Distance between two objects

Hi folks,
Who knows how I can discover the distance between two selected objects without using neither guides nor grids?
Thanks.

How do imagine this would working without using guides or grids? The way I normally do it is:
1. Drag out a guide to point A
2. Drag out a guide to point B
3. Hold shift and put the mouse cursoe between the two -- it shows you the distance
You could also use the measuring tool (click and hold the rectangle tool in the tool pallette.)
Or even just draw a rectangle and look at the width in the property panel. That's a fast and easy method I use sometimes.
Aaron Beall
http://fireworks.abeall.com

Similar Messages

How to get the distance between two object!!!

I have two GEOM object and want to know the distance between them, may u give me some solution to find the distance between them.

Hi!,
SDO_GEOM.SDO_DISTANCE
see: http://www.oracle.com/technology/documentation/spatial.html
regards, Andreas

Maintain distance between two objects

hi evryone,
i am trying to develop a simple car game, and to do that i have to maintain the distance between the two wheels.
for the collision detection i have used coreyoneil class, which i think is excellent. i cant get the distances to go smoothly. and basically i am finding it hard to get the physics to work. if anyone has an idea what i should do, or has a good example it would be greatly appreaciated.
i have attached the swf and fla for you to see.
thanks.

Basically you can put them together in a sprite, or you might even thing of using box2d or quickbox2d.
if that doesn't work with your setup then you might have a look in here:
http://www.gotoandplay.it/_articles/2004/12/inverseKinematics.php

Additional data on relationship between two objects

Hi
We have a requirement to capture additional data on a relationship between two objects. The data to be captured are custom fields that are unique to the relationship between the objects and not specific to either of the objects.
We created a new object type and related it to the position (S)and the job (C) object. In the customising (Personnel Management/Personnel Development/Basic Settings/Maintain Relationships there is an option to set up Additional Data. There are however several restrictions (e.g. the substructure has to be in T77AD). When you set up an existing substructure (e.g. PAD22) and screen (e.g. 3000), it works really well, however we have not been able to get this to read our own substructure and screen (since there is no customer include on HRP1001 and the 'Additional data' button seems to go to MP100100 to find the screen).
My question is two fold:
a) Is this an allowed customisation (e.g. can we create our own substructure, screen and Query string)? And if so, how does the data get into T77AD (since SAP recommends that data should not be added to this table)? and
b) Is there any documentation on this (thus far I have only received info on how to enhance infotypes which I don't think is relevant???)?
If this can not be maintained is there any other suggestions on how to deal with this scenario?
Any assistance will be appreciated.
Regards
Liezl

Hi everyone
Thanks for everyone who tried to assist us with this. I am happy to report that our in-house guru's have found the answer. So, for anyone who is interested:
In programme MP100100 you have a screen 6000 which is a customer enhancements screen. We set up two in-house function modules for the PBO and PAI with its own screen and added an append structure to PAD31 to add the fields required. In the configuration, we then specified PAD31 as the substructure with screen 6000 and then also specified our own PBO and PAI function modules. The parameters required for screen 6000 is set up within our own customer screens.
Hope this will be helpful to someone - it certainly seemed to open up some doors for us!
Regards
Liezl

Is there any css to vary the distance between two items in apex

Hi,
Is there any css to vary the distance between two items ie two columns horizontally / vertically in apex application at page line level
Regards,
Pavan

Hi ,
I done what u suggested above but i ll tel u clearly
i have name,plot no,street,city,distict,state,country,phone no,pincode items.. i need to align this items like
--------------------------------------------------------------------------main region----------------------------------------------------------------------------
--left region-------------------------------------------middle region------------------------------------------------------right region-------------------
name,___________
plot no,_________
street,________
city,___________                                    distict,_________
state,__________                                   country,_________                                                  nothing in it
phone no,__________                              pincode_________
to achieve this wat i have to do
Thanks,
pavan

Shortest distance between two line segments

Hi.
I am looking for the code of the "Shortest distance between two line segments". I would appreciate if anyone has and willing to share.
I can find some in the net but its in VB and i am not familiar with it.
THanks a lot.
regards,

There are a couple of things that are not clear:
What determines the rotation speed and lenght of each stick at any given time?
What is the program allowed to do to prevent collision (change speed/direction, change radius, stop everything)
Since you want to prevent collision, you need a predictive algorithm. Once they overlap, the collision has already happened. Too late!
What information does your algorithm get (e.g. r1, r2, theta1, theta2, delta-thetat1, delta-theta2, etc.), i.e. does the program only get static information and need to construct the trajectory from sequential history data or does it get dynamic information about speed and direction?
The trivial answer would be to just keep r1+r2 < distance(P1,P2). This will prevent all "potential" collisions.
LabVIEW Champion . Do more with less code and in less time .

