Display multiple record block in multiple canvases

Hi,
I am facing a problem while creating multiple canvases with the same blocks.
I have block A, B, C. Block B and C are detail of A. I want items from blocks B and C to appear in multiple canvases. I tried doing the synchronize with item. It works fine but I cannot see the scrollbar in other canvas. Is it possible to show scrollbar in multiple canvases?
Thanks in advance.
DK

If you mean that you want the scrollbar of the same block to be appeared on multiple canvases where items of this block are placed in different canvases... unfortunately... you cannot....
Greetings...
Sim

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Display multiple records in forms 6i

hi every body
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Hi Friends,
I have problem in update Statement for updating the record in multiple record data Block.
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Please Guide me
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As you do a loop over all the records in the block, of course every record is updated.
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Hello All,
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PHP MySQL
I have a MySQL table with several columns and multiple
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Nancy Gill
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Author: Dreamweaver 8 e-book for the DMX Zone
Co-Author: Dreamweaver MX: Instant Troubleshooter (August,
2003)
Technical Editor: DMX 2004: The Complete Reference, DMX 2004:
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"Jeff" <[email protected]> wrote in message
news:erindt$i70$[email protected]..
> PHP MySQL
> I have a MySQL table with several columns and multiple
records... it is
> easy to display these records in a <table> using
the repeat record server
> behavior applied to the <tr> that displays the
records.
>
> I would like to do this with CSS and eleminate
<table>'s
> My question is can this be done displaying the records
in a <div> using
> the repeat record server behavior?
> Or is this just one of those things that a <table>
is required?
>
> Jeff
>

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The event is as follows:
BEGIN:VCALENDAR
VERSION:2.0
PRODID:-//Apple Inc.//iCal 3.0//EN
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UID:EC6F5DBC-9BCC-4007-87F2-4A9C796C8551
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Post Author: foghat
CA Forum: Data Connectivity and SQL
If all the records you are displaying in your report
truly are duplicated, you could try check off 'select distinct records'
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likely the records aren't an exact duplicate and the problem is with your join criteria. To verify this you can: start by removing table b from the database expert altogether. does
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Display multiple paging

hello all,
i am having problem to paging my result in multiple pages. i'm already searching in this forum on how to solve on paging pages but none of them can help me. here is my code..
// paging section
int rownumb = listof.countData(offer_type);
out.println("row : " +rownumb);
int perpage = 2;
int pageno = rownumb/perpage;
int balance = rownumb - (pageno * perpage);
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<font color="#ff3366"><%=i%></font>
<% }
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function countData
String query = SELECT count(*) FROM offer
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function queryCategory
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</a>

I can offer my 2-cents but...
I'm assuming you are using a MySQL database. What does your query return when you run it from the MySQL prompt? It's good practice to execute your queries in some SQL client before hand.
From MySQL Reference Manual:
The LIMIT clause can be used to constrain the number of rows returned by the SELECT statement. LIMIT takes one or two numeric arguments.
If two arguments are given, the first specified the offset of the first row to return; the second specifies the maximum number of rows to return. The offset of the initial row is 0 (not 1):
mysql> select * from table LIMIT 5,10; # Retrieve rows 6-15
If one argument is given, it indicates the maximum number of rows to return:
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Just a note, LIMIT performs much faster on large result sets, however, it is a non-standard MySQL extension, and therefore, it is suggested to avoid using it in queries.
First thing I can see is that the way you are using LIMIT, the first two records will always be returned. You would need to pass two parameters (or at least one -> start) to queryCategory, i.e.
public void queryCatetory(int start, int count)
String query = "... LIMIT " + start + "," + count;
Also, you don't need to execute another query (the countData function) to get the record count, simply move the ResultSet cursor to the last position and get the row number, i.e.
rs.last();
noRows = rs.getRow();
For the pageno value, this is what you should be getting as a parameter to the page.
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For the query paging part, I can offer this bit of code which might help:
final int ROW_COUNT = 10;
int currPage, rowStart, rowStop, totalPages, noRows;
String scriptName = request.getRequestURI();
String query = "SELECT offerid, otitle, odescription, oposted_date, oexpiry_date FROM offer WHERE otype='"+offer_type+"' AND ostatus='posted' AND (oposted_date <= '"+currentDate+"' AND oexpiry_date >= '"+currentDate+"') ORDER BY offerid";
// get the page parameter
try { currPage = Integer.parseInt(request.getParameter("pageno"); }
catch (NumberFormatException e) { currPage = 1; }
// connect to database and execute query
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ResultSet rs = stmt.executeQuery();
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rs.last();
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if (noRows == 0)
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else
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// if current page is 2, we want to display records 11-20
rowStart = (currPage - 1) * ROW_COUNT + 1;
// alternatively, you can do:
// rowStop = Math.min(noRows, currPage * ROW_COUNT);
rowStop = Math.min(noRows, rowStart + ROW_COUNT - 1);
// division by integer yeilds a truncated integer value so we
// have to check for a remainder, but you can also do:
// totalPages = (int)Math.ceil(ROW_TOTAL / (ROW_COUNT * 1.0));
totalPages = (noRows / ROW_COUNT) + (noRows % ROW_COUNT == 0 ? 0 : 1);
// set result set to start position and print the records
rs.absolute(rowStart);
for (int row = rowStart; row <= rowStop; row++)
// display current record data
rs.next();
// print query paging links
out.print("<p align=\"center\">");
if (currPage > 1)
out.print(" <a href=\"" + scriptName + "?pageno=" + (currPage - 1) + "\">< Prev</a>");
for (int i = 1; i <= totalPages; i++)
if (i == currPage)
out.print(" <b>" + i + "</b>");
else
out.print(" <a href=\"" + scriptName + "?pageno=" + i + "\">" + i + "</a>");
if (currPage < totalPages)
out.print(" <a href=\"" + scriptName + "?pageno=" + (currPage + 1) + "\">Next ></a>");
out.print("</p>");
I'm sure there is a more elegant solution out there. I believe that the standard taglib has some tags which can do this for you. Hopefully someone can confirm this can possibly provide further details.
Hope this helps :)

Display multiple record block in multiple canvases

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