Figure out dates corresponding to days of the week, constructing a schedule

Hi everyone,
I'm sorry if this topic has already been covered. I've searched the forums for an answer, but did not see anything I took to be an answer (I'm not very good at this).
I'm trying to make a simple table to tell me which dates a particular day of the week falls on. For instance, I'm making a syllabus for a class that meets every Tuesday and Thursday. I want to know which dates corresponds to every Tuesday and Thursday from here on out.
I currently have a table with two columns. The first column is the day of the week. The first row is Tuesday, the second is Thursday, the third Tuesday, etc. I was able to do this easily with auto fill. I want the next column to be the date.
Here's a picture of what I mean:
Is there a formula that will let me do this?
Thanks!

Hi Macademic,
How about putting both into the first column?
Select all of column A and use the Cell Format inspector to set the format as Date and Time, with the Date: and Time: pop-up menus set to:
Date: Mon, Jan 5, 2009
or: Monday, January 5, 2009
or to a Custom format, Date and Time, including only the elements you want in the format you want them.
Time: None
Enter the starting date into A2, and confirm that it is either a Tuesday or a Thursday.
In A3, enter
=A2+2 (if the course starts on a Tuesday)
or
=A2+5 (if the course starts on a Thursday)
In A4, enter
=A2+7
Select A3 and A4, then grab the control (small circle at the lower right corner of the selection) and drag down until you reach the last date of the course.
Regards,
Barry

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Hi there,
I don't think there's a built-in Oracle procedure for what you want. However...
In SQL (at least, Oracle's SQL), you have the function TO_CHAR and TO_DATE that allow you to convert a date to a string and vice-versa. They work pretty much in a similar way, that is :
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Eurk.
Or you could write a function that would return the date of the first day of the week of a specific date, like :
create or replace
FUNCTION FDOW (P_DATE DATE) RETURN DATE
IS
R_FDOW DATE;
BEGIN
R_FDOW := to_date( (to_char(P_DATE,'YYYY') | | to_char( to_number( to_char(P_DATE,'DDD')) - to_number( to_char(P_DATE,'D')) + 1)),'YYYYDDD');
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(FDOW : First Day Of Week - not really original, I know)
Then, you can call it wherever you want:
SELECT FDOW(SYSDATE) FROM DUAL;
Have fun!
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i have tried the following
note : my sysdate is 3rd april 2007
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I'm considering MONDAY as the first working day of the current week. And, the code is accordingly --
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Need some help, this code below doesnt fit the requirement.
For this program, i need to: take in day, month,year of a date as int argument, return the day of the week for the date entered in App()
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Figure out dates corresponding to days of the week, constructing a schedule

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