E_recruiting Applicant management-- add columns to Candidate Selection scre

Hi
We would like to see the date of an action (either planned or complete) on the Candidate Selection --> Assignments screen, so that recruiters can at a glance see when an action is planned, or when it was completed. Is there any way of tailoring the view to include the action date on that screen?
Regards
Rob
Edited by: Rob Sesink Clee on Oct 16, 2008 7:28 PM

Hello Rob,
changing the table columns of the assignments table to the requisition is only possible by making a modification as the "personalization" only allows to hide and reorder the first 6 columns.
This modification is not that difficult and I already did for customers which had the same requirement. Basically you have to change the get_column_definitions method to add the column (this might be necessary on sveral points as the table is used in several modes) and you have to add some code in the render_cell_start to gather additional information or if you want to toggle between due_date and date_executed depending on the activity status.
The class you have to change depends on the release of e-recruiting you are using. Up to a certain point in release 300 the controller works as the iterator for the table view. Since the introduction of the "personalization" the iterator has been moved to a separete class which should be referenced in an attribute of the controller class which is called iterator. Although the controller still implments the iterator interface these methods are no longer processed in release 600.
If you need more detailed help please specify the release you are currently using.
Best regards
Roman Weise

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Help for a query to add columns

Hi,
I need for a query where I should add each TableC value as an additional column.
Please suggest...
I have 3 tables (TableA, TableB, TableC). TableB stores TableA Id and TableC stores TableB Id
Considering Id of TableA.
Sample data
TableA     :
ID     NAME     TABLENAME     ETYPE
23     Name1     TABLE NAMEA     Etype A
TableB     :
ID     A_ID     RTYPE     RNAME
26     23     RTYPEA     RNAMEA
61     23     RTYPEB     RNAMEB
TableC     :
ID     B_ID     COMPNAME     CONC
83     26     Comp Name AA     1.5
46     26     Comp Name BB     2.2
101     61     Comp Name CC     4.2
Scenario 1: AS PER ABOVE SAMPLE DATA Put each TableC value as an additional column.
For an Id in TableA(23) where TableB contains 2 records of A_ID (26, 61) and TableC contains 2 records for 26 and 1 record for 61.
Output required: Put each TABLEC value as an additional column
TableA.NAME TableA.ETYPE TableB.RTYPE TableC_1_COMPNAME     TableC_1_CONC TableC_2_COMPNAME     TableC_2_CONC
Name1 EtypeA RTypeA Comp Name AA 1.5 Comp Name BB 2.2     so on..
Name1 EtypeA RTypeB Comp Name CC 4.2 NULL NULL
Scenario 2: If Table C contains ONLY 1 row for each Id in TableB, output should be somewhat
Output:
TableA.NAME TableA.ETYPE TableB.RTYPE TableC_1_COMPNAME
TableC_1_CONCvalue     value     value     value               value

