Expressions in XML

Hello,
Is it possible to put expressions in XML file between tags. For example,
<name>
Debilius + "878"
<name/>
or
<name>
Debilius + getting number from DB
<name/>
Thank you,
Aleksej

ok, maybe i misundertood your question.
do you expect a parser to process some kind of expressions in XML and get the values for you? if yes, well... doesn't look very possible.
what you can do is use Java extension functions in XSL to process expressions, but it is some kind of lousy.
why do you intend to achieve?
why don't you read the resource bundle values in Java and put them in your XML doc?

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Belongs to the nuclear hormone receptor family. NR3 subfamily. SIMILARITY: Contains 1 nuclear receptor DNA-binding domain. WEB RESOURCE: Name=NIEHS-SNPs; URL="http://egp.gs.washington.edu/data/pgr/"; WEB RESOURCE: Name=Wikipedia; Note=Progesterone receptor entry; URL="http://en.wikipedia.org/wiki/Progesterone_receptor"; GENE SYNONYMS: NR3C3. COPYRIGHT: Protein annotation is derived from the UniProt Consortium (http://www.uniprot.org/). Distributed under the Creative Commons Attribution-NoDerivs License.
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</bp:XREF>
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−<bp:unificationXref rdf:ID="CPATH-LOCAL-112388">
<bp:DB rdf:datatype="xsd:string">UNIPROT</bp:DB>
<bp:ID rdf:datatype="xsd:string">A7X8B0</bp:ID>
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</bp:XREF>
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Dani3ll3 wrote:
Thanks a lot after I did that the regular expression worked. :)Good. But remember that in real life, you would then have to apply the XML rules to get the actual contents of the text node. For example it might be a CDATA section or it might include characters like ampersands which have been escaped and which you need to unescape. That's why it's better to use a proper parser, as already suggested.
It seems to me this forum is full of posts where people are doing homework questions which teach them to do things the wrong way. But of course there's nothing the student can do about that.

Regular expression and XML

Hello,
I have an XML file containing regular expressions and i parse the file, extract the pattern from it and search for it using java regex package. The problem is it works fine when patterns are words but when the pattern is something like
write \\d+ (write followed by a space followed by one or mre digits) it doesn't work.
I wrote the same code but with the pattern embedded in it,ie. without using XML and it worked. But when extracting with XML it fails.
Also if the pattern is write[0-9] it only extracts write[0-9 and gives an error of no closing bracket.
Could anyone please tell me what i am missing out
Thank you

thank you for your replies. Well i have still no got over the problem so i am posting my code here and hoping it can get solved
import org.xml.sax.*;
import org.xml.sax.helpers.*;
import java.io.*;
import java.util.regex.*;
class textextractor extends DefaultHandler{
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public void startElement(String namespaceURI,String localName,String qn,Attributes attr)
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public void characters(char [] text,int start,int length)throws SAXException {
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public class saxt2 {
     public static void main(String args[]) {
          try {
                XMLReader parser= XMLReaderFactory.createXMLReader();
                ContentHandler handler=new textextractor();
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}The xml file is
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Reprasenting regular expression in XML

hai,
i have the following regular expression to reprasent 13digit number enclosed in a pair of brakets
String r= "\$[0-9]{13,}+\$"
however when i reprasented in the XML tag as
<my>
<rs>\$[0-9]{13,}+\$</rs>
</my>
and read using DOM parser,.unable to match the seqence is not matching at all.
will anybody pls. tell me howto reprasent in String r in XML
Thx

If the content in the XML file is
\$[0-9]{13,}+\$
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Hi,
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WKID        >     THEADER.WKID
EXTID        >     THEADER.EXTID
ORDER     >     THEADER.ORDER
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It would help if you provide error message and its stack trace.
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Hi All,
I am working on a system that needs to convert some input from web browser into XML format and transform the data to some other format using XSLT. While doing this, I encounter some special characters that cannot be used in XML. To resolve this, I wrote a class using java.util.regex.Pattern to filter the input. Most of the special characters we successfully filtered except the following characters (as found so far):
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Xml regular expressions

Hi Friends,
I am very new to xml technologies.i want to generate regular expression in xml.
Like this
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Please help me to do this.Friends this is little bit urgent.pls help me friends.
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Awaiting for replay.
Regards,
Sai srinu.

You want to add these conditions in XMLP ?
or XML file ?

