Equal Number Of Entries For Each Group

Hi,
I have been working on the problem off and on for a couple of weeks. I posted a simplified version of the question earlier and got good answers but the problem was not in the answers but how I asked the question.
My issue is this: I have a large data set with many dimensions. One of those dimensions is line number. The way the data is enter if the value for line number is zero there is no entry for that line number. So say California has 40 line numbers and Alaska has 3. This layout will not work for a project we are doing. What we need it to have the same number of line entries for each dimensions. So California would have 140 line entries with zeros for the blank entries and Alaskia would also have 140 line entries with zeros for the blank entries.
I'm using Toad and Oracle 10

Hi,
Sure, you can do that. Outer-join a table (or result set) that has 140 rows to your real table.
Here's an example of a sub-query that has 140 rows:
WITH cntr AS
 SELECT LEVEL AS n
 FROM dual
 CONNECT BY LEVEL <= 140
) ...Later in the query, you can reference cntr as if it were a table. cntr.n will have the values 1, 2, 3, ..., 140.
I hope this answers your question.
If not, post a little sample data (CREATE TABLE and INSERT statements, relevant columns only) for all tables, and also post the results you want from that data. Simplify the problem as much as possible. For example, instead of needing 140 rows (when the actual data has only 3 or 40), say you want 4 rows, and post data that has 1 or 3 rows. You can change the numbers easily after you understand the solution.
Explain, using specific examples, how you get those results from that data.
Always say which version of Oracle you're using.

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I have a table which contains bookings for an event I am running, with one row for each booking and a column for the date of the booking. I am trying to create a line chart which shows me the progress of the number of bookings over time. So the X axis would have one label for each day of the month - even if there was no booking on that day, and the Y axis would have the number of bookings, i.e. the number of rows, matching the date.
I have tried a few things without success, so I wonder if someone could help with this?
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The top table is titled "Bookings" and the bottom table summariese the bookings by counting how many bookings fall on each day:
The bottom table:
B2=COUNTIF(Bookings :: $B, "="&A2)
select B2 and fill down as needed

Reset Page Number for each Group

I am currently creating a RTF template using XMLP 5.0
My demanding boss gets back in town in five days, and he expects
this report to be ready for production. :)
But I haven't been able to figure out one last spec.
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In my RDF file (from Oracle Apps), I am grouping by a DEPT field.
In my RTF template, I am page breaking on each DEPT.
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This way, each DEPT in the plant can receive their own individual report.
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We would be willing to upgrade our XMLP,
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Hi Mark
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How To Restrict Number Of Rows For Multiple Group In Report Output

Hi ,
I have a requirement to restrict number of rows in report output.I have three different group , if i use same no of rows to restrict then output is as expected but if i want Deduction group should have 7 rows , earning should have 5 rows and Tax group have 3 rows in report output then XML tag is not working.
Below is the XML tag i am using -
First i have declare the variable to restrict the rows -
<xsl:variable name="lpp" select="number(7)"/>
<xsl:variable name="lpp1" select="number(5)"/>
<xsl:variable name="lpp2" select="number(3)"/>
For Each -
<?for-each:PAYSLIP?>
<xsl:variable xdofo:ctx="incontext" name="DedLines" select=".//AC_DEDUCTIONS"/>
<xsl:variable xdofo:ctx="incontext" name="EarLines" select=".//AC_EARNINGS[ELEMENT_CLASSIFICATION!='Taxable Benefits']"/>
<xsl:variable xdofo:ctx="incontext" name="EarTaxLines" select=".//AC_EARNINGS[ELEMENT_CLASSIFICATION='Taxable Benefits']>
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<?if:(position()-1) mod $lpp2=0?><xsl:variable name="start2" xdofo:ctx="incontext" select="position()"/>
Report output is tabular form (one page has two column - Earning and Deduction ) . Tax group comes below earning group.
Deduction Group -
<?for-each-group:$DedLines;./REPORTING_NAME?><?if:position()>=$start and position()<$start+$lpp?>
<?REPORTING_NAME?>
<?end if?><?end for-each-group?>
Earning Group -
<?for-each-group:$EarLines;./REPORTING_NAME?><?if:position()>=$start1 and position()<$start1+$lpp1?>
<?REPORTING_NAME?>
<?end if?><?end for-each-group?>
Tax Group -
<?for-each-group:$EarTaxLines;./REPORTING_NAME?><?if:position()>=$start2 and position()<$start2+$lpp2?>
<?REPORTING_NAME?>
<?end if?><?end for-each-group?>
Please let me know in case additional detail is require.
Thanks in Advance.
Thanks,
Harsh
Edited by: Harsh.rkg on Jan 14, 2013 9:43 PM

