Editing While Loop Conditions hangs JDeveloper 10.1.3

Hi Guys,
Having a strange problem when I tried to edit the condition in a while loop after it was created and set first time. The IDE just hanged when I tried to open the expression builder and after a while, nothing happened, the expression builder didn't show up.
I went and deleted the condition by editing the source, basically made condition from:
<while name="While_1"
condition="bpws:getVariableData('inputVariable','payload','/client:WhileLoopTesterProcessRequest/client:input')<10">
to
<while name="While_1"
condition="">
Switched back to graphics mode, the expression builder opens up normally.
I understand that we are evaluation a Developers Preview, so just wanted to bring this to the notice of the developers.
Any solutions before the Production release?
Regards,
- Soumen.

Hi Willian,
Did you set up your "Model" Project to use the JDK 1.4 and rebuild the application ?
See " [Deploying to Application Servers That Support JDK 1.4|http://tinyurl.com/lfc6kc] "
Regards,
Didier.

Similar Messages

Help with a while loop condition

I'm trying to write to a File. I ask the user for input, then I enter a while loop and test the condition. The loop works, but it won't stop. I've tried everything. Here is my code please help!!
thanks
inputline = keyboard.readLine();//read the keyboard
try{
while( inputline != null ){
DiskOut.println( inputline );
DiskOut.flush();
inputline = keyboard.readLine();//read the keyboard again
}//end while
}//end try
catch (IOException e) {
e.printStackTrace();
}//end catch
also i've tried these while loop conditions:
while(inputline != "\n" || inputline != "\r") and the sort

while(inputline != "\n" || inputline != "\r")The condition
X!=Y OR X!=Z (given Y != Z)
is always true. X will always not be equal to at least one of the values. So you'll want to use:
while(!inputline.equals("\n") && !inputline.equals("\r"))In other words, "while inputline is not equal to either of them". Note the use of && instead of ||.
If "keyboard" is simply a BufferedReader on top of System.in (and not your own class), the trailing line feeds and carriage returns won't even be in the string returned by readLine(). Your best bet is this:
while(null != inputline && 0 != inputline.length())Make sure you type the two parts of that AND condition in the order above. If for whatever reason there are trailing \r and \n on the strings, you'll want to accomodate for platforms that may include both characters.
// trim the trailing newline characters
while(inputline.endsWith("\r") ||
inputline.endsWith("\n")) {
inputline = inputline.substring(0,inputline.length()-1);
// or maybe this will work if you don't mind losing
// the whitespace at the beginning of the string:
inputline = inputline.trim();Hope that helps somewhat.

If statement on a while loop condition

Hello,
I was just wondering whether it was possible to have an if statement on a while loop. Basically, I have a while loop that has the following terminating condition
do{
//...loop code here
while (netError > acceptableError && learningCycle < 100000 && alive);I'm looking to introduce a boolean "ignoreMaxCycles" that basically stops the loop from taking notice of the learningCycle clause of the condition.
do{
//...loop code here
while (netError > acceptableError && alive);I know it can be done repeating the two loops with an if statement governing which one is executed, but I was wondering whether there was a shorter/cleaner way of doing this?
Thanks,
Nick

nickd_101 wrote:
Hello,
I was just wondering whether it was possible to have an if statement on a while loop. Basically, I have a while loop that has the following terminating condition
do{
//...loop code here
while (netError > acceptableError && learningCycle < 100000 && alive);I'm looking to introduce a boolean "ignoreMaxCycles" that basically stops the loop from taking notice of the learningCycle clause of the condition.
do{
//...loop code here
while (netError > acceptableError && alive);I know it can be done repeating the two loops with an if statement governing which one is executed, but I was wondering whether there was a shorter/cleaner way of doing this?
Thanks,
Nick
do {
while(netError > acceptableError && (ignoreMaxCycles || learningCycle < 100000) && alive)wtf ? i took 2 minutes for that ?
Edited by: darth_code_r on Aug 29, 2008 9:21 AM

While loop condition check

Dear All,
attached is an NI that does the following.
1. The user inputs a frequency and amplitude range to drive a speaker.
2. A laser displacement sensor measure the speaker displacement, checks if it is in the desired range, and jumps on to the next frequency, if its not in the desired range it tries another drive voltage.
The program works fine, the problem is, is that the while loop checks the condition in the beginning or the middle of the loop, therefore if it is in range instead of stoping at that particular amplitude and frequency, it goes to the next amplitdue before going to the next frequency. Since at the begining of the loop execution the condition was different that in the middle.
How can I force the while loop to read the condition only after the sequence inside has completed.
Thank you
Ala
Attachments:
AmpFinder.vi ‏431 KB

