Error during file open

Question

String file = "C:\\Documents and Settings\\mit2kor\\Desktop\\1         1             1             1.txt";
Runtime.getRuntime().exec("rundll32 url.dll,FileProtocolHandler " + file);
Output:
I get an 'Unable to open "C:\Documents and Settings\mit2kor\Desktop\1 1 1 1.txt"' error message, when the code snippet is run. Enclosing the variable 'file' within a double quote also does not work.
Can anybody help?
Thank you in advance....

Answer 1

Actually, my file name is "1 1 1 1.txt". But the error message says it cannot open "1 1 1 1.txt".
My sample program is:
public class test
  public static void main(String[] args)
      try
        String file = "C:\\Documents and Settings\\mit2kor\\Desktop\\1         1             1             1.txt";
        Runtime.getRuntime().exec("rundll32 url.dll,FileProtocolHandler " + file);
      catch(Exception e)
        e.printStackTrace();
}Can you please help me with the renaming idea? How can I do that?
Thank you.