Problem in JDBC , when using LIKE operator. - VERY URGENT

Question

Problem in JDBC , when using LIKE operator.
LINE 1 : String temp = "AA";
LINE 2 : String query = "select * from emp where EMPNAME like '*temp*' ";
LINE 3 : Staement st = con.createStaement();
LINE 4 : ResultSet rs = st.executeQuery(query);
'*' character is not getting evaluated. In MS ACCESS2000 only * is accepted instead of '%'. Moreover in MS ACCESS the like operator has to be used within double quotes as a String. whereas in other databases, it accepts single quotes as a String.
Ex:
In MS ACCESS
     select * from emp where ename like "*aa*";
Other Databases
     select * from emp where ename like '%aa%';
In my situation iam passing a Variable inside a like operator and '*' is used.
For the above Scenario, Please help me out.
If possible Kindly let me know the exact Syntax.
Please give me the answer as LINE1,LINE2,LINE3,LINE4,
I have verified in JDBC Spec also, it has been specified to use escape sequence.that too did not work.
Due to this, My project is in hold for about 4 days. I could not find a suitable solution.
Please help me out.

Answer 1

I made a LIKE clause work with M$ Access, using PreparedStatement and the % wildcard:
            escapeStr                   = "%";
            String sql                  = "SELECT USERNAME, PASSWORD FROM USERS WHERE USERNAME LIKE ?";
            PreparedStatement statement = connection.prepareStatement(sql);
            statement.setString(1, ("user" + escapeStr));
            ResultSet resultSet         = statement.executeQuery();
            while (resultSet.next())
                System.out.println("username: " + resultSet.getObject("USERNAME") + " password: " + resultSet.getObject("PASSWORD"));