Hi,
Welcome to the forum!
Do you want the data from TableC presented
(1) in one column, or
(2) in several columns (a different column of results for each row in the original TableC)?
(1) Is called String Aggregation and is easier than (2).
The best way to do this is with a user-defined aggregate function (STRAGG) which you can copy from asktom.
Ignoring TableA for now, you could get what you want by saying
SELECT    b.rtype
,         STRAGG (   c.compname
                 || ' '
                 || c.conc
                 ) AS c_data
FROM      TableB b
JOIN      TableC c ON b.id = c.b_id
GROUP BY b.rtype;(2) Presenting N rows of TableC as it they were N columns of the same row is called a pivot. Search for "pivot" or "rows to columns" to find examples of how to do this.
The number of columns in a result set is hard-coded into the query. If you don't know ahead of time how many rows in TableC will match a row in TableB, you can:
(a) guess high (for example, hard-code 20 columns and let the ones that never contain a match be NULL) or,
(b) use Dynamic SQL to write a query for you, which has exactly as many columns as you need.
The two scripts below contain basic information on pivots.
This first script is similar to what you would do for case (a):
--     How to Pivot a Result Set (Display Rows as Columns)
--     For Oracle 10, and earlier
--     Actually, this works in any version of Oracle, but the
--     "SELECT ... PIVOT" feature introduced in Oracle 11
--     is better. (See Query 2, below.)
--     This example uses the scott.emp table.
--     Given a query that produces three rows for every department,
--     how can we show the same data in a query that has one row
--     per department, and three separate columns?
--     For example, the query below counts the number of employess
--     in each departent that have one of three given jobs:
PROMPT     ========== 0. Simple COUNT ... GROUP BY ==========
SELECT     deptno
,     job
,     COUNT (*)     AS cnt
FROM     scott.emp
WHERE     job     IN ('ANALYST', 'CLERK', 'MANAGER')
GROUP BY     deptno
,          job;
Output:
    DEPTNO JOB              CNT
        20 CLERK              2
        20 MANAGER            1
        30 CLERK              1
        30 MANAGER            1
        10 CLERK              1
        10 MANAGER            1
        20 ANALYST            2
PROMPT     ========== 1. Pivot ==========
SELECT     deptno
,     COUNT (CASE WHEN job = 'ANALYST' THEN 1 END)     AS analyst_cnt
,     COUNT (CASE WHEN job = 'CLERK'   THEN 1 END)     AS clerk_cnt
,     COUNT (CASE WHEN job = 'MANAGER' THEN 1 END)     AS manager_cnt
FROM     scott.emp
WHERE     job     IN ('ANALYST', 'CLERK', 'MANAGER')
GROUP BY     deptno;
--     Output:
    DEPTNO ANALYST_CNT CLERK_CNT MANAGER_CNT
        30           0          1           1
        20           2          2           1
        10           0          1           1
--     Explanation
(1) Decide what you want the output to look like.
     (E.g. "I want a row for each department,
     and columns for deptno, analyst_cnt, clerk_cnt and manager_cnt)
(2) Get a result set where every row identifies which row
     and which column of the output will be affected.
     In the example above, deptno identifies the row, and
     job identifies the column.
     Both deptno and job happened to be in the original table.
     That is not always the case; sometimes you have to
     compute new columns based on the original data.
(3) Use aggregate functions and CASE (or DECODE) to produce
     the pivoted columns.
     The CASE statement will pick
     only the rows of raw data that belong in the column.
     If each cell in the output corresponds to (at most)
     one row of input, then you can use MIN or MAX as the
     aggregate function.
     If many rows of input can be reflected in a single cell
     of output, then use SUM, COUNT, AVG, STRAGG, or some other
