Doubt in Firing Query with multiple opportunities UUID/IDs

HI Folks!
I might have simple doubt but please help me on this!
1. I have a custom BO with association to opportunities.
[DeploymentUnit(CustomerRelationshipManagement)] businessobject Sy_Trade {
[AlternativeKey] [Label("Trade Id")] element tradeid : BusinessTransactionDocumentID;
node RelatedOpportunities [0,n]{
                              element BusinessTransactionDocumentReference : BusinessTransactionDocumentReference;
                              element BusinessTransactionDocumentRelationshipRoleCode : BusinessTransactionDocumentRelationshipRoleCode;
                               association RelatedOpportunity[0,1] to Opportunity;
2. I have success fully used association and i am able to view create all the opportunities related to my custom Bo.
ISSUE : I want a facet where i just want DISPLAY the activities and sales document assigned in the RELATED OPPORTUNITIES ( N opportunities )
How do i query with Multiple opportunities ID and fetch the activities against it?
Btw I want to use query in UI Designer... I have created an  advanced list pane and there i want the result list
I hope i am clear!
Thanks in adavance...
Regards
Dhruvin

Hi Ludger,
I have successfully displayed Related Opportunities associated with trade.( i am able to create , delete also )
Issue : I am not able to "Display" ( i don't need to edit or create ) all the activities created against all the opportunities in a different tab.
I tried to approaches :
1: Query : Created a Query on Activity BO and tried to pass multiple related opportunities ( but seems not possible , please tell me any possibility to pass range of opportunity via transformation or anything? )
2 : binding : I have a Node Related Opportunity so just tried to bind it with BO model but problem is it is displaying all the activities of first opportunity of the list...
i think why because :
In Data model I have created a table bind with Related Opportunities...
now that node is 1 to N , association to opportunity 0 to 1 , hence i think it fetches only 1 opportunities activity
should i create like below ( Or is it possible)
Node Reltdoppts[0,1]
association [0,N] to opportunity BO ?
Although i strongly feel SAP should provied us two things :
1. We need to pass range of opportunities in a query.
2. We need to just write some absl code where i can fill the table and display it
and also is there any possibility to create a report or something to display activities as we just want to display the activities!
P.S : I have been getting a lot of bashing from client because some of the product restriction in cloud! i hope and wish SAP give developers free hand to develop right now its like our hands are tied to many things

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         (SELECT  blocking_session||' (Inst-'||blocking_instance || ')' blocker,
                 SID||' (Inst-'||inst_id || ')' waiter
            FROM gv$session
           WHERE blocking_instance IS NOT NULL AND blocking_session IS NOT NULL)
    SELECT     LPAD (' ', 2 * (LEVEL - 1)) || waiter lock_tree
          FROM (SELECT *
                  FROM lk
                UNION ALL
                SELECT DISTINCT 'root', blocker
                           FROM lk
                          WHERE blocker NOT IN (SELECT waiter
                                                  FROM lk))
    CONNECT BY PRIOR waiter = blocker
    START WITH blocker = 'root';
    Result:-
    ===========
    LOCK_TREE
    1966 (Inst-1)
      908 (Inst-1)
      1906 (Inst-1)
      1900 (Inst-1)
    981 (Inst-1)
      921 (Inst-1)
      937 (Inst-1)
      962 (Inst-1)
      1889 (Inst-1)
      1904 (Inst-1)
      974 (Inst-1) But what i expect is like below. My below query works when there is only one root blocker, but fails when there are multiple root node.
    WITH lk AS
         (SELECT blocking_session || '(Inst-' || blocking_instance || ')' blocker,
                 SID || '(Inst-' || inst_id || ')' waiter
            FROM gv$session
           WHERE blocking_instance IS NOT NULL AND blocking_session IS NOT NULL)
    SELECT     blocker, SUBSTR (SYS_CONNECT_BY_PATH (waiter, ';'), 2) waiters
          FROM (SELECT   blocker, waiter, ROW_NUMBER () OVER (ORDER BY waiter)
                                                                              val
                    FROM lk
                GROUP BY blocker, waiter)
         WHERE CONNECT_BY_ISLEAF = 1
    START WITH val = 1
    CONNECT BY PRIOR val = val - 1
    Result:-
    ===========
      WAITERS# BLOCKER                                                                                 WAITERS
             3 981(Inst-1)                                                                             1904(Inst-1);921(Inst-1);937(Inst-1)
    ....lot of duplicates
    expected result:-
    ===========
      WAITERS# BLOCKER                                                                                 WAITERS
             4 981(Inst-1)                                                                             1904(Inst-1);921(Inst-1);937(Inst-1);974(Inst-1)
             3 1966(Inst-1)                                                                             908 (Inst-1);1906 (Inst-1);1900 (Inst-1) can you please help me correct above query or suggest other ways to archive this result.
    Thanks in advance
    MidhunGT

