Different ways to get the last 5 records ordered by date
I have a query no that returns the tickets ordered by moddt, modification date,
I was thinking of adding a select on top, to get the last 5 records of that list the select already generates. An other way was to use that select to create a view,
and get the 5 last records that way. I also though of a possibly impossible cursor with a sequence, but hmm well I consider that not a good solution.
So I'm trying to find a way, using a select, the topmost select which is not completed yet, to get the last 5 records. Maybe I should just try the rownumber thing again or something likewise.
Select * from(
select * from(
Select ticketid, appliecatiecd, categorieid, substr(titel,&,200)||' ...' "titel", klantproriteitid, interneprioriteitid,
(select g.voornaam||' '||g.naam
from gebruiker g
Where g.gebruikerid = t.gebruikerid
And t.applicatiecd = NVL(:P0_applicatiecd, :F101_applicatiecd))"aangemaakt door",
(select s.statusdefoms "status"
From status s
Where s.statusid = t.statusid
And t.applicatiecd = NVL(:P0_applicatiecd, :F101_applicatiecd)) "status",
Versieid,
Moddt,
Row_number() over (order by ticketid desc) rn
From ticket t
Where applicatiecd = NVL(:P0_applicatiecd, :F101_applicatiecd) )
Order by moddt)
Where --
Hi Floris,
You can also use RANK: http://www.dba-oracle.com/oracle_news/oracle_faq/faq_beg_sql_top_n_rows.htm
Regards Pete
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