Error in query(on 2nd April)

Question

Hi all,i am getting the error in following query.
Error is:Not a sigle group-group function.
SELECT S.SCHOOLNAME,COUNT(DISTINCT LR.RESPONSER_ID) AS LCOUNT,
SUM(DISTINCT DECODE(LR.QUESTIONNAIRE_ID,62, L.WORK_SPACE))/5 As LITSUM,
MIN(DECODE(LR.QUESTIONNAIRE_ID,62, L.WORK_SPACE)) As LITMIN,
MAX(DECODE(LR.QUESTIONNAIRE_ID,62, L.WORK_SPACE)) As LITMAX,
SUM(DISTINCT DECODE(LR.QUESTIONNAIRE_ID,61, L.WORK_SPACE))/5 As NUMSUM,
MIN(DECODE(LR.QUESTIONNAIRE_ID,61, L.WORK_SPACE)) As NUMMIN,
MAX(DECODE(LR.QUESTIONNAIRE_ID,61, L.WORK_SPACE)) As NUMMAX,
MIN((NVL(SUM(DISTINCT DECODE(LR.QUESTIONNAIRE_ID,62, L.WORK_SPACE)),0)/5 + NVL(SUM(DISTINCT DECODE(LR.QUESTIONNAIRE_ID,61, L.WORK_SPACE)),0)/5)) AS OMIN
FROM TQDB_LEARNER_RESPONSE L LEFT JOIN TQDB_LEARNER_RESPONSERS LR ON LR.RESPONSER_ID=L.RESPONSER_ID LEFT JOIN
SCHOOLS S ON S.SCHOOLID=LR.SCHOOL_ID
GROUP BY S.SCHOOLNAME,LR.QUESTIONNAIRE_ID
Getting error at,MIN(NVL(
When i add Min Function here.
Pls help me

Answer 1

And for the love of all that's holy:
1. use a meaningful subject line. Here the error message would have been good. And why are you putting the date in the subject line?
2. Format your code (and your data, but you didn't provide any). This can be done with [code] and [/code] tags, then any whitespace will be preserved. It will then look like this:
SELECT S.SCHOOLNAME,
       COUNT(DISTINCT LR.RESPONSER_ID) AS LCOUNT,
       SUM(DISTINCT DECODE(LR.QUESTIONNAIRE_ID,62, L.WORK_SPACE))/5 As LITSUM,
       MIN(DECODE(LR.QUESTIONNAIRE_ID,62, L.WORK_SPACE)) As LITMIN,
       MAX(DECODE(LR.QUESTIONNAIRE_ID,62, L.WORK_SPACE)) As LITMAX,
       SUM(DISTINCT DECODE(LR.QUESTIONNAIRE_ID,61, L.WORK_SPACE))/5 As NUMSUM,
       MIN(DECODE(LR.QUESTIONNAIRE_ID,61, L.WORK_SPACE)) As NUMMIN,
       MAX(DECODE(LR.QUESTIONNAIRE_ID,61, L.WORK_SPACE)) As NUMMAX,
       MIN((NVL(SUM(DISTINCT DECODE(LR.QUESTIONNAIRE_ID,62, L.WORK_SPACE)),0)/5 +
            NVL(SUM(DISTINCT DECODE(LR.QUESTIONNAIRE_ID,61, L.WORK_SPACE)),0)/5
           )) AS OMIN
FROM TQDB_LEARNER_RESPONSE L
     LEFT JOIN
     TQDB_LEARNER_RESPONSERS LR ON LR.RESPONSER_ID=L.RESPONSER_ID
     LEFT JOIN
     SCHOOLS S ON S.SCHOOLID=LR.SCHOOL_ID
GROUP BY S.SCHOOLNAME,LR.QUESTIONNAIRE_IDMuch more readable (although still not brilliant).