Dynamically change directory in FileAdapter while write file

my situation is:
I would like to write a file to a specified directory with specified file name. I found there is not directory parameter in fileAdapterOutboundHeader.wsdl. When I specify fileName, it is always plus with the Logical/PhysicalDirectory. And if I configure the Logical/PhysicalDirectory as empty, it doesn't work.
please check it for me.
thanks

File directory information goes to second WSDL which is created by FileAdapter it looks like this
<jca:operation
PhysicalDirectory="C:\Project\Integration\temp\FileWrite"
InteractionSpec="oracle.tip.adapter.file.outbound.FileInteractionSpec"
FileNamingConvention="service_%SEQ%.xml"
NumberMessages="1"
ElapsedTime="60"
FileSize="1024000"
OpaqueSchema="false" >
</jca:operation>
I also want to change it dynamically. lets see if we get lucky :)

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Dynamically changing the name of the .dll file to load in call Library

Our current model is to use dll files as "plug-in" modules for instruments and a top layer test step calls the appropriate driver dll.
For instance
the TestStep is called with the kenmore.dll passed as a parameter so the kenmore.dll file is loaded, the functions are registered and the functions are called. Next the TestStep is called with whirlpool.dll as a parameter now the whirlpool.dll is loaded the functions are registered and the functions are called. This works very well in our current CVI/LabWindows environment. Now we plan to work with LabView, we wish to retain this model (as DLL files, there are advantages in our model for us). We have not found a way to load these dll files from LabView without hard coding the path and filenames in.
Any suggestions on how to dynamically change the path in the Call Library module, or another suggested method of loading the dll via LabView?
Thanks,

John Stuart wrote:
Our current model is to
use dll files as "plug-in" modules for instruments and a top layer test
step calls the appropriate driver dll.
For instance
the TestStep is called with the kenmore.dll passed as
a parameter so the kenmore.dll file is loaded, the functions are
registered and the functions are called. Next the TestStep is
called with whirlpool.dll as a parameter now the whirlpool.dll is
loaded the functions are registered and the functions are called.
This works very well in our current CVI/LabWindows environment.
Now we plan to work with LabView, we wish to retain this model (as DLL
files, there are advantages in our model for us). We have not
found a way to load these dll files from LabView without hard coding
the path and filenames in.
Any suggestions on how to dynamically change the path in the Call
Library module, or another suggested method of loading the dll via
LabView?
Thanks,
As Ben has pointed out LabVIEW
scripting may be a possibility but you are going with that in highly
unsupported area. Also I happen to know that changing the library name
of a Call Library Node through scripting has produced unsupported
feature errors previous to LabVIEW 7.1 eventhough the method was there.
And LabVIEW 8 hides the whole scripting business behind the license
manager.
Another approach at least if the different DLLs do not change to often
thier functions and parameters would be to create a wrapper DLL. Have
it a method that loads the desired DLL and links its functions to
internal function pointers. Then when calling the actual function entry
points just redirect directly to the correct fucntion through that
function pointer. Since you are already working in CVI creating such a
DLL should be only a matter of taking out a little bit of your already
existing code and put it into a DLL project.
Rolf Kalbermatter
Message Edited by rolfk on 04-12-2006 07:40 AM
Rolf Kalbermatter
CIT Engineering Netherlands
a division of Test & Measurement Solutions

Change Directory Structure Created in MPZIP file

I'm trying to standardize my Multisim projects for inclusion in our documentation control system. As I build my project, I have a directory structure that I'm using. When I include the files in the project, the directory structure is remembered in the MPZIP file. However, the default is to unpack all files into the External(Project Name) folder. Following the help,
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Solved!
Go to Solution.

Hi Doug,
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Tien P.
National Instruments
Attachments:
unpack.png ‏17 KB

Access denied error -- while copying file to a specific directory

Hi Friends,
I have gone through scores of examples and i am failing to understand the right thing to be done to copy a file from one directory to another. Here is my class
package ZipTest;
import java.io.File;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.io.IOException;
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     FileOutputStream fout = null;
     byte[] buffer = new byte[4096];
     int bytesRead;
     try
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     at java.io.FileOutputStream.open(Native Method)
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     at java.io.FileOutputStream.<init>(FileOutputStream.java:131)
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     ... 5 more
It would be really helpful to have your guidance.
Thanks & Regards
VS

vishnuS1984 wrote:
Hi Friends,
I have gone through scores of examples and i am failing to understand the right thing to be done to copy a file from one directory to another. Here is my class...So let's see... C:\GetMe1 is a directory on your machine, right? And this is what you are doing with that directory:
public static void copyFiles(File src, File dest) throws IOException
// dest is a 'File' object but represents the C:\GetMe1 directory, right?
fout = new FileOutputStream (dest);If it's a directory, where in your code are you appending the source file name to the path, before trying to open an output stream on it? You're not.
BTW, this is awful:
catch (IOException e)
IOException wrapper = new IOException("copyFiles: Unable to copy file: " +
src.getAbsolutePath() + "to" + dest.getAbsolutePath()+".");
wrapper.initCause(e);
wrapper.setStackTrace(e.getStackTrace());
throw wrapper;
}1) You're hiding the original IOException and replacing it with your own? For what good purpose?
2) Even if you had a good reason to do that, this would be simpler and better:
throw new IOException("your custom message goes here", e);
rather than explicitly invokign initCause and setStackTrace. Yuck!

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MessageId: {926F44F2-9180-4B33-96FF-9E4CBC459382}
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Below is the error I'm getting on BizTalk while trying to write files to a designated folder on a client's SFTP server.
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is suspended.
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Hi Yaeli1,
From the error message above, please check the permission for file writing , it seems that this issue is related to access permission.
Best regards,
Angie
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Just tried to import CD in my iTunes music library, but get this error code "error occurred while converting file. You do not have the privilege to make changes"....any thoughts? Have not tried to change anything- only import CD ??

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>
Dharamveer Gaur wrote:
> Hi
> Look this same thread:
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Dynamically change directory in FileAdapter while write file

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