Extract specific value of a Clob column with multiple nodes,similar name

Question

Hi,
There is a clob column in the table USER_DETAILS which hold the values similar to the one given below, i would like to form a query which should fetch the entire record where the age<30, as all the child nodes are with similar name i couldn't fetch it out using xmltype.extract. Also the order of the node values may change for eg. age may follow salary or age can be the first node in the list. Please help me to fetch the desired details.
<Details>
<parameter>
<enter>
<value>name</value>
<value>jacob</value>
</enter>
<enter>
<value>Age</value>
<value>30</value>
</enter>
<enter>
<value>Salary</value>
<value>20000</value>
</enter>
<enter>
<value>DOB</value>
<value>12091980</value>
</enter>
Thanks, gilbert

Answer 1

Let's start with the easy part.
Cells on a Numbers table can contain data entered directly, or can contain a formula. They can't contain both. That means you cannot 'type the conditions into a single cell' in column A ("the left header" cell) AND have a formula which sets that cell to TRUE if the typed in data contains an "A".
There's no problem doing this using column A as the key holder and columns B:Z to hold the TRUE/FALSE results, staring in both cases on row 2.
Here's an example
The column header cells (row 1) contain the letter corresponding to that column.
The row header cells (starting at row 2) contain the 'bunch of letters' you describe. Note (A4) that the letters do not have to be entered in any particular order, and that extraneous characters (eg. a space) are ignored.
The formula shown is entered B2, and filled down and right from there.
=IFERROR(FIND(B$1,$A2)>0,FALSE)
FIND returns the position of the first occurrence of the target string (in this case, the single letter at the top of the column) in the search string, then compares that with the value zero. For any letter that is included in the search string, the find value will be at least 1, so the comparison will return TRUE. If the target letter is not found, FIND returns an error. IFERROR traps this and returns FALSE.
Since the target depends on the letter at the top of the column, all that's needed to extend the range of possible letters to the full alphabet is to enter an A in cell B1, then run through the alphabet A to Z, with Z in cell AA1.
Depending what you want to do with the TRUE or FALSE values in these 26 columns, it may be possible to skip the auxiliary column step and use a formula similar to the one above as the condition argument of an IF(condition,do-if-true,do-if-false) statement.
Regards,
Barry