Find missing numbers in array

HI !
I have an array which holds 999 different numbers between 1-1000
(which means that 1 number between 1-1000 does not appear in the array).
I need to find the missing number in one pass and it's easy.
My question is:
Do you have any idea how can I find 2 missing numbers in the array ?
Is it possible ?
I cant use any data structure and I need to find the missing numbers in one pass.
Thank you

Using array.sort() and using another array is out of the question as its inhrently banned in the "i cant use any data structure" so this is
Homework! tut tut
ok so far an array with 1 number missing "its easy" yeah, just add em all up and see whats missing.
for 2 numbers missing you should take a hint from what you are studying in the course ie solving Quadratic Equations..
shall i make snoopy beg yet??
naw, ok here goes
on your 1 permitted pass add up all the mumbers that are there, also have another total for the squares of the numbers
call the numbers you are looking for A and B
subtract the first total from what it would be if there were all 1000, call this N
subtract the second total from what the total of the squares would be if there were all 1000, call this M
so..
A+B=N
solve for B in terms of A
so..
B=N-A
and A^2+B^2=M
should i quit now???
no, ok
substitute B in the second equation, shuffle a bit and..
2A^2-2NA+N^2-M=0
recognise the terms of the quadratic and..
A=(2N +/- (4N^2-8(N^2-M))^.5)/4
note the +/- plus OR minus will give you 2 results, these will be the 2 missing munbers
tahh dahh
See maths does have some use

Similar Messages

Finding Missing Numbers

I want to find missing numbers from a column which is alpha numeric, its last five positions are numeric. At first three positions there are different combinations of alphas i.e. *'BA ','BAW','SA ','SAA' ..........* if alphas are two then 3rd position is blank. I also need it to generalised this to cover all existing alpha numeric series.
SELECT SUBSTR (a.claim_no, 4, 5) + 1
FROM core_business.cb_pensioner a
WHERE SUBSTR (a.claim_no, 1, 3) = 'BA '
   AND NOT EXISTS (
                 SELECT NULL
                   FROM core_business.cb_pensioner b
                  WHERE to_number(SUBSTR (b.claim_no, 4, 5)) = to_number(SUBSTR (a.claim_no, 4, 5)) + 1)
   order by SUBSTR (a.claim_no, 4, 5);I am getting ORA-01722 error

You have two issues with such a task.
Problem 1 is how to convert the trailing part into a number so that you can compare values.
to_number(SUBSTR (b.claim_no, 4, 5)) works, but only if the value in b.claim_no is always a number regardless of the other column criteria.
A statement like
WHERE SUBSTR (a.claim_no, 1, 3) = 'BA ' /* filter 1 */
and to_number(SUBSTR (b.claim_no, 4, 5)) > 1 /* filter 2 */
...might fail because your table might have a value like
b.claimno = 'XYZ1234b'
The way you wrote the query the database will decide which filter criteria it executes first. It might be filter1, but could also be filter2. If filter2 is executed first then you will get the error message.
Problem 2 how to order and compare different rows, so that you can find the missing values.
Here the analytic LEAD(LAG) function is very helpful. it will give you access to the next (or previous row).
Both problems can be overcome.
Here is my try, but I'm not sure if it works in your case. You might need to adapt a little.
This should work if all the rows are numeric that belong to the specific groups. if you can have wrong data in there too, then a different approach is needed.
with testdata as (select 'XYZ1234b' claim_no from dual union all
            select 'BA 12345' claim_no from dual union all
            select 'BA 12346' claim_no from dual union all
            select 'BA 12350' claim_no from dual union all
            select 'BAW11111' claim_no from dual union all
            select 'BAW11113' claim_no from dual union all
            select 'XYZ1234b' claim_no from dual )
/* end of test data creation */
select claim_no, substr(claim_no, 1,3) part1, substr(claim_no, 4) part2,
       to_number(substr(claim_no, 4)) current_num,
       lead(to_number(substr(claim_no, 4))) over (partition by substr(claim_no, 1,3) order by to_number(substr(claim_no, 4))) next_num,
       lead(to_number(substr(claim_no, 4))) over (partition by substr(claim_no, 1,3) order by to_number(substr(claim_no, 4)))
        - 1 - to_number(substr(claim_no, 4))
        as "missing_values"
from testdata
where substr(claim_no, 1,3) in ('BAW','BA ')
order by claim_no;
CLAIM_NO PAR PART2 CURRENT_NUM   NEXT_NUM missing_values
BA 12345 BA 12345       12345      12346              0
BA 12346 BA 12346       12346      12350              3
BA 12350 BA 12350       12350
BAW11111 BAW 11111       11111      11113              1
BAW11113 BAW 11113       11113Problem 1 is solved because the where condition is always executed before the function in the select clause, especially in connection with an analytic function.
Problem 2 is also solved by using the analytic function LEAD function. And this is fast, because you access the same table only one time. Other solution might do a subquery to fetch the value from the previous/next row. This means several accesses to the same table and is usually much slower.
Edited by: Sven W. on Sep 20, 2010 2:32 PM

