#error in formula row of the form sum([1])/2

Question

Greetings!
I have a necessity to use formula row in some forms to get an aggregated value of rows above, sometimes i have to use sum([1])/2 and this results me into a problem: in cells where formula is not valid (all values in specific column are blanks) it shows #error instead of values.
Question is, how to avoid that? like in excel for example =IF(A1="";"";A1/2)
Thanks in advance.

Answer 1

Version is 11g
I've found 2 ways how to avoid #errors, not elegant, but working properly.
#error shows in formula cells if the LAST argument of function returns #error and others are #missing
1st way) You can use expression of the from 0 + sum([1])/2 and it would return "0" in formula cell
2nd way) You can use an expression of the from sum([1])/2 + sum([2]). NOTE that sum([2]) + sum([1])/2 would return an error if sum([2]) returns a #missing value, if swap arguments formula would return #missing value and it would give us an empty cell
IF you do not have any other rows, which summary would give you #missing, here is a trick sum([1])/2 + sum([1]) - sum([1]), first sum returns an #error (#missing/2), second returns #missing, third returns #missing and you will have #missing in formula cell as result
Question about formula, i need to sum row[1] values of [C:E] columns, is there any way to indiate a range like that in sum() function?