputStream.getNextEntry();
if (zipEntry == null) break;
final String destination = Utils.getUserDataDirectory() + zipEntry.getName();
if (overwrite == false) {
if (Utils.isFileOrDirectoryExist(destination)) continue;
if (zipEntry.isDirectory())
Utils.createCompleteDirectoryHierarchyIfDoesNotExist(destination);
else
final File file = new File(destination);
// Ensure directory is there before we write the file.
Utils.createCompleteDirectoryHierarchyIfDoesNotExist(file.getParentFile());
int size = zipInputStream.read(data);
if (size > 0) {
outputStream = new FileOutputStream(destination);
do {
outputStream.write(data, 0, size);
size = zipInputStream.read(data);
} while(size >= 0);
catch (IOException exp) {
log.error(null, exp);
status = false;
break;
finally {
if (outputStream != null) {
try {
outputStream.close();
catch (IOException exp) {
log.error(null, exp);
break;
if (zipInputStream != null) {
try {
zipInputStream.closeEntry();
catch (IOException exp) {
log.error(null, exp);
break;
} // while(true)
catch (IOException exp) {
log.error(null, exp);
status = false;
finally {
if (zipInputStream != null) {
try {
zipInputStream.close();
} catch (IOException ex) {
log.error(null, ex);
if (inputStream != null) {
try {
inputStream.close();
} catch (IOException ex) {
log.error(null, ex);
return status;
*"MyDirectory\MyFile.txt" instead of MyFile.txt being placed under folder MyDirectory.*
I try to solve the problem by changing the zip file creation code to
+String[] filenames = new String[]{"MyDirectory" + "/" + "MyFile.txt"};+
But, is this an eligible solution, by hard-coded the seperator? Will it work under Mac OS? (I do not have a Mac to try out)
p/s To be honest, I do a cross post at [http://stackoverflow.com/questions/2549766/create-zip-file-in-windows-and-extract-zip-file-in-linux|http://stackoverflow.com/questions/2549766/create-zip-file-in-windows-and-extract-zip-file-in-linux] Just want to get more opinion on this.
Edited by: yccheok on Apr 26, 2010 11:41 AM
Your solution lies in the File.separator constant; this constant will contain the path separator that is used by the operating system. No need to hardcode one, Java already has it.
edit: when it comes to paths by the way, I have the bad habit of always using the front slash ( / ). This will also work under Windows and has the added benefit of not needing to be escaped.
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drop table t1;
create table t1 (file_name varchar2(100), file_blob blob);
declare
v_new_blob blob;
v_file_name varchar2(100);
v_buffer_raw raw(1000);
v_length integer;
b_zipped_blob BLOB;
zip_files zz_zip.file_list;
t_file blob;
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dbms_lob.freetemporary(v_new_blob);
dbms_lob.createtemporary(v_new_blob,true);
v_buffer_raw := UTL_RAW.cast_to_raw('BBBBBBBBB');
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dbms_lob.writeappend(v_new_blob, v_length, v_buffer_raw);
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dbms_lob.createtemporary(v_new_blob,true);
v_buffer_raw := UTL_RAW.cast_to_raw('DDDDDDDDDDDDDDDDDDDDDDDDDD');
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dbms_lob.freetemporary(v_new_blob);
commit;
select file_name, file_blob into v_file_name, v_new_blob
from t1 where file_name = 'tmp\FileA.txt';
zz_zip.add1file(b_zipped_blob, v_file_name, v_new_blob);
select file_name, file_blob into v_file_name, v_new_blob
from t1 where file_name = 'tmp\FileB.txt';
zz_zip.add1file(b_zipped_blob, v_file_name, v_new_blob);
select file_name, file_blob into v_file_name, v_new_blob
from t1 where file_name = 'tmp\FileC.txt';
zz_zip.add1file(b_zipped_blob, v_file_name, v_new_blob);
zz_zip.finish_zip(b_zipped_blob);
zip_files := zz_zip.get_file_list( b_zipped_blob );
for i in zip_files.first() .. zip_files.last
loop
dbms_output.put_line( zip_files( i ) );
end loop;
dbms_output.put_line('--');
-- Output
FileA.txt
FileB.txt
FileC.txt
-- Save zip in t1
insert into t1 values ('ZipZZ.zip',b_zipped_blob);
commit;
-- Create new zip file and add ZipZZ.zip and FileD.txt
b_zipped_blob := null;
select file_name, file_blob into v_file_name, v_new_blob
from t1 where file_name = 'ZipZZ.zip';
zz_zip.add1file(b_zipped_blob, v_file_name, v_new_blob);
select file_name, file_blob into v_file_name, v_new_blob
from t1 where file_name = 'tmp\FileD.txt';
zz_zip.add1file(b_zipped_blob, v_file_name, v_new_blob);
zz_zip.finish_zip(b_zipped_blob);
zip_files := zz_zip.get_file_list( b_zipped_blob );
for i in zip_files.first() .. zip_files.last
loop
dbms_output.put_line( zip_files( i ) );
end loop;
dbms_output.put_line('--');
/* output
ZipZZ.zip
tmp\FileD.txt
-- save ZipXX.zip
insert into t1 values ('ZipXX.zip',b_zipped_blob);
commit;
end;
--Test with other zip files.