     aggregate function.
     GROUP BY the column that identifies rows.
PROMPT     ========== 2. Oracle 11 PIVOT ==========
WITH     e     AS
(     -- Begin sub-query e to SELECT columns for PIVOT
     SELECT     deptno
     ,     job
     FROM     scott.emp
)     -- End sub-query e to SELECT columns for PIVOT
SELECT     *
FROM     e
PIVOT     (     COUNT (*)
          FOR     job     IN     ( 'ANALYST'     AS analyst
                         , 'CLERK'     AS clerk
                         , 'MANAGER'     AS manager
NOTES ON ORACLE 11 PIVOT:
(1) You must use a sub-query to select the raw columns.
An in-line view (not shown) is an example of a sub-query.
(2) GROUP BY is implied for all columns not in the PIVOT clause.
(3) Column aliases are optional.
If "AS analyst" is omitted above, the column will be called 'ANALYST' (single-quotes included).
{code}
The second script, below, shows one way of doing a dynamic pivot in SQL*Plus:
{code}
How to Pivot a Table with a Dynamic Number of Columns
This works in any version of Oracle
The "SELECT ... PIVOT" feature introduced in Oracle 11
is much better for producing XML output.
Say you want to make a cross-tab output of
the scott.emp table.
Each row will represent a department.
There will be a separate column for each job.
Each cell will contain the number of employees in
     a specific department having a specific job.
The exact same solution must work with any number
of departments and columns.
(Within reason: there's no guarantee this will work if you
want 2000 columns.)
Case 0 "Basic Pivot" shows how you might hard-code three
job types, which is exactly what you DON'T want to do.
Case 1 "Dynamic Pivot" shows how get the right results
dynamically, using SQL*Plus.
(This can be easily adapted to PL/SQL or other tools.)
PROMPT     ========== 0. Basic Pivot ==========
SELECT     deptno
,     COUNT (CASE WHEN job = 'ANALYST' THEN 1 END)     AS analyst_cnt
,     COUNT (CASE WHEN job = 'CLERK'   THEN 1 END)     AS clerk_cnt
,     COUNT (CASE WHEN job = 'MANAGER' THEN 1 END)     AS manager_cnt
FROM     scott.emp
WHERE     job     IN ('ANALYST', 'CLERK', 'MANAGER')
GROUP BY     deptno
ORDER BY     deptno
PROMPT     ========== 1. Dynamic Pivot ==========
--     ***** Start of dynamic_pivot.sql *****
-- Suppress SQL*Plus features that interfere with raw output
SET     FEEDBACK     OFF
SET     PAGESIZE     0
SPOOL     p:\sql\cookbook\dynamic_pivot_subscript.sql
SELECT     DISTINCT
     ',     COUNT (CASE WHEN job = '''
||     job
||     ''' '     AS txt1
,     'THEN 1 END)     AS '
||     job
||     '_CNT'     AS txt2
FROM     scott.emp
ORDER BY     txt1;
SPOOL     OFF
-- Restore SQL*Plus features suppressed earlier
SET     FEEDBACK     ON
SET     PAGESIZE     50
SPOOL     p:\sql\cookbook\dynamic_pivot.lst
SELECT     deptno
@@dynamic_pivot_subscript
FROM     scott.emp
GROUP BY     deptno
ORDER BY     deptno
SPOOL     OFF
--     ***** End of dynamic_pivot.sql *****
EXPLANATION:
The basic pivot assumes you know the number of distinct jobs,
and the name of each one. If you do, then writing a pivot query
is simply a matter of writing the correct number of ", COUNT ... AS ..."\
lines, with the name entered in two places on each one. That is easily
done by a preliminary query, which uses SPOOL to write a sub-script
(called dynamic_pivot_subscript.sql in this example).
The main script invokes this sub-script at the proper point.
In practice, .SQL scripts usually contain one or more complete
statements, but there's nothing that says they have to.
This one contains just a fragment from the middle of a SELECT statement.
Before creating the sub-script, turn off SQL*Plus features that are
designed to help humans read the output (such as headings and
feedback messages like "7 rows selected.", since we do not want these
to appear in the sub-script.
Turn these features on again before running the main query.
{code}

