Date Format in received column
Hi guys, does anybody knows how to change the date format of the received column of the mails in the messenger express (6.1).
We speak spanish and we usually use the date in this format dd/mm/yyyy.
Thanks sincerely,
Andr�s.
That should be one of the things under "settings". I dont' have a Spanish version handy to check, though.
Similar Messages
-
Is there a way to customise format of received column in Outlook 2013?
I'm using Outlook 2013 on one machine.
I's like to change the date format in an email collection view to something that suits me. (Say in a Received column.)
There is a humorously named advanced settings widget, that gives me a range of preselected formats. (Including something called "Best Fit".) This however doesn't let me define my own formats.
Is there a facility that enables me define what I want?
Maybe defining a new registry key.
System wide settings (short and long date) are not the answer I'm looking for.
(In code I can define dates, where is that in Outlook?)Hi,
May I know what format you want it to be? For example, "m/d/yyyy" or others?
Actually I have found a lot of other formats beside the "Best Fit", none of them fits your need?
As you may have found in Outlook, we can customize the view to change how the time or date is displayed from the
Format dropbox, as I know, it's always based on your Windows’ defaults. There's no such registry key to modify this that I can find.
Thanks,
Melon Chen
Forum Support
Come back and mark the replies as answers if they help and unmark them if they provide no help.
If you have any feedback on our support, please click
here -
In Thunderbird, how do I change the date format for the column display?
I want the date to show as DD-MM-YYYY HH:MM AM/PM. Although this should be really obvious (and I know I've done it in the past), I can't find where to do this and can't find anything in Thunderbird Help on this, not even when I search "Thunderbird, change date format".
Thunderbird usually uses the computer date and time and settings.
I'm using Windows and notice that TB is using the short date format which I set up under Regional & Language Options.
Are you using the International settings or Date/Time settings?
It should pick up the settings from the 'International' or maybe its called now called 'Language & Text' setting.
not sure which of these suits your macbook:
http://www.macyourself.com/2008/08/31/modify-the-default-clock-in-os-xs-menu-bar-to-show-the-full-date/
http://www.dummies.com/how-to/content/language-text-preferences-on-your-macbook.html
http://www.dummies.com/how-to/content/how-to-change-your-macs-date-and-time.html
http://www.youtube.com/watch?v=2zBMl8Vb3wc
http://support.apple.com/kb/TS3579 -
Hi Experts,
I have a requirement where in I have to show my data for a column in the following way i.e into 3 different rows.
Column
Navigate to;
Value of A=10;
Value of B=20;
Now I have the Column holding the values in two rows.
Column
Navigate to;Value of A=10;
Value of B=20;
Your help is highly appreciated.
ThanksHi user,
Your requirement cant be done directly in obiee,might a work around but cant think of now.First thing tat hit my mind seeing your question is write a SQL and force it on BI.
The SQl should be written in this format,check hoek post in the below link break 1 column in to multiple
hope helps you.
Cheers,
KK -
Implicit date format conversion of report column
Hello,
The following expression defines date format for report column implicitly and doesn't reflect FSP_LANGUAGE_PREFERENCE with language independent format mask of the column attribute anymore:
decode(end_date, to_date('31.12.2047', 'dd.mm.yyyy'), null, end_date) closed
end_date is of TIMESTAMP(0) WITH LOCAL TIME ZONE type, format mask of the column attribute: DS TS
Is it expected behavior?
ThanksEdward Shevtsov wrote:
Hello,
The following expression defines date format for report column implicitly and doesn't reflect FSP_LANGUAGE_PREFERENCE with language independent format mask of the column attribute anymore:
decode(end_date, to_date('31.12.2047', 'dd.mm.yyyy'), null, end_date) closed
end_date is of TIMESTAMP(0) WITH LOCAL TIME ZONE type, format mask of the column attribute: DS TS
Is it expected behavior?
ThanksThe reason might be that you compare different datatypes in the SQL statement. The output of decode depends on those parameters.
You can cast the column to a specific datatype or you make sure that your wanted datatype is used during the decode.
example
decode(end_date, to_timestamp_tz('31.12.2047', 'dd.mm.yyyy'), null, end_date) closed
or
cast(decode(end_date, to_date('31.12.2047', 'dd.mm.yyyy'), null, end_date) as timestamp(0) with local time zone) closed -
Hi,
I have created a SQL Report with following select statement. Looks like portal has default format mask for date type as 'DD-MM-YY'.