insert into t1 values ('File1.zip',null);
commit;
-- I've created a small zip file File1.zip using Winzip. It contains only 1 small text file File1.txt
-- I use toad to insert into blob column.
declare
v_new_blob blob;
v_file_name varchar2(100);
v_buffer_raw raw(1000);
v_length integer;
b_zipped_blob BLOB;
zip_files zz_zip.file_list;
t_file blob;
begin
select file_name, file_blob into v_file_name, v_new_blob
from t1 where file_name = 'File1.zip';
dbms_output.put_line('Blob length: '||dbms_lob.getlength(v_new_blob));
zz_zip.add1file(b_zipped_blob, v_file_name, v_new_blob);
zz_zip.finish_zip(b_zipped_blob);
zip_files := zz_zip.get_file_list( b_zipped_blob );
for i in zip_files.first() .. zip_files.last
loop
dbms_output.put_line( zip_files( i ) );
end loop;
dbms_output.put_line('--');
-- save new file as Zip1.zip
insert into t1 values ('ZipFF.zip',b_zipped_blob);
commit;
end;
Output
Blob length: 1855
File1.zip
File1.txt
Now, new zip file contains both File1.zip and File.txt.
My expected result was just File1.zip
Thanks.Your first example looks like I would expect (or do I miss something?).
Your second example is strange, but it I can't reproduce it. If I zip a zipfile with my package it contains only the zipfile:
declare
my_zip blob;
new_zip blob;
zip_files as_zip.file_list;
function file2blob(
p_dir in varchar2
, p_file_name in varchar2
return blob
is
file_lob bfile;
file_blob blob;
begin
file_lob := bfilename( p_dir
, p_file_name
dbms_lob.open( file_lob
, dbms_lob.file_readonly
dbms_lob.createtemporary( file_blob
, true
dbms_lob.loadfromfile( file_blob
, file_lob
, dbms_lob.lobmaxsize
dbms_lob.close( file_lob );
return file_blob;
exception
when others
then
if dbms_lob.isopen( file_lob ) = 1
then
dbms_lob.close( file_lob );
end if;
if dbms_lob.istemporary( file_blob ) = 1
then
dbms_lob.freetemporary( file_blob );
end if;
raise;
end;
begin
my_zip := file2blob( 'MY_DIR', 'as_fop.zip' );
dbms_output.put_line('zip file to start with');
zip_files := as_zip.get_file_list( my_zip );
for i in zip_files.first() .. zip_files.last
loop
dbms_output.put_line( zip_files( i ) );
end loop;
dbms_output.put_line('--');
-- now create a new zip file containing the existing zip file as_fop.zip
as_zip.add1file( new_zip, 'as_fop.zip', my_zip );
as_zip.finish_zip( new_zip );
-- see what's in the new zip
dbms_output.put_line('zip file containing a zipfile');
zip_files := as_zip.get_file_list( new_zip );
for i in zip_files.first() .. zip_files.last
loop
dbms_output.put_line( zip_files( i ) );
end loop;
dbms_output.put_line('--');
end;
Connected to:
Oracle Database 10g Express Edition Release 10.2.0.1.0 - Production
zip file to start with
as_fop.sql
zip file containing a zipfile
as_fop.zip
PL/SQL procedure successfully completed.
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Thank you all in advance,
CaioToOn!ejp wrote:
Thank you for the answer, but no. The path is correct.That's not what he meant. Zip file/directory entries are supposed to use / as the path separator. It is possible to use \ but such Zip files will only work under Windows. You may have erred here.Ohhh, I had really missunderstood what Ray said. But, I still think that this is not the problem, since the ZIP is a single SWF file generated by Flex SDK 3.4 and compressed in the ZLIB open standard (as in page 13, at [http://www.adobe.com/devnet/swf/pdf/swf_file_format_spec_v9.pdf|http://www.adobe.com/devnet/swf/pdf/swf_file_format_spec_v9.pdf] ). This is how Flash Compiler compress the files.
jschell wrote:
If the above suggestions do not solve the problem...Specify in detail with the exact steps used how you determined that it was corrupted.The reason why I believe the SWF is getting corrupted is that when it is loaded by Flash Player (in the client-side) the Player throws a VerifyError: Error # 1033. The [documentation says (see error 1033)|http://help.adobe.com/en_US/AS3LCR/Flash_10.0/runtimeErrors.html] that this error means that the SWF file is corrupted.
As I said, what intrigues me is that this work perfectly in a Windows Server 2008 server. I just had setup a CentOS server and deployed the application. The client-remains unchanged, so why could the result change?
raychen wrote:
I would remove the side effect you are doing and send the file straight through, with decompress and compress, the servlet. It is more likely that you have a bug in your swf processor than the zip library.
I had already tried it when first coding, in Windows Server 2008, it had not worked.
Thank you all for the help.
CaioToOn!
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