Extracting compressed files of 2byte filename?

Sometimes I get zip files containing files 2byte letter-name archived from windows systems.
Most of the time, Tiger's unzip feature cannot show the extracted file name correctly.
They are shown in numbers like this, "\270\360\300\307\260\355\273\347"
If the files are from Mac, but Tiger handles the files very well and shows the correct extracted file names.
I think it's because the charset of compressed file-names are not unicode...
is there any way to solve this problem?
Oh, I've also used Stuffit, but stuffit shows even more cracked letters.

Do you know what language is involved exactly? The numbers are octal representations of individual bytes and, as you surmise, are probably caused by the file names being in an encoding that OS X cannot read directly. It's a longshot for Windows files, but you might have a look at this utility:
http://docs.info.apple.com./article.html?artnum=86182
Just ignore any error messages when you try to install it. It will be found in Applications/Utilities and works by drag/drop.

Similar Messages

Extracting compressed file (zip) using PL/SQL

Hi!
Can anyone help me on how to extract data out of a compressed file(ZIP) using pl sql.
Regards,
dhekz

user8707902 wrote:
Can anyone help me on how to extract data out of a compressed file(ZIP) using pl sql.Bear in mind that the Lempel-Zif-Welch (LZW) compression used in zip files may still have patent issue relating to Unisys (not sure of the patent has expired now or what, it's always been somewhat confusing). So, if you already have software written to zip/unzip files you should use that as it should be licenced already. If you write your own LZW compression/decompression routine for use in any commercial software you may be required to register and submit royalties to Unisys for the privilege. As I say, I don't know the latest, so you may be ok, but it's something to be aware of and check out if you intend to write your own and it's for commercial reasons.

Batch file extracting all files from nested archives

I have managed to leverage a powerful
forfiles command line utility with the mighty
7z compression program.
Below is a simple batch file extracting all files from nested archives hidden at any depth inside other archives and/or folders. After the extraction each archive file turns into a folder having the archive file name. If, for example, there was an "outer.rar"
archive file containing nothing but an "inner.zip" archive with only "afile.txt" inside, "outer.rar" becomes "...\outer.rar\inner.zip\afile.txt" file system path.
@echo off
rem extract_nested_archives.bat
move %1 "%TMP%"\%2
md %2
7z x -o%1 -y %TMP%\%2
del "%TMP%"\%2
for %%a in (zip rar jar z bz2 gz gzip tgz tar lha iso wim cab rpm deb) do forfiles /P %1 /S /M *.%%a /C "cmd /c if @isdir==FALSE extract_nested_archives.bat @path @file"
ARCHIVES ARE DELETED DURING THE EXTRACTION! Make a copy before running the script!
"7z.exe" and "extract_nested_archives.bat" should be in folders available via the %PATH% environment variable.
The first parameter of extract_nested_archives.bat is the full path name of the archive or folder that should be fully expanded; the second parameter is just the archive or folder name without the path. So you should run "c:\temp\extract_nested_archives.bat
c:\temp\outer.rar outer.rar" from the command line to completely expand "outer.rar". "c:\temp" must be the current folder.
Best regards, 0x000000AF

Incredibly useful! Thank you so much. I did make a couple of small changes to make the script a little easier to use from the end-user perspective.
First - I don't like making the user input the redundant second parameter, so I added this snippet which extracts it from the first parameter. The first line of the snippet enables delayed expansion so that special characters in our file name don't
break anything. The second line pulls the parameter into a variable, and the 3rd line uses delayed expansion on that new variable. Before implementing delayed expansion I had problems with file paths which included parentheses.
SetLocal EnableDelayedExpansion
Set SOURCE=%1
For %%Z in (!source!) do (
set FILENAME=%%~nxZ
set FILENAME=%FILENAME:"=%
Anyway once that was done, I just used %FILENAME% everywhere in the script instead of
%2 (making sure to correct quotes as needed)
This way, to run my script all you need to run is:
C:\temp\extract_nested_archives.bat C:\temp\Archive.zip
Second - I didn't want to modify the Windows environment variable. So I replaced
7z with "%PROGRAMFILES%\7-zip\7z.exe"
I also replaced extract_nested_archives.bat with "%~f0" (which represents the full path+filename of the current script).
Here is my full script now. Tested on Windows 8 with the 64-bit version of 7-zip installed:
@echo off
Setlocal EnableDelayedExpansion
Set source=%1
For %%Z in (!source!) do (
set FILENAME=%%~nxZ
set FILENAME=%FILENAME:"=%
move /Y %1 "%TMP%\%FILENAME%"
md "%FILENAME%"
"%PROGRAMFILES%\7-zip\7z.exe" x -o%1 -y "%TMP%\%FILENAME%"
DEL "%TMP%\%FILENAME%"
for %%a in (zip rar jar z bz2 gz gzip tgz tar lha iso wim cab rpm deb) do (
forfiles /P %1 /S /M *.%%a /C "cmd /c if @isdir==FALSE "%~f0" @path @file"