How to find Missing Numbers, simplest way

Hi All,
Table 1
Invoice_books_issues
Columns are Transaction_date,serail_no_start,serial_no_end.
Ex Data is :
1/1/2005...........1000.............2000
2/2/2005...........4500.............5500
My Invoice_table is
Inv_no
1908
1005
4502
4589
5509......on and on...
so i need to get the missing nos out of the issues. like
1000
1001
1002
1003
1004 ... note here 1005 alrady been used.
1006
... on and on.
Thanks in advance.

something like this :
1. create view holding surrogate numbers:
CREATE OR REPLACE VIEW NUM_VIEW
(NUM)
AS
SELECT thous.x+huns.x+tens.x+ones.x num FROM
(SELECT 0 x FROM dual
UNION SELECT 1 FROM dual
UNION SELECT 2 FROM dual
UNION SELECT 3 FROM dual
UNION SELECT 4 FROM dual
UNION SELECT 5 FROM dual
UNION SELECT 6 FROM dual
UNION SELECT 7 FROM dual
UNION SELECT 8 FROM dual
UNION SELECT 9 FROM dual) ones,
(SELECT 0 x FROM dual
UNION SELECT 10 FROM dual
UNION SELECT 20 FROM dual
UNION SELECT 30 FROM dual
UNION SELECT 40 FROM dual
UNION SELECT 50 FROM dual
UNION SELECT 60 FROM dual
UNION SELECT 70 FROM dual
UNION SELECT 80 FROM dual
UNION SELECT 90 FROM dual) tens,
(SELECT 0 x FROM dual
UNION SELECT 100 FROM dual
UNION SELECT 200 FROM dual
UNION SELECT 300 FROM dual
UNION SELECT 400 FROM dual
UNION SELECT 500 FROM dual
UNION SELECT 600 FROM dual
UNION SELECT 700 FROM dual
UNION SELECT 800 FROM dual
UNION SELECT 900 FROM dual) huns,
(SELECT 0 x FROM dual
UNION SELECT 1000 FROM dual
UNION SELECT 2000 FROM dual
UNION SELECT 3000 FROM dual
UNION SELECT 4000 FROM dual
UNION SELECT 5000 FROM dual
UNION SELECT 6000 FROM dual
UNION SELECT 7000 FROM dual
UNION SELECT 8000 FROM dual
UNION SELECT 9000 FROM dual) thous
this one holds numbers up to 9999 - should be up to the maximum value for your invoice number.
2.
CREATE TABLE INVOICE
INV_NO NUMBER(5)
Insert into invoice
(INV_NO)
Values
(1000);
Insert into invoice
(INV_NO)
Values
(4501);
Insert into invoice
(INV_NO)
Values
(4505);
COMMIT;
3.
CREATE TABLE INVOICE_BOOKS_ISSUES
SERIAL_NO_START NUMBER,
SERIAL_NO_END NUMBER
Insert into INVOICE_BOOKS_ISSUES
(SERIAL_NO_START, SERIAL_NO_END)
Values
(1000, 1006);
Insert into INVOICE_BOOKS_ISSUES
(SERIAL_NO_START, SERIAL_NO_END)
Values
(4500, 4507);
COMMIT;
4.
SQL> select * from invoice;
INV_NO
4501
1000
1005
4505
SQL> select * from Invoice_books_issues;
SERIAL_NO_START SERIAL_NO_END
1000 1006
4500 4507
SQL>
select num
from num_view nv
where exists
(select serial_no_start, serial_no_end from Invoice_books_issues ibi
where nv.num >= ibi.SERIAL_NO_START and nv.num <= ibi.SERIAL_NO_END)
and
not exists (select inv_no from invoice inv where inv.INV_NO = nv.num)
NUM
1001
1002
1003
1004
1006
4500
4502
4503
4504
4506
4507
11 rows selected.
SQL>
hope this helped.
Mike