How to add column dynamically based on user input in oracle?

**how to add column dynamically based on user input in oracle?**
I am generating monthly report based on from_date to to_date below is my requirement sample table
EMPLOYEE_CODE| Name | CL_TAKEN_DATE | CL_BALANCE | 01-OCT-12 | 02-OCT-12 | 03-OCT-12
100001.............John...........02-OCT-12...............6
100002.............chris...........01-OCT-12...............4
Based on user input, that is, if user need the report from 01-OCT-12 TO 03-OCT-12, i need to add that dates as column in my table, like 01-OCT-12 | 02-OCT-12 | 03-OCT-12....
below is my code
create or replace
procedure MONTHLY_LVE_NEW_REPORT_demo
L_BUSINESS_UNIT IN SSHRMS_LEAVE_REQUEST_TRN.BUSINESS_UNIT%TYPE,
--L_LEAVE_TYPE_CODE IN SSHRMS_LEAVE_REQUEST_TRN.LEAVE_TYPE_CODE%TYPE,
L_DEPARTMENT_CODE IN VARCHAR2,
--L_MONTH IN SSHRMS_LEAVE_REQUEST_TRN.LVE_FROM_DATE%TYPE,
L_FROM_DATE IN SSHRMS_LEAVE_REQUEST_TRN.LVE_FROM_DATE%TYPE,
L_TO_DATE in SSHRMS_LEAVE_REQUEST_TRN.LVE_TO_DATE%type,
MONTHRPT_CURSOR OUT SYS_REFCURSOR
AS
O_MONTHRPT_CURSOR_RPT clob;
v_return_msg clob;
BEGIN
IF (L_BUSINESS_UNIT IS NOT NULL
AND L_FROM_DATE IS NOT NULL
and L_TO_DATE is not null
-- AND L_DEPARTMENT_CODE IS NOT NULL
THEN
OPEN MONTHRPT_CURSOR FOR
select EMPLOYEE_CODE, EMPLOYEE_NAME AS NAME, DEPARTMENT_CODE AS DEPARTMENT,DEPARTMENT_DESC, CREATED_DATE,
NVL(WM_CONCAT(CL_RANGE),'') as CL_TAKEN_DATE,
case when NVL(SUM(CL2),0)<0 then 0 else (NVL(SUM(CL2),0)) end as CL_BALANCE,
from
SELECT DISTINCT a.employee_code,
a.EMPLOYEE_FIRST_NAME || ' ' || a.EMPLOYEE_LAST_NAME as EMPLOYEE_NAME,
a.DEPARTMENT_CODE,
a.DEPARTMENT_DESC,
B.LEAVE_TYPE_CODE,
B.LVE_UNITS_APPLIED,
B.CREATED_DATE as CREATED_DATE,
DECODE(b.leave_type_code,'CL',SSHRMS_LVE_BUSINESSDAY(L_BUSINESS_UNIT,to_char(b.lve_from_date,'mm/dd/yyyy'), to_char(b.lve_to_date,'mm/dd/yyyy'))) CL_RANGE,
DECODE(B.LEAVE_TYPE_CODE,'CL',B.LVE_UNITS_APPLIED)CL1,
b.status
from SSHRMS_EMPLOYEE_DATA a
join
SSHRMS_LEAVE_BALANCE C
on a.EMPLOYEE_CODE = C.EMPLOYEE_CODE
and C.STATUS = 'Y'
left join
SSHRMS_LEAVE_REQUEST_TRN B
on
B.EMPLOYEE_CODE=C.EMPLOYEE_CODE
and c.EMPLOYEE_CODE = b.EMPLOYEE_CODE
and B.LEAVE_TYPE_CODE = C.LEAVE_TYPE_CODE
and B.STATUS in ('A','P','C')
and (B.LVE_FROM_DATE >= TO_DATE(L_FROM_DATE, 'DD/MON/RRRR')
and B.LVE_TO_DATE <= TO_DATE(L_TO_DATE, 'DD/MON/RRRR'))
join
SSHRMS_LEAVE_REQUEST_TRN D
on a.EMPLOYEE_CODE = D.EMPLOYEE_CODE
and D.LEAVE_TYPE_CODE in ('CL')
AND D.LEAVE_TYPE_CODE IS NOT NULL
group by EMPLOYEE_CODE, EMPLOYEE_NAME, DEPARTMENT_CODE, DEPARTMENT_DESC, CREATED_DATE
else
v_return_msg:='Field should not be empty';
end if;
END;
my code actual output
EMPLOYEE_CODE| Name | CL_TAKEN_DATE | CL_BALANCE
100001....................John............02-OCT-12.................6
100001....................chris...........01-OCT-12.................4
how to add column dynamically based on from_date to to_date?
Thanks and Regards,
Chris Jerome.

