DateTime is stored as an int. How to convert to datetime format??

Question

According to the database, StartTime is stored as int: 471895438
When Viewed in the software it comes out like this: 9/29/2010
10:05:26 AM
Any ideas on how to convert this using sql?
-Tim

Answer 1

I tried to play with some "reverse engineer" to get the convert value but I dont see the logic. since I dont find a pure date that fit the convert but maybe this will help:
declare @I INT = 471895438
declare @DT datetime = '20100929 10:05:26'
select
@DT
,DATEADD(MS, @I*(-1), @DT)
,DATEADD(SECOND, @I*(-1), @DT)
--,DATEADD(MINUTE, @I*(-1), @DT) -- out of range
(No column name) (No column name) (No column name)
2010-09-29 10:05:26.000 2010-09-23 23:00:30.563 1995-10-16 16:01:28.000
by those result I guess that it is in MINUTE or SECOND
and according to those result i will need to guess that one of those convert may work for the OP:
SELECT DATEADD(MILLISECOND, @I, '2010-09-23 23:00:30.563')
SELECT DATEADD(SECOND, @I, '1995-10-16 16:01:28.000')
* I tried to use datetime2 as well and check the result for microsecond and nanosecond but the solution was not better and look like 2010-09-29 10:05:25.5281046, 2010-09-29 09:57:34.1045620
** This is really strange if someone use a value like 2010-09-23 23:00:30.563 as a base time, and even the base value 1995-10-16 16:01:28.000 then it look strange! but maybe this is the time that the developer born or some other specific time that fits his
needs :-)
** I used my birthday date (but never not a min time), several times in application that I developed as a base time :-)
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