Find the total number of saved reports in Disco 10g using Disco Admin tool

Hi,
I am trying to find the total number of saved or scheduled reports in Discoverer 10g using Discoverer Administrator tool. Can anyone help?
Irene.

The EUL STATUS workbooks might help
http://docs.oracle.com/html/B13916_04/eul_status.htm
HTH
Srini

Similar Messages

How do i find the total number of fields within all tables in one of my databases

I'm in the process of creating some "gee whiz" metrics for one of my applications and want to find the total number of columns contained in its database. Is there a stored procedure to get this information that would save me the effort
of opening each of my 66 tables and counting the columns? I also have the same question for my 138 views. Thank you for any ideas you care to offer...............Phil Hoop
Phil Hoop

Hi Phil,
Assumes SQL 2005 or higher
Let 's try simple one ....
SELECT COUNT(col.column_name), col.table_name
FROM information_schema.columns col
JOIN information_schema.tables tbl
ON tbl.table_name = col.table_name
AND tbl.table_schema = col.table_schema
AND tbl.table_catalog = col.table_catalog
AND tbl.table_type = 'VIEW'
GROUP BY col.table_name
Let me know if this will help you.
If you think my suggestion is useful, please rate it as helpful.
If it has helped you to resolve the problem, please Mark it as Answer.
Varinder Sandhu www.varindersandhu.in

How do I find the total number of elements in a multi dim array

How do I find the total number of elements in a single or multi dim array?
For example, a 2x3 array has 6 elements, and a 2x3x4 has 24. How do I compute this very easily - is there a single VI that does this?
David
Solved!
Go to Solution.

Use "array size" (array palette) followed by "multiply array elements" (numeric palette)
(Works also equally well for 3D arrays and higher)
For a 1D array, just use "array size".
Message Edited by altenbach on 02-05-2009 05:57 PM
LabVIEW Champion . Do more with less code and in less time .
Attachments:
NumberOfElements.png ‏3 KB

Hi, I just purchased Adobe Illustrator and I cant find the serial number. When I try to download using Cloud it says it does not support my computer system. Just yesterday I finished my trial. What shall i do?

I just purchased Adobe Illustrator and I cant find the serial number. When I try to download using Cloud it says it does not support my computer system. Just yesterday I finished my trial. What shall i do?

To locate the serial number:
http://helpx.adobe.com/x-productkb/global/find-serial-number.html
http://helpx.adobe.com/x-productkb/policy-pricing/serial-number-retrieval-process-faq.html

How to find the total number of pair under particular parent according to pattern 1:2or2:1,1:1 day to day maximum up to 5 pair caping daily