Any way to extract *.sca files

hi there,
is there is any way to extract *.sca files, or you have to use JSPM or SDM tool to deploy these patches......Please let me know...thanks Kumar

HI,
If you want to compress or extract the files i.e., to create or extract SCA or SDA archives use the command jar -xvf filename (in HP-UX).If you are not able to do then try to run this command from the folder /usr/sbin.
Thanks,
Sagar Askani.

Create Zip File In Windows and Extract Zip File In Linux

I had created a zip file (together with directory) under Windows as follow (Code are picked from [http://www.exampledepot.com/egs/java.util.zip/CreateZip.html|http://www.exampledepot.com/egs/java.util.zip/CreateZip.html] ) :
package sandbox;
import java.io.File;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.io.IOException;
import java.util.zip.ZipEntry;
import java.util.zip.ZipOutputStream;
* @author yan-cheng.cheok
public class Main {
     * @param args the command line arguments
    public static void main(String[] args) {
        // These are the files to include in the ZIP file
        String[] filenames = new String[]{"MyDirectory" + File.separator + "MyFile.txt"};
        // Create a buffer for reading the files
        byte[] buf = new byte[1024];
        try {
            // Create the ZIP file
            String outFilename = "outfile.zip";
            ZipOutputStream out = new ZipOutputStream(new FileOutputStream(outFilename));
            // Compress the files
            for (int i=0; i<filenames.length; i++) {
                FileInputStream in = new FileInputStream(filenames);
// Add ZIP entry to output stream.
out.putNextEntry(new ZipEntry(filenames[i]));
// Transfer bytes from the file to the ZIP file
int len;
while ((len = in.read(buf)) > 0) {
out.write(buf, 0, len);
// Complete the entry
out.closeEntry();
in.close();
// Complete the ZIP file
out.close();
} catch (IOException e) {
e.printStackTrace();
The newly created zip file can be extracted without problem under Windows, by using [http://www.exampledepot.com/egs/java.util.zip/GetZip.html|http://www.exampledepot.com/egs/java.util.zip/GetZip.html]
However, I realize if I extract the newly created zip file under Linux, using modified version of [http://www.exampledepot.com/egs/java.util.zip/GetZip.html|http://www.exampledepot.com/egs/java.util.zip/GetZip.html] . The original version doesn't check for directory using zipEntry.isDirectory()).public static boolean extractZipFile(File zipFilePath, boolean overwrite) {
InputStream inputStream = null;
ZipInputStream zipInputStream = null;
boolean status = true;
try {
inputStream = new FileInputStream(zipFilePath);
zipInputStream = new ZipInputStream(inputStream);
final byte[] data = new byte[1024];
while (true) {
ZipEntry zipEntry = null;
FileOutputStream outputStream = null;
try {
zipEntry = zipInputStream.getNextEntry();
if (zipEntry == null) break;
final String destination = Utils.getUserDataDirectory() + zipEntry.getName();
if (overwrite == false) {
if (Utils.isFileOrDirectoryExist(destination)) continue;
if (zipEntry.isDirectory())
Utils.createCompleteDirectoryHierarchyIfDoesNotExist(destination);
else
final File file = new File(destination);
// Ensure directory is there before we write the file.
Utils.createCompleteDirectoryHierarchyIfDoesNotExist(file.getParentFile());
int size = zipInputStream.read(data);
if (size > 0) {
outputStream = new FileOutputStream(destination);
do {
outputStream.write(data, 0, size);
size = zipInputStream.read(data);
} while(size >= 0);
catch (IOException exp) {
log.error(null, exp);
status = false;
break;
finally {
if (outputStream != null) {
try {
outputStream.close();
catch (IOException exp) {
log.error(null, exp);
break;
if (zipInputStream != null) {
try {
zipInputStream.closeEntry();
catch (IOException exp) {
log.error(null, exp);
break;
} // while(true)
catch (IOException exp) {
log.error(null, exp);
status = false;
finally {
if (zipInputStream != null) {
try {
zipInputStream.close();
} catch (IOException ex) {
log.error(null, ex);
if (inputStream != null) {
try {
inputStream.close();
} catch (IOException ex) {
log.error(null, ex);
return status;
*"MyDirectory\MyFile.txt" instead of MyFile.txt being placed under folder MyDirectory.*
I try to solve the problem by changing the zip file creation code to
+String[] filenames = new String[]{"MyDirectory" + "/" + "MyFile.txt"};+
But, is this an eligible solution, by hard-coded the seperator? Will it work under Mac OS? (I do not have a Mac to try out)
p/s To be honest, I do a cross post at [http://stackoverflow.com/questions/2549766/create-zip-file-in-windows-and-extract-zip-file-in-linux|http://stackoverflow.com/questions/2549766/create-zip-file-in-windows-and-extract-zip-file-in-linux] Just want to get more opinion on this.
Edited by: yccheok on Apr 26, 2010 11:41 AM

