Eliminate duplicate values in a column
I have a table with following data
Dat id name
24-sep-2008 1 a
24-sep-2008 2 b
25-sep-2008 3 c
25-sep-2008 4 d
I want fetch only unique dat feild .
ex:
the result of the query im only expecting
24-sep-2008
25-sep-2008
I want fetch only unique dat feild . you have answer in your question itself :-)
How about some reading on the document.
http://download.oracle.com/docs/cd/B19306_01/server.102/b14200/statements_10002.htm#SQLRF01702
Similar Messages
-
Finding duplicate values in a column with different values in a different c
I'm finding duplicate values in a column of my table:
select ba.CLAIM_NUMBER from bsi_auto_vw ba
group by ba.CLAIM_NUMBER
having count(*) > 1;
How can I modify this query to find duplicate values in that column where I DON'T have duplicate values in a different specific column in that table (the column CLMT_NO in my case can't have duplicates.)?Well, you can use analytics assuming you don't mind full scanning the table.....
select
count(owner) over (partition by object_type),
count(object_type) over (partition by owner)
from all_objects;You just need to intelligently (i didn't here) find your "window" (partition clause) to sort the data over, then make use of that (the analytics would be in a nested SQL and you'd then evaluate it in outside).
Should be applicable if i understand what you're after.
If you post some sample data we can mock up a SQL statement for you (if what i tried to convey wasn't understandable). -
How find out the duplicate value from each columns.
I have below four columns,
How can i find out the duplicate value from each columns.
with All_files as (
select '1000' as INVOICE,'2000' AS DELIVERYNOTE,'3000' CANDELINVOICE,'4000' CANDELIVERYNOTE from dual union all
select '5000','6000','7000','8000' from dual union all
select '9000','1000','1100','1200' from dual union all
select '1200','3400','6700','8790' from dual union all
select '1000','2000','3000','9000' from dual union all
select '1230','2340','3450','4560' from dual
SELECT * FROM All_files
Output should be as per below.
1000 2000 3000 4000
9000 1000 1100 1200
1200 3400 6700 8790
1000 2000 3000 9000
Required to check uniqueness in cross columns.
Thanks.Try this (sorry about the formatting)...
WITH all_files AS (SELECT '1000' AS INVOICE,
'2000' AS DELIVERYNOTE,
'3000' CANDELINVOICE,
'4000' CANDELIVERYNOTE
FROM DUAL
UNION ALL
SELECT '5000',
'6000',
'7000',
'8000'
FROM DUAL
UNION ALL
SELECT '9000',
'1000',
'1100',
'1200'
FROM DUAL
UNION ALL
SELECT '1200',
'3400',
'6700',
'8790'
FROM DUAL
UNION ALL
SELECT '1000',
'2000',
'3000',
'9000'
FROM DUAL
UNION ALL
SELECT '1230',
'2340',
'3450',
'4560'
FROM DUAL),
t_base
AS (SELECT invoice
|| ','
|| deliverynote
|| ','
|| candelinvoice
|| ','
|| candeliverynote
str
FROM all_files),
t_str
AS (SELECT str || ',' AS str,
(LENGTH (str) - LENGTH (REPLACE (str, ','))) + 1
AS no_of_elements
FROM t_base),
t_n_rows
AS ( SELECT LEVEL AS i
FROM DUAL
CONNECT BY LEVEL <=
( SELECT SUM (no_of_elements) FROM t_str)),
t_build AS (SELECT t_str.str,
nt.i AS element_no,
INSTR (t_str.str,
DECODE (nt.i, 1, 0, 1),
DECODE (nt.i, 1, 1, nt.i - 1))
+ 1
AS start_pos,
INSTR (t_str.str,
1,
DECODE (nt.i, 1, 1, nt.i))
AS next_pos
FROM t_str
JOIN
t_n_rows nt
ON nt.i <= t_str.no_of_elements),
t_build2
AS (SELECT RTRIM (str, ',') AS original_string,
SUBSTR (str, start_pos, (next_pos - start_pos))
AS single_element,
element_no
FROM t_build),
t_build3
AS (SELECT single_element,
COUNT( * )
OVER (PARTITION BY single_element
ORDER BY single_element)
ele_count
FROM t_build2)
SELECT DISTINCT INVOICE,
DELIVERYNOTE,
CANDELINVOICE,
CANDELIVERYNOTE
FROM all_files, t_build3
WHERE ele_count > 1
AND ( INVOICE = single_element
OR DELIVERYNOTE = single_element
OR CANDELINVOICE = single_element
OR CANDELIVERYNOTE = single_element)I think this will be faster than the previous solution?
