Draw arc with three point( start, middle, end)

hi all,
i want to draw an arc with start point, middle point and end point, how can i do this?

Not clear what you want, but will try
How to calculate - the unit is the pixel it takes practice thats all & a bit of trial and error.
       | intB (pixels from the top)
       |
       |
intA |_____________________________
(from left)                          |
       |                             |
       |                             |
       |                             |
       |                             |
       |                             |
       |                             |
       |                             |
       |                             |
       |_____________________________| intD (from top)
                                     intC (from left)The pie slice goes from the centre of the undrawn square
If you only want an arc then you can paint over it again with eg
g.setColor(Color.white);
g.fillRect(0, 0, width, height);
g.setColor(Color.blue);
g.fillArc(intA, intB, intC, intD, intStartArc, intEndArc);
g.setColor(Color.white);
g.fillArc(intA, intB, intC-1, intD-1, intStartArc, intEndArc);
or something similar

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Draw an arc with three point

A . .C
B.
Hi all, i try to draw an arc A-B-C but i only has these three point, can anybody tell me how to do this and if these three point is almost colinear can i do this,
thanks!

I would think the Parabolic version would be able to
make a Circular arc as well as a Parabolic one.By a parabolic arc in this case I meant the arc of a parabola whose axis is the line bisector of AC and that passes through the points A, B, and C. You will get infinitely many parabolic arcs by choosing the axis differently. Generally a circular arc and a parabolic arc through three points are different.
But even though there are infinitely many arcs that pass through three points, it seems quite probable that the OP wants a circular one....

How, in Illustrator CS5, can I select all objects with three points (or nodes)?

I am quite new to Illustrator, but it seems this should be simple. (It is trivial in CorelDraw X4: After selecting an object with three nodes, I go to Edit > Find and Replace > Find Objects > Find objects that match the currently selected object, and navigate through the remaining menus.)
In Illustrator CS5, the options under Select > Same do not seem to include selecting all objects with the same number of nodes as the currently selected object.
Double-clicking on the Magic Wand Tool also fails to provide such an option.
Thank you for any help.
P.S. Also useful would be knowing how to add other criteria to this search, e.g. how to select all objects with three points *and* the current fill color.

There is a script that can select "less than x points"
Kelso Cartography

Custom Control Help: Draw a line and output start and end points

I'm looking to find or make a custom control (or simple subVI) that will appear as a 100x100 unit grid and allow me to draw a line from one point to another on that grid. It will then output the (x,y) of the starting and end point of that line on the grid. Any help or ideas?
Thanks,
Steve
LabVIEW 2009 SP1
Solved!
Go to Solution.

What you basically want is a loop with an event structure where you process Mouse Down, Move and Up events for your controls. There are any number of ways of implementing something like this, but this one will probably be the simplest:
Use a multicolumn listbox or a table for your grid. Hide the scrollbars and headers.
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You can even color the selected cells in the table using the table properties.
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I would also suggest processing Mouse Enter and Leave events to change the cursor and cancel if the user leaves in the middle of dragging.
Try to take over the world!

I am fairly new to iPhone and noticed yesterday that up by the bluetooth icon there is a small circle with a point on the end and a lock in the middle. I cannot find out what this is in my manual

I am fairly new to the iPhone and noticed yesterday up by the Bluetooth icon a small circle that is 90% complete and has an arrow at the end and a small lock in the middle. I have made no changes in my settings and cannot figure out what this is. Any help would be appreciated.
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Orientation lock. See p. 13 of the iPhone User Guide.
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Draw a arc with 3 points.

Hi all,
If you want to draw a arc in LabVIEW, You need star angle and angle, angle can - or +, that means your need know the direction,
if CW angle is +;
if CCW angle is -;
We can use cross product to get Z to get direction:
Welcome to QQ Group: LabVIEW_Home 213985957
Boone
Solved!
Go to Solution.