If I put DD-MM-YYYY or DD-MM-RRRR in Format Mask field in Column Formatting screen, the reports generates 04-10-0002 . It should
be 04-10-2002.
select process_id, last_update_date
from obm
where process_id like (:process_id)
I tried to use the to_char function as following. But it errors ORA-06502:PL/SQL:numeric or value error. Even though it works fine in
my sqlplus session.
select process_id, to_char(last_update_date, 'DD-MM-YYYY')
from obm
where process_id like (:process_id)
Does anyone have any idea?
ThanksHi,
Which version of portal are you using? The error with to_char comes in 30984. This is a bug. The bug no is 2567445. A one-off has been issued. Please look in metalink for it. And for the date formatting in the column formatting section the formatting should work fine. Please check the data in your table.
Thanks,
Sharmila -
Hi All,
I have creted the snapshot as
CREATE SNAPSHOT EMPLOYEE_CRIS_MVIEW
PCTFREE 10
PCTUSED 40
MAXTRANS 255
TABLESPACE users
STORAGE (
INITIAL 40960
NEXT 73728
PCTINCREASE 1
MINEXTENTS 1
MAXEXTENTS 505
BUILD IMMEDIATE
REFRESH ON DEMAND
With rowid
AS
select
emp_id,
join_dt,
emp_stat,
from employee_CRIS
The date format for the column join_dt is dd-mon-yyyy.
But I want to modify the date format for this column as 'MM/DD/YYYY'.
For that I tried
ALTER snapshot EMPLOYEE_CRIS_MVIEW modify(TO_CHAR(join_dt,'MM/DD/YYYY'));
But I got the error
ERROR at line 1:
ORA-00902: invalid datatype
Could you please help me to change the change the date format of the column of the snapshot
with out dropping the snapshot.
Please help me.
Thanks in advance.What people are saying is that date columns (of DATE datatype) are stored internally using a fixed internal notation, which is essentially a series of bytes that describe the date.
e.g.
SQL> select empno, ename, hiredate, dump(hiredate) as dump_hiredate from emp;
EMPNO ENAME HIREDATE DUMP_HIREDATE
7369 SMITH 17/12/1980 00:00:00 Typ=12 Len=7: 119,180,12,17,1,1,1
7499 ALLEN 20/02/1981 00:00:00 Typ=12 Len=7: 119,181,2,20,1,1,1
7521 WARD 22/02/1981 00:00:00 Typ=12 Len=7: 119,181,2,22,1,1,1
7566 JONES 02/04/1981 00:00:00 Typ=12 Len=7: 119,181,4,2,1,1,1
7654 MARTIN 28/09/1981 00:00:00 Typ=12 Len=7: 119,181,9,28,1,1,1
7698 BLAKE 01/05/1981 00:00:00 Typ=12 Len=7: 119,181,5,1,1,1,1
7782 CLARK 09/06/1981 00:00:00 Typ=12 Len=7: 119,181,6,9,1,1,1
7788 SCOTT 19/04/1987 00:00:00 Typ=12 Len=7: 119,187,4,19,1,1,1
7839 KING 17/11/1981 00:00:00 Typ=12 Len=7: 119,181,11,17,1,1,1
7844 TURNER 08/09/1981 00:00:00 Typ=12 Len=7: 119,181,9,8,1,1,1
7876 ADAMS 23/05/1987 00:00:00 Typ=12 Len=7: 119,187,5,23,1,1,1
7900 JAMES 03/12/1981 00:00:00 Typ=12 Len=7: 119,181,12,3,1,1,1
7902 FORD 03/12/1981 00:00:00 Typ=12 Len=7: 119,181,12,3,1,1,1
7934 MILLER 23/01/1982 00:00:00 Typ=12 Len=7: 119,182,1,23,1,1,1
14 rows selected.Here, you can see from the dumped dates that they are all stored as 7 bytes of data, which sort of resemble the date you see on the screen in some way, but not quite. It's an internal format that Oracle understands and uses, and it's important it's stored in this way so that date arithmetic and date range comparisons can be performed easily (and quickly) in queries.
If we were to alter our sessions date format (the display format for our session only) and query the data again in the same way...
SQL> alter session set nls_date_format='YYYY-MM-DD';
Session altered.