You cannot add columns dynamically. But you can define a maximum number of numbers and then hide unused columns in your form useing SET_ITEM_PROPERTY(..,VISIBLE, PROPERTY_FALSE);

Provision a document library definition with managed metadata column using Visual Studio 2010 designer

hi all,
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also would like to know how to refer the parent list / column[field] in the loopkup field
help is appreciated!
thnx

Hi,
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http://gheckoplus.blogspot.com/2011/10/how-to-sharepoint-2010-list-definition.html
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http://abdulazizfarooqi.wordpress.com/2012/08/17/provisioning-lookup-field-in-sharepoint-2010-lookup-field-in-the-list-in-sharepoint-2010/
http://ronsp.wordpress.com/2011/04/27/declaratively-adding-a-lookup-field-to-a-list-schema-using-customschema-attribute-in-listinstance/
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Best regards
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TechNet Community Support

Issue when filtering with Managed Metadata Columns in Share Point Document Library

Hi All
I have a document library, and a four Metadata Columns in it, with each column having a number of term in it. I have no issues in adding a document or in term sets. We have set property of Managed Metadata Column as Allow Multiple Values. So some of the items
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We have a number of country sites having the document library with same metadata columns. In document library default view i am showing Metadata column, User want to filter the documents (view) based on Metadata column selected.
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I checked we have already kept the Metadata Navigation and Filtering under site action feature as activated. It was even more weird when i deactivated the feature on one country site and the filtering was working fine. And on other country site where i
kept the feature as activated and the filtering was giving an error.
Thanks & Regards
Amit

Hi Amit,
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then check if the issue would still persist.
Please see more information from below article with similar issue.
http://blog.tippoint.net/filter-by-managed-metadata-field-in-asset-picker-dialog/
Thanks,
Daniel Yang
Forum Support
Please remember to mark the replies as answers if they help and unmark them if they provide no help. If you havefeedback for TechNet Subscriber Support, contact [email protected]
Daniel Yang
TechNet Community Support

Updating a managed metadata column from choice column value

I am trying loop through
all lists in a web, and for each list,
1. create a managed metadata column->Working
2.
Pull value from choice column->Working
3. Move
choice column value to managed metadata column->Not Working
Point number 3 is not working. Please advise
Here is the code:
static void Main(string[] args)
//Pulling the rootweb of the Site
const string SPLocationListColumn = "CHECK6";
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Microsoft.SharePoint.Taxonomy.TaxonomySession taxonomySession = new Microsoft.SharePoint.Taxonomy.TaxonomySession(site);
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Console.WriteLine(termStore.Name);
Group group = termStore.Groups["KM Metatags"];
Console.WriteLine(group.Name);
TermSet termSet = group.TermSets["Document Classification"];
Guid termsetid = termSet.Id;
Console.WriteLine(termSet.Name);
Term term = termSet.Terms["Document subclassification"];
TermCollection terms = termSet.Terms;
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SPWebCollection collWebsite = site.AllWebs;
for (int i = 0; i < collWebsite.Count; i++)
using (SPWeb oWebsite = collWebsite[i])
//Looping through all lists in web
SPListCollection collList = oWebsite.GetListsOfType(SPBaseType.DocumentLibrary); ;
for (int j = 0; j < collList.Count; j++)
SPList list = collList[j];//if the list name is Documents, create a new field of MMS type
if (list.Title == "Documents")
Console.WriteLine(list.Title);
TaxonomyField field = list.Fields.CreateNewField("TaxonomyFieldType", SPLocationListColumn) as TaxonomyField;
field.SspId = termSet.TermStore.Id;
Console.WriteLine(termSet.TermStore.Id);
field.TermSetId = termSet.Id;
Console.WriteLine(termSet.Id);
field.AnchorId = Guid.Empty;
try
{//Add the newly added MMS field to default view
Console.WriteLine("Entering");
Console.WriteLine("Entering");
list.Fields.Add(field);
Console.WriteLine("Entering");
Console.WriteLine("Entering1");
SPView view = list.DefaultView;
Console.WriteLine("Entering2");
list.Update();
SPViewFieldCollection collViewFields = view.ViewFields;
collViewFields.Add("CHECK6");
Console.WriteLine("Entering3");
view.Update();
Console.WriteLine("Entering4");
catch (Exception e1)
Console.WriteLine(e1.Message);
}//Capture a choice field by name subclass and move it to the newly added MMS field
for (int f = 1; f < list.ItemCount; f++)
if (list.Title == "Documents")
Console.WriteLine(list.Title);
SPListItem item = list.Items[f];
if (item.Fields.ContainsField("subclass"))
SPField field9 = item.Fields["subclass"];
String subclassvalue = field9.GetFieldValueAsText(item["subclass"]);
Console.WriteLine(subclassvalue);
TaxonomyField taxonomyField = item.Fields["CHECK6"] as TaxonomyField;
TaxonomyFieldValue taxonomyFieldValue = new TaxonomyFieldValue(taxonomyField);
taxonomyFieldValue.TermGuid = term.Id.ToString();
taxonomyFieldValue.Label = subclassvalue;
taxonomyField.Update();
item.Update();
list.Update();