Dear All,
I think this fixes the problem
Cheers,
Ala
Attachments:
AmpFinder.vi ‏431 KB

How to code a parallel 'for loop' and 'while loop' where the while loop cannot terminate until the for loop has finished?? (queues also present)

I've attached a sample VI that I just cannot figure out how to get working the way that I want. I've labeled the some sections with black-on-yellow text boxes for clarity during the description that follows in the next few sentences. Here's what I want:
1) overall -- i'm intend for this to be a subVI that will do data acquisition and write the data to a file. I want it to use a producer/consumer approach. The producer construct is the 'parallel for loop' that runs an exact number of times depending on user input (which will come from the mainVI that is not included). For now I've wired a 1-D array w/ 2 elements as a test case. During the producer loop, the data is acquired and put into a queue to be delt with in the consumer loop (for now, i just add a random number to the queue).
2) the consumer construct is the 'parallel while loop'. It will dequeue elements and write them to a file. I want this to keep running continuously and parallel until two conditions are met.
      i. the for loop has finished execution
      ii. the queue is empty.
   when the conditions are met, the while loop will exit, close the queue, and the subVI will finish. (and return stuff to mainVI that i can deal with on my own)
Here's the problems.
1) in the "parallel for loop" I have a flat sequence structure.. I haven't had time to incorporate some data dependency into these two sequential sections, but basically, I just care that the "inner while loop" condition is met before the data is collected and queued. I think I can do this on my own, but if you have suggestions, I'm interested.
2) I can easily get the outer for and while loops to run sequentially, but I want them to run in parallel. My reasoning for this is that that I anticipate the two tasks taking very different amounts of time. .. basically, I want the while loop to just keep polling the queue to get everything out of it (or I suppose I could somehow use notifiers - suggestions welcome)... the thing is, this loop will probably run faster than the for loop, so just checking to see that the queue is empty will not work... I need to meet the additional condition that nothing else will be placed in the queue - and this condition is met when the for loop is complete. basically, I just can't figure out how to do this.
3) for now, I've placed a simple stop button in the 'parallel while loop', but I must be missing something fundamental here, because the stop button is totally unresponsive. i.e. - when I press it, it stays depressed, and nothing happens.
suggestions are totally welcome!
thanks,
-Z
Attachments:
daq01v1.vi ‏59 KB

I'd actually like to add a little more, since I thought about it a bit and I'm still not quite certain I understand the sequence of events...
altenbach wrote:
zskillz wrote:
So i read a bit more about the 'dequeue element' function, and as I understand it, since there is no timeout wired to the dequeue element function, it will wait forever, thus the race condition I suggested above can never happen!
Yes, you got it!
As I've thought about it a bit more, there's a few things that surprise me... first, the reason the 'dequeue element while loop' errors is not because there's nothing in the queue, it's becaues the queue has been released and it's trying to access that released queue... However the problem I have is this --- Even though there's no timeout wired to the dequeue element, I still would think that the while loop that contains it would continue to run at whatever pace it wanted -- and as i said before.. most of the time, it would find that there is nothing to dequeue, but once in a while, something is there. however, it seems that this loop only runs when something has been enqueued. the reason I say this is illustrated in the next code sample MODv2 that's attached below. I've added a stop button to the "queue size while loop" so the program runs until that is pressed. I've also added a simple conditional in the "dequeue while loop" that generates a random number if it a button is pressed... but this button is totally non-responsive... which means to me that the "dequeue while loop" isn't actually continuously running, but only when an element is added to the queue. this still seems almost like the 'dequeue while loop" waits for a notifier from the queue telling it to run. can you explain this to me? because it is different from what I expect to be happening.
rasputin wrote:
I tried to open your VIs but it doesn't work. LV
is launched, the dialog box (new, open, configure...) opens and then...
nothing. Not even an error message. I guess it isn't a problem of LV
version or a dialog box would appear saying this. Could you, please,
send a image of the code?
Thanks,
Hi Rasputin, I'm using LV8. I assume that was your problem, but who knows. I've attached a pic of of altenbach's solution since it's what I needed.
thanks
-Z
Message Edited by zskillz on 10-20-2006 11:49 AM
Attachments:
daq01v1MODv2.vi ‏63 KB
daq01v1MODpic.JPG ‏116 KB

Why does a sequence structure execute if a while loop is to the left of it?