How to deserialize xml with structure of abitrary nested layers of base class?

let say i want to represent arithmetic expression using xml:
<?xml version="1.0" encoding="utf-8" ?>
<expr>
<add>
<num>10</num>
<num>20</num>
</add>
</expr>
and here is my classes to represent this:
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using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
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public abstract class Evaluable
public abstract int Eval();
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Xml.Serialization;
namespace Test
[Serializable]
[XmlRoot("expr")]
public class Expr
[XmlElement]
public Evaluable Evaluable { get; set; }
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Xml.Serialization;
namespace Test
[Serializable]
[XmlRoot("add")]
[XmlType("add")]
public class Add : Evaluable
[XmlElement]
public List<Evaluable> Elems { get; set; }
public override int Eval()
return Elems.Select(e => e.Eval()).Sum();
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Xml.Serialization;
namespace Test
[Serializable]
[XmlRoot("num")]
[XmlType("num")]
public class Num : Evaluable
[XmlText]
public int Val { get; set; }
public override int Eval()
return Val;
but it doesn't work, and it's reasonable, since Serializer doesn't know any thing about the subclass. but how to make it work?
here is my deserialization code:
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Expr expr = null;
using (var file = new StreamReader("expr.xml"))
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I think what you want is to set the XmlElement attribute on the container (Elems).
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is to create a class that contains all the potential children including the class itself and serialize that. Seems a little like cheating.]
Here is a complete example:
[Serializable]
public class Foo
[XmlAttribute( "name" )]
public string name;
[XmlElement( "Foo", Type = typeof( Foo ) )]
[XmlElement( "Bar", Type = typeof( Bar ) )]
public List<Foo> children = new List<Foo>();
public void Dump( int level )
ShowProperties( level );
foreach( var f in children ) {
f.Dump( level + 1 );
protected virtual void ShowProperties( int level )
Console.WriteLine( "{0}{1}", new string(' ', level * 4 ), name );
[Serializable]
public class Bar : Foo
public string stuff;
protected override void ShowProperties( int level )
base.ShowProperties( level );
Console.WriteLine( "{0}{1}", new string(' ', level * 4 ), stuff );
class Program
static void Main( string[] args )
// <Foo name="A">
// <Bar name="B">
// <Foo name="D" />
// <stuff>B's Stuff</stuff>
// </Bar>
// <Bar name="C">
// <stuff>C's Stuff</stuff>
// </Bar>
// </Foo>
// A
// B
// B's Stuff
// D
// C
// C's Stuff
Foo a = new Foo() { name = "A" };
Bar b = new Bar() { name = "B", stuff="B's Stuff" };
Bar c = new Bar() { name = "C", stuff="C's Stuff" };
Foo d = new Foo() { name = "D" };
a.children.Add( b );
a.children.Add( c );
b.children.Add( d );
XmlSerializer xs = new XmlSerializer( typeof( Foo ) );
// There:
XmlSerializerNamespaces ns = new XmlSerializerNamespaces( new[] { XmlQualifiedName.Empty } );
StringBuilder sb = new StringBuilder();
using( XmlWriter xw = XmlWriter.Create( sb, new XmlWriterSettings() {
OmitXmlDeclaration = true,
Indent = true
xs.Serialize( xw, a, ns );
Console.WriteLine( sb.ToString() );
// And Back Again:
using( StringReader sr = new StringReader( sb.ToString() ) )
Foo root = (Foo)xs.Deserialize( sr );
root.Dump( 0 );

XPath Exception on Bursting Control File Template Filter Expression

I am getting the following exception for this bursting control file in EBS 11.5.10.2 on the template filter expression:
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<?xml version="1.0" encoding="UTF-8"?>
<xapi:requestset xmlns:xapi="http://xmlns.oracle.com/oxp/xapi">
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<![CDATA[
<html>
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Message
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</html>
]]>
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     <xapi:request select="/XXCUS_RAXINV/LIST_G_DIST/G_DIST">
          <xapi:delivery>
               <xapi:print id="print" printer="${XXCUS_PRINTER_NAME}" />
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          </xapi:document>
     </xapi:request>
</xapi:requestset>According to the docs, you can use any valid XPath expression. Any idea on what might be wrong here? I am trying to exclusively print or email based on the data. Currently, it prints AND emails all documents regardless of the value of XXCUS_DIST_CODE.
Thanks,
Kurz

Error lies on this line --- filter="./XXCUS_DIST_CODE='P'"
you need to use it like this --
Suppose you want condition on name in following XML Struction
<STUDENT>
<Name> Jatin </NAME>
</STUDENT>
the it should be ...
filter=".//<STUDENT>[NAME = 'Jatin']"
Not in your case ui suppose it should be filter=".//XXCUS_RAXINV/LIST_G_DIST/G_DIST[XXCUS_DIST_CODE='P']".
Hope it solves the problem.

Expressions in XML

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