Dear friends,
I provide full details here ,my database table structure ,data and stored procedure and my problem ,
please review it and provide the solution or any idea to solve my problem.
I am working on a project in which members are added in a tree pattern, and get the payment accordingly.
below is my table structure ,data and stored procedure
CREATE TABLE Associate_Income
ID varchar(30) NOT NULL,
ParentID varchar(30) NULL,
IsLeft tinyint NULL,
IsRight tinyint NULL,
joingdate datetime NOT NULL
go
INSERT Associate_Income
(ID, ParentID, IsLeft, IsRight, joingdate)
SELECT 'Ramesh123', NULL, NULL, NULL '2014-01-03 16:31:15.000' UNION ALL
SELECT 'Sonu', 'Ramesh123', 1, NULL, '2014-01-03 16:45:21.000' UNION ALL
SELECT 'Pawan kumar', 'Ramesh123', NULL, 1, '2014-01-04 16:50:23.000' UNION ALL
SELECT 'Ravi123', 'Sonu', 1, NULL, '2014-01-04 17:03:22.000' UNION ALL
SELECT 'Vineet123', 'Sonu', NULL, 1, '2014-01-04 17:26:01.000' UNION ALL
SELECT 'dev123', 'Ravi123', 1, NULL, '2014-01-05 19:35:16.000' UNION ALL
SELECT 'Mukesh123', 'Ravi123', NULL, 1, '2014-01-05 19:40:41.000' UNION ALL
SELECT 'poonam123', 'Vineet123', 1, NULL, '2014-01-05 19:49:49.000' UNION ALL
SELECT 'monu', 'Pawan kumar', 1, NULL, '2014-01-05 17:32:58.000' UNION ALL
SELECT 'Arti123', 'Pawan kumar', NULL, 1, '2014-01-05 19:54:35.000' UNION ALL
My database table Associate_Income structure and data is as follow:
ID ParentID IsLeft IsRight joingdate
Ramesh123 NULL NULL NULL 2014-01-03 16:31:15.000
Sonu Ramesh123 1 NULL 2014-01-03 16:45:21.000
Pawan kumar Ramesh123 NULL 1 2014-01-04 16:50:23.000
Ravi123 Sonu 1 NULL 2014-01-04 17:03:22.000
Vineet123 Sonu NULL 1 2014-01-04 17:26:01.000
dev123 Ravi123 1 NULL 2014-01-05 19:35:16.000
Mukesh123 Ravi123 NULL 1 2014-01-05 19:40:41.000
poonam123 Vineet123 1 NULL 2014-01-05 19:49:49.000
monu Pawan kumar 1 NULL 2014-01-05 17:32:58.000
Arti123 Pawan kumar NULL 1 2014-01-05 19:54:35.000
by using below stored procedure i can count the total number of pairs under particular node in 2:1,1:1 ratio means first pair is completed when two node added to the left side of given parent node and one node added
right side of given parent node after that all pairs are completed when one node added left side and one node added right side of parent node (1:1 ratio)
example if i execute my stored procedure as follows it would return following.
EXEC count_pairs 'Ramesh123'
3
so there is 3 pairs as shown in my figure.
when we execute my stored procedure for ParentID 'sonu' it would return following.
EXEC count_pairs 'sonu'
2
so there is 2 pairs as shown in my figure.
My problem is to find the query which can return the total number of pair under particular node any given parent node. day to
day maximum 5 pairs in a day please any one can suggest us
CREATE proc [dbo].[count_pairs]
@ParentID nvarchar(50)
as
begin
Declare @ParentSUM SMALLINT = 0
Declare @SubLeftID nvarchar(50)
Declare @SubRightID nvarchar(50)
SELECT @SubLeftID = CASE WHEN [IsLeft] = 1 THEN [ID] ELSE @SubLeftID END
,@SubRightID = CASE WHEN [IsRight] = 1 THEN [ID] ELSE @SubRightID END
FROM Associate_Income
WHERE ParentID = @ParentID
IF @SubLeftID IS NOT NULL AND @SubRightID IS NOT NULL AND EXISTS(SELECT 1 FROM Associate_Income WHERE [IsLeft] = 1 AND ParentID = @SubLeftID)
BEGIN
SET @ParentSUM = 1
;WITH Associate_Income_CTE AS
SELECT [ID], [ParentID], [IsLeft], [IsRight], 0 AS [Level]
FROM Associate_Income
WHERE [ParentID] = @ParentID
UNION ALL
SELECT RecursiveMember.[ID], RecursiveMember.[ParentID], RecursiveMember.[IsLeft], RecursiveMember.[IsRight], Level + 1
FROM Associate_Income RecursiveMember
INNER JOIN Associate_Income_CTE AnchorMember
ON RecursiveMember.[ParentID] = AnchorMember.[ID]
SELECT @ParentSUM = @ParentSUM + COUNT([ParentID])
FROM
SELECT [ParentID]
,'IsLeft' AS [Direction]
,1 AS [Value]
FROM Associate_Income
WHERE [IsLeft] = 1
AND [ID] <> @ParentID --AND [ID] NOT IN (@SubLeftID, @ParentID)
AND [ParentID] NOT IN (@ParentID, @SubLeftID)
UNION ALL
SELECT [ParentID]
,'IsRight' AS [Direction]
,1 AS [Value]
FROM Associate_Income
WHERE [IsRight] = 1
AND [ParentID] <> @ParentID
) AS Associate_Income
PIVOT
MAX([Value]) FOR [Direction] IN ([IsLeft], [IsRight])
) PVT
WHERE [IsLeft] IS NOT NULL AND [IsRight] IS NOT NULL
END
SELECT @ParentSUM
Jitendra Kumar Sr. Software Developer at Ruvixo Technologies 7895253402