Cheers
Ben
Edited by: Munky on Feb 17, 2011 2:11 PM - "I think this will be faster than the previous solution?", nope - it's not :( -
How to delete duplicate values in a column?
consider a table contains 2 columns(NAME & DEPARTMENT)
NAME DEPARTMENT
santhosh finance
santhosh marketing
rahul sales
stephen IT
stephen sales
In the above table how to delete only the duplicate values(santhosh,stephen) in the column?If you don't care??
delete emp
where 1 < (select row_number() over(partition by deptno order by 1) from emp)
Error at line 1
ORA-01427: single-row subquery returns more than one rowI'd use something like
delete emp e1
where exists
(select null
from (select deptno, rowid rid, row_number () over (partition by deptno order by 1) rn from emp) e2
where e1.rowid = e2.rid
and 1 < rn) -
How to test if there are duplicate values in a column using PL/SQL
Hello,
I want to be able to test if there are duplicate values (VARCHAR2) in a particular column of the database using PL/SQL.
Thanks
DouglasIf I have understood your requirement, then you are asking for a query like following.
Select column_name from Tbl_name
group by column_name
having count(*) > 1; -
How to remove all duplicate values from a column
For some reason when a user is adding a record, it duplicates it three times. Why is that happening?
Since there is many how can I remove any records that contains a duplicate in a specific column?Is this happening for all lists in site collection or this is the only one?
Check on the list if there is any workflow attached. If yes then open the workflow in designer and check its logic it might be written to copy list items.
Investigate if there is an event receiver deployed in your site where it creates duplicate entries. There has to be some custom code running which is causing this duplication otherwise out of the box behavior of lists is never like this.
Please remember to click 'Mark as Answer'
if the reply answers your query or 'Upvote' if it helps you. -
How to restrict the duplicate values in lov column of VO based Adv Table
Hi Gurus,
I want to restrict the duplicate values at lov which is a colunm in an Adv Table.
If user enters duplicate values then first it should show an error msg that Duplicate values have been entered.
After the duplicate values have been removed, then the user can save all the values in the table.
My Adv Table is based on a VO.
The link how to restrict the duplicate values at form level
talks about Adv Table based on a EoVO, which doesnot work in my case.
My Approach,
I am iterating through RowSetIterator and committing through PROCEDURE.
I am able to avoid duplicate entry through a function checkRespId. (given below)
Below code is for iterating and committing.
public void saveline(String reqid,String userid)
System.out.println("RequestId/saveline"+reqid);
System.out.println("UserId/saveline"+userid);
OAViewObject vo = (OAViewObject)getRespLineVO1();
RespLineVORowImpl row = null;
int fetchedRowCount = vo.getFetchedRowCount();
RowSetIterator deleteIter = vo.createRowSetIterator("deleteIter");
if (fetchedRowCount > 0)
deleteIter.setRangeStart(0);
deleteIter.setRangeSize(fetchedRowCount);
for (int i = 0; i < fetchedRowCount; i++)
System.out.println("Inside the for LOOP");
row = (RespLineVORowImpl)deleteIter.getRowAtRangeIndex(i);
String respoidid = row.getAttribute("ResponsibilityId")+"";
String respname = row.getAttribute("ResponsibilityName")+"";
String stdate = row.getAttribute("StartDate")+"";
String enddate = row.getAttribute("EndDate")+"";
String linestatus ="A";
if(userid!=null)
if(!(respoidid.equals("null")) && respoidid!=null)
String checkingrespid=null;
checkingrespid = checkRespId(userid,respoidid);+contains no if not duplicate and yes if its duplicate+
System.out.println("checkingrespid for Resp with ID :"+respoidid+"exists or not "+checkingrespid);
if(checkingrespid.equals("No"))
String message, result = null;
Connection txn = getOADBTransaction().getJdbcConnection();
try
calling PROC ...