Finding Distance between two zipcodes with longtitude and latitude

Want to find distance between two zipcodes that have their latitude and longitude stored in a table.
The table is as follows
CREATE TABLE distance (zipcode VARCHAR2, LNG NUMBER, LAT NUMBER)
I couldn't come up with a calculation or understand the mathematical calculation on line.. Can you help me with some stored procedure that will do..?
Thanks

There is no logical complexity in your query besides knowing the basics of
http://en.wikipedia.org/wiki/Spherical_coordinates
Also, the table name "Distance" cannot be more confusing; what you have is essentially "PointsOnSphere".
select R*sqrt(
(sin(pi-p1.lng)*cos(p1.lat)-sin(pi-p2.lng)*cos(p2.lat))* (sin(pi-p1.lng)*cos(p1.lat)-sin(pi-p2.lng)*cos(p2.lat))
+
(sin(pi-p1.lng)*sin(p1.lat)-sin(pi-p2.lng)*sin(p2.lat))*
(sin(pi-p1.lng)*sin(p1.lat)-sin(pi-p2.lng)*sin(p2.lat))
+
(cos(pi-p1.lng)-cos(pi-p2.lng))*(cos(pi-p1.lng)-cos(pi-p2.lng))
from distance p1, distance p2
where R is the radius of Earth, and pi=3. Don't forget to convert angular degrees into radiants before you plug in them into the query above
Correction: This was euclidean distance sqrt((x1-x2)^2+(y1-y2)^2+(z1-z2)^2) between the points (x1,y1,z1) and (x2,y2,z2). Spherical distance is
sqrt(
(R*(colatitude1-colatitude2))^2+
(R*sin(colatitude1-colatitude2)*(longtitude1-longtitude2))^2
Message was edited by:
Vadim Tropashko

How to draw a line(shortest distance) between two ellipse using SWING

how to draw a line(should be shortest distance) between two ellipse using SWING
any help will be appreciated
regards

import java.awt.*;
import java.awt.event.*;
import java.awt.geom.*;
import javax.swing.*;
import javax.swing.event.MouseInputAdapter;
public class ELine extends JPanel {
    Ellipse2D.Double red = new Ellipse2D.Double(150,110,75,165);
    Ellipse2D.Double blue = new Ellipse2D.Double(150,50,100,50);
    Line2D.Double line = new Line2D.Double();
    protected void paintComponent(Graphics g) {
        super.paintComponent(g);
        Graphics2D g2 = (Graphics2D)g;
        g2.setRenderingHint(RenderingHints.KEY_ANTIALIASING,
                            RenderingHints.VALUE_ANTIALIAS_ON);
        g2.setPaint(Color.green.darker());
        g2.draw(line);
        g2.setPaint(Color.blue);
        g2.draw(blue);
        g2.setPaint(Color.red);
        g2.draw(red);
    private void connect() {
        double flatness = 0.01;
        PathIterator pit = blue.getPathIterator(null, flatness);
        double[] coords = new double[2];
        double x1 = 0, y1 = 0, x2 = 0, y2 = 0;
        double min = Double.MAX_VALUE;
        while(!pit.isDone()) {
            int type = pit.currentSegment(coords);
            switch(type) {
                case PathIterator.SEG_MOVETO:
                case PathIterator.SEG_LINETO:
                    Point2D.Double p = getClosestPoint(coords[0], coords[1]);
                    double dist = p.distance(coords[0], coords[1]);
                    if(dist < min) {
                        min = dist;
                        x1 = coords[0];
                        y1 = coords[1];
                        x2 = p.x;
                        y2 = p.y;
                    break;
                case PathIterator.SEG_CLOSE:
                    break;
                default:
                    System.out.println("blue type: " + type);
            pit.next();
        line.setLine(x1, y1, x2, y2);
    private Point2D.Double getClosestPoint(double x, double y) {
        double flatness = 0.01;
        PathIterator pit = red.getPathIterator(null, flatness);
        double[] coords = new double[2];
        Point2D.Double p = new Point2D.Double();
        double min = Double.MAX_VALUE;
        while(!pit.isDone()) {
            int type = pit.currentSegment(coords);
            switch(type) {
                case PathIterator.SEG_MOVETO:
                case PathIterator.SEG_LINETO:
                    double dist = Point2D.distance(x, y, coords[0], coords[1]);
                    if(dist < min) {
                        min = dist;
                        p.setLocation(coords[0], coords[1]);
                    break;
                case PathIterator.SEG_CLOSE:
                    break;
                default:
                    System.out.println("red type: " + type);
            pit.next();
        return p;
    public static void main(String[] args) {
        final ELine test = new ELine();
        test.addMouseListener(test.mia);
        test.addMouseMotionListener(test.mia);
        JFrame f = new JFrame();
        f.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
        f.add(test);
        f.setSize(400,400);
        f.setLocation(200,200);
        f.setVisible(true);
        EventQueue.invokeLater(new Runnable() {
            public void run() {
                Graphics g = test.getGraphics();
                g.drawString("drag me", 175, 80);
                g.dispose();
    private MouseInputAdapter mia = new MouseInputAdapter() {
        Point2D.Double offset = new Point2D.Double();
        boolean dragging = false;
        public void mousePressed(MouseEvent e) {
            Point p = e.getPoint();
            if(blue.contains(p)) {
                offset.x = p.x - blue.x;
                offset.y = p.y - blue.y;
                dragging = true;
        public void mouseReleased(MouseEvent e) {
            dragging = false;
        public void mouseDragged(MouseEvent e) {
            if(dragging) {
                double x = e.getX() - offset.x;
                double y = e.getY() - offset.y;
                blue.setFrame(x, y, blue.width, blue.height);
                connect();
                repaint();
}