I don't think this is homework, I am not sure how helpful it was by Kalman to merge the two threads. It appears that two different persons posted the questions. It could be though, that it is the same problem and Jitendra has taken over Chandra's
task.
However, I was not able to understand the problem nor the figure. And nor the definition of pairs in this context. My assumption is that what Jitendra posted is an abstraction of the actual problem in order to not reveal intellecutal property. Possibly this
makes the problem more difficult to understand for us outsiders.
I've come so far that I worked out a table definition and INSERT statements with sample data, as well as a call to the procedure which returns 3 and this appears to map to the figure, but I don't know what it means. Since I don't know what this
is about, I have not made any attepmts to understand the code, but I would appreciate clarification about the underlying business rules as well as the expected results for various test cases.
CREATE TABLE Associate_Income(ID varchar(30) NOT NULL,
ParentID varchar(30) NULL,
IsLeft tinyint NULL,
IsRight tinyint NULL,
joingdate datetime NOT NULL)
go
INSERT Associate_Income (ID, ParentID, IsLeft, IsRight, joingdate)
SELECT 'Ramesh123', NULL, NULL, NULL, '2014-01-03 16:31:15.000' UNION ALL
SELECT 'Sonu', 'Ramesh123', 1, NULL, '2014-01-03 16:45:21.000' UNION ALL
SELECT 'Pawan kumar', 'Ramesh123', NULL, 1, '2014-01-04 16:50:23.000' UNION ALL
SELECT 'Ravi123', 'Sonu', 1, NULL, '2014-01-04 17:03:22.000' UNION ALL
SELECT 'Vineet123', 'Sonu', NULL, 1, '2014-01-04 17:26:01.000' UNION ALL
SELECT 'dev123', 'Ravi123', 1, NULL, '2014-01-05 19:35:16.000' UNION ALL
SELECT 'Mukesh123', 'Ravi123', NULL, 1, '2014-01-05 19:40:41.000' UNION ALL
SELECT 'poonam123', 'Vineet123', 1, NULL, '2014-01-05 19:49:49.000' UNION ALL
SELECT 'monu', 'Pawan kumar', 1, NULL, '2014-01-05 17:32:58.000' UNION ALL
SELECT 'Arti123', 'Pawan kumar', NULL, 1, '2014-01-05 19:54:35.000'
go
CREATE proc [dbo].[count_pairs]
@ParentID nvarchar(50)
as
begin
Declare @ParentSUM SMALLINT = 0
Declare @SubLeftID nvarchar(50)
Declare @SubRightID nvarchar(50)
SELECT @SubLeftID = CASE WHEN [IsLeft] = 1 THEN [ID] ELSE @SubLeftID END
,@SubRightID = CASE WHEN [IsRight] = 1 THEN [ID] ELSE @SubRightID END
FROM Associate_Income
WHERE ParentID = @ParentID
IF @SubLeftID IS NOT NULL AND @SubRightID IS NOT NULL AND EXISTS(SELECT 1 FROM Associate_Income WHERE [IsLeft] = 1 AND ParentID = @SubLeftID)
BEGIN
SET @ParentSUM = 1
;WITH Associate_Income_CTE AS
SELECT [ID], [ParentID], [IsLeft], [IsRight], 0 AS [Level]
FROM Associate_Income
WHERE [ParentID] = @ParentID
UNION ALL
SELECT RecursiveMember.[ID], RecursiveMember.[ParentID], RecursiveMember.[IsLeft], RecursiveMember.[IsRight], Level + 1
FROM Associate_Income RecursiveMember
INNER JOIN Associate_Income_CTE AnchorMember
ON RecursiveMember.[ParentID] = AnchorMember.[ID]
SELECT @ParentSUM = @ParentSUM + COUNT([ParentID])
FROM
SELECT [ParentID]
,'IsLeft' AS [Direction]
,1 AS [Value]
FROM Associate_Income
WHERE [IsLeft] = 1
AND [ID] <> @ParentID --AND [ID] NOT IN (@SubLeftID, @ParentID)
AND [ParentID] NOT IN (@ParentID, @SubLeftID)
UNION ALL
SELECT [ParentID]
,'IsRight' AS [Direction]
,1 AS [Value]
FROM Associate_Income
WHERE [IsRight] = 1
AND [ParentID] <> @ParentID
) AS Associate_Income
PIVOT
MAX([Value]) FOR [Direction] IN ([IsLeft], [IsRight])
) PVT
WHERE [IsLeft] IS NOT NULL AND [IsRight] IS NOT NULL
END
SELECT @ParentSUM
END
go
EXEC count_pairs 'Ramesh123'
go
DROP PROCEDURE count_pairs
DROP TABLE Associate_Income
Erland Sommarskog, SQL Server MVP, [email protected]

HT1349 In the recent version Itunes, I can't find the total number of songs status line in my song library window as before.

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From the View menu > Select "Show Status bar...'
http://osxdaily.com/2012/11/29/5-tips-make-itunes-look-normal/

How can I find the total number of songs in my iTunes library?

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There dosn't appear to be a method in CNiPlot.

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teststandhelp.com
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How do I print the total number of pages in report, like Page 1 of 5?

