First and last frame disappearing off every clip

Hi,
Every clip I import in Final cut pro 6.0 loses its first and last frame.
The clips I import are in photoJpeg / 24p (verified with the -get info- of Quicktime Pro), but once in FCP they are marked as 23.98 ?!?!
In the browser the info of the clip says 23.98 and also indicates that the clip is 2 frames shorter.
When opened in the viewer the first and last frames are really missing.
It gets worse, when a clip is longer (ie: 500 frames), the first and last TWO frames are missing ?!?!
Am I alone with this problem?
Please help!!!

How are these clips getting created? Quicktime does not necessarily associate each frame with a certain TC, and the frame rate is dynamically calculated, rather than simply being hard-coded into the QT metadata. This results in Quicktimes that get created outside of FCP often showing up with different frame rates than you expect.
You might try exporting movies back out of FCP, ether from the master clips, or from sequences. I have noticed that when I export from a sequence at the correct frame rate, the missing frames come back. Other tools that might come in handy are Compressor for converting batches of files to QTs that FCP will like better, and Cinema Tools for conforming clips to a particular frame rate (like changing them from 24 to 23.98)
You might also try Dumpster which is a bare-bones utility that will allow you to view and edit the QT metadata directly.
Try some experiments and post back and let us know what you find out. I found that placing the clips in sequences at the proper frame rate and exporting new movie files worked well, but I have seen timing and frame rate shifts with some clips using this method...
Hope this helps -
Max Average

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Hello,
I am using Crystal Report XI.
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Adomacro,
you could do a function, like this
<cffunction name="getReportdates" returntype="struct"
hint="Given an arbitrary month and year, the function returns a
structure containing the first and last day of the previous
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<cfargument name="mnth" type="string" required="No"
default="#monthAsString(month(now()))#">
<cfargument name="yr" type="numeric" required="No"
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<cfset firstDayOfGivenMonth = parseDateTime("1 " &
arguments.mnth & " #arguments.yr#")>
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<cfset numberOfDaysOfPreviousMonth =
daysInMonth(lastDayOfPreviousMonth)>
<cfset firstDayOfPreviousMonth =
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<cfset reportDates = structNew()>
<cfset reportDates.firstDayOfPreviousMonth =
firstDayOfPreviousMonth>
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lastDayOfPreviousMonth>
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Given month: March
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Java 1.6.0_05 does not recognize first and last property in jnlp file