Finding missed sequence numbers and rows from a fact table

Finding missed sequence numbers and rows from a fact table
Hi
I am working on an OLAP date cube with the following schema:
As you can see there is a fact transaction with two dimensions called cardNumber and Sequence. Card dimension contains about three million card numbers.
Sequence dimension contains a sequence number from 0 to 255. Fact transaction contains about 400 million transactions of those cards.
Each transaction has a sequence number in 0 to 255 ranges. If sequence number of transactions of a card reaches to 255 the next transaction would get 0 as a sequence number.
For example if a card has 1000 transactions then sequence numbers are as follows;
Transaction 1 to transaction 256 with sequences from 0 to 255
Transaction 257 to transaction 512 with sequences from 0 to 255
Transaction 513 to transaction 768 with sequences from 0 to 255
Transaction 769 to transaction 1000 with sequences from 0 to 231
The problem is that:
Sometimes there are several missed transactions. For example instead of sequence from 0 to 255, sequences are from 0 to 150 and then from 160 to 255. Here 10 transactions have been missed.
How can I find all missed transactions of all cards with a MDX QUERY?
I really appreciate for helps

Thank you Liao
I need to find missed numbers, In this scenario I want the query to tell the missed numbers are: 151,152,153,154,155,156,157,158,159
Relative transactions are also missed, so I think it is impossible to get them by your MDX query
Suppose this:
date
time
sequence
20140701
23:22:00
149
20140701
23:44:00
150
20140702
8:30:00
160
20140702
9:30:00
161
20140702
11:30:00
162
20140702
11:45:00
163
As you can see the sequence number of the last transaction at the 20140701 is 150
We expecting that the first transaction of the next day should be 151 but it is 160. Those 10 transactions are totally missed and we just need to
find missed sequence numbers

Code for find the missing number in array without sorting/comparing in java

Hi all,
We have 1 to 100 number in an array, but one number is missing (from 1 to 100). we have to find it out without sorting or comparing of this missing number in array.
please help me out to find the solution this query.
regards & thanks
Mohan Kumar
Bangalore,
India

Maybe you could sum up the numbers you've got in your array and subtract the result from 5050 [the term [code](N*N+N)/2 where N is your upper bound (i.e. 100)]. You'll get the sum of all missing values (which in this case would be exactly the missing number). n.b. that you could genaeralize on that for arbitrary finite series.
Kind Regards,

Find unique numbers in an array.

How would I find unique numbers in an array by using only one array?

At the above codes, I use the String representation of the number that I want to find. I know that it is an easy example but it can give you an idea that how Hash works in Java.
Give symbols(aliases) to your numbers which helps you to remember the each specific number, so you can find specific number by only using its symbol(nickname) instead of using its location which is more difficult to remember.
import java.util.*;
* ...Hashdescription...
* @author ...yourname...
* @version 1.00, 2006/05/19
public class Hash
     // properties
     ArrayList keys;
     ArrayList values;
     // constructors
     public Hash(){
          keys = new ArrayList();
          values = new ArrayList();
     // methods
     public void add(int val){
          values.add(new Integer( val));
          keys.add("" + val);
     public int get(String key){
          int index = keys.indexOf(key);
          return ((Integer)(values.get(index )) ). intValue();
     public static void main( String[] args)
          Hash list = new Hash();
          list.add(1);
          list.add(2);
          list.add(3);
          list.add(4);
          list.add(5);
          list.add(6);
          list.add(7);
          list.add(8);
          list.add(9);
          System.out.println(list.get("3"));
} // end of class Hash

"Open VI Reference" Option "Prompt user to find missing subVIs"

I am using "Open VI Reference" to dynamically load a VI. For the "option" control of the "Open VI Reference" node, I pass "0x10" or "10" in hexadecimal, which supposedly "prompt user to find missing subVIs." Nevertheless, I don't get a prompt message dialog when I intentionally pass an invalid or missing VI path. Instead I just get an Error Code 7. What does this option "Prompt user..." suppose to do?