Boone301 wrote:
Yes, it is a solttion.
As we kown a lot of CNC have G02 and G03, but without G05, we can use this as G05.
Boone
A screenshot does not make a solution.
It is useless!
Post your VI.
How many times do we have to say it????

Drawing small, short curves in Photoshop draws straight line between start and end points

I recently installed Windows 8 Professional, Photoshop and the latest Wacom Bamboo tablet drivers and have been experiencing this issue. I've turned off windows flicks and ink. This only happens in Photoshop with the brush tool and I can't seem to find a setting that this corresponds to.
Basically, when I draw small, short curves (particularly letters like 'c' and 'h'), when I lift up my pen, Photoshop automatically connects the end and start points together with a straight line ('c' almost becomes 'o' or 'a'). I'm not holding the shift or any modifier keys. I've tried googling this issue, but I have no idea how to phrase it properly to get any results.
Here's an image of what I'm talking about (the top was drawn with the pencil tool, the bottom with the brush tool which demonstrates the issue. I've highlighted the start and end points with red dots):
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Is caps lock on?

TS1702 Maps program does not work. In standard it only shows a grid. If I ask for a route it shows start and end point and three route boxes but nothing else. It does show directions. If I switch to hybrid it shows to routes but no roads. Background is a

Maps program does not work. In standard it only shows a grid. If I ask for a route it shows start and end point and three route boxes but nothing else. It does show directions. If I switch to hybrid it shows to routes but no roads. Background is a blur.

Do you have a question? This is a user to user help forum. Apple is not here only other users like yourself. You don't report problems to Apple here.
By the way, it might help if you indicated where you are located.
To complain to Apple use http://www.apple.com/feedback/ipad.html

Custom text component with different start and end points for each line

I'm trying to create a custom component extending textArea in which each individual line in the textArea would have different start and end points. For example, the start/end points for line 1 might be 20 pixels in the front and 35 pixels at the end but start/end points for line 2 might be 25 pixels in front and 20 pixels at the end, etc. These boundary values would be passed in. The width of the entire textArea component would be a fixed size. The result would be something like this:
Jack and Jill
ran up the hill
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depending on the boundary values of each individual line of course. The custom component would take a string and render it in the text component with the appropriate individual line start and end points. I'm trying to do this by adding the text component to the display with the passed in string and then adding in spaces in the beginning of each line and adding a "/n" at the end of the line wherever appropriate based on the start and end values for that line.
Just wondering if I'm on the right track and if anyone has any advice on this.

> Applying the marker places the same icon on all lines of the graph and I need a different one for each
What do you have selected when you assign the marker? It
shouldn't apply to all the markers on the whole graph unless you have all the existing markers selected when you apply the new one.
Assigning marker designs is exactly analogous to assigning bar graph designs.
If you have a single marker selected when you assign the new design, it will apply to only that graph data point.
If you use the group select tool (or option-click with the direct select tool) to reclick on an already-selected marker until all the markers for the same line are selected, and then assign a design, the new design will apply only to the selected line. (You can extend the graph by adding more rows, and the new data points will inherit the marker for the line they are on.)
The thread linked to below demonstrates in more detail how the marker designs are scaled:
http://www.adobeforums.com/cgi-bin/webx/.3bc10970/0

How to draw an arc with width more than 1

Hi!
I got the following problem:
I need to draw an arc under JDK1.1.
It works fine, but I need to be able to adjust the
thickness. I didn't find anything in the graphics-
class.
Who knows?
Valentin

I think you're just gunna have to draw multiple arcs with start/end points that are pixel increments away from each other. In Java2 you could use set the "stroke" with Java 2D, but that's not availale in 1.1.