Your solution lies in the File.separator constant; this constant will contain the path separator that is used by the operating system. No need to hardcode one, Java already has it.
edit: when it comes to paths by the way, I have the bad habit of always using the front slash ( / ). This will also work under Windows and has the added benefit of not needing to be escaped.

Reading a Compressed File from a ZIP File, which is an entry of ZIP File

Hello, Experts,
Would it be possible somebody to help me with code example for the following problem?
I want to read a compressed file from a ZIP file, which is an entry of ZIP File, without extacting/writing files on file system. Is this possible?
Lets say we have a ZipFile1. There is ZipFile2 inside ZipFile1. And inside ZipFile2 is FileA. The scenario is reading FileA without extracting on file system.
Thank you in advance for your help.
Cheers
RADY

The classes you want to be using are java.util.zip.ZipInputStream and and ZipEntry from the same package. Construct the ZipInputStream with the input you have for the outer zip. Loop with ZipInputStream.getNextEntry until you find the inner zip you're looking for - that method returns a ZipEntry, and you get the name of the zip entry with ZipEntry.getName. Read the ZipInputStream from that point into some buffer, and read that buffer into a new ZipInputStream - rinse and repeat until you have the contents of the file in the zip in the zip...

How to extract cpio file ?

Hi all,
We are trying to install application server and download file is .cpio file. How do we extract this file. I have tried the following command and its just hanging.
cpio -i (Filename)
cpio -idmv (file_name)
cpio -idcmv (filename)
cpio -Hhpodc -idmv (file_name)
none of above commands are working.
Please advise.
Thanks a bunch in advance.

Actually I tried the command cpio -idmv <file_name>I somehow doubt you tried that exact string. Perhaps you tried
cpio -idmv somefile.cpio
In which case it would appear to hang, but in reality it would be waiting for input from standard in. The other posters correctly stated you should use
cpio -idmv < somefile.cpio
which means "run the cpio command with options idmv and take input from the somefile.cpio in place of default standard input device."
Note that in Linux and Unix shells, the triangle brackets have meaning.

How to extract CPIO file to install Oracle in LINUX REDHAT9

I DOWNLOADED THE ORACLE 9I SOFTWARE FROM ORACLE SITE FOR
LINUX REDHAT9. NOW I DONT KNOW HOW TO EXTRACT THE FILE WITH CPIO.
CAN ANY BODY HELP ME.
THANKS.

extract the cpio file with the following command:
cpio -idmv < filename.cpio
hope this will help you
SUMIT

How to extract war file

how to extract war file? explain technoloby behind in war

hi
go to your dir :
jar xvf filename.warhelp, simply type jar, above baluc mention is right, jar/war/ear is like a zip file contains *.classes, images, xml , etc....
jar i hope it will help u

Extracting Embedded Files From a PDF with Adobe.APS

I'm not sure if this needs to be here in security or if it needs to be in another forum, so if an admin feels it needs to move to a different forum, feel free to.
The situation I am in is that I get about 100-150 pdf's a day that I need to extract an embeeded file from. Right now this is a completely manual process and is very time consuming. What I have been trying to do is automate the process of extraction.
The issue I am running into is that the files are encrypted with Adobe.APS, and so my java code won't handle the security, and I can't find any other software that handles Adobe.APS.
I was wondering if Adobe had a product that could do this, or if there was an API that could handle this. I can perform the extraction on a platform of any flavor (Windows, Mac, Linux, etc...).
Any help in this regard would be greatly appreciatted. Thanks.