    Hi All,
    Thank you all for your support. I never knew these many ways to see blocking lock in database :)
    Somehow i was able get the desired result for my specific requirement with below query
    sql> WITH lk AS
      2       (SELECT blocking_session || ' (Inst-' || blocking_instance
      3               || ')' blocker,
      4               SID || ' (Inst-' || inst_id || ')' waiter
      5          FROM gv$session
      6         WHERE blocking_instance IS NOT NULL AND blocking_session IS NOT NULL)
      7  SELECT     blocker,
      8             LTRIM
      9                (MAX (SYS_CONNECT_BY_PATH (waiter, ','))KEEP (DENSE_RANK LAST ORDER BY cnt),
    10                 ','
    11                ) AS waiters,
    12             MAX (cnt) waiters#
    13        FROM (SELECT blocker, waiter,
    14                     ROW_NUMBER () OVER (PARTITION BY blocker ORDER BY waiter)
    15                                                                         AS cnt
    16                FROM lk)
    17    GROUP BY blocker
    18  CONNECT BY cnt - 1 = PRIOR cnt AND blocker = PRIOR blocker
    19  START WITH cnt = 1;
    BLOCKER         WAITERS                                                                            WAITERS#
    1946 (Inst-1)   1987 (Inst-1),879 (Inst-1),910 (Inst-1)                                                3
    930 (Inst-1)    1919 (Inst-1),1945 (Inst-1),1953 (Inst-1),1983 (Inst-1)                                4please advice, if any scope for improvement
    Thanks and Regards,
    MidhunGT

  • Sql query with multiple joins to same table

    I have to write a query for a client to display business officers' names and title along with the business name
    The table looks like this
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    OfficerName
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    90% of the businesses have exactly 4 officer records, although some have less and some have more.
    There is a separate table that has the AcctNumber, BusinessName about 30 other fields that I don’t need
    An individual account can have 30 or 40 records on the other table.
    The client wants to display 1 record per account.
    Initially I wrote a query to join the table to itself:
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    This returned tons of duplicate rows for each account ( number of records * number of records, I think)
    So added
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    Welcome to the forum!
    user13319842 wrote:
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    The table looks like this
    AcctNumber
    OfficerTitle
    OfficerName
    RecKey
    90% of the businesses have exactly 4 officer records, although some have less and some have more.
    There is a separate table that has the AcctNumber, BusinessName about 30 other fields that I don’t need
    An individual account can have 30 or 40 records on the other table.
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    Initially I wrote a query to join the table to itself:
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    This returned tons of duplicate rows for each account ( number of records * number of records, I think)
    So added
    And A.RecKey > B.RecKey and B.RecKey > C. RecKey and C.RecKey . D.RecKey
    This works when there are exactly 4 records per account. If there are less than 4 records on the account it skips the account and if there are more than 4 records, it returns multiple rows.
    But when I try to l join this to the other table to get the business name, I get a row for every record on the other table
    I tried select distinct on the other table and the query runs for ever and never returns anything
    I tried outer joins and subqueries, but no luck so far. I was thinking maybe a subquery - if exists - because I don't know how many records there are on an account, but don't know how to structure that
    Any suggestions would be appreciatedDisplaying 1 column from n rows as n columns on 1 row is called Pivoting . See the following link fro several ways to do pivots:
    SQL and PL/SQL FAQ
    Pivoting requires that you know exactly how many columns will be in the result set. If that number depends on the data in the table, then you might prefer to use String Aggregation , where the output consists of a huge string column, that contains the concatenation of the data from n rows. This big string can be formatted so that it looks like multiple columns. For different string aggregation techniques, see:
    http://www.oracle-base.com/articles/10g/StringAggregationTechniques.php
    The following thread discusses some options for pivoting a variable number of columns:
    Re: Report count and sum from many rows into many columns

  • MDM ABAP API: Query with Multiple Parameters

    I would like to query MDM repository passing multiple parameters. I used the following code, however, it didn't work.
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    Hi,
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    DATA ls_query                 TYPE mdm_query.
    DATA lv_search_text       TYPE string.
    DATA lt_result_set            TYPE mdm_search_result_table.
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        APPEND ls_query TO lt_query.
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  • Display a query with multiple results and a little addon :D

    Hello everybody,
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    Better if you post the code, I'm not a good JSP writer
    thanks everybody for your attention and your time
    Kind regards

    You're right.. I'd post nothing..
    But it's all still in progress and I don't know what to post..
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  • Update query with multiple foreign key parameters

    I am trying to perform an update query on one field that uses multiple foreign key parameters from one table to update the other table. The data in all three foreign key parameter fields are not constant. Accuracy is absolutely critical. I tied this as well as other various scenarios with no success. Can anyone help?
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    I would check symbols by a user name and number of posts before calling anyone a hot shot, especially damorgon.<br><br>
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  • SQL query with multiple tables - what is the most efficient way?

    Hello I am learning PL/SQL. I have a simple procedure where I need to find number of employees and departments per location as per user input of location_id.
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    Here is the query I came up with for PL/SQL procedure:
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    I do get the correct result, but I am just wondering if my query is on the right track and if there is a more "efficient" way of doing this.
    Thanks in advance for helping a newbie out.

