Finding the number of weeks or months in a Date range

I have a couple of text boxes that a user inputs a start date and an end date. What I want to know is there a way to tell the number of months or the the number of days in this date range?
For example:
Start Date = 02/12/2004
End Date = 03/12/2004
The number of weeks = 4 //May not be accurate, just showing an example.
The number of months = 2

For month, I would define it as the dates that fall in the actual calendar month. If my start date input from the user is 1/21/04, then I want to define a time period of 1/21/04 through 1/31/04 to be included in the first month. I know that it is not an actual month, but I am trying to make graphs based on monthly performance.
For weeks, I want the days to run Sunday through Saturday. If the first date starts on a Wednesday, then I want my first week to include days only Wednesday through Saturday.

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How to find the number of records per months in cube

Hi,
how to find the number of records per months for my all cubes?
Can i use the ListCube transaction to find totl number f records per cube monthwise ?
Jimmy

Hi,
Here is a program to generate no of records and list of ODS and Cubes in Active version.Schedule this program in background and create a cube to load this information and schedule to the data from the file generated by the program. Schedule this all per you requirement.
1.Copy the code into your Z<programname> from Se38.
2.change the FILENAME in CALL FUNCTION 'GUI_DOWNLOAD' in the program to the location from where you can pick the information to load data to cube(eg Application server).
3.Save program.
4.Schedule the program in background as required
5.Create cube with infoobjects to hold no of records and Infoprovider name
6.Load this cube based on event after the program job is done.
Hence you can report on this cube to see no of records in CUBE or ODS in your box.
Please find the code below.
Cheers,
Kavitha Kamesh.
types: begin of itabs ,
      tabname type dd02l-tabname,
      end of itabs.
data: itab type itabs occurs 0 with header line.
data: counter type i.
data: begin of itab1 occurs 0,
tabname type dd02l-tabname,
counter type i,
end of itab1.
DATA: ITABTABNAME TYPE STRING.
DATA: LENGTH TYPE I.
DATA: OBJECT(30).
data: str(6) type c.
select tabname from dd02l into table itab where ( tabname LIKE '/BIC/F%' or tabname LIKE '/BIC/A%00' )
and TABCLASS = 'TRANSP' and AS4LOCAL = 'A'.
loop at itab.
select count(*) from (itab-tabname) into counter.
str = itab-tabname.
if str = '/BIC/F'.
LENGTH = STRLEN( ITAB-TABNAME ).
SHIFT itab-tabname BY 6 PLACES LEFT.
ELSEIf str = '/BIC/A'.
SHIFT itab-tabname BY 6 PLACES LEFT.
LENGTH = STRLEN( ITAB-TABNAME ).
LENGTH = LENGTH - 2.
endif.
itab1-tabname = itab-tabname(LENGTH).
append itab1.
itab1-counter = counter.
clear itab-tabname.
clear: COUNTER.
endloop.
*********** itab1
loop at itab1.
write:/ itab1-tabname, itab1-counter.
endloop.
CALL FUNCTION 'GUI_DOWNLOAD'
EXPORTING
*   BIN_FILESIZE                    =
    FILENAME                        = 'c:records.xls'
    FILETYPE                        = 'ASC'
*   APPEND                          = ' '
    WRITE_FIELD_SEPARATOR           = ','
*   HEADER                          = '00'
*   TRUNC_TRAILING_BLANKS           = ' '
*   WRITE_LF                        = 'X'
*   COL_SELECT                      = ' '
*   COL_SELECT_MASK                 = ' '
*   DAT_MODE                        = ' '
*   CONFIRM_OVERWRITE               = ' '
*   NO_AUTH_CHECK                   = ' '
*   CODEPAGE                        = ' '
*   IGNORE_CERR                     = ABAP_TRUE
*   REPLACEMENT                     = '#'
*   WRITE_BOM                       = ' '
*   TRUNC_TRAILING_BLANKS_EOL       = 'X'
*   WK1_N_FORMAT                    = ' '
*   WK1_N_SIZE                      = ' '
*   WK1_T_FORMAT                    = ' '
*   WK1_T_SIZE                      = ' '
* IMPORTING
*   FILELENGTH                      =
TABLES
    DATA_TAB                        = itab1
*   FIELDNAMES                      =
* EXCEPTIONS
*   FILE_WRITE_ERROR                = 1
*   NO_BATCH                        = 2
*   GUI_REFUSE_FILETRANSFER         = 3
*   INVALID_TYPE                    = 4
*   NO_AUTHORITY                    = 5
*   UNKNOWN_ERROR                   = 6
*   HEADER_NOT_ALLOWED              = 7
*   SEPARATOR_NOT_ALLOWED           = 8
*   FILESIZE_NOT_ALLOWED            = 9
*   HEADER_TOO_LONG                 = 10
*   DP_ERROR_CREATE                 = 11
*   DP_ERROR_SEND                   = 12
*   DP_ERROR_WRITE                  = 13
*   UNKNOWN_DP_ERROR                = 14
*   ACCESS_DENIED                   = 15
*   DP_OUT_OF_MEMORY                = 16
*   DISK_FULL                       = 17
*   DP_TIMEOUT                      = 18
*   FILE_NOT_FOUND                  = 19
*   DATAPROVIDER_EXCEPTION          = 20
*   CONTROL_FLUSH_ERROR             = 21
*   OTHERS                          = 22
IF SY-SUBRC <> 0.
* MESSAGE ID SY-MSGID TYPE SY-MSGTY NUMBER SY-MSGNO
*         WITH SY-MSGV1 SY-MSGV2 SY-MSGV3 SY-MSGV4.
ENDIF.