In my case I have a drop-down list of files with preloaded filenames to attach. Here is the code that works for me on a click of button.
var selectFileName = form1.subform.DropDownList1.rawValue;
if (selectFileName != "Please Select") {
var doc = event.target;
doc.importDataObject(selectFileName);
var MyPar1 = doc.getDataObject(selectFileName);
var filename = MyPar1.path;
After you click the button it open a windows dialog box asking you to choose the file and adds the attachment to the attachment pane in runtime. To view the attachments simply view the attachment pane in runtime after you add the attachments.
Good luck,
SekharN

Passing a binary file to class outputing a compressed file

Hi,
Am i writing a program which gets passed a file to encode via "java compressor < <filename>".
Compressor is a class with main method.
what i have right now is simply:
public class Compressor {
     * @param args the command line arguments
    public static void main(String[] args) {
        InputStream in = new FileInputStream ("");
        File f = new File ("");
        ByteArrayOutputStream out = new ByteArrayOutputStream (f.length());
        int i;
        while ((i = in.read()) != -1) {
            out.write(i);
        in.close();
        byte[] result = out.toByteArray();
        for (int j = 0 ; i < result.length ; j++) {
            byte a = result[j];
} The program is suppose to read the input one byte at a time and treats each one as an instruction which encodes byte compressoring the file and finally outputing this newly compressed file. I'm not sure how the main method will take the filename i.e "java compressor examplefile", any guidance would help greatly.
Thanks

in the case above, the command line arguments are passed in the aaaaaaaaaaaaaaaaaaaaaaarggggggggggs array
you probably want aaaaaaaaaaaaaaaaaaaaaaarggggggggggs[0] for the filenameAm not sure i understand, do you mean i must change the param of the main method to String[] args[0] as this resulted in error when i did so. Or do you mean at command line instead file simply being passed to the Compressor program as
"java Compressor < examplefilename"
It has to be "java Compressor < examplefilename[0]" ?
If you could expand on this, would be grateful,
Thanks.

Editing a compressed file

So say I have a project in 1080i60 and i compress it down to an MP4 or just a smaller .mov at H.264. Then I delete the original 1080i60 but I need to change the volume level or cut out a small part of the movie. If I put the compressed file in FCP and export it...will it have the same compressed quality? I know obviously it wont be better quality....what is the best way to export it to maintain the quality...knowing that since it is already compressed?
Or the basic question...should you even edit a compressed file or just take your loss and re-edit the original 1080i60?

If all you are doing is cutting, then you probably will not be recompressing. An easy way to tell is how long it takes to export. It it looks like it will take a long time, then it is probably conforming and recompressing the video. That is bad. But it might be possible to cut out a portion, and save as a self-contained movie rather quickly.
You could try doing that with QT Pro, as it is sometimes clearer than FCP about saving video versus compressing video. Some codecs require conforming in FCP if you look at them funny.
As far as audio, I'm guessing you would be able to extract the audio and video tracks, modify the audio, and add the tracks back together. Again, I personally would feel better about this kind of track manipulation in QT Pro.

I compressed Activity Monitor and deleted the compressed file in error. How do I get it back?

In trying to reduce my CPU load, I compressed the Activity Monitor. Before I can use the compressed file, I mistakenly deleted it and now when I try to open it, I get the dreaded spinning wheel. After a long wait, I forced quit.
What happened and how do I get Activity Monitor back?

Never tamper with programs which come with the system. You could try downloading and applying the 'combo updater':
http://support.apple.com/kb/DL1399
However this won't help if Activity Monitor hasn't been updated since the initial release, which may well be the case. In that event you will need to reinstall Snow Leopard from your original install disks and then apply the combo updater again.
Alternatively it may be possible to extract Activity Monitor from the installed disk by using Pacifist - no promises about that.