catch(Exception e)
message = "Error in Inserting into line" + e;
throw new OAException(message, OAException.ERROR);
else
throw new OAException("You have entered duplicate no. of values", OAException.ERROR);
else
System.out.println("respoidid is null");
break;
deleteIter.closeRowSetIterator();
public String checkRespId(String userid,String respoidid)
String createRow="No";
OAViewObject vo = (OAViewObject)findViewObject("CheckRespVO1");
if (vo != null)
vo.setWhereClauseParams(null);
vo.setWhereClauseParam(0, userid);
vo.setWhereClauseParam(1, respoidid);
vo.executeQuery();
System.out.println("ROW COUNT IS "+vo.getRowCount());
if(vo.getRowCount()>0)
createRow="Yes";
else
createRow="No";
return createRow;
Problem:
I remove the duplicate entries and click on save and get this error.
Unable to perform transaction on the record. \nCause: The record contains stale data. The record has been modified by another user.
\nAction: Cancel the transaction and re-query the record to get the new data.
Thanks,
SombitHi Anil,
I am trying out your code but stuck in inserting the rows
using your code in URL: http://oracleanil.blogspot.com/2010/09/oaf-passing-table-type-object-to-oracle.html
I am always getting the same exception i.e COde blast in when I run.
My modified code is:
String[] as = null;
Number[] vNumber = null;
Number[] vNumberrespid = null;
Number reqidnumber = null;
reqidnumber = new Number(Integer.parseInt(reqid));
Connection txn = getOADBTransaction().getJdbcConnection();
String mCreateSearchRequestStatement = null;
OAViewObject vo = (OAViewObject)findViewObject("RespLineVO1");
int j = vo.getFetchedRowCount();
try
System.out.println("abouce try");
vo.reset();
if (vo.getFetchedRowCount() > 0)
System.out.println(String.valueOf("Fetched row count ").concat(String.valueOf(vo.getFetchedRowCount())));
int i = 0;
as = new String[j];
vNumber = new Number[j];
vNumberrespid = new Number[j];
while (vo.hasNext())
vo.next();
System.out.println(String.valueOf("Inisde the do while loop").concat(String.valueOf(i)));
vNumber[i] = (reqidnumber);
vNumberrespid = ((Number)vo.getCurrentRow().getAttribute("ResponsibilityId"));
as[i] = String.valueOf(vo.getCurrentRow().getAttribute("ResponsibilityName")).concat(String.valueOf(""));
System.out.println("Request ID "+reqidnumber[i]);//getting null even there is some value selected
System.out.println("ResponsibilityId "+vNumberrespid[i]);//getting null even there is some value selected
System.out.println("Resp Name "+as[i] );//getting null even there is some value selected
i++;
CallableStatement cs = txn.prepareCall("{call XX_PassTableType.XX_PassTableType_prc(:1, :2,:3)}");
ARRAY array = new ARRAY(new ArrayDescriptor("APPS.JTF_NUMBER_TABLE", txn), txn, vNumber);
ARRAY arraynew = new ARRAY(new ArrayDescriptor("APPS.JTF_NUMBER_TABLE", txn), txn, vNumberrespid);
ARRAY array1 = new ARRAY(new ArrayDescriptor("APPS.JTF_VARCHAR2_TABLE_100", txn), txn, as);
cs.setArray(1, array);
cs.setArray(2, arraynew);
cs.setArray(3, array1);
cs.registerOutParameter(3, 2003, "JTF_VARCHAR2_TABLE_100");
cs.execute();
ARRAY error = null;
error = (ARRAY)cs.getArray(2);
if ((error != null) && (error.length() > 0))
System.out.println(String.valueOf("Error is ").concat(String.valueOf(error.getArray())));
String[] retError = new String[j];
retError = (String[])error.getArray();
System.out.println(String.valueOf("Error in saving data").concat(String.valueOf(retError[0])));
cs.close();
catch (Exception exception)
throw new OAException("code blast", OAException.ERROR);
Thanks,
Sombit -
Find duplication values from multiple columns in a big table
Hi All,
I am working on a 11gR2 database in linux. i want to display record that have duplicate values in 2 columns.
