Dynamic Hyperlink

Question

Hello,
I have a web page that uses a php MySQL recordset to display
database info. I would like to add an expression to the recordset
that will make the text value from the FileName field display as a
hyperlink in a repeating region table and link to a file in a
folder on the site. It would be similar to displaying an image from
the images folder in an image placeholder. I can make the hyperlink
appear if I place the filename inside of html tags with an href in
the database, for example, <a
href="Patches/MyPatch.zip">MyPatch.zip</a>
but I would like to be able to reference it on the page so
that users don't have to enter these in the field for every record.
The purpose of the page is to enable users to download zipped
folders from a folder named Patches located on the site. I would
appreciate any help in coding this procedure. Thank you.

Answer 1

aopro wrote:
> I have a web page that uses a php MySQL recordset to
display database info. I
> would like to add an expression to the recordset that
will make the text value
> from the FileName field display as a hyperlink in a
repeating region table and
> link to a file in a folder on the site.
If all files are stored in the same folder, just store the
filename in
the database, and use a dynamic text object to build the
link. Using
your example, it would look like this in Code view:
<a href="Patches/<?php echo
$row_recordsetName['FileName']; ?>">
<?php echo $row_recordsetName['FileName'];
?></a>
If the files are to be kept in different folders, you should
store the
path in the database, and then use a PHP custom function to
extract just
the filename.
Put this code block anywhere in your page:
<?php
// extract filename after last forward slash
function getName($path) {
$name = '';
// find position of last forward slash
$pos = strrpos($path, '/');
// if no forward slash, use the full value
if ($pos === false) {
$name = $path;
// otherwise extract everything after the last slash
else {
$name = substr($path, $pos);
return $name;
?>
So, taking your example again, you store
"Patches/MyPatch.zip" (without
the quotes) in the database, and wrap the text part of the
link in the
getName() function to extract just the filename. In Code
view, it will
look like this:
<a href="<?php echo $row_recordsetName['FileName'];
?>">
<?php echo getName($row_recordsetName['FileName']);
?></a>
David Powers, Adobe Community Expert
Author, "The Essential Guide to Dreamweaver CS3" (friends of
ED)
Author, "PHP Solutions" (friends of ED)
http://foundationphp.com/