Distance between two PCIe x 16 slot of P55 GD85

Hello,
Does anyone have an idea what is the clear distance between two PCIe x 16 slot of P55 GD85? planning to get one if my 2 x GTX 285 with modified cooling fan will fit in. each VGA with modified fan is around 55mm in height.
thank you,

Exactly, there was no "rude" intention or the will to provoke you behind my previous answer. In fact, I spent 15 minutes to find a ruler in order to measure the port distance on three different ATX Board to make sure I am not telling you anything wrong. I would not have bothered to do that if I had been planning to write a rude reply.
[On the flip side: Personally, I find it kind of rude that you are accusing me of 'rudeness'. However, I suggest we better drop the whole 'who is really being rude here' discussion.]
Quote
The distance between the center lines of two neighbouring slots is always ~ 2.05cm. There are two slots between the PCI-E-x16 slots of the P55-DG85. Simply do the math!
Quote
I am not a mathematician
The distance between the center lines of the two PCI-E-x16-slots of the P55-GD85 is ~6.15cm (there are two more slots in between --> 2.05cm x 3).
This means that this ...
Quote
each VGA with modified fan is around 55mm in height.
... should actually fit.

Distance between two pixel in screen

Hi all ,
How can I get the distance between two pixel of the screen .
Thanks and Regards
Anshuman Srivastava

You're welcome. Do spend more time with the API, there are a wealth of methods available in classes like Toolkit, SwingUtilities, Utilities and Robot that help solve many rather obscure problems.
db

Distance between two GPS points

Is there an inbuilt function in PL/SQL for calulating the distance between two GPS (lat/long) points?
I'm using Oracle 9i. There's a thing called SDO_GEOM available, but I'm not sure if this is what its used for or if it's the best option.

If the earth is a complete globe and its circumference is 40000km,
I make the function as follows.
create ore replace
function distance
(a_lat number,a_lon number,b_lat number, b_lon number)
return number is
circum number := 40000; -- kilometers
pai number := acos(-1);
a_nx number;
a_ny number;
a_nz number;
b_nx number;
b_ny number;
b_nz number;
inner_product number;
begin
if (a_lat=b_lat) and (a_lon=b_lon) then
return 0;
else
a_nx := cos(a_lat*pai/180) * cos(a_lon*pai/180);
a_ny := cos(a_lat*pai/180) * sin(a_lon*pai/180);
a_nz := sin(a_lat*pai/180);
b_nx := cos(b_lat*pai/180) * co s(b_lon*pai/180);
b_ny := cos(b_lat*pai/180) * sin(b_lon*pai/180);
b_nz := sin(b_lat*pai/180);
inner_product := a_nx*b_nx + a_ny*b_ny + a_nz*b_nz;
if inner_product > 1 then
return 0;
else
return (circum*acos(inner_product))/(2*pai);
end if;
end if;
end;
I rewrite it by using the factorization and the triangle function's sum and difference formulas:
cos(x-y) = cos(x)cos(y)+sin(x)sin(y)
As result, this function is same to the 1st method of Billy Verreynne.
create or replace
function distance
(a_lat number,a_lon number,b_lat number, b_lon number)
return number is
circum number := 40000; -- kilometers
pai number := acos(-1);
dz number;
dx2y2 number;
inner_product number;
begin
if (a_lat=b_lat) and (a_lon=b_lon) then
return 0;
else
dz := sin(a_lat*pai/180)*sin(b_lat*pai/180);
dx2y2 := cos(a_lat*pai/180)*cos(b_lat*pai/180)*cos((a_lon-b_lon)*pai/180);
inner_product := dz*dz + dx2y2;
if inner_product > 1 then
return 0;
else
return (circum*acos(inner_product))/(2*pai);
end if;
end if;
end;
Message was edited by:
ushitaki

How to measure distance between two points uisng uiaccelerometer

Hello all,
I am trying to measure distance between two points.So for that i am used uiaccelerometer but its give only rotation changes. I am moving my whole device from one point to another point so for that all x,y & z changes remain same. So how can get the device movement for that?
Thank you..