From here:
http://www.c-sharpcorner.com/uploadfile/anavijai/programmatically-set-value-to-the-taxonomy-field-in-sharepoint-2010/
taxonomyFieldValue.TermGuid = term.Id.ToString();
taxonomyFieldValue.Label = term.Name;
SPListItem item = list.Items.Add();
# item["Title"] ="Sample";
item["TaxonomyField"] = taxonomyFieldValue;
item.Update();
list.Update();
it appears you're missing the point where you assign that taxonomyFieldValue to the item's taxonomy field in question.

Get/retreive managed metadata column value from Document Library using SharePoint 2013 JSOM

Hi,
I am trying to retrieve managed metadata column (NewsCategory) value in SharePoint 2013 Document library using JSOM.
I get "Object Object" rather than actual value.
I tried:-
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alert(newsCat) //Displays [Object Object]
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But, I get the error "Object doesn't support property or method get_label()"
I also tried :-
var newsTags = item.get_item(' NewsCategory ');
for (var i = 0; i < newsTags.get_count() ; i++) {
var newsTag = newsTags.getItemAtIndex(i);
var newsTagLabel = newsTag.get_label();
var newsTagId = newsTag.get_termGuid();
Even now I get the error "Object doesn't support property or method get_count()"
I have included " NewsCategory " in the load request:- context.load(items, 'Include(File, NewsCategory)');
Any idea what the issue is? Do I have to add any *.js file using $.getScript?
I added following .js files
var scriptbase = _spPageContextInfo.webServerRelativeUrl + "/_layouts/15/";
$.getScript(scriptbase + "SP.Runtime.js", function () {
$.getScript(scriptbase + "SP.js", function () {
$.getScript(scriptbase + "SP.Core.js", function () {
Thanks in Advance,