variable lpp2 is declare to restrict EarTaxLines -
<xsl:variable name="lpp2" select="number(2)"/>
This will help to restrict the no of rows on one page , if we have more then two tax benefits line then layout will roll over to continuation page.
As part of report output my expectation is if i restrict Earning , Deduction and Tax benefits to same no of line for example - variable lpp ,lpp1 and lpp2 have same value "number(2)" , we can see the layout is continue on next page (restrict every group can have max two lines) .This is the reason we have 4 header grid , deduction and Tax Benefit lines are rolled over to continuation page .But if we restrict different value for each variable then continuation page layout is missing .
When we tried for <xsl:variable name="lpp2" select="number(3)"/> value continuation page layout is not getting generate for both employee number .

SQL help: return number of records for each day of last month.

Hi: I have records in the database with a field in the table which contains the Unix epoch time for each record. Letz say the Table name is ED and the field utime contains the Unix epoch time.
Is there a way to get a count of number of records for each day of the last one month? Essentially I want a query which returns a list of count (number of records for each day) with the utime field containing the Unix epoch time. If a particular day does not have any records I want the query to return 0 for that day. I have no clue where to start. Would I need another table which has the list of days?
Thanks
Ray

Peter: thanks. That helps but not completely.
When I run the query to include only records for July using a statement such as following
============
SELECT /*+ FIRST_ROWS */ COUNT(ED.UTIMESTAMP), TO_CHAR((TO_DATE('01/01/1970','MM/DD/YYYY') + (ED.UTIMESTAMP/86400)), 'MM/DD') AS DATA
FROM EVENT_DATA ED
WHERE AGENT_ID = 160
AND (TO_CHAR((TO_DATE('01/01/1970','MM/DD/YYYY')+(ED.UTIMESTAMP/86400)), 'MM/YYYY') = TO_CHAR(SYSDATE-15, 'MM/YYYY'))
GROUP BY TO_CHAR((TO_DATE('01/01/1970','MM/DD/YYYY') + (ED.UTIMESTAMP/86400)), 'MM/DD')
ORDER BY TO_CHAR((TO_DATE('01/01/1970','MM/DD/YYYY') + (ED.UTIMESTAMP/86400)), 'MM/DD');
=============
I get the following
COUNT(ED.UTIMESTAMP) DATA
1 07/20
1 07/21
1 07/24
2 07/25
2 07/27
2 07/28
2 07/29
1 07/30
2 07/31
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Thanks
Ray

Getting the first row for each group

Hi Everyone,
I have a query which returns a number of rows, all of which are valid. What I need to do is to get the first row for each group and work with those records.
For example ...
client flight startairport destairport stops
A fl123 LGW BKK 2
A fl124 LHR BKK 5
B fl432 LGW XYZ 7
B fl432 MAN ABC 8
.... etc.
I would need to return one row for Client A and one row for Client B (etc.) but find that I can't use the MIN function because it would return the MIN value for each column (i.e. mix up the rows). I also can use the rownum=1 because this would only return one row rather than one row per group (i.e. per client).
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So what I really new is a "MIN by group" or a "TOP by group" or a "ROWNUM=1 by group" function.
Can anyone help me with this? I'm sure that there must be a command to handle this.
Regards and any thanks,
Alan Searle
Cologne, Germany

Something like this:
select *
from (
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   from table1
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In the "order by" clause you define which will have row_number = 1.
Edit:
PS. The [url http://download.oracle.com/docs/cd/E11882_01/server.112/e17118/functions004.htm#i81407]docs have more examples on using analytical functions ;-)
Edited by: Kim Berg Hansen on Sep 16, 2011 10:46 AM

Number of entries in each table

Hi,
I have a requirement to find the number of entries in each table in the system, how do I find this? If I have to goto each table & find out it is a tedious job. Do we have any standard report kind of thing to find out the number of entries in all the tables at a time....
Thanks,
Chandra

I do not think that there is a Std. SAP report for this. If you check there is a FM CATT_GET_TABLE_ENTRIES that actually gets the table entries. But this is called dynamically.
Hope this helps.
Regards,
Mani