SQL> select empno, ename, hiredate, dump(hiredate) as dump_hiredate from emp;
EMPNO ENAME HIREDATE DUMP_HIREDATE
7369 SMITH 1980-12-17 Typ=12 Len=7: 119,180,12,17,1,1,1
7499 ALLEN 1981-02-20 Typ=12 Len=7: 119,181,2,20,1,1,1
7521 WARD 1981-02-22 Typ=12 Len=7: 119,181,2,22,1,1,1
7566 JONES 1981-04-02 Typ=12 Len=7: 119,181,4,2,1,1,1
7654 MARTIN 1981-09-28 Typ=12 Len=7: 119,181,9,28,1,1,1
7698 BLAKE 1981-05-01 Typ=12 Len=7: 119,181,5,1,1,1,1
7782 CLARK 1981-06-09 Typ=12 Len=7: 119,181,6,9,1,1,1
7788 SCOTT 1987-04-19 Typ=12 Len=7: 119,187,4,19,1,1,1
7839 KING 1981-11-17 Typ=12 Len=7: 119,181,11,17,1,1,1
7844 TURNER 1981-09-08 Typ=12 Len=7: 119,181,9,8,1,1,1
7876 ADAMS 1987-05-23 Typ=12 Len=7: 119,187,5,23,1,1,1
7900 JAMES 1981-12-03 Typ=12 Len=7: 119,181,12,3,1,1,1
7902 FORD 1981-12-03 Typ=12 Len=7: 119,181,12,3,1,1,1
7934 MILLER 1982-01-23 Typ=12 Len=7: 119,182,1,23,1,1,1
14 rows selected.... whilst the hiredate is now showing on the screen in the format we've chosen, the actual internal storage of those dates remains completely unchanged. i.e. we don't have to change the format of the internal storage of dates to make them display differently.
Likewise you can format dates manually as part of your query using to_char function...
SQL> select empno, ename, to_char(hiredate,'DD Month YYYY') as hiredate, dump(hiredate) as dump_hiredate from emp;
EMPNO ENAME HIREDATE DUMP_HIREDATE
7369 SMITH 17 December 1980 Typ=12 Len=7: 119,180,12,17,1,1,1
7499 ALLEN 20 February 1981 Typ=12 Len=7: 119,181,2,20,1,1,1
7521 WARD 22 February 1981 Typ=12 Len=7: 119,181,2,22,1,1,1
7566 JONES 02 April 1981 Typ=12 Len=7: 119,181,4,2,1,1,1
7654 MARTIN 28 September 1981 Typ=12 Len=7: 119,181,9,28,1,1,1
7698 BLAKE 01 May 1981 Typ=12 Len=7: 119,181,5,1,1,1,1
7782 CLARK 09 June 1981 Typ=12 Len=7: 119,181,6,9,1,1,1
7788 SCOTT 19 April 1987 Typ=12 Len=7: 119,187,4,19,1,1,1
7839 KING 17 November 1981 Typ=12 Len=7: 119,181,11,17,1,1,1
7844 TURNER 08 September 1981 Typ=12 Len=7: 119,181,9,8,1,1,1
7876 ADAMS 23 May 1987 Typ=12 Len=7: 119,187,5,23,1,1,1
7900 JAMES 03 December 1981 Typ=12 Len=7: 119,181,12,3,1,1,1
7902 FORD 03 December 1981 Typ=12 Len=7: 119,181,12,3,1,1,1
7934 MILLER 23 January 1982 Typ=12 Len=7: 119,182,1,23,1,1,1
14 rows selected.
SQL>Again, the internal date format remains the same.
It is important that, when you store date information you store it as DATE datatype and let oracle use it's internal format, so that it can accurately do the date arithmetic, date range searches and date ordering etc., that everyone likes to do in queries. If you try and store it as VARCHAR2 then not only can information be lost (i.e. is '01/02/2010' representing 1st February 2010 or is it 2nd January 2010?) but you prevent date arithmetic, range searches and ordering in your queries from working correctly (i.e. '03/01/2009' would work out to be a greater date than '01/02/2010'). To prove it...
SQL> select 'Wrong' from dual where '03/01/2009' > '01/02/2010';
'WRON
Wrong
SQL> ed
Wrote file afiedt.buf
1* select 'Wrong' from dual where to_date('03/01/2009','DD/MM/YYYY') > to_date('01/02/2010','DD/MM/YYYY')
SQL> /
no rows selected -
Hi,
I am building a data model using a SQL query in BI Publisher, the date format of the column in the database is DD-MON-YYYY. When I use this format in BI Publisher the query returns no results:
where trim(w.date_added) = '19-MAY-2010'
I have tried using trim(to_date(w.date_added, 'YYYY-MM-DD')) = '19-MAY-2010'
This also returns no results, however when running against the database I do see resullts.