Make sure you set the properties on the integer input into the “options” control to the “Open VI Reference” to be a Hexadecimal format (right-click on the “options” control input, select Format and Precision…, then select Hexadecimal). Now, if you re-run your VI and wire in a VI with a missing subVI, the Open VI Reference will appear with a dialog that will prompt you to browse to the missing subVI. This is exactly the same message LabVIEW displays when it attempts to open a VI and cannot find its subVIs.
I’ve attached a simple example program to demonstrate. Enter the path to the “number extractor.vi” as the VI to open. You should see a dialog prompt appear asking for the “Search 1D Array – Complete.vi”.
Hope this helps!
Attachments:
openVIRefExample.zip ‏20 KB

Finding missing sequence

Hello all.
I'm using the Oracle 10g Database. i'm trying to figure out how to write a simple sql query to:
find the missing numbers in a table between say 86002895 and 86005197 (inclusive)
Ex: Current Scenario : table_1 :
tracking_no | id_value
86002895 | 10
86002896 | 10
86002899 | 10
86002900 | 10
86002910 | 10
86005196 | 10
86005197 | 10
Expected Result1:
" missing tracking_id " where id_value = 10 from table_1 ;
86002897
86002898
86002900 to 86002910
86002910 to 86005196
Thanks in advance :)

user8635888 wrote:
Ex: Current Scenario : table_1 :
tracking_no | id_value
86002895 | 10
86002896 | 10
86002899 | 10
86002900 | 10
86002910 | 10
86005196 | 10
86005197 | 10
Expected Result1:
" missing tracking_id " where id_value = 10 from table_1 ;
86002897
86002898
86002900 to 86002910
86002910 to 86005196
Thanks in advance :)Maybe something like the following:
SQL> SELECT * FROM TEST_TAB
2 /
TRACKING_NO   ID_VALUE
   86002895         10
   86002896         10
   86002899         10
   86002900         10
   86002910         10
   86005196         10
   86005197         10
7 rows selected.
SQL> SELECT   CASE
2              WHEN tracking_no + 1 = lead_no - 1 THEN TO_CHAR (tracking_no +1)
3              ELSE TO_CHAR (tracking_no + 1) || '-' || TO_CHAR (lead_no - 1)
4           END
5              Missing_track_no
6    FROM   (SELECT   tracking_no,
7                     LEAD (tracking_no, 1, NULL)
8                        OVER (ORDER BY tracking_no ASC)
9                        lead_no
10              FROM   test_tab
11             WHERE   ID_VALUE = 10)
12   WHERE   lead_no != tracking_no + 1
13 /
MISSING_TRACK_NO
86002897-86002898
86002901-86002909
86002911-86005195
3 rows selected.
SQL>You can tweak the above query to match your requirement.
Hope this helps.
Regards,
Jo

Looking to write a query to give me the missing numbers in a sequence

My query here gives me a list of numbers:
select distinct cast(SUBSTRING(docket,7,999) as INT) from [DHI_IL_Stage].[dbo].[Violation] where InsertDataSourceID='40'
and ViolationCounty='Carroll' and SUBSTRING(docket,5,2)='TR' and LEFT(docket,4)='2011'
order by 1
Gives back:
I want to find the numbers missing in the sequence

CREATE TABLE t1 (C INT NOT NULL PRIMARY KEY)
insert t1 select 1 union all
select 3 union all
select 4 union all
select 5 union all
select 7 union all
select 10
SELECT
c+n FROM t1, (
SELECT 0 n UNION ALL SELECT 1
) T
GROUP BY c+n
HAVING MIN(n) = 1 and c+n < (select max(c) from t1)
Best Regards,Uri Dimant SQL Server MVP,
http://sqlblog.com/blogs/uri_dimant/
MS SQL optimization: MS SQL Development and Optimization
MS SQL Consulting:
Large scale of database and data cleansing
Remote DBA Services:
Improves MS SQL Database Performance
SQL Server Integration Services:
Business Intelligence

Import Catalog vs. Find Missing Files

I had my primary image storage hard drive fail. I am switching to my full backup, however I have hundreds of folders containing 118,000+ files and want the best way to access them.
I can have the existing catalog Find Missing Files, and that preserves the History from teh Develop panel, but it seems that I can only find files within a subfolder, which means that I have to do that for every individual subfolder in the sack.
I can also Import Catalog, but my question is: Will that preserve the History from the Develop Panel or will it simply import the files, as edited, but without showing the step-by-step edits previosuly completed?
I imported a couple of individual subfolders (not the Import Catalog option) and the files came through with edits intact, but no History (History began with the new Import).
Any ideas? Finding Missing Files folder by folder is a potential time suck of epic proportion, but I want to preserve my work history.
Thanks,
David Feldman
LR5 on an iMac running 10.8.5