I have a while loop in a case structure whose boolean is wired to a sub vi. To the right of this structure I have a sequence that executes regardless of the while loops condition. I assumed that the program would not continue to the case structure until the while loop stopped. Then it would proceed to the case structure.
Thank You

jemengineering wrote:
I have a while loop in a case structure whose boolean is wired to a sub vi. To the right of this structure I have a sequence that executes regardless of the while loops condition. I assumed that the program would not continue to the case structure until the while loop stopped. Then it would proceed to the case structure.
As others have mentioned, you have to familiarize yourself with the core idea of dataflow programming. One of the great powers of LabVIEW is the fact that things can occur in paralell unless there is data dependency.
A good start would be the LabVIEW beginners online tutorial:
http://www.ni.com/swf/presentation/us/labview/aap/default.htm
The quiz #1 on slide 11 deals with the above issues. Try to answer it.
In your particular case, you need to force execution order. This can be done by creating a data dependency (preferred) or by the use of a sequence structure. You could e.g. create a 2-frame flat sequence and place the loop in the first frame and the case structure in the second frame.
The picture shows a few scenarios for comparison. Can you spot the differences? Understanding dataflow is crucial for writing any LabVIEW program.
Message Edited by altenbach on 07-31-2006 06:49 AM
LabVIEW Champion . Do more with less code and in less time .
Attachments:
ExecutionOrder.png ‏19 KB

I have a for loop inside of while loop.when i press stop for while loop, i also would like to stop for loop.how can i solve this problem?thanks

i have a for loop inside of while loop.when i press stop for while loop, i also would like to stop for loop.how can i solve this problem?thanks

Hi fais,
Following through with what JB suggested. The steps involved in replacing the inner for loop with a while loop are outlined below.
You can replace the inner for loop with a while by doing the following.
1) Right-click of the for loop and select "Repalce" then navigate to the "while loop".
2) Make sure the tunnels you where indexing on with the for loop are still indexing.
3) Drop an "array size" node on your diagram. Wire the array that determines the number of iterations your for loop executes into this "array size".
4) Wire the output of the array size into the new while loop.
5) Set the condition terminal to "stop if true".
6)Drop an "OR" gate inside the while loop and wire its output to the while loops condition terminal.
7) C
reate a local of the boolean "stop" button, and wire it into one of the inputs of your OR gate. This will allow you to stop the inner loop.
8) Drop a "less than" node inside the inner while loop.
9) Wire your iteration count into the bottom input of the "less than".
10) Wire the count (see step 4 above) into the top input of the less than. This will stop the inner loop when ever the inner loop has processed the last element of your array.
Provided I have not mixed up my tops and bottoms this should accomplish the replacement.
I will let others explain how to takle this task using the "case solution".
Ben
Ben Rayner
I am currently active on.. MainStream Preppers
Rayner's Ridge is under construction

While loop problems

hey guys,
i made a program that counts any system with single character values (binary, ternary, octal, decimal,...etc) I am asking the user to input a starting point to count from and a stoping point to stop at. It starts from the correct place but does not stop.
For some reason it is ignoring my while loop condition. anyone got any idea why this would happen?
import javax.swing.*;
import java.util.*;
class Counting
     public static void main(String[] args)
          String input,start,stop,s;
          int spaces;
          input = JOptionPane.showInputDialog("Enter number of spaces.");
          spaces = Integer.parseInt(input);
          s = JOptionPane.showInputDialog("Enter counting symbols in sorted order.");
          start = JOptionPane.showInputDialog("Enter the stating number. (" + spaces + " characters).");
          stop = JOptionPane.showInputDialog("Enter the number to stop at. (" + spaces + " characters).");
          StringBuffer num = new StringBuffer(start);
          int lspace = spaces - 1;
          int i,j;
          String k,z;
          System.out.println(num);
          while(num.equals(stop)!=true)
               k = Character.toString((num.charAt(lspace)));
               z = Character.toString((s.charAt(s.length()-1)));
               if(k.equals(z)==false)
                    i = s.indexOf(num.charAt(lspace));
                    num.setCharAt(lspace, s.charAt(i+1));
               else
                    num.setCharAt(lspace, s.charAt(0));
                    lspace--;
                    i = s.indexOf(num.charAt(lspace));
                    num.setCharAt(lspace, s.charAt(i+1));
                    lspace = spaces - 1;
               System.out.println(num);
          System.exit(0);
}