Can anyone help?
Thanks
Edited by: sliderrules on 16-Sep-2010 02:22Hi,
If I run the query in the database using date format 'DD-MON-YYYY', I do get results. The problem lies within BI Publisher query, I have tried using java date format:
trim(to_date(w.date_added, 'MM-dd-yyyy')) = '05-19-2010'
This also returns no results, the actual date format in the table appears as '19-MAY-2010' -
DATE FORMAT Conversion FOR SQL Reports
Hi,
Am building a report and am stuck here where this piece of code that throws the following error
The conversion of a varchar data type to a datetime data type resulted in an out-of-range value.
My query goes some thing like this
DECLARE @StartDate varchar(15),
@EndDate Varchar(15)
SELECT @StartDate = '01/08/2014',
@EndDate = '31/08/2014'
SELECT DISTINCT
[Operation] = CASE WHEN p.DATE_OF_START BETWEEN @StartDate AND @EndDate THEN 'Add'
ELSE 'Update' END
FROM SNZ_HR_Reporting_POSMGNT as s
LEFT OUTER JOIN PERSON as p on s.EMP_NO = p.EMP_NO
WHERE s.CHANGE_DATE BETWEEN @StartDate AND @EndDate
The date format in the column DATE_OF_START is like yyyy-mm-dd 00.00.00.000 .
My question is how to convert this format to dd/mm/yyyy format and execute the queries
Many Thanks,
BhanuSQL Date Format:
http://www.sql-server-helper.com/tips/date-formats.aspx
Please Mark This As Answer if it helps to solve the issue -
Settng Data Format Dynamically
Hi All,
How to set the data format to a column dynamically?
I have a column, which displays Amount, in a Request. For this Column, I have chosen 'Override Default Data Format' and set the 'Decimal Places' to 2.
But, for some Reports I need to display the Amount without any decimal places viz., 1234.00 ---> 1234.
How can I do this?
Thanks in Advance,
-VencyYou'd apply the formatting in the Business Model and Mapping layer - and then drag the columns into the Presentation layer.
Right mouse click the source column, click 'duplicate'. Select the duplicated column (call it what you want) click properties, and from the data type tab edit the mapping applying any format expression you want.
The other alternative is to do it in the physical layer, most of my base objects are database views so I could just add the extra column in there. -
Group by month/year from DATE FORMAT column
Hi Chaps,
I have a recordset that pulls data from a database, then presents the data in a table. The data is grouped by 'projid', repeated for every 'projid', with a show/hide control, to show all the 'jobid's' relating to that particular 'projid'
This is what I have so far:
Code:
SELECT
tbl_projects.projid,
tbl_projects.projtitle,
tbl_projects.projdue, DATE_FORMAT(tbl_projects.projdue, '%%d/%%m/%%Y') as projdue_format,
tbl_projects.projtype,
tbl_projects.projinvtype,
tbl_projects.FK_custid,
tbl_projects.projcompletedate
tbl_languaget.langtname,
tbl_doctype.doctypename,
tbl_jobs.jobid,
tbl_jobs.FK_projid,
tbl_jobs.jobname,
tbl_jobs.FK_langid,
tbl_jobs.jobpages,
tbl_jobs.jobshipped,
tbl_jobs.jobinvsent,
tbl_jobs.jobtranslatorcharge,
'tbl_jobs' as fromtable,
tbl_customers.custid,
FROM tbl_projects
INNER JOIN tbl_jobs
ON tbl_projects.projid=tbl_jobs.FK_projid
INNER JOIN tbl_languaget
ON tbl_languaget.langtid=tbl_jobs.FK_langid
INNER JOIN tbl_customers
ON tbl_customers.custid=tbl_projects.FK_custid
INNER JOIN tbl_costs
ON tbl_costs.FK_custid=tbl_customers.custid
INNER JOIN tbl_doctype
ON tbl_doctype.doctypeid=tbl_jobs.FK_doctypeid
WHERE tbl_projects.projstatus='Complete'
AND tbl_projects.projinvtype='Costing Sheet'
AND langtname!='TH'
AND langtname!='ID'
AND langtname!='KO'
AND langtname!='JP'
AND jobinvsent='y'
AND FK_custid = %s
ORDER BY projid ASC", GetSQLValueString($colname_rsInvPending, "int");
$rsInvPending = mysql_query($query_rsInvPending, $conndb2) or die(mysql_error());