Hi
Has anybody else seen this?
The jnlp file contains five properties, but the JRE does not recognize the first nor the last property.
It has been working great since 1.4.2, through 1.5 and 1.6 until 1.6.0_05.
<property name='bog' value='%2fdata%2fkirkeboeger1892%2f'/>
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Pressing 's' in the console gives me this
Dump system properties ...
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file.encoding = Cp1252
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file.separator = \
http.auth.serializeRequests = true
https.protocols = TLSv1,SSLv3
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java.awt.printerjob = sun.awt.windows.WPrinterJob
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java.endorsed.dirs = C:\Program Files\Java\jre1.6.0_05\lib\endorsed
java.ext.dirs = C:\Program Files\Java\jre1.6.0_05\lib\ext;C:\Windows\Sun\Java\lib\ext
java.home = C:\Program Files\Java\jre1.6.0_05
java.io.tmpdir = C:\Users\MAJ-BR~1\AppData\Local\Temp\
java.library.path = C:\Program Files\Java\jre1.6.0_05\bin;.;C:\Windows\Sun\Java\bin;C:\Windows\system32;C:\Windows;C:\Program Files\Java\jre1.6.0_05\bin;C:\Program Files\Mozilla Firefox;C:\Windows\system32;C:\Windows;C:\Windows\System32\Wbem;"C:\Program Files\Java\jre1.6.0_05\bin"
java.protocol.handler.pkgs = com.sun.javaws.net.protocol|com.sun.deploy.net.protocol
java.runtime.name = Java(TM) SE Runtime Environment
java.runtime.version = 1.6.0_05-b13
java.security.policy = file:C:\Program Files\Java\jre1.6.0_05\lib\security\javaws.policy
java.specification.name = Java Platform API Specification
java.specification.vendor = Sun Microsystems Inc.
java.specification.version = 1.6
java.vendor = Sun Microsystems Inc.
java.vendor.url = http://java.sun.com/
java.vendor.url.bug = http://java.sun.com/cgi-bin/bugreport.cgi
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java.vm.info = mixed mode, sharing
java.vm.name = Java HotSpot(TM) Client VM
java.vm.specification.name = Java Virtual Machine Specification
java.vm.specification.vendor = Sun Microsystems Inc.
java.vm.specification.version = 1.0
java.vm.vendor = Sun Microsystems Inc.
java.vm.version = 10.0-b19
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javawebstart.version = javaws-1.6.0_05
jnlpx.heapsize = 64m,128m
jnlpx.home = C:\Program Files\Java\jre1.6.0_05\bin
jnlpx.jvm = "C:\Program Files\Java\jre1.6.0_05\bin\javaw.exe"
jnlpx.remove = false
jnlpx.splashport = 49557
line.separator = \r\n
opslag = aa001/AB/007/0000a-A.Jpg,aa001/AB/007/0002a-F.Jpg,...
os.arch = x86
os.name = Windows Vista
os.version = 6.0
path.separator = ;
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sessionId = ed0l5n55yu2h04alvqxdpbn3
sun.arch.data.model = 32
sun.boot.class.path = C:\Program Files\Java\jre1.6.0_05\lib\resources.jar;C:\Program Files\Java\jre1.6.0_05\lib\rt.jar;C:\Program Files\Java\jre1.6.0_05\lib\sunrsasign.jar;C:\Program Files\Java\jre1.6.0_05\lib\jsse.jar;C:\Program Files\Java\jre1.6.0_05\lib\jce.jar;C:\Program Files\Java\jre1.6.0_05\lib\charsets.jar;C:\Program Files\Java\jre1.6.0_05\classes;C:\Program Files\Java\jre1.6.0_05\lib\javaws.jar;C:\Program Files\Java\jre1.6.0_05\lib\deploy.jar
sun.boot.library.path = C:\Program Files\Java\jre1.6.0_05\bin
sun.cpu.endian = little
sun.cpu.isalist = pentium_pro+mmx pentium_pro pentium+mmx pentium i486 i386 i86
sun.desktop = windows
sun.io.unicode.encoding = UnicodeLittle
sun.java.launcher = SUN_STANDARD
sun.jnu.encoding = Cp1252
sun.management.compiler = HotSpot Client Compiler
sun.os.patch.level =
trustProxy = true
user.country = DK
user.dir = C:\Users\Maj-Britt\Documents
user.home = C:\Users\Maj-Britt
user.language = da
user.name = Maj-Britt
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We also have this problem, but it's not first and last property.
We have 6 properties, and the 3. property is gone.
If I download the jnlp file, the property is there, if I choose show jnlp file in "javaws -viewer" it's not there. Only difference between this property and the working properties is length.
The length is char 255, and the data is base64 encoded.
I worked fine before upgrading to Java 6 update 5.
Anyone any ideas?

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First and Last Word on Page

Hi,
I am trying to create a document that is similar to a dictionary or an index of information.
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I have this problem too but movies and music delete a couple days later. I can watch half a movie one day and the next it disappears. I can also load music and listen to it all one day then they disappear in front of my eyes the next. these have all bern downloaded from the cloud on wifi at home.

