Date function(SQL) problem.........URGENT

Hi have created a table named emp2
1* create table emp2 as select empno,hiredate,hiredate hiredate_1 from emp
SQL> /
Table created.
1* update emp2 set hiredate_1=null
where empno=7788
SQL> /
1 row updated.
SQL> select
2 empno,
3 to_char(hiredate,'dd/mm/yyyy hh24:mi')hiredate,
4 to_char(hiredate_1,'dd/mm/yyyy hh24:mi') hiredate_1
5 from emp2;
EMPNO HIREDATE HIREDATE_1
7788 19/04/1987 00:00
7839 17/11/1981 00:00 17/11/1981 00:00
7844 08/09/1981 00:00 08/09/1981 00:00
7876 23/05/1987 00:00 23/05/1987 00:00
7900 03/12/1981 00:00 03/12/1981 00:00
7902 03/12/1981 00:00 03/12/1981 00:00
7934 23/01/1982 00:00 23/01/1982 00:00
7 rows selected.
Here hiredate_1 is null only empno 7788.
but i need null value will be (hiredate 12:00)
like
7788 19/04/1987 00:00 19/04/1987 12:00
IN THIS SQL
SQL> select
2 empno,
3 to_char(hiredate,'dd/mm/yyyy hh24:mi')hiredate,
4 to_char(hiredate_1,'dd/mm/yyyy hh24:mi') hiredate_1
5 from emp2;
advance thanks
Mostafiz

Dear biswabijay
thanks
your where condition is empno = 7698. my null
value (hiredate_1)
is for empno=7788 i need value hiredate_1
1 should be empno=7788's
hiredate and time 12:00
Your code fails..
SQL> select 2 empno, 3
to_char(hiredate,'dd/mm/yyyy hh24:mi')hiredate, 4
4
to_char(nvl(hiredate_1,to_date('01/01/1987','mm/dd/yy
yy')),'dd/mm/yyyy hh24:mi') hiredate_1 5 from emp1
where empno = 7698; EMPNO HIREDATE
HIREDATE_1---------- ----------------
-------- ---------------- 7698 01/05/1981 00:00
01/01/1987 00:00
thanks
MostafizDear Sir,
I have answered to the other person USER458... that his/her code fails.. the code given below was not my code, just look at the post one step above that "code fails" post you will get your desired output.
And also I tested the SQL script with empno = 7698, that does not mean that you have to use the same empno, use your empno i.e. 7788 and you should get your desired result. The empno I used. just another case study and to check the stateent is working fine.

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