Delay trigger

Question

Hi,
I am trying to program a Labview application.  The application monitors an analog signal.  After the signal reaches a given threshold the VI should send a digital pulse after a user specified delay.  In the attached wire diagram, I simulate the input trigger with the lower loop.  Once the counter of this loop reaches 100 it notifies the main loop with the trigger signal.  The main loop then generates a digital pulse after the given delay (delay in millisecond control).  I think I have the logic right but was wondering if there was a more efficient way to do this.
thanks
Azim 
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Attachments:
delayedTrigger_vi.jpg ‏275 KB

Answer 1

Hi zimR,
      Thank you for the Kudos!
Your message suggests that there might be another way to proceed without using a notifier. could you explain?  
Also, I notice that in the loop that waits for notification you wired the error terminal of the wait on notifier node to the case structure instead of the notification terminal.  Can you explain why you wired it this way.
I don't know why, but I thought you might need to re-trigger - in which case the Notifier method seemed to introduce a potential response latency, necessitating a different approach!
In my example the Notifier is being used to:
1) communicate an event (though we don't care what value - True or False - is sent!)
2) terminate the top loop when Notifier is destroyed (in bottom loop)
3) prevent execution of pulse when [top] loop is stopped (by Notifier destroyed)
But since we don't need to re-trigger, the top loop goes away!  So point 2) is moot and point 3) is of questionable value.
The attached example uses the Occurrance to communicate trigger-event instead of a Notifier - see warning-note on diagram!
Cheers!
Message Edited by tbd on 12-12-2008 01:19 PM
"Inside every large program is a small program struggling to get out." (attributed to Tony Hoare)
Attachments:
DelayedPulse_Occurrance.vi ‏16 KB