Last() not returning correct value within for-each-group

I've found inconsistent results between JDeveloper and SOA Suite using the xslt 2.0 for-each-group construct.
<xsl:for-each-group select="Po/PoLine" group-by="itemId">
<xsl:if test="position()=1">
<GroupCount>
<xsl:value-of select="last()"/>
</GroupCount>
</xsl:if>
</xsl:for-each-group>
What I expect is the function last() to give me the number of groups which is the unique number of itemIds.
In JDeveloper 10.1.3.4, testing this construct gives me what I expect.
At run-time (deployed to 10.1.3.3 SOA Suite), the value returned is the total number of records, not the number of groups.
For example, given the following XML
<Po>
<PoLine>
<itemId>001</itemId>
<description>Hammer</description>
<quantity>10</quantity>
</PoLine>
<PoLine>
<itemId>001</itemId>
<description>Hammer</description>
<quantity>10</quantity>
</PoLine>
<PoLine>
<itemId>002</itemId>
<description>Nail</description>
<quantity>10</quantity>
</PoLine>
</Po>
Grouping by itemId, last() should return 2 as there are two groups (001 and 002). JDeveloper does this.
When deployed to SOA Suite, last() returns 3.
Any ideas?

Hi,
if JDeveloper is doing the right thing then this issue should be reported to the SOA Suite forum or BPEL BPEL , what do you think ?
Frank

Count() for each group, but only groups having 1+ element like... AND all elements like...

There are tables(and columns) like:
'Clients'(clientID)
'Houses' (houseID)
'Visits' (clientID, houseID, visit_date)
'Contracts'(contractID, houseID, clientID, rentDate_from, rentDate_end)
I have problem with writing MS SQL query of this kind:
how many visits to houses did each client, before renting one of them?
Its easy to count total number of Visits for each client, listing all visits + group by clientID and selecting count(*) for each group.
Lets say this is select_1, and select_2 is listing all Contracts for all clients.
Select_1 is not answer, because count must be performed only on groups, which:
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"where s1.clientID=s2.clientID and s1.houseID=s2.houseID"
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maybe: "datediff(day, s1.visit_date, s2.rentDate_from) >= 0"

In future, please provide proper DML, DDL and example data, like I have for you below.
DECLARE @clients TABLE (clientID INT, name VARCHAR(20))
INSERT INTO @clients (clientID, name)
VALUES (1, 'Jonathan'),(2, 'Christopher'),(3, 'James'),(4, 'Jean-Luc'),(5, 'William')
DECLARE @houses TABLE (houseID INT, address VARCHAR(20))
INSERT INTO @houses (houseID, address)
VALUES (1, 'NX01'),(2, 'NCC 1701'),(3, 'NCC 1071A'),(4, 'NCC 1701D'),(5, 'NCC 1701E')
DECLARE @visits TABLE (clientID INT, houseID INT, visitDateTime DATETIME)
INSERT INTO @visits (clientID, houseID, visitDateTime)
VALUES (1,1,'2001-01-01 12:13:14'),
(2,2,'2001-01-02 12:13:14'),
(3,2,'2001-01-01 12:13:14'),(3,3,'2001-01-01 12:13:14'),
(4,4,'2001-01-01 12:13:14'),(4,5,'2001-01-01 12:13:14'),
(5,4,'2001-01-01 12:13:14'),(5,5,'2001-01-01 12:13:14')
DECLARE @contracts TABLE (contractID INT IDENTITY, houseID INT, clientID INT, rentStartDate date, rentEndDate date)
INSERT INTO @contracts (houseID, clientID, rentStartDate, rentEndDate)
VALUES (1,1,'2001-01-02',NULL),(2,2,'2001-01-02',NULL),(3,3,'2001-01-02',NULL),(4,4,'2001-01-02',NULL),(5,5,'2001-01-02',NULL)
SELECT contractID, c.houseID, c.clientID, rentStartDate, rentEndDate, cl.clientID, name, h.houseID, address, COUNT(v.clientID) AS visits
FROM @contracts c
LEFT OUTER JOIN @clients cl
ON c.clientID = cl.clientID
LEFT OUTER JOIN @houses h
ON c.houseID = h.houseID
LEFT OUTER JOIN @visits v
ON c.clientID = v.clientID
AND c.rentStartDate >= v.visitDateTime
GROUP BY contractID, c.houseID, c.clientID, rentStartDate, rentEndDate, cl.clientID, name, h.houseID, address

Create standby maximum number of logfiles for each thread

The oracle doc states this equation for appropriate number of standby redo log file groups
(maximum number of logfiles for each thread +1) * maximum number of threads
How do you get the maximum number of logfiles for each thread and the max thread?
Thanks!

