Curve 9380: Return from character input to QWERTY keyboard

Question

Hello,
I own BlackBerry Curve 9380 smartphone (all touch, without physical keyboard).
I have the following issue:
Consider you're writing a text message, when you need a question mark you're tapping on the "&% 123"  button in the left-down corner and selecting the question mark. In order to return back to the original QWERTY keyboard you need to tap on the button again, now "ABC".
Is that possible to automate the return to the QWERTY keyboard from character input keyboard after tapping the "space" button?
Keyboard is returning automatically back only if you will tap on the "Enter" button.
Adding the "space" button would be a great enhancement for touch-based devices featuring BlackBerry 7 OS.
Thank you.
P.S. I didn't find any better medium for my concern than this forum, if somebody knows how to reach directly to software engineering group, please let me know.

Answer 1

You still have the constructor declared inside the main method! :-)
public class TrySimpleVectorWithKeyboardInput
public static void main(String[] args)
public TrySimpleVectorWithKeyboardInput()
{}Move the two lines to outside the main. It should look something like this..
import java.util.*;
import java.io.*;
public class TrySimpleVectorWithKeyboardInput {
    public TrySimpleVectorWithKeyboardInput() {
      // constructor code goes here
    public static void main(String[] args)    {
        Vector names = new Vector();       
        FormattedInput kb = new FormattedInput();       
        for (int i = 0; i < 5; i++) {         
            try {           
                System.out.print("Enter a  name ");           
                names.add( kb.readString());         
            } catch (InvalidUserInputException e) {           
                System.out.println("InvalidUserInputException thrown. \n" + e.getMessage());         
        System.out.println("\nThe names in the vector are:\n ");       
        Iterator j = names.iterator();       
        while (j.hasNext()) {
            System.out.println(j.next());       
}