Hi Patrick,
I already added those references. I just pasted the parts of script snippet in my initial post. To avoid confusion I am pasting here complete script.
2.1.1.min.js"></script>
<script type="text/javascript">
$(document).ready(function(){
var scriptbase = _spPageContextInfo.webServerRelativeUrl + "/_layouts/15/";
$.getScript(scriptbase + "SP.Runtime.js", function () {
$.getScript(scriptbase + "SP.js", function () {
$.getScript(scriptbase + "SP.Core.js", function () {
function getdata() {
var context = new SP.ClientContext.get_current();
var web = context.get_web();
var list = web.get_lists().getByTitle('Documents');
var camlQuery = new SP.CamlQuery();
var filterCategory = 'Solutions';
var IDfromTaxonomyHiddenList = 15;
camlQuery.set_viewXml('<View><Query><Where><Eq><FieldRef LookupId="TRUE" Name="'+filterCategory+'" /><Value Type="ID">' + IDfromTaxonomyHiddenList +'</Value></Eq></Where></Query></View>');
/*the above CAML query successfully gets all the list items matching the criteria including "NewsCategory" managed metadata column values
But when I try to display the value it retrieved it ouputs/emits Object Object rather than actual values */
var items = list.getItems(camlQuery);
context.load(items, 'Include(File,NewsCategory)');
context.executeQueryAsync(
Function.createDelegate(this, function (sender, args) {
if (items.get_count() > 0) {
var listItemEnumerator = items.getEnumerator();
while (listItemEnumerator.moveNext()) {
var oListItem = listItemEnumerator.get_current();
var file = oListItem.get_file();
var name = file.get_name();
var newsCat = oListItem.get_item('NewsCategory'); alert(newsTags.constructor.getName());
alert(newsCat) //Displays [Object Object]
var newsCatLabel = newsCat.get_label(); // Here it errors out with message "Object doesn't support property or method get_label()"
var newsCatId = newsCat.get_termGuid();
} //end while
}//end if
Function.createDelegate(this, function (sender, args) {
alert('Request failed. ' + args.get_message() + '\n' + args.get_stackTrace());
ExecuteOrDelayUntilScriptLoaded(getdata, "SP.Core.js");
</script>
In the above script "var name = file.get_name(); " gets the exact file name.
But the line "var newsCat = item.get_item('NewsCategory');
alert(newsCat) //Displays [Object Object] rather than actual value.
Issue resolved replace "oListItem.get_item('NewsCategory');" with oListItem.get_item('NewsCategory').get_label();"
Thanks

Add Column name conditionally in a query

Hi i have an stored procedure where one parameter is passing
@Type
UserTable (columns) => username, canAdminDelete,canCustomerDelete,CanMerchantDelete
i wants to add column conditionally like when usertype =1 then query should be like
Select * from userTable where canAdminDelete=0
when userType=2
Select * from userTable where canCustomerDelete=0
Like in this way. I know i can write three if statments and write specific query.
But this is just an example i have very big query actually.
Please give some idea.
Thanks
Niki

Hi Niki,
As per my understanding, I think the query post by Olaf is correct. It only return the results when column canAdminDelete = 0 and userTpe = 1 or column canCustomerDelete = 0 and userType = 2.
So when userType=1 and column canAdminDelete=1, how could you get the results? Could you please test the issue again based on the query post by Olaf.
If there are any misunderstanding, please elaborate the issue for further investigation.
Thanks,
Katherine Xiong
Katherine Xiong
TechNet Community Support

In table view, how to add one button for selecting page?