    Hi,
    Welcome to the forum!
    Something like this will be more efficient:
    SELECT    COUNT (employee_id)               AS ECount
    ,       COUNT (DISTINCT department_id)     AS DCount
    FROM       employees
    WHERE       department_id IN (     SELECT     department_id
                        FROM      departments
                        WHERE      location_id = :userInput
    ;You should also try a join instead of the IN subquery.
    For efficiency, do only the things you need to do.
    For example, you don't need a count of employees in each department, so don't compute one. That means you won't need the in-line view, so don't have one.
    You don't need PL/SQL for this job, so don't use PL/SQL if you don't have to. (I realize this question was out of context, so you may have good reasons for doing this in PL/SQL.)
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  • Tricky query with multiple hierarchial sub queries

    Here's a pussle that I cannot solve. Who can help me?
    Given table F (records form a binary tree with levels 0, 1, and
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    Id IdParent
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    F2 F1
    F3 F2
    F4 F2
    F5 F1
    F6 F5
    F7 F5
    and given table D (records form a similar binary tree with
    levels 0, 1, and 2):
    Id IdParent
    D1 null
    D2 D1
    D3 D2
    D4 D2
    D5 D1
    D6 D5
    D7 D5
    and given table P (cross referencing tables F and D):
    IdF IdD
    F2 D6
    F3 D2
    F5 D7
    and given table S (which holds the seed to the query):
    IdF
    F3
    and given table I (just any collection of records that reference
    table D which we want to select records from):
    Id IdD
    I1 D1
    I2 D2
    I3 D3
    I4 D4
    I5 D5
    I6 D6
    I7 D7
    I8 D1
    I9 D5
    all together being related like in figure 1:
    S.IdF =>> F.Id
    F.Id <- P.IdF
    P.IdD -> D.Id
    D.Id <<= I.IdD
    where =>> denotes 'is or is a descenden of'
    and -> denotes 'is'
    I want to build a query that lets me select all records from
    table I, which reference table D, such that the referenced
    records in table D are hierarchial descendents of any record
    that is referenced by records in table P, for which they
    reference records in table F, which are ancestors to records
    referenced by records in table S.
    If it wasn't for the hierarchial approach on both sides of the
    cross referencing table, matters would have been easy. Then the
    releational map would have been like in figure 2:
    S.IdF <- P.IdF
    P.IdD -> I.IdD
    and the query would have been:
    SELECT I.Id
    FROM I, P, S
    WHERE I.IdD = P.IdD
    AND P.IdF = S.IdF
    So in what I am looking for, you may say that the '='-signs in
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    going towards the side of table P.
    Given the tables listed above and given the query I am seeking,
    I expect to retrieve the following result set:
    I.Id
    I2
    I3
    I4
    I6
    Tricky, eh? I belive the figures are the best angles to
    understand this problem.

    You do this with subqueries and hierarchical queries...
    First the hierarchal subquery on F...
    SQL> SELECT f.id
      2    FROM f
      3   CONNECT BY PRIOR f.idp = f.id
      4   START WITH f.id IN ( SELECT idf FROM s )
      5       ;
    ID
    F3
    F2
    F1
    Then join with the cross reference table...
    SQL> SELECT p.idd
      2    FROM p
      3       , (  SELECT f.id
      4              FROM f
      5             START WITH f.id IN ( SELECT idf FROM s )
      6             CONNECT BY PRIOR f.idp = f.id
      7         ) s
      8   WHERE s.id = p.idf
      9       ;
    ID
    D6
    D2
    Use this as a subquery in a hierarchial query for the
    descendents in D...
    SQL> SELECT d.id
      2    FROM d
      3   START WITH d.idd IN ( SELECT p.idd
      4                         FROM p
      5                            , ( SELECT f.id
      6                                  FROM f
      7                                 START WITH f.id IN ( SELECT
    idf FROM s )
      8                                 CONNECT BY PRIOR f.idp = f.id
      9                             ) s
    10                        WHERE s.id = p.idf
    11                      )
    12   CONNECT BY PRIOR d.id = d.idp
    13       ;
    ID
    D2
    D3
    D4
    D6
    Then use that as a subquery to return the I result set...
    SQL> SELECT i.id
      2    FROM i
      3   WHERE i.idd  IN  ( SELECT d.id
      4                        FROM d
      5                       START WITH d.id IN ( SELECT p.idd
      6                                             FROM p
      7                                                , ( SELECT
    f.id
      8                                                      FROM f
      9                                                     START
    WITH f.id IN ( SELECT idf FROM s )
    10                                                     CONNECT
    BY PRIOR f.idp = f.id
    11                                                 ) s
    12                                            WHERE s.id = p.idf
    13                                          )
    14                       CONNECT BY PRIOR d.id = d.idp
    15                    )
    16       ;
    ID
    I2
    I3
    I4
    I6Good Luck...

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