//$row_rsInvPending = mysql_fetch_assoc($rsInvPending);
$totalRows_rsInvPending = mysql_num_rows($rsInvPending);
Code:
// REPEAT - FOR EVERY PROJECT
<?php
$previousProject = '';
if ($totalRows_rsInvPending > 0) {
// Show if recordset not empty
while ($row_rsInvPending = mysql_fetch_assoc($rsInvPending)) {
if ($previousProject != $row_rsInvPending['projid']) {
// for every Project, show the Project ID
?>
Code:
// SHOW/HIDE CONTROL
<tr>
<td colspan="9" class="highlight"><span class="blueBold"><a href="#" onclick="toggle2('proj1<?php echo $row_rsInvPending['projid'] ?>', this)"><img src="../../Images/plus.gif" border="0" /></a> <?php echo $row_rsInvPending['projid'] ?> - </a></span><span class="blueNOTBold"><em><?php echo $row_rsInvPending['projtitle'] ?></em></span></td>
</tr>
Code:
// SHOW/HIDE
<?php $previousProject = $row_rsInvPending['projid']; } ?>
<tr class="proj1<?php echo $row_rsInvPending['projid'] ?>" style="display:none">
<td>column 1</td>
<td>column 2</td>
What I want, is to put in another grouped by stage, where the 'projid's' themselves are in a show/hide region, grouped by 'projcompletedate' (year/month). 'projcompletedate' is in DATE format, but how to I get PHP/SQL to take the month and year and then group them correctly?Hi David, I'm not sure if I've got this right, would you mind looking at my latest code?:
<table border="0" cellpadding="0" cellspacing="0" id="tblinvoice">
<tr>
<th>Job Title</th>
<th>Type</th>
<th>Language</th>
<th>Translator</th>
<th>Total</th>
<th>Full</th>
<th>Fuzzy</th>
<th>Proof</th>
<th>Full Price</th>
<th>Discount Price</th>
<th>Document Format</th>
<th>Pages</th>
<th>Typesetting Cost</th>
<th>EN Proofreading Cost</th>
<th>Total</th>
<th>Translator Charge</th>
<th>Profit</th>
<th>Profit Percentage</th>
</tr>
<?php
$previousMonth = '';
if ($totalRows_rsInvPending > 0) {
// Show if recordset not empty
do ($row_rsInvPending = mysql_fetch_assoc($rsInvPending)) {
if ($previousMonth != $row_rsInvPending['themonth']) {
// for every Month, show the Month Name
?>
<tr>
<td colspan="18" class="highlight"><?php echo $row_rsInvPending['theyear'] ?> - <?php echo $row_rsInvPending['themonth'] ?></td>
</tr>
<?php $previousMonth = $row_rsInvPending['themonth']; } ?>
<?php
$previousProject = '';
if ($totalRows_rsInvPending > 0) {
// Show if recordset not empty
while ($row_rsInvPending = mysql_fetch_assoc($rsInvPending)) {
if ($previousProject != $row_rsInvPending['projid']) {
// for every Project, show the Project ID
?>
<tr>
<td colspan="18" class="highlight"><span class="blueBold"><a href="#" onclick="toggle2('proj1<?php echo $row_rsInvPending['projid'] ?>', this)"><img src="../../Images/plus.gif" border="0" /></a> <?php echo $row_rsInvPending['projid'] ?> - </a></span><span class="blueNOTBold"><em><?php echo $row_rsInvPending['projtitle'] ?></em></span></td>
</tr>
<?php $previousProject = $row_rsInvPending['projid']; } ?>
<tr class="proj1<?php echo $row_rsInvPending['projid'] ?>" style="display:none">
<td><?php echo $row_rsInvPending['jobname']; ?></td>
<td><?php echo $row_rsInvPending['projtype']; ?></td>
<td><?php echo $row_rsInvPending['langtname']; ?></td>
<td><?php echo $row_rsInvPending['translator']; ?></td>
<td></td>
<td></td>
<td></td>
<td></td>
<td></td>
<td></td>
<td></td>
<td></td>
<td></td>
<td></td>
<td></td>
<td></td>
<td></td>
<td></td>
<td></td>
</tr>
<?php } while ($row_rsInvPending = mysql_fetch_assoc($rsInvPending)); ?>
<?php } // Show if recordset not empty ?> -
Not able to save date column with custom date format. in OBIEE 11g
Hi,
I have migrated one report from OBIEE 10g to 11g. There is a date column with customized date format(i.e. Default format is 'dd-MMM-yyyy' and I have used 'MMM-yyyy').