1. Table Structure :-
CREATE TABLE A
ID NUMBER(10),
F_NAME VARCHAR2(100 BYTE),
L_NAME VARCHAR2(100 BYTE)
2. Sample Data:-
Insert into A
(ID, F_NAME, L_NAME) Values (1,'TONY' ,'SUMIT');
Insert into A
(ID, F_NAME, L_NAME) Values (2,'SUMIT' ,'KEITH');
Insert into A
(ID, F_NAME, L_NAME) Values (3,'NORA','SMITH');
Insert into A
(ID, F_NAME, L_NAME) Values (4,'APRIL','TONY');
Insert into A
(ID, F_NAME, L_NAME) Values (5,'ROSS','TAM');
ID F_NAME L_NAME
1 TONY SUMIT
2 SUMIT KEITH
3 NORA SMITH
4 APRIL TONY
5 ROSS TAM
4. My requirement is i need display IDs that it's F_NAME or L_NAME has duplication in F_NAME or L_NAME columns.
The result should be
ID
1 reason: F_NAME (TONY) equals to L_NAME of record 4, L_NAME (SUMIT) equals to F_NAME of record 2
2 reason: F_NAME (SUMIT) equals to L_NAME of record 1
4 reason: L_NAME (TONY) equals to F_NAME of record 1
record 3, 5 aren't in the result because there is no duplication in F_NAME or L_NAME columns for NORA,SMITH, ROSS, TAM
The table contains 10 million records, i really need to consider the performance.
kindly suggest me the solutionNote: Forum members please suggest better approach to this -- below.. convert into SQL :)
I know I will be opposed by many people in this forum for posting such in-efficient solution.
But trying to learn along with you.. its an interesting problem which must deal with all rows vs all rows to get all combinations.
But I am still thinking how to write it in SQL, probably will learn from this post after we receive some good SQL solution for the code what I am currently doing now.
step 1: created a table B similar to table A and added a column reason
CREATE TABLE B
ID NUMBER(10),
F_NAME VARCHAR2(100 BYTE),
L_NAME VARCHAR2(100 BYTE),
REASON VARCHAR2(1000 BYTE) --- ADDED THIS
)Definetely inefficient :(
BEGIN
FOR rec_outer IN (SELECT * FROM A) LOOP
FOR rec_inner IN (SELECT * FROM A) LOOP
IF (rec_outer.f_name = rec_inner.l_name) THEN
UPDATE B
SET reason =
rec_outer.id
|| ' reason: F_NAME ('
|| rec_outer.f_name
|| ') equals to L_NAME of record '
|| rec_inner.id
WHERE b.id = rec_outer.id;
END IF;
END LOOP;
FOR rec_inner IN (SELECT * FROM A) LOOP
IF (rec_outer.l_name = rec_inner.f_name) THEN
UPDATE B
SET reason =
reason
|| CASE
WHEN reason IS NULL THEN
rec_outer.id || ' reason: '
ELSE
END
|| 'L_NAME ('
|| rec_inner.f_name
|| ') equals to F_NAME of record '
|| rec_inner.id
WHERE b.id = rec_outer.id;
END IF;
END LOOP;
END LOOP;
COMMIT;
EXCEPTION
WHEN OTHERS THEN
rollback;
RAISE;
END;OUTPUT:
ID F_NAME L_NAME REASON
1 TONY SUMIT 1 reason: F_NAME (TONY) equals to L_NAME of record 4,L_NAME (SUMIT) equals to F_NAME of record 2
2 SUMIT KEITH 2 reason: F_NAME (SUMIT) equals to L_NAME of record 1
3 NORA SMITH
4 APRIL TONY 4 reason: L_NAME (TONY) equals to F_NAME of record 1
5 ROSS TAM Cheers,
Manik.
Edited : Added rollback -
Duplicate value in export file
Hi,
I have a sql report where I have implemented download to excel using the print attribute. When I export the report into Excel, there are few columns whose values getting duplicated in the spreadsheet where as those column values are blank in the report.
for example.
Query:
select col1 col2 col3 col4 from table1;
The report displays the correct value for col1 col2 col3 col4 but in the export file value for col1, col2, col3 are correct but col4 is picking up the value of col3.
Any help? Thanks.
--ManishHi Scott,
Could you please have a look at it.
http://apex.oracle.com/pls/otn/f?p=47427:12
When you will click download_excel at the bottom of the page, the export file will show you the duplicate values for the column [G-L].
Thanks again for your help.
--Manish
Message was edited by:
Manish Jha -
3.1 EA3 - Column value filter dropdown returns duplicate values
Hello,
SQL Developer 3.1 EA3 introduces a regression: the column value filter in the table data editor dropdown (filter column) now shows duplicate values. Previous versions (at least 3.0) returned unique values to select from.