i got it to work.
here is the if anyone is interested. Thank for the help!
import javax.swing.*;
import java.util.*;
class Counting
     public static void main(String[] args)
          String input,start,stop,s;
          int spaces;
          input = JOptionPane.showInputDialog("Enter number of spaces.");
          spaces = Integer.parseInt(input);
          s = JOptionPane.showInputDialog("Enter counting symbols in sorted order.");
          start = JOptionPane.showInputDialog("Enter the stating number. (" + spaces + " characters).");
          stop = JOptionPane.showInputDialog("Enter the number to stop at. (" + spaces + " characters).");
          StringBuffer num = new StringBuffer(start);
          int lspace = spaces - 1;
          int i,j;
          String k,z;
          System.out.println(num);
          while(!num.toString().equals(stop))
               k = Character.toString((num.charAt(lspace)));
               z = Character.toString((s.charAt(s.length()-1)));
               if(k.equals(z)==false)
                    i = s.indexOf(num.charAt(lspace));
                    num.setCharAt(lspace, s.charAt(i+1));
               else
                    while((Character.toString((num.charAt(lspace)))).equals(z)==true)
                         num.setCharAt(lspace, s.charAt(0));
                         lspace--;
                    i = s.indexOf(num.charAt(lspace));
                    num.setCharAt(lspace, s.charAt(i+1));
                    lspace = spaces - 1;
               System.out.println(num);
          System.exit(0);
}

Quit while loop in event structure

Hello,
I used event structure in my application and I would like to quit a while loop in an event structure when I pressed a control. But I have a problem because I'm in the event.
Do you have a solution.
Sam.
Attachments:
Problem.vi ‏34 KB

Hi,
connect a true constant to the While loop conditional terminal in the STOP event case.
See your example modified.
Good luck,
Alberto
Attachments:
Problem[2].vi ‏35 KB

Cluster Controls causes either one loop to hang or LabVIEW to hang

I am working on a program that has three clusters. Each cluster has LED controls inside them. During the test the Board Image, Block Diagram, and Measurement Number controls will be changed accordingly. When probing, the while loops that hang most often are the top one (board Image) and the bottom one (schematic). Sometimes LabVIEW becomes unresponsive and I have to abort the program. Any suggestions?
Solved!
Go to Solution.

usman.arif wrote:
Hi and slam to all
I have a problem. i had made a labview program for controlling an electronic box. I had designed a GUI. GUI has to work 24/7. It worked best for a month or so. then my GUI started getting malfunctioning specially string control became disabled showing no data and some case statements stopped working. Is that true that Labview is no an industrial grade tool, its just for lab purpose...??? These bugs have threaten my reputation alot.
This seems completely unrelated to the topic of this old thread that is already marked as solved. (and why did you quote that entire first message, incuding the images???)
Let's make sure your reputation as a forum poster is not getting tarnished by these strange habits.
I recommend that you start a new thread.
LabVIEW is "industrial grade" and used everywhere for mission critical applications (CERN, SpaceX, etc. etc.)
Please post your code. It is possible that you have programmed your code inefficiently in a way that it uses more and more memory over time, until it finally runs out. How do you tell if a case statement stops working? String controls are to enter data, not to show data. What is an "electronic box"? can you be more specific?
LabVIEW Champion . Do more with less code and in less time .

While loop hangs in my script

Hi guys,
I want to check if SCCM (install windows image) is ready.
If it's not, than it has to sleep. I want this in a while loop because when it takes longer, it must loop another
5 minutes.
When the image is ready it must go back to the rest of this script.
My loop hangs and the script never finishes. What am i doing wrong?
Kind regards,
André
$compObject = get-wmiobject -query "select * from SMS_R_SYSTEM WHERE Name='$hostName'" -computername "dhgms401" -namespace "ROOT\SMS\site_S01"
$compObjectstatus = $compObject.client
do {
Start-Sleep -Seconds 300
while ($compObjectstatus -eq 0)
write "Sccm is klaar "
Write "$hostName has been started"
$newHostName = Get-ADComputer -filter {(name -eq $hostName)}