Append to a compressed file

I have some test results that I want to save into a test result file. Since I will be accumulating many test results, I want to keep overhead down, so I would like to simply append the result to the end of the file. Here is what I have done...
1) Create an empty array, flatten to XML and write to a file.
2) When I want to add a record, I take the record control, flatten to XML, and then overwrite the </Array> at the end of the file with the XML record. I then append another </Array> onto the end of that to properly close it out.
3) I can then read this XML file back into an array of test record structures at a later time.
I chose to do it this way, because when I am generating the test records, I do not want the overhead of "file read->XML Parse entire file->append code->XML export appended structure->File write". I figured that by simply appending the XML record to the end of the file, I could cut down on a lot of this IO overhead.
The problem is that XML is a bit "chatty". I'd like to be able to read, write and append to compressed files (since XML compresses very well). The lvzlib routines only have a read and a write, but no append. My understanding of the compression schemes is that it makes a table of the common byte patterns and replaces them with shorter tokens. If I compress each record, I will have a table of tokens for each record that will basically be the same as all the other records. I can get better compression if I use one table for all records.
Has anybody implemented this, or do I need to dig into the guts of zlib?
Alternatively, can the normal File I/O routines be configured to work on a file in a compressed archive (like a zip file) and let the OS handle all the compression?
Thanks,
Brian Rose

Mister Rose wrote:
I have some test results that I want to save into a test result file. Since I will be accumulating many test results, I want to keep overhead down, so I would like to simply append the result to the end of the file. Here is what I have done...
1) Create an empty array, flatten to XML and write to a file.
2) When I want to add a record, I take the record control, flatten to XML, and then overwrite the </Array> at the end of the file with the XML record. I then append another </Array> onto the end of that to properly close it out.
3) I can then read this XML file back into an array of test record structures at a later time.
I chose to do it this way, because when I am generating the test records, I do not want the overhead of "file read->XML Parse entire file->append code->XML export appended structure->File write". I figured that by simply appending the XML record to the end of the file, I could cut down on a lot of this IO overhead.
The problem is that XML is a bit "chatty". I'd like to be able to read, write and append to compressed files (since XML compresses very well). The lvzlib routines only have a read and a write, but no append. My understanding of the compression schemes is that it makes a table of the common byte patterns and replaces them with shorter tokens. If I compress each record, I will have a table of tokens for each record that will basically be the same as all the other records. I can get better compression if I use one table for all records.
Has anybody implemented this, or do I need to dig into the guts of zlib?
Alternatively, can the normal File I/O routines be configured to work on a file in a compressed archive (like a zip file) and let the OS handle all the compression?
Thanks,
I'm not sure what you mean by appending. If you mean appending new data to an existing file in a ZIP archive this can't be done in any way. The ZIP file is not structured in a way that would allow appending data to an internal file stream inside the archive. I'm not even sure there is any compression scheme that would allow that. The only way for all standard compression schemes for this is to extract the file append the new data and then replace the existing file in the archive with the new one.
If you mean appending a new file to an existing archive then the newest released version 2.3 of lvzlib can do it. The ZLIB Open Zip Archive.vi function has an append mode input. Previously this was a boolean that indicated if a new file was to be created or if the archive should be tacked to the end of an existing file. In the new version this is an enum with an additional entry (adding to existing archive).
Rolf Kalbermatter
Message Edited by rolfk on 10-04-2007 09:21 AM
Rolf Kalbermatter
CIT Engineering Netherlands
a division of Test & Measurement Solutions

Pull compressed file (.gz format) via FTP and place on Application server

Hello!
Greetings.
We have a requirement where a compressed file in the format *.gz is to be pulled via FTP and saved to the application server after extracting.
I searched the forums and found options to pull text or XL files, but nothing about pulling a compressed file. I wished to know if there is any process for the same. After pulling the file, it is to be saved to Application server after extracting. My doubts are as below:
1. How to pull a *.gz file via FTP (Need batch processing)
2. Can I extract and rename th file before saving it to applciation server? Or I need a temporary location to place the file before extraction?
Any inputs are appreciated.
Thanks,
Shishir.

Hi Sandra.
Thanks for the confirmation.
There is a change is the requirement. We need to Poll the FTP server for the file for the duration of one week every month.
When the file is found, we are to take the *.gz file, extract and put on the application server.
My question is how do we poll the application FTP server? I searched the forums and found a few threads that say that an FTP adapter is to be setup for polling the FTP server and then we can schedule it using u201CAvailability Time Planningu201D.
/people/shabarish.vijayakumar/blog/2006/11/26/adapter-scheduling--hail-sp-19-
I wished to know if that is the only way to approach this requirement.
Any help is appreciated.
Thanks and Regards,
Shishir.
Edited by: Shishir Kinkar on Apr 26, 2011 11:07 AM

Extracting compressed files of 2byte filename?

Similar Messages

Maybe you are looking for