"embed" image data into java code

I have a mind that is it possible embed image file into java code?
That mean an image file information already store in java code, thus no need using the image file in run-time. Then can prevent user change other image file instead.
Do anyone try before, are there technologies required?
I just want to know is it possible or not....thanks.

technologies? The solution you are asking for is all about storing your data in static variables such as byte[][] used to build your image instance. I guess you should have a look at the different constructors of BufferedImage.

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Hello
You may try the following AppleScript script. It will ask you to choose a root folder where to start searching for *.map files and then create a CSV file named "out.csv" on desktop which you may import to Excel.
set f to (choose folder with prompt "Choose the root folder to start searching")'s POSIX path
if f ends with "/" then set f to f's text 1 thru -2
do shell script "/usr/bin/perl -CSDA -w <<'EOF' - " & f's quoted form & " > ~/Desktop/out.csv
use strict;
use open IN => ':crlf';
chdir $ARGV[0] or die qq($!);
local $/ = qq(\\0);
my @ff = map {chomp; $_} qx(find . -type f -iname '*.map' -print0);
local $/ = qq(\\n);
#     CSV spec
#     - record separator is CRLF
#     - field separator is comma
#     - every field is quoted
#     - text encoding is UTF-8
local $\\ = qq(\\015\\012);    # CRLF
local $, = qq(,);            # COMMA
# print column header row
my @dd = ('column 1', 'column 2', 'column 3', 'column 4', 'column 5', 'column 6');
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# print data row per each file
while (@ff) {
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EOF
Hope this may help,
H

How to transform this pascal code into java code!

I want to transform this pascal code into java code . Please tel me how to do it because I really don't know how to do it!
Thanks!
{CALCULATE HOHN-LONDON FACTORS}
var kk:tab4;
PROCEDURE INTENS(var kk:tab4);
begin
for n:=0 to nr+2 do
begin
kk^[1,n]:=sqrt(lup*lup*yg*(yg-4)+4*sqr(n+1)) +lup*(yg-2);
kk^[2,n]:= sqrt(lup*lup*yg*(yg-4)+4*sqr(n+1))-lup*(yg-2);
kk^[3,n]:=0.5*(kk^[1,n]*kk^[1,n]+4*(sqr(n+1)-lup*lup));
kk^[4,n]:= 0.5*(kk^[2,n]*kk^[2,n]+4*(sqr(n+1)-lup*lup));
kk^[5,n]:= sqrt(ldown*ldown*yd*(yd-4)+4*sqr(n+1)) +ldown*(yd-2);
end;
end;
BEGIN
new (kk);
intens(kk);
writeln(f2,' ','N ','V','branch ','H-L');
for n:=1 to np do
begin
fp1[n,v]:=(n-ldown)*(n+ldown+1)*sqr(kk^[2,n-1]*kk^[6,n]+4*(n+ldown)*(n-ldown+1));
fp1[n,v]:=fp1[n,v]/(4*(n+0.5)*kk^[4,n-1]*kk^[8,n]) ;
writeln(f2,' ',n,' ',v,' fp1 ',fp1[n,v]:10:2);
end;
for n:=1 to nq do
begin
fq1[n,v]:=sqr(kk^[2,n]*kk^[6,n]*(ldown+0.5)+4*(n-ldown+1)*(n+ldown+1)*(ldown-0.5)) ;
fq1[n,v]:=fq1[n,v]/(2*(n+0.5)*kk^[4,n]*kk^[8,n]*(n+1.5));
fq1[n,v]:=fq1[n,v]*(n+1);
writeln(f2,' ',n,' ',v,' fq1 ',fq1[n,v]:10:2);
end;
for n:=1 to nr do
begin
fr1[n,v]:=sqr(kk^[2,n+1]*kk^[6,n]+4*(n-ldown+2)*(n+ldown+1));
fr1[n,v]:=fr1[n,v]/(4*kk^[4,n+1]*kk^[8,n]*(n+1.5));
fr1[n,v]:=fr1[n,v]*(n-ldown+1)*(n+ldown+2) ;
writeln(f2,' ',n,' ',v,' fr1 ',fr1[n,v]:10:2);
end;

Basically it looks like this:
public class KK{
     private your_type[][] kk = new your_type[length][length];
     private void intens(your_type[] kk){
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               kk[3][n] = 0.5*(kk[1][n]*kk[1][n]+4*(Math.pow((n+1), 2)-lup*lup));
               kk[4][n] = 0.5*(kk[2][n]*kk[2][n]+4*(Math.pow((n+1), 2)-lup*lup));
               kk[5][n] = Math.sqrt(ldown*ldown*yd*(yd-4)+4*Math.pow((n+1), 2)) +ldown*(yd-2);
     public static void main(String args[]){
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          k.intens(kk);
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          for(int n=1; n< nq;n++){
               fq1[n][v] = Math.pow((kk[2][n]*kk[6][n]*(ldown+0.5)+4*(n-ldown+1)*(n+ldown+1)*(ldown-0.5)), 2);
               fq1[n][v] = fq1[n][v]/(2*(n+0.5)*kk[4][n]*kk[8][n]*(n+1.5));
               fq1[n][v] = fq1[n][v]*(n+1);
               System.out.println(f2 + ' ' + n + ' ' + v + ' fq1 ' + fq1[n][v]:10:2);
          for(int n=1; n < nr; n++){
               fr1[n][v] = Math.pow((kk[2][n+1]*kk[6][n]+4*(n-ldown+2)*(n+ldown+1)), 2);
               fr1[n][v] = fr1[n][v]/(4*kk[4][n+1]*kk[8][n]*(n+1.5));
               fr1[n][v] = fr1[n][v]*(n-ldown+1)*(n+ldown+2) ;
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What about the converter I told you about?

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Goodday all :),
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To clear it up a little more;
1. Define unknown variable
2. Define values of other two variables
3. Program calculates
x1. unkown variable is 'a'
x2. b = 20 , c = 40
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What i was thinking as a concept;
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                         running = true;
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If a, b or c is pressed it will ask for the values of the other two
and it will be such a code as above, repeating itself;
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Now my question is;
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Aargh! No. This code snippet might be of help.
try {
   int x = Integer.parseInt("42");
   System.out.println("X = " + x);
} catch( NumberFormatException e ) {
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   e.printStackTrace();
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Any sugession??

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Document will be of ASCII characters right?? but image data will be in binary format. as per database concept it is stored as binary large object. But in datawarehousing the back end is also going to be some database such as Oracle or other DBs.
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i visited that url, i was able to know much about xml.
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http://help.sap.com/saphelp_erp2004/helpdata/en/12/904f42d5f811d2b469006094192fe3/content.htm
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*Please mark all the helpful answers

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