Not 100% sure but, I believe the issue is with your conditional statement for your while loop
while ($compObjectstatus -eq 0)
$compObjectStatus will never change so your while loop will never equal 0 unless it did from the begining. You will have to requery each time to get an update on the status, so possibly create a function on the query end of things, and just run the function
Function GetStatus
$compObject = get-wmiobject -query "select * from SMS_R_SYSTEM WHERE Name='$hostName'" -computername "dhgms401" -namespace "ROOT\SMS\site_S01"
$compObjectstatus = $compObject.client return $compObjectstatus
do {
Start-Sleep -Seconds 300
while (GetStatus -eq 0)
write "Sccm is klaar "
Write "$hostName has been started"
$newHostName = Get-ADComputer -filter {(name -eq $hostName)}
I cannot test so I do not know if it works as expected
If you find that my post has answered your question, please mark it as the answer. If you find my post to be helpful in anyway, please click vote as helpful.
Don't Retire Technet

Running java process in a while loop using Runtime.exec() hangs on solaris

I'm writting a multithreaded application in which I'll be starting multiple instances of "AppStartThread" class (given below). If I start only one instance of "AppStartThread", it is working fine. But if I start more than one instance of "AppStartThread", one of the threads hangs after some time (occasionaly). But other threads are working fine.
I have the following questions:
1. Is there any problem with starting a Thread inside another thread?. Here I'm executing the process in a while loop.
2. Other thing i noticed is the Thread is hanging after completing the process ("java ExecuteProcess"). But the P.waitFor() is not coming out.
3. Is it bcoz of the same problem as given in Bug ID : 4098442 ?.
4. Also java 1.2.2 documentation says:
"Because some native platforms only provide limited buffer size for standard input and output streams, failure to promptly write the input stream or read the output stream of the subprocess may cause the subprocess to block, and even deadlock. "
I'm running this on sun Solaris/java 1.2.2 standard edition. If any of you have experienced the same problem please help me out.
Will the same problem can happen on java 1.2.2 enterprise edition.?
class AppStartThread implements Runnable
public void run()
while(true)
try
Process P=Runtime.getRuntime().exec("java ExecuteProcess");
P.waitFor();
System.out.println("after executing application.");
P.destroy();
P = null;
System.gc();
catch(java.io.IOException io)
System.out.println("Could not execute application - IOException " + io);
catch(java.lang.InterruptedException ip)
System.out.println("Could not execute application - InterruptedException" + ip);
catch (Exception e)
System.out.println("Could not execute application -" + e.getMessage());

I'm writting a multithreaded application in which I'll
be starting multiple instances of "AppStartThread"
class (given below). If I start only one instance of
"AppStartThread", it is working fine. But if I start
more than one instance of "AppStartThread", one of the
threads hangs after some time (occasionaly). But other
threads are working fine.
I have the following questions:
1. Is there any problem with starting a Thread inside
another thread?. Here I'm executing the process in a
while loop.Of course this is OK, as your code is always being run by one thread or another. And no, it doesn't depend on which thread is starting threads.
2. Other thing i noticed is the Thread is hanging
after completing the process ("java ExecuteProcess").
But the P.waitFor() is not coming out.This is a vital clue. Is the process started by the Runtime.exec() actually completing or does the ps command still show that it is running?
3. Is it bcoz of the same problem as given in Bug ID :
4098442 ?.
4. Also java 1.2.2 documentation says:
"Because some native platforms only provide limited
ed buffer size for standard input and output streams,
failure to promptly write the input stream or read the
output stream of the subprocess may cause the
subprocess to block, and even deadlock. "These two are really the same thing (4098442 is not really a bug due to the reasons explained in the doc). If the program that you are exec'ing produces very much output, it is possible that the buffers to stdout and stderr are filling preventing your program from continuing. On Windows platforms, this buffer size is quite small (hundreds of characters) while (if I recall) on Solaris it is somewhat larger. However, I have seent his behavior causing problem on Solaris 8 in my own systems.
I once hit this problem when I was 'sure' that I was emitting no output due to an exception being thrown that I wasn't even aware of - the stack trace was more than enough to fill the output buffer and cause the deadlock.
You have several options. One, you could replace the System.out and System.err with PrintStream's backed up by (ie. on top of) BufferedOutputStream's that have large buffers (multi-K) that in turn are backed up by the original out and err PrintStream's. You would use System.setErr() and System.setOut() very early (static initializer block) in the startup of your class. The problem is that you are still at the mercy of code that may call flush() on these streams. I suppose you could implement your own FilterOutputStream to eat any flush requests...
Another solution if you just don't care about the output is to replace System.out and System.err with PrintStreams that write to /dev/nul. This is really easy and efficient.
The other tried and true approach is to start two threads in the main process each time you start a process. These will simply consume anything that is emitted through the stdout and stderr pipes. These would die when the streams close (i.e. when the process exits). Not pretty, but it works. I'd be worried about the overhead of two additional threads per external process except that processes have such huge overhead (considering you are starting a JVM) that it just won't matter. And it's not like the CPU is going to get hit much.
If you do this frequently in your program you might consider using a worker thread pool (see Doug Lea's Executor class) to avoid creating a lot of fairly short-lived threads. But this is probably over-optimizing.
Chuck