SQL (first and last record)

Hi All,
WITH t AS
SELECT 100 region_id, 1001 Client_Id, 'client 1' Client_Name, 1 Status_id, 'progress' Status_name, SYSDATE + 1 Start_Date, SYSDATE + 1 End_Date FROM dual UNION ALL
SELECT 100 region_id, 1001 Client_Id, 'client 1' Client_Name, 2 Status_id, 'hold' Status_name ,SYSDATE + 1 Start_Date, SYSDATE + 1 End_Datet FROM dual UNION ALL
SELECT 100 region_id, 1001 Client_Id, 'client 1' Client_Name, 3 Status_id ,'reject' Status_name, SYSDATE + 1 Start_Date, SYSDATE + 1 End_Date FROM dual UNION ALL
SELECT 200 region_id, 1002 Client_Id, 'client 2' Client_Name, 1 Status_id, 'progress' Status_name, SYSDATE + 1 Start_Date, SYSDATE + 1 End_Date FROM dual UNION ALL
SELECT 200 region_id, 1002 Client_Id, 'client 2' Client_Name, 2 Status_id, 'hold' Status_name ,SYSDATE + 1 Start_Date, SYSDATE + 1 End_Datet FROM dual UNION ALL
SELECT 200 region_id, 1002 Client_Id, 'client 2' Client_Name, 3 Status_id ,'reject' Status_name, SYSDATE + 1 Start_Date, SYSDATE + 1 End_Date FROM dual UNION ALL
SELECT 200 region_id, 1002 Client_Id, 'client 2' Client_Name, 3 Status_id ,'progress' Status_name, SYSDATE + 1 Start_Date, SYSDATE + 1 End_Date FROM dual
SELECT * FROM t;Desired output:
REGION_ID     CLIENT_ID     CLIENT_NAME     STATUS_ID     STATUS_NAME     START_DATE                    END_DATE
100     1001     client 1                      1                     progress                     9/3/2011 12:26               9/3/2011 12:26
100     1001     client 1                      3                     reject                     9/3/2011 12:26                     9/3/2011 12:26
200     1002     client 2                      1                     progress                     9/3/2011 12:26                     9/3/2011 12:26thanks,

Hi,
Like Sven, I don't understand why you only want one output row for client_id=1002. Also, I don't understand what order determine "first" and "last". It's hard to guess because so many of the columns have the same value on every row.
My best guess is that status_id plays a part in deciding who is "first" and "last", and that you don't want to include ties (multiple rows with a equal claim to being "first" or "last") in the output.
WITH     got_analytics     AS
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     ,     ROW_NUMBER () OVER ( PARTITION BY region_id
                         ,             client_id
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                         ORDER BY        end_date
                         ,             start_date
                         ,             status_id
                        )     AS a_num
     ,     ROW_NUMBER () OVER ( PARTITION BY region_id
                         ,             client_id
                         ,             client_name
                         ORDER BY        end_date     DESC
                         ,             start_date     DESC
                         ,             status_id     DESC
                        )     AS d_num
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                         ,             client_id
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                         ,             start_date
                         ,             status_id
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SELECT       region_id, client_id, client_name, status_id, start_date, end_date
FROM       got_analytics
WHERE       (     a_num     = 1
       OR     d_num     = 1
AND       cnt     = 1
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HT202058 iphone 6+ somehow has switched my name on emails into my nephew's name. We share a first and last name but not a middle name. For example, my name might be John George Doe and his name John James Doe. How did this happen? How do I correct it.

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So if the solution recommended by Ralph is not working then the other option is this:
Please make sure that the emails work correctly when signed into, on a computer
Then delete the account off your phone - you will not lose the emails
Reset the phone
Re add the account back in and see if that helps the issue
Thanks

How do I bulk edit contact's nicknames to first and last names?