Thanks for the suggestions. But here's more details...
The Find Missing Folders so far (I will see if I am missing someting) has not worked from the parent directory. I will look again to see if I glossed over an important step.
As for the drive, it is a Drobo S 5-disk array. The disk experienced a bad sector reorganization, which was successful (all partitions readable and writeable). I prepared to swap out the newly-classified "bad" disk and install the new drive. My major blunder was to accept the Drobo firmware update because IMMEDIATELY after doing to upon reboot the Drobo now showed that ALL OF MY DRIVES WERE NOT INSTALLED, not just the one empty bay waiting for the newer, bigger backup drive.
Needless to say, I'm out of the 90-day "we'll help you" period, but they are trying to get a one-time papel dispensation to allow me to receive assistance via e-mail.
So, for now, I ain't doing squat to the Drobo array until they come up with a way to access my data. I would, however, like ot keep working, hence the need for a new catalog.

Finding discontiguous numbers

Greetings,
I need to write a plsql scripts that will find discontiguous numbers. For example, say I have a table..
id int
store varchar
tracking_num int
Each store uses a different sequence for their tracking number. ii need to find and list the contiguous segments for each store, and the total number of items shipped. For example..
STORE MIN MAX
STORE X 100 105
STORE X 107 110
STORE X 112 115
STORE X TOTAL 14
STORE Y 901 903
STORE Y 905 907
STORE Y 908 910
STORE X TOTAL 9
OK, I figure I need a cursor to be able to do this. I figure I'll loop through each store's records, increment a counter for the total. For the discontinuous I figure I'll add a new column which I'll use to group the contiguous segments together, then I can just a max and min tracking number for each store's contiguous groups.
The problem I'm having is wrapping my head around how to build a dataset with a cursor populating the new contiguous column IN MEMORY, in an line view or something, without having to create a physical table.
Anyone have any suggestions, or see any flaws with this logic?

Using Oracle 10.2.0.4
I thought this was a simple enough question that I could get away without specific examples. Tha being said
create table store_tracking (
id int,
store varchar2(20),
tracking int
INSERT INTO STORE_TRACKING (SELECT 1, 'STORE X', 100 FROM DUAL );
INSERT INTO STORE_TRACKING (SELECT 2, 'STORE X', 101 FROM DUAL );
INSERT INTO STORE_TRACKING (SELECT 3, 'STORE X', 102 FROM DUAL );
INSERT INTO STORE_TRACKING (SELECT 4, 'STORE X', 103 FROM DUAL );
INSERT INTO STORE_TRACKING (SELECT 5, 'STORE X', 104 FROM DUAL );
INSERT INTO STORE_TRACKING (SELECT 6, 'STORE X', 105 FROM DUAL );
INSERT INTO STORE_TRACKING (SELECT 7, 'STORE X', 107 FROM DUAL );
INSERT INTO STORE_TRACKING (SELECT 8, 'STORE X', 108 FROM DUAL );
INSERT INTO STORE_TRACKING (SELECT 9, 'STORE X', 109 FROM DUAL );
INSERT INTO STORE_TRACKING (SELECT 10, 'STORE X', 110 FROM DUAL);
INSERT INTO STORE_TRACKING (SELECT 11, 'STORE X', 112 FROM DUAL);
INSERT INTO STORE_TRACKING (SELECT 12, 'STORE X', 113 FROM DUAL);
INSERT INTO STORE_TRACKING (SELECT 13, 'STORE X', 114 FROM DUAL);
INSERT INTO STORE_TRACKING (SELECT 14, 'STORE X', 115 FROM DUAL);
INSERT INTO STORE_TRACKING (SELECT 15, 'STORE Y', 901 FROM DUAL);
INSERT INTO STORE_TRACKING (SELECT 16, 'STORE Y', 902 FROM DUAL);
INSERT INTO STORE_TRACKING (SELECT 17, 'STORE Y', 903 FROM DUAL);
INSERT INTO STORE_TRACKING (SELECT 18, 'STORE Y', 905 FROM DUAL);
INSERT INTO STORE_TRACKING (SELECT 19, 'STORE Y', 906 FROM DUAL);
INSERT INTO STORE_TRACKING (SELECT 20, 'STORE Y', 907 FROM DUAL);
INSERT INTO STORE_TRACKING (SELECT 21, 'STORE Y', 908 FROM DUAL);
INSERT INTO STORE_TRACKING (SELECT 22, 'STORE Y', 909 FROM DUAL);
INSERT INTO STORE_TRACKING (SELECT 23, 'STORE Y', 910 FROM DUAL); Expected Output is ...
STORE      MIN     MAX
STORE X   100     105
STORE X   107     110
STORE X   112     115
STORE X TOTAL 14
STORE      MIN     MAX
STORE Y   901     903
STORE Y   905     907
STORE Y   908     910
STORE Y TOTAL 9The explaination of the output is that we need to identify the contiguous segments of tracking numbers for each store (and thereby implicitly indicating where we are missing tacking numbers), and the total number of tracking number for each store.
I hope this helps. let me know if you have additional questions.
Edited by: user7352432 on Apr 9, 2010 8:21 AM