If you are running RAC you can, in theory, be running with a diferent count
of Online Redo Logs in each thread (instance).
However, normally, you would have the same number of Redo Logs in each
thread.
The theoretical max is prescribed at the CREATE DATABASE and can be
changed with a CREATE CONTROLFILE. If you do an
ALTER DATABASE BACKUP CONTROLFILE TO TRACE
the sql script in the tracefile shows the maximum number of logs and members.

Maximum number of logfiles for each thread

Hi all,
When I configure a Standby Redo Log, to determine the appropriate number of standby redo log file groups, I should use the following formula:
appropriate number of standby redo log file groups: (maximum number of logfiles for each thread + 1) * maximum number of threads
My question is: how can I determine the maximum number of logfiles for each thread ? Is it the online redo log file per group? or total of redo log files in all groups?
SQL> ed
Wrote file afiedt.buf
1* select group#, thread#, sequence#, members from v$log
SQL> /
    GROUP#    THREAD# SEQUENCE#    MEMBERS
         1          1         40          1
         2          1         38          1
         3          1         39          1

user8994263 wrote:
Hi,
If you have 5 redo log groups on primary, do you suggest to create 6 standby redo log groups on standby?
If yes, why ?
-KalidasYou did two mistakes
1) Responded to old question Posted: Jun 1, 2010 8:52 PM
2) Its not your question & asking into others threads.
-- Please lock this thread

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COLUMN 1:
<?for-each-group:row_table;./ YEAR?><?sort: YEAR;'ascending';data-type='text'?><?YEAR?>
COLUMN 2:
<?for-each-group:current-group();./DESCR?><?DESCR?>
NESTED TABLE (with 4 columns):
+<?for-each:current-group()?><?SUBJECT?><?CATALOG_NBR?><?DESCR250?><?GRADE?><?end for-each?>+
<?end for-each-group?> <?end for-each-group?>
I'm able to sort by YEAR in the "for-each-group" on the left column. But I also want to do a custom sort on DESCR in the right column.
I've seen this blog on custom sorting by Vetriselvan: http://winrichman.blogspot.com/2009/09/custom-dynamic-sort-in-bi-publisher.html and I tried inserting this sort below after <?for-each-group:current-group();./DESCR?> but I get an error message.
<?sort:(number(DESCR='Status')*1)+(number(DESCR='First Semester')*2)+(number(DESCR='Second Semester')*3);'ascending';data-type='number'?>
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<?for-each:DESCR?><?sort:(number(DESCR='Status')*1)+(number(DESCR='First Semester')*2)+(number(DESCR='Second Semester')*3);'ascending';data-type='number'?>
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Hi Vetsrini,
I tried adding <?sort: ./DESCR;'ascending';data-type='text'?> after <?for-each-group:current-group();./DESCR?> but I'm getting an error message.
The DESCR values are below and I'm trying to sort them in the following order.
STATUS
SUMMER SEMESTER
FIRST SEMESTER
AUTUMN SEMESTER
WINTER SEMESTER
SECOND SEMESTER
SPRING SEMESTER
Because I need them in the above order, I can't use ascending or descending, and instead need to use a custom sort order. Do you know how I can go about creating a custom sort order?
Thanks!

Using If condition in For EACH Group

Hi all,
I want to use if condition in for-each-group. Basically my requirement is that i want to use dynamic grouping. There will be two groups and the upper group and lower group will be selected on the basis of a report parameter.
I hope i made it clear enough. So please help me in this. Any ideas will be highly appreciable.
Thanks and regards
Naveed

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Thanks,

Top N for each grouping?

Is there a way to show in OBIEE the Top N results for each group?
I want to show the top 10 amounts for each region in my table. If using a Top N filter, it returns the Top N overall results. I tried creating a pivot table and using 'Region' as the section separator, but got the same results. It's only returning 10 amounts total, and I want to see 10 amounts for each region.
Kevin

Yep,
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regards
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http://obiee101.blogspot.com/

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Hello all,
When I give a page break inside the for-each-group the group doesn't iterate any code after the page break. I can't give <?split-by-pagebreak?> in this case because I want that loop to be iterated for every department, and should show the report in one column(ms word column), and the department description in two columns.....as this has to happen for every department I can't write separate code........everything should go into one file......
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DK

bipuser thanks for your response
i will have table data also so i cannot keep in the same line.
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Equal Number Of Entries For Each Group

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