Duplicated records - continued

Question

Hi All,
I am using following script to find records, having two columns with duplicated values in one or more records. It works OK, but columns used to find the records are not keys and therefore can't precisely identify them, so I need to print column WORKORDER_NUMBER to identify the record.
Environment: Oracle 10g.
SELECT compid, compjobid, count(*)
FROM Workorder
WHERE deptid = 221000001 AND wostatus NOT IN (7)
GROUP BY compid, compjobid
HAVING count(*) > 1
ORDER BY compid, compjobid
Please advice the solution. Many thanks in advance.
Aleks

Answer 1

You want something like:
SQL> ed
Wrote file afiedt.buf
  1  WITH t AS (select 1 AS PID, 123 as PAKey, 1 as SG from dual union all
  2             select 2, 123, 1 from dual union all
  3             select 3, 123, 1 from dual union all
  4             select 4, 123, 2 from dual union all
  5             select 5, 234, 1 from dual union all
  6             select 6, 234, 2 from dual union all
  7             select 7, 234, 2 from dual)
  8  -- END OF TEST DATA
  9  select t.pid, t.pakey, t.sg
10  from t, (select pakey, sg
11           from t
12           group by pakey, sg
13           having count(*) > 1
14          ) tx
15  where t.pakey = tx.pakey
16* and   t.sg = tx.sg
SQL> /
       PID      PAKEY         SG
         1        123          1
         2        123          1
         3        123          1
         6        234          2
         7        234          2
SQL>