UIAccelerometer does not give rotation changes, it senses acceleration in each of the 3 axis in g-force units. Moving in a plane from one point to another and stopping will result in a net g-force in that axis of zero. To get distance one has to measure the initial acceleration and then the time before a deceleration is detected. It gets really complicated in real life since the start and stop are not instantaneous.

Find driving distance between two points without using API by use of Lat & Long?

Using Google geocode API : http://maps.googleapis.com/maps/api/geocode/xml?address=thane&sensor=true
We performed get distance between search criteria entered by user and all related clubs by lat & long stored at db.
2. Two different points such as
(origin: Lat1 & Long1) and (destination: Lat2 & Long2)
We tried for to get distance between these two points,
(Lat2 & Long2) to (Lat1 & Long1)
But distance which we get by calculation is simple straight line distance
Origin Destination
(Lat1 & Long1) (Lat2 & Long2)
3. This is not driving distance as google shows in exact Km
4. For that Google provide another API (distancematrix API)
http://maps.googleapis.com/maps/api/distancematrix/xml?origins=Thane&sensor=true&destinations=khopat&mode=driving&language=en%20-%20EN
5. But there is limit for DistanceMatrix-Service without ClientID and client key
100 elements per query.
100 elements per 10 seconds.
2 500 elements per 24 hour period.
But as element request exceeds it shows : OVER_QUERY_LIMIT error
6. In case of Client ID and Client key
In Distance Matrix 100 000 elements per 24 hour period,a maximum of 625 elements per query and a maximum of 1 000 elements per 10 seconds.
As per this one there is option to get purchase these API but basic question is remain same for us if we are requesting single origin and multiple destination then how element calculation done by google?
But in document google says :
Elements
The information about each origin-destination pairing is returned in an element entry. An element contains the following fields:
Status: See Status Codes for a list of possible status codes.
Duration: The duration of this route, expressed in seconds (the value field) and as text. The textual representation is localized according to
the query's language parameter.
Distance: The total distance of this route, expressed in meters (value) and as text. The textual value uses the unit system specified with the
unit parameter of the original request, or the origin's region.

Any information that you see in a google map webpage can be retrieved using the API. The best way of finding the tags on the webpage is to manually perform the query using an IE webpage. Then capture the source and save to a file so you
can use a text editor to look at results. I often on a webpage use the menu : View - Source and then copy the source to a text file.
jdweng

Event dispatch between two objects not received

Hi,
In my application there are two objects: one is
myAc:ArrayCollection and the second is a mySprite:Sprite. myAC
stores coordinates and other custom fields of the mySprite objects.
I would like the sprite object to dispatch an event to the
array so that when changes are made to the mySprite object the myAC
can update itself.
In the mySprite object I have added the following code to
dispatch the event.
var e:Event = new Event("spriteMove", true);
dispatchEvent(e);
trace("dispatched");
In the myAC object I have set the following listener
this.addEventListener("spriteMove", spriteMoveHandler, true);
private function spriteMoveHandler( event:Event ):void
trace("recd event");
var sp:Object = event.target;
trace(sp.x);
I do not receive the event in the myAC object.
However, when I set a similar thing between the mySprite
object and one of its subobjects viz. myPoint I am able to receive
the event.
Thanks for the help,
Raju

Please do not duplicate your posts. It can be very confusing when two different persons answer the post in different ways.

Angle between two objects approximated as lines

Hi there,
I have NI Vision and have been wondering the best way to get the angle of two objects that has been approximated by a line (say using edge detection). I have attached one frame of the avi file for your perusal. The scene is changing from frame to frame where the objects are constantly being shifted and rotated. I can track either the small object or the big object in isolation using pattern matching algorithms but the issue lies in moving the edge detection rake from frame to frame for two objects in a single trial. Please advise.
Cheers, B.
Attachments:
example.jpg ‏20 KB

Hi,
You can do this in several ways. The straight forward way would be to use the trigonometric funtions. If you filter the image you are acquiring to get the co-ordinates of the edges of the stick and also the refence to ground, as shown in the image attached, you can use the known values to calculate the angle the stick is aligned to ground.
Here, treat the picture as a 2D image, get the x,y co-ordinates of the point of interception (C) and the co-ordinates of a point in your stick (A). The difference in value of y between A and ground is your "p" and the difference in value of x between C and x value of the point (A) is your "b". Use the supplied equation to work out the angle as shown in image.
This should get you started and hope it helps.
Regards,
CLA | LabVIEW 7.1... 2013
www.renishaw.com
Attachments:
triangle1.JPG ‏12 KB

Distance between two objects

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