File to file scenario. Pls help

Hi All,
I have to make file to file scenario.
XI will pick file from File Sender System and put file at
File Receiver System. From there file will go to printer.
File name has to be constant at receiveing system like "ABC.txt"
There is one condition:
Now suppose there is file at Receiver system and Printer gets jammed so file will not be picked from Receiver system.
At that time XI should not send 2nd file and should wait till the
receiving file directory is empty again.
How to implement the above condition.
Pls suggest.

Rich,
Seriously I couldn't understand why u are opening multiple threads. It's not like you open new thread the solutions gonna be different, always the solution will be same. It will be easy for u to track as well as easy for us to suggest. Plz co-operate with this, we know that u are in urgent situation, but opening multiple threads doesn't solve ur issue for sure, it makes the participants to be frustrated and left your question unanswered, plz understand this.
I hope u can undestand!
I know ur scenario is only File 2 File, I don't what could be the frequency of the Sender File or how often the File will be triggered. I will try to explain the best possible way I can.
I'm going to explain with example , IS_RETRY_LIMIT - 2
See,
First trigger , File picked by XI and sent to Receiving folder , Printer picked the file - XI Job is done.
Second trigger, File picked by XI and sent to Receing folder, Printer is jammed - XI Job is done.
Third trigger, File picked by XI , it couldn't able to deliver to the Receiving folder ,coz file ABC.txt is already there. So please understand the concept of IS_RETRY_LIMIT, XI retries once again after some interval, it couldn't able to deliver,file is there. - XI Job is not done- in process
Fourth trigger, File picked by XI , it couldn't able to deliver to the Receiving folder ,coz file ABC.txt is already there,(Printer is not resolved yet, Second trigger file is already there). XI will retry to send file again after some interval it couldn't able to deliver,file is there. - XI Job is not done- in process
XI retries the file for Third trigger process, it couldn't able to deliver, XI set the message to FAILED status.
Fifth Trigger, File picked by XI , it couldn't able to deliver to the Receiving folder ,coz file ABC.txt is already there,(Printer is not resolved yet, Second trigger file is already there) XI will retry to send file again after some interval it couldn't able to deliver,file is there. - XI Job is not done- in process
Printer Problem Solved
File Picked by the printer, Second Trigger is done.
XI retries the file for Fourth trigger process, it successfully delivers the message to the printer - XI Job is done
XI retries the file for Fifth trigger process, it successfully delivers the message to the printer - XI Job is done
Sixth Trigger, File picked by XI and sent to Receiving folder , Printer picked the file - XI Job is done.
So, now the job continues as usual..
Now your question might be what to do for the FAILED message in the Third trigger, As I mentioned in the other thread, you need to re-deliver it by the link given in the other thread.
I hope u can understand , how IS_RETRY_LIMIT helps in your scenario!
raj.

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When i compile UseMusic.java i get the following:
i can't figure it out..
Thank You for Time!
D:\java\cENG310\Ass2>javac UseMusic.java
UseMusic.java:29: cannot resolve symbol
symbol : variable middlec
location: class UseMusic
 mm.caldis(middlec); // compute freqs
 ^
UseMusic.java:42: cannot resolve symbol
symbol : variable middlec
location: class UseMusic
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 ^
UseMusic.java:86: getfreq(java.lang.String[],java.lang.String) in Music cannot be app
ang.String)
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 ^
5 errors
* Filename : UseMusic.java
import iopack.Io;
import java.text.DecimalFormat;
* UseMusic this class is
public class UseMusic {
 public static void main(String[] args) {
 Music mm = new Music();
 DecimalFormat fmt = new DecimalFormat("0.###"); // round output to 3 decimals places
 boolean newmidc = false;
 boolean notelookup = false;
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 mm.caldis(middlec); // compute freqs
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 System.out.println("\t************************");
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 for (int i = 0; i < mm.noteName.length; i ++) {
 // display values onto screen
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 System.out.println(" " + mm.noteFreq[i] + " Hz *\n");
 mm.setzero(middlec); // reset middlec to zero
 // prompt user for value of midddle c
 while (!newmidc) {
 //read value new value for middle c
 double middlec = Io.readDouble("\n\tEnter value for Middle C [Between 250 - 265] (Hz)");
 // vaildate value for middlec
 // vaild if valeu for middle is between 250-265
 if ((middlec > 250) && (middlec < 265)) {
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 for (int i = 0; i < mm.noteName.length; i ++) {
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 } // end of while for newmidc
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 while (!notelookup) {
 //read value new value for
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 } //end of else
 } //end of while
 }// end of static main
} // end of Class UseMusic
* Filename : Music.java
import java.*;
public class Music
 static int MAXSIZE = 12; // max # of elements (13 elements)
 static double INITALMIDDLEC = 256; // set default value of middle c to 256
 double middlec; // user value for middlec
 String[] noteName; // array stores name of notes
 double[] noteFreq; // array stores freq of notes
boolean vaildstr; // track whether entered string is vaild
 char replay; // user's reponse to continue prompt
 boolean uContinue; // whether or not to continue
 int sub; // index of searched string
 // Default Constructor
 Music () {
 String[] noteName = {"C","C#","D","D#","E","F","F#","G","G#","A","A#","B","C'"};
 double[] noteFreq = new double[noteName.length];
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 vaildstr = false; // signify whether user entered value
 sub = 0;
 void caldis(String[] noteName, double[] noteFreq, double middlec) {
 // calculate the values based upon middlec
 double temp = 0; // dummy used to store value
 double semitone = (double)Math.pow(2,(1/12));
 temp = middlec; //set the value of the first element to middlec
 // fill noteFreq with values wrt middlec
 // no magic #s - noteName since noteFreq has # of elements
 for (int i = 0; i < noteName.length; i++) {
 temp = noteFreq[i-1]; // save value of previous elements
 noteFreq[i] = temp + (temp * semitone);
 } //end of for
 double getmiddlec(double middlec) {
 return middlec; // Returns the value of middlec
 int getfreq(String[] noteName, String strkey) {
 for (int i = 0 ; i < noteName.length ; i++) {
 if (strkey.compareTo(noteName) == 0) {
sub = i;
return sub;
 double setzero(double middlec) {
 middlec = 0;
 return middlec;
String getnoteName(int index) {
return noteName[index];
double getnoteFreq(int index) {
return noteFreq[index];
boolean checkvaild(String[] noteName, String strkey) {
vaildstr = noteName.equals(strkey);
return vaildstr;
} //end of Class Music

>
What part can't you figure out? The compiler is
telling you that it can't resolve "middlec", which it
can't, because you apparently didn't define it
anywhere. Actually he did define it, but he defined it after he passed it to those methods. If that's not simply an oversight on his part, I can't begin to understand what he was thinking.

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>
srikanth vadlamani wrote:
> Hi experts,
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>
> regards,
> Sri..
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