Assign Month within a date range (by most days in a given month)

I have a begin and end date, sample data as such
select to_date('01-13-12','mm-dd-yy') from_dt,
to_date('02-23-12','mm-dd-yy') to_dt
from dual
union all
select to_date('03-15-2012','mm-dd-yy') from_dt,
to_date('04-16-2012','mm-dd-yy') to_dt
from dual
union all
select to_date('05-13-2012','mm-dd-yy') from_dt,
to_date('07-23-2012','mm-dd-yy') to_dt
from dual
How do I assign a month by the most days in a month within that date range? Sometimes the date range might have the exact same amount of days in a month (like 3/15/2012 has 16 days and 4/16/2012 has 16 days). In this case, I want the earlier month (march).
So from the sample data:
01/13/2012, 02/23/2012, February
03/15/2012, 04/16/2012, March
05/13/2012, 07/23/2012, June
Thanks
Edited by: user4422426 on Mar 1, 2012 5:15 PM

Hi,
Here's one way:
WITH     cntr          AS
     SELECT     LEVEL - 1     AS n
     FROM     (
               SELECT      1 + MAX (to_dt - from_dt)     AS max_day_cnt
               FROM     table_x
     CONNECT BY     LEVEL     <= max_day_cnt
,     got_r_num     AS
     SELECT     x.from_dt, x.to_dt
     ,     TRUNC (x.from_dt + c.n, 'MONTH')     AS month
     ,     count (*)                    AS cnt
     ,     ROW_NUMBER () OVER ( PARTITION BY from_dt, to_dt
                         ORDER BY        COUNT (*)     DESC
                         ,             TRUNC (x.from_dt + c.n, 'MONTH')
                       )     AS r_num
     FROM       cntr     c
     JOIN       table_x x ON c.n <= x.to_dt - x.from_dt
     GROUP BY x.from_dt, x.to_dt
     ,       TRUNC (x.from_dt + c.n, 'MONTH')
SELECT     from_dt, to_dt
,     TO_CHAR (month, 'Mon YYYY')     AS mon
,     cnt
FROM     got_r_num
WHERE     r_num     = 1
;Thanks for posting code to create the same data. Please test your code before you post it: you got the order of arguments to TO_DATE reversed.