Hi Experts,
In the OBIEE 11.1.1.6, we have one uncommon requirement that customers want to randomly select actual page to view expected data in table view.
For example:
We make use of some columns to create one report in table view, and set 'Rows per Page' equal to '5',
if this report contains 60 rows, it will have 12 pages, so customers want to select sepcial page number to view the some data. Is it possible to implement this requirement? Maybe we should write JS code.
Note: Below table view, it has four buttons: First Row, Previous Row, Next Row and Display (500) rows in per page. So we want to add one button to select per page.
We look at orgnial codes in WebBrowse, but do not know the following codes derive from which JS file.
Could you please tell me how to find this file?
<td class="TapeDeckCell"><img class="TapeDeckImage" onclick="" onkeypress="" src="res/s_blafp/viewui/pivot/first_dis.png" title="" alt="" ><img class="TapeDeckImage" onclick="" onkeypress="" src="res/s_blafp/viewui/pivot/previous_dis.png" title="" alt="" ><img class="TapeDeckImageEna" onclick="PTRowScroll('saw_5083_b','5','5', event)" onkeypress="PTRowScroll('saw_5083_b','5','5', event)" src="res/s_blafp/viewui/pivot/next_ena.png" tabIndex="0" onmouseover="PTTD(event, 'res/s_blafp/viewui/pivot/next_ovr.png');" onmouseout="PTTDO(event)" onmousedown="PTTD(event, 'res/s_blafp/viewui/pivot/next_dwn.png');" title="Next 5 Rows" alt="Next 5 Rows" ><img class="TapeDeckImageEna" onclick="*PTRowScroll*('saw_5083_b','-1)', event)" onkeypress="PTRowScroll('saw_5083_b','-1)', event)" src="res/s_blafp/viewui/pivot/showallrows_ena.png" tabIndex="0" onmouseover="PTTD(event, 'res/s_blafp/viewui/pivot/showallrows_ovr.png');" onmouseout="PTTDO(event)" onmousedown="PTTD(event, 'res/s_blafp/viewui/pivot/showallrows_dwn.png');" title="Display maximum (500) rows per page" alt="Display maximum (500) rows per page" > <Span class="TapeDeckRecords">Rows 1 - 5</Span></td>

Hi Kobe,
Thanks for listening me.
I agree 11g have some issues unlike 10g. I've tried the same by creating a measure rcount(1) and name it as Page in RPD. I just pulled column Page in pivot table section 'Pivot Table Prompts' it is working but this may not answer your requirements.
I would suggest to use the column in Prompt and go by between operator to allow user to select the rows between.
In the report make Page as prompted.
If you are okay with this can look forward to tweak it further, like values in the prompt multiple of 5 or 10s some thing like that.
let me know updates on the same.

Add columns to datagridview

Hello everyone
I use vb.net with excel
i have a button "get the name of the columns" which give me the name of the columns of the sheet that i opened
this button with combobox , when i select an item a worksheet add named the name of the colomun i select :
is it possible to add the containt of this sheet in datagridview ???
please help me :)

this is the rest of my code
i open any
column excel this is the code:
Public Sub ComboBox2_SelectedIndexChanged(ByVal sender As System.Object, ByVal e As System.EventArgs)
xlWorkSheet = CType(xlWorkBook.Sheets(ComboBox1.Text), Excel.Worksheet)
xlWorkSheet.Activate()
xlApp.Visible = True
Dim key As String = CStr(DirectCast(ComboBox2.SelectedItem, KeyValuePair(Of Integer, String)).Key)
Dim value As String = DirectCast(ComboBox2.SelectedItem, KeyValuePair(Of Integer, String)).Value
Dim DoesSheetExists As Boolean = False
For Each xs In xlApp.Sheets
If xs.Name = value Then
DoesSheetExists = True
End If
Next
If DoesSheetExists = True Then
MsgBox("Sheet already exists", CType(MessageBoxIcon.Error, MsgBoxStyle))
Else
With xlWorkSheet
Dim lastrow As Integer = xlWorkSheet.Cells.Rows.End(XlDirection.xlDown).Row
Dim colletter As String = ColumnIndexToColumnLetter(CInt(key))
exWS2 = DirectCast(xlWorkBook.Sheets.Add, Microsoft.Office.Interop.Excel.Worksheet)
exWS2.Name = value
xlWorkSheet.Range("A1:A" & lastrow.ToString).Copy(exWS2.Range("A1"))
xlWorkSheet.Range(colletter & "1:" & colletter & lastrow.ToString).Copy(exWS2.Range("B1"))
End With
Me.Hide()
Form3.Show()
End If
End Sub
this
column will be add in the new sheet which has the name of the column that i select of the combobox .
what
i want is to add the column that i opened in datagridview1
Also
i have to calculate sum , max and min of the column, I want to add also the sum , max and min in datagridview2
my
form that open excel file and add the sheet :
And my file
excel :

E_recruiting Applicant management-- add columns to Candidate Selection scre

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