Line Graph repeats the starting data point at the end also

Hi,
We have a Line Graph as below. This graph is used to show the Salary changes of a person, over time.
But this graph shows an additional non existing data point. Basically it shows the starting data point once again at the end of the other data points.
The model VO for this graph, does not contain this additional data point record. But the graph repeats the starting data point at the end also.
In the screen-shot you can see that, the graph has three data points. But the table has only two. The first data point in the graph is repeated as the last data point.
Is this a Bug..?
Or an issue with the usage of the DVT tags?
The code is given below.
Please advice.
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13 graphType="LINE_VERT_ABS"
14 shortDesc="#{HcmEmploymentTopGenBundle}"
15 markerDisplayed="true"
16 continuousTimeAxisInterval="CTAI_DAY"
17 contentDelivery="immediate" animationOnDisplay="AUTO"
18 imageFormat="FLASH" stylePath="April"
19 timeSelectorListener="#{backingBeanScope.AssignmentChangesAndSalaryBean.changeTime}"
20 timeAxisType="TAT_MIXED_FREQUENCY" dynamicResize="DYNAMIC_SIZE"
21 inlineStyle="height:40em;"
22 binding="#{backingBeanScope.AssignmentChangesAndSalaryBean.asgSalaryGraph}">
23 <dvt:background>
24 <dvt:specialEffects/>
25 </dvt:background>
26 <dvt:graphPlotArea/>
27 <dvt:seriesSet>
28 <dvt:series/>
29 </dvt:seriesSet>
30
31 <dvt:o1Axis scrolling="asNeeded"/>
32 <dvt:y1Axis/>
33 
34 
42 <dvt:o1MajorTick/>
43 <dvt:o1TickLabel/>
44 <dvt:o1Title id="o1Title1">
45 <dvt:graphFont id="graphFont1"/>
46 </dvt:o1Title>
47
48 <dvt:attributeFormat id="af1" name="DateFrom">
49 <af:convertDateTime pattern="#{applCorePrefs.dateFormatPattern}" />
50 </dvt:attributeFormat>
51
52 <dvt:markerText>
53 <dvt:y1Format>
54 <af:convertNumber pattern="#{applCorePrefs.numberFormatPattern}"/>
55 </dvt:y1Format>
56 </dvt:markerText>
57
58
59 </dvt:graph>

If I understand your question, this from the Pages online help may give the answer:
To mark line, area, and scatter charts with data point symbols:
Select the entire chart. You can also select the chart series (the line or area shape) that you want to mark with data point symbols.
Click Inspector in the toolbar, and then click the Chart Inspector button.
Click Series (except for scatter charts).
Choose a symbol from the Data Point Symbol pop-up menu.
Choose one of the following options from the Symbol Fill pop-up menu:
To fill the symbol with the same color as its outline, choose Use Stroke Color.
To fill the symbol with a solid color, choose Color Fill, click the Fill color well, and pick a color.
To fill the symbol with a gradient, choose Gradient Fill and use the gradient controls to set the colors and change the angle of the gradient.
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Can both Locator & spatial store three point curves or arcs?

1) can both Oracle Locator and Oracle Spatial store three pint curves or arcs?
2) Can both Oracle Locator and Oracle Spatial receive input of bearing / distance to creat a line segment?

hmmm, i got this exact question in mail today. someone is double-dipping!
Both Locator and Spatial allow storage of three point circular arcs. Circular arcs are only supported in non-geodetic coordinate systems.
In Oracle 10g Release 2 both Locator and Spatial include a function called sdo_util.point_at_bearing. If you enter a point, a distance, and a bearing (in radians) we return the end point. With the end point and the original input point a line segment can be contructed very easily.

How to find a line/edge that starts at the same point as the end of another

I have an edges table of Lat/Lon data and for a specific edge I want to find any other edges that have the same start point as the end point of the given edge.
I tried the following query:
select geo_street_id from geo_street s2
where SDO_LRS.GEOM_SEGMENT_START_PT(s2.geom) =
(select SDO_LRS.GEOM_SEGMENT_END_PT(s.geom) as geom from geo_street s
where geo_street_id = 122978214)
but it gets the following error:
ORA-22901: cannot compare nested table or VARRAY or LOB attributes of an object type
Any Ideas?