Since this is EA3 and not yet production, should I file a bug for this?
Best Regards and many thanks for this tool,
Olivier.
Edited by: user9378013 on Jan 9, 2012 1:08 PMYes it's a regression. Fixed it recently. In the next released build it should work properly.
-Raghu -
Hi SanjayPradhan,
Based on your formula, I could reproduce this issue in my SharePoint 2013 without any CUs.
Then I created a new column using other types not Date&Time, add the formula =IF(ISBLANK([New Column]),"Employee","ExEmployee"), there is no duplicate values when filtering the calculated column. It seems that this issue only
happens when judging Date&Time column in a calculated column.
I tested in my SharePoint Online, and found I could not reproduce this issue on SharePoint Online.
So, for your issue, please check whether you install any CUs
for your SharePoint 2013. And please install the latest CU for SharePoint 2013.
You can find the latest CU for SharePoint as the link:
http://www.toddklindt.com/blog/Lists/Posts/Post.aspx?ID=346
Best Regards,
Wendy
Wendy Li
TechNet Community Support -
Prevent duplicate value being entered into a column
How do we prevent user to enter duplicate value into one of the column of a multiple record block before we commit the form ?
Can anybody help ?
Thanks,
Shu WenDo you want the duplicate to be detected as soon as the item is validated ?
If so, the only way I have found to do so is to maintain a copy of the contents of the block in a record group. Rather cumbersome and a few triggers needed, but I have one application where I had to do it. I have always found it restrictive that you cannot read values from other records without navigating to them. If anyone has found a better method I would be interested to hear. -
Hi all,
I have created a form with one data block MATURED_FD_DTL which looks like below:
ACCT_FD_NO
CUST_CODE
FD_AMT
FD_INT_BAL
TDS
CHQ_NO
ADD_FD_AMT
P_SAP_CODE
P_TYPE
CREATE TABLE MATURED_FD_DTL
ACCT_FD_NO VARCHAR2(17 BYTE) NOT NULL,
CUST_CODE NUMBER(9),
FD_AMT NUMBER(15),
FD_INT_BAL NUMBER(15),
TDS NUMBER(15),
CHQ_NO NUMBER(10),
ADD_FD_AMT NUMBER(15),
P_SAP_CODE NUMBER(10),
P_TYPE VARCHAR2(1 BYTE)
For MATURED_FD_DT.ACCT_FD_NO, Trigger: KEY_NEXT_ITEM, I have written the following code:
DECLARE
V1 NUMBER;
V2 NUMBER;
BEGIN
V1:=:MATURED_FD_DTL.ACCT_FD_NO;
MESSAGE('V1:'||V1);
MESSAGE(' ');
END;
GO_ITEM('MATURED_FD_DTL.CUST_CODE');
This is just a dummy code.
When ever i enter the value in the field of ACCT_FD_NO, it pops up a message saying "V1:Value of ACCT_FD_NO",
So i want to store that value .
Compare them & if it is egual, it should pop up a message saying duplicate value is entered and must not allow to enter, at form_level.
So how can I compare the ACCT_FD_NO value between FIRST_RECORD and NEXT_RECORD ??
Help Me .
Thank You.
Oracle Forms 6i.
Oracle 9i.Thank You HamidHelal.
Actually before posting the code, I went through the first link you have mentioned. I tried also, it is quite tedious procedure, however i dint get the proper result, may be i have done some mistake. Anyways , can you tell me how do i check in database table, if a value exists OR IF VALUE FOUND & then message and raise form trigger failure; something like below.
IF :MATURED_FD_DTL.ACCT_FD_NO EXISTS
THEN MESSAGE('YOU HAVE ENTERED AN EXISTING OR DUPLICATE VALUE');
MESSAGE(' ');
RAISE FORM_TRIGGER_FAILURE;
END;
OR
IF :MATURED_FD_DTL.ACCT_FD_NO FOUND
THEN MESSAGE('YOU HAVE ENTERED AN EXISTING OR DUPLICATE VALUE');
MESSAGE(' ');
RAISE FORM_TRIGGER_FAILURE;
END;
Is there any equivalent in the form in oracle forms 6i?? Please let me know how do i do this?? -
How to eliminate duplicates from multiple subscriptions in iCal?