Is it possible to change the number of weeks to be displayed in the month view in calendar (mavericks)?

I'd like to know if it's possible to change the number of weeks to be displayed in the month view in calendar? Thanks!

No.
There are up to six calendar weeks that might be used to display the 31 possible days in a month.
So the month view displays six weeks.

FM to find the number of fiscal weeks in a year

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Eric Cartman wrote:
Ámit Güjärgoüd wrote:
> > Eric,
> >
> > Did you actually enjoy 2004 ?
wasn't bad...
do you mean, there were 53 weeks in that year? because I have concern, how it is actually counted...
wasn't bad... :)
Thats sounds Sweet
do you mean, there were 53 weeks in that year?
Yes
because I have concern, how it is actually counted...
If in a leap year fabruary falls in 5 weeks then that is the only possibility for 53 weeks
Cheers
PS:But No logic would be applied in this case

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How do I find the start day of each month

Hi all,
Hope someone can give a a hand here I've to do a calender project for college and I'm not allowed to use any built in Java classes so fun all the way so far :-)
I've got one question that is bugging me at the moment. and that is how to find the start day for each month in a year and store them in an array.
I'm starting my week at Monday (0) and stopping at Sunday (6) and I do have a formula for discovering the first day in Jan of the given year its
((y-1900)*365 + (y-1901)/4)%7
I was just wondering how I could amend this to find the first day in Feb, March etc.
Any suggestions greatly accepted.
Thanks in advance.

Irish-Student wrote:
newark maybe I didnt make clear exactly what I want to do.
I have each day of the week starting at 0 for Monday up to 6 for Sunday I want to map what the start day of a month as a number between 0 and 6.
The formula I have discovering the first day of Jan of a given year will give you 1 i.e. Tuesday
what I need to do is find out what number between 0 and 6 the start day of each other month of a given year is.
For example the 1st of Feb is a Friday which is 4 on the weekday map.
Your suggestion of 31%7 won't work for this, sorry more than likely my fault for not being clearer in what my requirements were.
Cheers for the help so far and yep your right not being able to use the built in classes is a pain :-)
Edited by: Irish-Student on 03-Mar-2008 20:01This doesn't really change much of my first suggestion. If you can already calculate the first day of the month of January for any given year, then there's no problem figuring out the other months. Say I want to know the first day April 1, 1978. You already know how to find January 1, 1978. So find that. Then find the number of days between January 1 and April 1 (remember to account for leap years). Once you have the number of days, you can figure out how many weeks and days that is, and thus what day of the week it is.

How to find the number of ODBC connections to Oracle Database

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What Ed said is true that Oracle doesn't note which type of protocol is connecting to the database, however, you can see which program is accessing the database.
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How do you show the number of days per month?

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thanks..
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If you are young work to Learn, not to earn.
Solved!
Go to Solution.

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If I have helped you, why not giving me a kudos?

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Eric Steven Raymond
Rick Moen
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We've found by experience that people who are careless and sloppy writers are usually also careless and sloppy at thinking and coding (often enough to bet on, anyway). Answering questions for careless and sloppy thinkers is not rewarding; we'd rather spend our time elsewhere.
So expressing your question clearly and well is important. If you can't be bothered to do that, we can't be bothered to pay attention. Spend the extra effort to polish your language. It doesn't have to be stiff or formal ? in fact, hacker culture values informal, slangy and humorous language used with precision. But it has to be precise; there has to be some indication that you're thinking and paying attention.
Spell, punctuate, and capitalize correctly. Don't confuse "its" with "it's", "loose" with "lose", or "discrete" with "discreet". Don't TYPE IN ALL CAPS; this is read as shouting and considered rude. (All-smalls is only slightly less annoying, as it's difficult to read. Alan Cox can get away with it, but you can't.)
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Message was edited by:
Sudhindra Chandrashekar

Finding the number of weeks or months in a Date range

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