EJB QL "LIKE" OPERATOR NIGHTMARE

Question

i want to pass input parameter to my ejb ql.
it will look like this :
"SELECT OBJECT(p) FROM EntityBeanTable p WHERE p.Title LIKE ?1"
But it seem its imposible with ejb 2.0. am i right ?
how to overcome this then,
"LIKE" operator is so damn important, without this we can't continue our development.
shall we use bmp ? or ????

Answer 1

You can use the like operator with parameters, you just have to put your wildcards into the parameter. Here's an excerpt:
A query that uses a LIKE operator would look something like this:
SELECT DISTINCT OBJECT(user)
FROM User user
WHERE user.userInfo.lastName LIKE ?1
If you check out the code in the code listing on the left-hand side of this panel, you will
note that a method exposes this functionality from the UserManagement session bean
so that you can access it from the client with the getUserByLastNameLike()
method. Thus, to use getUserByLastNameLike(), you can specify the pattern
string as a parameter.
For example, to find users with last names like "High", you would pass the following
parameter value:
users = userMgmt.getUserByLastNameLike("High%");