i imported contacts to the contacts app and they all say "NoName".
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ohh and i used both of the following applescripts and nothing happened:
tell application "Address Book"
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ANDDDDDD
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davide gislon wrote:
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Hope this is helpful.
Cheers,
Davide
Edited by: davide gislon on 08-Jan-2009 07:19Your query does nothing you say it does. TO_DATE('&year','YYYY') returns first day of the current month for year &year. And the only reason it returns January 1, &year is that we are currently in January:
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2 /
Enter value for year: 2005
old   1: select TO_DATE('&year','YYYY') from dual
new   1: select TO_DATE('2005','YYYY') from dual
TO_DATE('
01-JAN-05
SQL> As soon as we roll into February:
SQL> alter system set fixed_date = '2009-2-1' scope=memory
2 /
System altered.
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2 /
SYSDATE
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2 /
Enter value for year: 2005
old   1: select TO_DATE('&year','YYYY') from dual
new   1: select TO_DATE('2005','YYYY') from dual
TO_DATE('
01-FEB-05
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2 /
System altered.
SQL> select sysdate from dual
2 /
SYSDATE
08-JAN-09
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SQL> ALTER SESSION SET NLS_TERRITORY=GERMANY -- enforce Monday as first day of the week
2 /
Session altered.
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6 WHEN '5' THEN TO_DATE('0101&&year','MMDDYYYY')+((&&week-1)*7+3)
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8 WHEN '7' THEN TO_DATE('0101&&year','MMDDYYYY')+((&&week-1)*7+1)
9 END BEGIN_FISICAL_WEEK
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11 /
BEGIN_FI
04.01.10
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2 /
TRUNC(TO
28.12.09
SQL> 2 user10772980:
Use:
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SQL> SY.

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Hi Try this,
Whileprintingrecords;
if ={?EmpID} then
Also check the option "Default values for null" in the formula editor.
Regards,
Vinay

Get First and last day of Month..

Hi Friends,
I am trying to fetch First and Last day of a month and would like to implement that in the following code:
SELECT COALESCE(Date_A, Date_B, Date_C)
FROM dual
Here Date A and B are in Format of MM DD YYYY (March 14, 2008)
and Date C is like MM YYYY (March 2008)
How can I get the Date_C as March 1, 2008 OR March 31, 2008 format if Date A and B are NULL ?
Thanks!
Edited by: user11095386 on Apr 23, 2009 10:45 AM

Hi,
In my earlier message, I thought that you were starting with strings like '03 12 2009' and that you wanted to display them as 'March 12 2009'. If what you have is just the reverse, then just reverse the format strings in my first message. Add a comma, if you want one, in the appropriate format string.
I believe this is what you want:
COALESCE ( TO_CHAR ( TO_DATE ( Date_A, 'fmMonth DD YYYY'), 'MM DD YYYY')
         , TO_CHAR ( TO_DATE ( Date_B, 'fmMonth DD YYYY'), 'MM DD YYYY')
         , TO_CHAR ( TO_DATE ( Date_C, 'fmMonth YYYY'),    'MM DD YYYY')
         )Notice how, on the 3rd line, TO_DATE is called without DD in the format string:
TO_DATE ( Date_C, 'fmMonth YYYY')When you do this, the day defaults to the 1st of the month, so this is all you have to do to convert the VARCHAR2 'March 2009' to the DATE 01-Mar-2009.
If you want the last day of the month, not the first, when Date_C is chosen, then use LAST_DAY:
COALESCE ( TO_CHAR ( TO_DATE ( Date_A, 'fmMonth DD YYYY'), 'MM DD YYYY')
         , TO_CHAR ( TO_DATE ( Date_B, 'fmMonth DD YYYY'), 'MM DD YYYY')
         , TO_CHAR ( LAST_DAY ( TO_DATE ( Date_C
                                          , 'fmMonth YYYY'
             , 'MM DD YYYY'
         )

Getting first and last day of week

Dear all .
Is there any funcion module which gives first and last day of the current week .
Eg . todays day is 15.11.2006
start date of week : 13.11.2006
end date of week : 19.11.2006
in the same way I want how many days are there in month .
Eg : for Nov month :
         30 days .
      for dec month 31 days .
Thank you in advance

Use FM GET_WEEK_INFO_BASED_ON_DATE
Import parameters               Value
DATE                            15.11.2006
                                                                                Export parameters               Value
WEEK                            200646
MONDAY                          13.11.2006
SUNDAY                          19.11.2006
Use FM HR_E_NUM_OF_DAYS_OF_MONTH
Import parameters               Value
P_FECHA                         15.11.2006
Export parameters               Value
NUMBER_OF_DAYS                    30
I hope it helps.
Best Regards,
Vibha
*Please mark all the helpful answers

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