How to compare consecutive groups of numbers in arrays

Hi
I require to place the solution into a 1D array.
I need to compare two arrays and save the same numbers that are in both arrays but also save groups of numbers that may be in only one of the two arrays being compared.
In the example l have not been able to place all consecutive groups of numbers 8,9,10,11,12 into a 1D array.
In the example l need to filter out the zeros and the number four.
The numbers in both arrays are always in descending order however may not be in the order of index number of array. That is 15 = 15 index number
A consecutive group of numbers in this example is a group that increase by a value of 1. E.g.. 8,9,0,22,23,24 are two consecutive groups of numbers.
Thank you
Solved!
Go to Solution.
Attachments:
Compare numbers and consecutive numbers in arrays.vi ‏17 KB

Hi Lynn
I did have a look at the consecutive array solution. I have looked and looked l thought l knew how it worked but after a number of separate evaluations with other code l have failed. I am just glad it works. With the consecutive array solution l tried today my own code but l lost either the first number of the last number of a consecutive group of numbers.
I may have confused you but in doing so you have provided a real different view which l am very grateful. You have viewed the consecutive number problem as just a single 1D array problem. By doing this you have opened my eyes to another way to do the job and a way to handle this type of data. However l am also comparing two arrays. For example l have to pick up say two equal values in two columns that the consecutive array does not detect and then correctly locate a value in the final array if the value is not in the final array.
What l have not told you is also l have to be able to identify groups of numbers in two 1D arrays. E.g... Array 1 has 1,2,9,10 next array has 9,10 the final array ends up 9,10 when l would like 0,9,10. When viewing numbers by rows later on l can then detect with a array length vi the length of the 1,2 groups of numbers over a large number of columns. If 9,10 jumps to the front it becomes a wrong length. This is actually my main problem which has caused me a large amount of extra programming. I have gone back to basics to see what l can do differently and you have provided the first clue with the consecutive array. I placed it in my main program today and it filtered a lot variable data which l could not remove without losing real data. The main data lost in your solution was the say 17 number in two columns which in an image is a horizontal line. I know what l have just provided you in this paragraph is all new information but it provides a background as to what l am up to. I am getting pixel data from a 2D array and comparing +1 index 1D array with a normal array. This way l can view the data of the next column to see if there is a pattern. I am actually trying to program an array as how humans view objects in images.
I will have another go at integrating your solution next week
Regards
Michael

Property or method to find missing fonts...

Hi Everyone,
Is there any direct property or method to find missing fonts in EPS doucments in Illustrator CS4 like we do in InDesign. I have tried this by doing comparison of document fonts and application fonts to get missing fonts but it won't work.
Any help would be appreciatable. Thanks in advance.
Regards
Thiyagu

Have you tried a search of this forum… Im sure I posted a work around to this… The simple answer is NO not in the Illustrator DOM you can however read the file as text and the stuff you want is in the Illustrator file comments…

Is there not an easier way to find missing songs?

Is there a smarter way to find missing songs and albums besides having to go through each one individually? Some kind of batch process would be nice...
How do you guys efficiently find missing songs or albums?

don't you just love the way Apple answers your questions in this forum?

Find no numbers characters in a string

HI, how i can find no numbers characters in a string
By example.
'45125454564#4545'.
I only want to know if the string contains no number characters or not, i dont want to know the character '#'.
Is there a function module for doing that?
Thanks

You can try:
NUMERIC_CHECK
OR
IF var CO '0123456789'.
ENDIF.

Find missing numbers in array

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