But when I use this custom format and try to save the report in 11g its giving this below error.
''Catalog object privilege validation failed for user to path /shared/ALM BI/Finacial Results/History Income Statement Detail.
You do not currently have sufficient privileges to save a report or dashboard page that contains HTML markup.
This HTML might be present in column headings, table headings, text views, narrative views, the print header,
or the print footer and must be removed before saving.''
Please let me know what changes I need to do for this.
Regards,
Ambika Nanda.Hi ,
privilage issues...check the security settings once..
Thanks,
Ananth -
I am having trouble getting a numbers spreadsheet to hold different formats in the same column. A column with a date formatted heading will not convert to $ for the cells below. Any suggestions would help.
Hi Wayne,
Thank you for this response. I have tried this but when I start enterring $ amounts some, such as $6.00, go in OK others such as $4.00 appear as a date ie 4 Oct 12.
Kind regards
Paul -
DATE format - while defining the table column
Hi Friends,
I came across a piece of code which was applying a TO_DATE() function on a date type column.
I have two tables t1 and t2 and they have col1 and col2 columns respectively of type DATE
t1
col1 DATE
t2
col2 DATEalso there is a variable var1 and is defined as below:
var1 DATE;now I have conditions as below in the code:
AND to_date(t1.col1,'dd/mm/yyyy') = to_date(t2.col2,'dd/mm/yyyy')
AND to_date(t1.col1,'dd/mm/yyyy') = to_date(var1,'dd/mm/yyyy')This code failed on Production with an error: ORA-01861 literal does not match format string
I changed the code to remove TO_DATE() and it worked fine. Dev clarified that they used this function so that if the two columns or variable are in diff date format.,..they can be put in sync.
e.g. if col1 is dd/mm/yyyy and col2 is mm/dd/yyyy then there will be an issue.
My doubt is.. in a given environment if we are creating a table and defining a column of type DATE , or defining a variable of type DATE, can their format be different at any time? I think No.?
In what scenario can the date format be different?
Thanks,Having said that date format is only for display purposes, if you tend to avoid the error without changing the code then you can modify the NLS_DATE_FORMAT parameter at session level.
SQL> alter session set nls_date_format = 'dd-mm-yyyy'
2 /
Session altered.
SQL> select to_date(sysdate,'dd/mm/yyyy') from dual
2 /
TO_DATE(SY
29-12-2008
SQL> alter session set nls_date_format = 'mm-dd-yyyy'
2 /
Session altered.
SQL> select to_date(sysdate,'dd/mm/yyyy') from dual
2 /
select to_date(sysdate,'dd/mm/yyyy') from dual
ERROR at line 1:
ORA-01843: not a valid month
SQL> select to_date(sysdate,'mm/dd/yyyy') from dual
2 /
TO_DATE(SY
12-29-2008Thanks,
Karthick. -
Column data formatting in OBIEE ANSWERS
Hi,
I have a requirement of putting '-' whenever column value is NULL. I am doing this ANSWERS. I am doing this by using the below.
IFNULL(CAST("COLUMN NAME" AS CHAR),'-').
It is correctly replacing by '-' whenever data is NULL but it is also overriding default data format as Treat Text As(custom Text Format) if you look at the data format tab in the column properties. So if column has data like 23.1 it is displaying as 23.123456667777.
But I want to overwrite custom text format as number format to show as 23.1.
Please help me on this.
Thanks,
SRKI have made a solution for you :
http://gerardnico.com/weblog/2009/04/09/how-to-mix-string-and-number-data-type-in-one-column-and-get-a-sum/
Replace the condition by your value is null in the conditional formatting and you are done.
Success
Nico
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Set up assistant stuck transferring data from iMac to iMac
Hi there. I've got a 2008 iMac running Mavericks and have just upgraded to the new 27" iMac. During set up I opted to transfer my information from the old iMac using wi fi. Once I saw that it was going to take 51 hours, I found an ethernet cable and
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How do I save a number to contacts that was messaged to me?
I had one of my friends message me a number. When I clicked on the number it sent me to the call screen with the only option to call the number. I just want to save the number to my contacts.