How to call sub VI and close the main VI in while loop and sequence condition

Hiya,
I have a problem with the while loop and the sequential condition in placed together i.e while loop as Global and sequential condition as local (i.e inside the Global loop). For example,when calling the sub vi from the main vi (main vi as main menu and sub vi as sub menu.)My problem is I can't run my sub menu when the particular icon is pressed through the main menu and only the front panel appears. My concerned was if possible the sub menu is activated in few second then jump back to the main menu again (analyze through the diagram).So, I don't know what should I need to do. If possible, please advice me how to encountered that particular problem.
Thanks!

Go to your block diagram of your main menu, then click on the "Hightlight Execution" it is something like a bulb. then you execute your vi. then LV will show you all your data flow.
When you feel sad, laugh

Writing a file for prescribed amount of time in a while loop after the triggering condition is met

Hello Guys,
I am trying to program an application in which if the trigger condition is met it should start to write the file.
I was able to do that, but if I want it to be written for certain amount of time, and once the trigger condition is met, it should continue to write the files for prescribed amount of time. I was not able to do this. The file name should also be updated accordingly.
I tried to with some options by keeping the creation of the file outside of the loop, if I do that then if the trigger condition is not met it will stop writing and I dont want that, as once the trigger condition is met it should be true thereafter.
So I cant keep any thing outside the while loop, bcaz then it checks the condition of the shift register for the trigger and I have it as a false constant.
I am attaching my application which is kind of mess and I have written in the application where I am having problems. For every iteration of while loop it makes a new file, and i dont want that, I want to write specific amount of time data to the each file.
Please take a look at my code and help me in solving the problem. Any insights and examples on how to do this thing will be a relief to me.
Thanks in advance.
Regards,
Nitin
Attachments:
PXI_4462_Sync_and_Stream_trigger.zip ‏192 KB

what i am saying is to keep track of how much data you have written and whenever you need to make a new file you make 1.
here is a vi that i just made that should show you. let me know if you need any help understanding it.
Attachments:
new file exemple.vi.zip ‏21 KB

While loop and for loop condition terminal

Hello friends,
I am using labview 8.6. The condition terminal of the while loop and conditional for loop is behaving in just the opposite way.
When i wire a true to the condition terminal of my loop, the while loop continues to run when I click on run. when I wire a FALSE, it stops.
Is there any setting change that I have to make it to get it work properly.
Please suggest on this.
Thanks and regards,
Herok

Please do NOT attach .bmp images with the extension changed to .jpg to circumvent the forum filters!
Herok wrote:
I am sending you the VI. I am not sure if this would help you because only in 2 computers this behaviour is seen. In others, it works as it is supposed to work.
Whatever you are seeing must be due to some corruption or folding error. It all works fine here.
To make sure there are no hidden objects, simply press the cleanup button which would reveal any extra stuff (which is obviously not there). Does it fix itself if you click the termination terminal an even number of times? What if you remove the bad loop and create a new one?
Could it be you have some problems with the graphics card and the icon of the conditional terminal does not update correctly?
Whay happens if you connect a control instead of a diagram constant?
What is different on the computers where it acts incorrectly (different CPU (brand, model), #of cores, etc.)
LabVIEW Champion . Do more with less code and in less time .

Editing While Loop Conditions hangs JDeveloper 10.1.3

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