Is there a way to eliminate duplicate entries created when subscribing to multiple calendars? As an example - I have a subscription with each of my kids school calendars (one is in middle school the other elementary). I end up with several duplicates such as the following:
February 14, 2014
* Valentines Day (calendar)
* Valentines Day (elementary)
* Valentines Day (middle school)
Thanks for your help!
-CurtYour specification can be interpreted more than one way.
In the examples you give, "duplicate records" not only have the same EMPNO, but all the data is the same. If this is what you are trying to avoid, use DISTINCT. Instead ofFROM EMP_TEST Ewrite FROM (select distinct * from EMP_TEST) EThis will eliminate duplicates if and only if every column has the same value.
Again, not sure if this is what you want but it would work for your sample data.
P.S. I agree with sb92075, you should make EMPNO a primary key and avoid the problem altogether. -
Eliminate duplicates in subseries
Hi,
I am looking for a better solution for my problem. I've already solved it by pipeline function and just wonder if there is another (faster or more sophisticated) way.
Source (subquery) provides record by record in certain order. I want to eliminate record if some fields are equal to relevant fields in previous record(s).
Example data:
with
source as (select 1 rn , 'a' a, 'a' b, 10 c from dual union all
select 2, 'a', 'a', 10 from dual union all
select 3, 'a', 'b', 10 from dual union all
select 4, 'a', 'b', 10 from dual union all
select 5, 'a', 'b', 10 from dual union all
select 6, 'c', 'd', 10 from dual union all
select 7, 'c', 'd', 10 from dual union all
select 8, 'a', 'a', 10 from dual union all
select 9, 'a', 'a', 10 from dual)
select * from source;
RN A B C
1 a a 10
2 a a 10
3 a b 10
4 a b 10
5 a b 10
6 c d 10
7 c d 10
8 a a 10
9 a a 10Query should eliminate
- record rn=2 because columns A and B are the same in rn=1 (previous record)
- record rn=4 and rn=5 because columns A and B are the same in record rn=3 (previous and previous' previous)
- record rn=7 because columns A and B are the same in rn=6 (previous record)
- record rn=9 because columns A and B are the same in rn=8 (previous record)
Record rn=8 shouldn't be eliminated because previous record is different in A and B.
Another words I want to achieve first occurence in subseries of same records.
Additional info: Column C is constant for all records. Real source produces a few thousand records with many 'duplicates' (~99%)
Desired output should be like that:
' RN A B C
1 a a 10
3 a b 10
6 c d 10
8 a a 10Thanks in advance,
BartekHi, Bartek,
Yiou can do that with the analytic LAG function:
with
source as (select 1 rn , 'a' a, 'a' b, 10 c from dual union all
select 2, 'a', 'a', 10 from dual union all
select 3, 'a', 'b', 10 from dual union all
select 4, 'a', 'b', 10 from dual union all
select 5, 'a', 'b', 10 from dual union all
select 6, 'c', 'd', 10 from dual union all
select 7, 'c', 'd', 10 from dual union all
select 8, 'a', 'a', 10 from dual union all
select 9, 'a', 'a', 10 from dual)
, got_dif AS
SELECT rn, a, b c
, CASE
WHEN a = LAG (a) OVER ( PARTITION BY c
ORDER BY rn
AND b = LAG (b) OVER ( PARTITION BY c
ORDER BY rn
THEN 0
ELSE 1
END AS dif
FROM source
SELECT rn, a, b c
FROM got_dif
WHERE dif = 1;This assumes that each value of c is a world unto itself: only rows with the same value iof c will be compared to one another. If that's not what you want, just remove "PARTITION BY c" from both analytic clauses.
Thanks for posting the sample data in such a convenient way! That's very helpful.
Edited by: Frank Kulash on Jul 14, 2009 3:35 PM
This solution is pretty close to Sanjay's solution.
Sanjay used only one test in the CASE expression:
case when lag(a||b) over ( order by rn) = a||b then 1 else 0 end grp but that assumes that you never have, for example
a='X' and b='YZ" on one row, and
a='XY' and b='Z' on the next.
Even though these two rows are different in both a and b, the concatenation of a||b ('XYZ') is the same. Sanjay's solution will only display the first row; the solution above will display both rows.
Maybe you are looking for
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