1. to compare geometry to be equal you should use appropriate function (SDO_GEOM.RELATE http://download.oracle.com/docs/html/B14255_01/sdo_objgeom.htm#sthref1561) or operators (sdo_relate http://download.oracle.com/docs/html/B14255_01/sdo_operat.htm#i78531) with specific mask EQUAL.
2. to filter down the resultset in first place you can use the operator SDO_RELATE with mask TOUCH as this will return already the set of lines sharing endpoints, but will also include lines touching eachother not at endpoints (endpoint intersecting the otherone's interior)
something like
select geo_street_id from geo_street s2, geo_street s
where
s.geo_street_id = 122978214
AND
sdo_relate(s2.geom, s.geom,'mask=touch') = 'TRUE'
AND
sdo_geom.relate(SDO_LRS.GEOM_SEGMENT_START_PT(s2.geom),
'EQUAL',
SDO_LRS.GEOM_SEGMENT_END_PT(s.geom),0.005)='EQUAL'
3. if you would do this for the full table, an SDO_JOIN (http://download.oracle.com/docs/html/B14255_01/sdo_operat.htm#BGEDJIBF) might be more appropriate.
4. you might also consider 4 cases:
start = start
start = end
end = start
end = end
5. alternative would be to take only the endpoints of your selected geometry and perform a touch with the edges. using the sdo_util.APPEND on the startpoint en endpoint of your geometry will return a multipoint. although there might some specific cases that this would not return respected result I think
something like:
select geo_street_id from geo_street s2, geo_street s
where
s.geo_street_id = 122978214
AND
sdo_relate(s2.geom,
SDO_UTIL.APPEND(
SDO_LRS.GEOM_SEGMENT_START_PT(s.geom),
SDO_LRS.GEOM_SEGMENT_END_PT(s.geom)
,'mask=touch') = 'TRUE'
Let us know how it works.
Luc

XML Parsing with Java - Only some attributes have start and end tags

Hello,
I am trying to interpret the XML response from a server after a HTTP request is sent to it. I have modified an example off Wikipedia below to give an example of what it looks like.
Example XML:
<Asset name="bread" prep_time="5 mins" cook_time="3 hours">
<Attribute name="Ingredient: ">Flour</Attribute>
<Attribute name="Ingredient: ">Water</Attribute>
<Attribute name="Used in Recipes:" />
</recipe>
I have been trying to display the above XML in a format such as:
name: bread prep_time: 5 mins cook_time: 3 hours
Ingredient: Flour
Ingredient: Water
Used in Recipes:
Right now I have been trying to do it manually using indexOf and substring of the XML text, but I would like to find a better way of doing this. I have found some examples online that show had to deal with cases such as
<person>
<first>Kiran</first>
<last>Pai</last>
<age>22</age>
</person>
but I do not know what to do when I encounter something like the last item, when there are no "Used in Recipe" items, and it ends with a />, instead of an ending tag </Attribute>.
Are there any suggestions as to how to handle the example XML code that I have posted?
Any help would be appreciated. Thanks.

jtahlborn wrote:
Tolls wrote:
I suppose so, but since the idea is to turn it into text in a different format, XSLT strikes me as a better fit than hand crafting it.i agree if the end goal is formatted text. however, i wasn't sure if the OP was just writing some test code to figure out how to access the data or if the formatted text was the final desired output.No, true. It is open to interpretation.
jschell wrote:
(Quoting the same bit)
As long as one is mindful of the potential performance and maintenance impacts of course.Again, it depends what he's doing...true. I was making some assumptions, since (as usual) we don't really know the requirements beyond a base technical one (ie "I have this, and I need it to look like this"). In general, though, if you have XML data and you need it formatted differently then I'd say your first port of call ought to be transformation.
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Of course, YMMV.

Schedule type LineChart with clients and unavailable start and end dates

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I guess I still have lots to learn about Flex and Renderers. I downloaded a Gantt chart with Code and they used the AdvancedDataGrid with renderers and such. I modified the code to work for me. but if I had to create it myself right now, I would be in trouble. Lots more to learn.

Draw arc with three point( start, middle, end)

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