Hi
How do I print the total number of pages in report, like Page 1 of 5?
thanks,
kiran.M

Hi,
Check for the below code:
*Declare a variable
DATA L_PAGE_COUNT(5) TYPE C.
*Copy this code to the end of program
*Page count will be printed on each page here
WRITE SY-PAGNO TO L_PAGE_COUNT LEFT-JUSTIFIED.
DO SY-PAGNO TIMES.
READ LINE 1 OF PAGE SY-INDEX.
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MODIFY CURRENT LINE.
ENDDO.
TOP-OF-PAGE.
WRITE: /(70) 'Heading' CENTERED, 70 SY-PAGNO,'of ', '-----'.
You will find your solution in below thread with code:
Total Pages in Basic List
Rgds,
Shakuntala

How to find out the total, subtotal in alv report

hi dears,
how to find out the total, subtotal in alv report?
pls tell me logic ,
i will be waiting for eply
regards
eswar

Hi,
<b>ALV Grid List with sub-totals</b>
REPORT z_demo_alv_sort.
* This program lists orders (VBAK) with sort and sub-total for        *
* 'sold-to-party' (KUNNR) and 'Sales organization' (VKORG)            *
TABLES : vbak.
TYPE-POOLS: slis.                      " ALV Global types
SELECT-OPTIONS :
s_vkorg FOR vbak-vkorg,              " Sales organization
s_kunnr FOR vbak-kunnr,              " Sold-to party
s_vbeln FOR vbak-vbeln.              " Sales document
SELECTION-SCREEN :
SKIP, BEGIN OF LINE,COMMENT 5(27) v_1 FOR FIELD p_max.
PARAMETERS p_max(2) TYPE n DEFAULT '20' OBLIGATORY.
SELECTION-SCREEN END OF LINE.
DATA:
BEGIN OF gt_vbak OCCURS 0,
    vkorg LIKE vbak-vkorg,             " Sales organization
    kunnr LIKE vbak-kunnr,             " Sold-to party
    vbeln LIKE vbak-vbeln,             " Sales document
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END OF gt_vbak.
INITIALIZATION.
v_1 = 'Maximum of records to read'.
START-OF-SELECTION.
PERFORM f_read_data.
PERFORM f_display_data.
*      Form f_read_data
FORM f_read_data.
SELECT * INTO CORRESPONDING FIELDS OF TABLE gt_vbak
           FROM vbak
             UP TO p_max ROWS
          WHERE kunnr IN s_kunnr
            AND vbeln IN s_vbeln
            AND vkorg IN s_vkorg.
ENDFORM.                               " F_READ_DATA
*      Form f_display_data
FORM f_display_data.
DEFINE m_fieldcat.
    add 1 to ls_fieldcat-col_pos.
    ls_fieldcat-fieldname   = &1.
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    ls_fieldcat-cfieldname = &3.
    append ls_fieldcat to lt_fieldcat.
END-OF-DEFINITION.
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    ls_sort-fieldname = &1.
    ls_sort-up        = 'X'.
    ls_sort-subtot    = &2.
    append ls_sort to lt_sort.
END-OF-DEFINITION.
DATA:
    ls_fieldcat TYPE slis_fieldcat_alv,
    lt_fieldcat TYPE slis_t_fieldcat_alv,
    lt_sort     TYPE slis_t_sortinfo_alv,
    ls_sort     TYPE slis_sortinfo_alv,
    ls_layout   TYPE slis_layout_alv.
m_fieldcat 'VKORG' '' ''.
m_fieldcat 'KUNNR' '' ''.
m_fieldcat 'VBELN' '' ''.
m_fieldcat 'NETWR' 'X' 'WAERK'.
m_fieldcat 'WAERK' '' ''.
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m_sort 'KUNNR' 'X'.                  " Sort by kunnr and subtotal
m_sort 'VBELN' ''.                   " Sort by vbeln
ls_layout-cell_merge = 'X'.
CALL FUNCTION 'REUSE_ALV_GRID_DISPLAY'
       EXPORTING
            is_layout   = ls_layout
            it_fieldcat = lt_fieldcat
            it_sort     = lt_sort
       TABLES
            t_outtab    = gt_vbak.
ENDFORM.                               " F_DISPLAY_DATA
***************** END OF PROGRAM Z_DEMO_ALV_SORT **********************
Regards
Sudheer

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Is there any way we can display the total number of rows for the report.
Kindly help me.. Its very urgent requirement.
MAny Thank in advacne

Check this http://obiee100.blogspot.com/2011/07/display-total-number-of-records-in.html
and
http://docs.oracle.com/cd/E28280_01/bi.1111/e10544/appsql.htm#CHDCDIDA
You have to go something like as suggested in previous link.
Mark as correct/helpful

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i found the solution, thanks

Lost my ipod and cant report it stolen without serial number, where do I find the serial number without my ipod or the packaging it came in

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OT

Getting the total number of pages inside a report

Post Author: jportelas
CA Forum: .NET
Good afternoon:
How can I get the total number of pages inside a reportdocument object???
I'm currently using VS.NET 2005.
Thanks for the help.

There's no public API to get this info directly from RAS.
Option is to either walk through pages in the CrystalReportViewer till you get to the end, or use the non-public not-for-public use API:
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Sincerely,
Ted Ueda

Find the total number of saved reports in Disco 10g using Disco Admin tool

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