Errors not validated

Question

Hi,
The XML i'm validating is with error (minLength is violated). However, error msg is not shown.
I've already created a class that implements the defaultHandler, still it's to no avail. Can someone please advice?
Thanks!

Answer 1

By default only fatal errors are displayed (bad formed).
To manage validation errors, you have to implement an Error Handler, like this for example :
import java.io.PrintStream;
import org.xml.sax.ErrorHandler;
import org.xml.sax.SAXException;
import org.xml.sax.SAXParseException;
public class XmlError implements ErrorHandler {
private PrintStream out;
protected String message(SAXParseException e){
String message = "Message : "+e.getMessage()+"\n";
message += "Ligne "+e.getLineNumber()+", colonne "+e.getColumnNumber()+"\n";
message += "Public id : "+e.getPublicId()+"\n";
message += "System id : "+e.getSystemId();
return message;
public XmlError() {
public XmlError(PrintStream out) {
this.out = out;
public void error(SAXParseException e) throws SAXException {   
String systemId = e.getSystemId();
if (systemId == null) {
systemId = "null";
System.err.println("Erreur (URI="+ systemId +" ligne " +
e.getLineNumber() + ", col " +
e.getColumnNumber() + ") : " + e.getMessage());
String message = "*** Erreur lors de la validation ***\n";
message += message(e);
SAXException se = new SAXException(message, e);
throw se;
public void fatalError(SAXParseException e) throws SAXException{
System.err.println("Erreur fatale : " + e.getMessage());
String message = "*** Erreur fatale ***\n";
message += message(e);
SAXException se = new SAXException(message, e);
throw se;
public void warning(SAXParseException e) throws SAXException{
System.err.println("warning : " + e.getMessage());
}