First day of year and next monday of the year

Dear all;
Given a year, how do you determine the very first day of that year and the next two mondays for that year...

Hi,
user13328581 wrote:
Dear all;
Given a year, how do you determine the very first day of that year and the next two mondays for that year...As Sayan hinted, you can use NEXT_DAY to find the next Monday after (not the same as) a given date.
NEXT_DAY(trunc(SYSDATE), 'MON') next_mondayis the next Monday after today. (You may not need TRUNC in the example above.)
For the Monday after January 1 of this year:
NEXT_DAY ( TRUNC (SYSDATE, 'YEAR')
, 'Monday'
)If the year happens to begin on a Monday, this will return Jaunary 8, the 2nd Monday of the year; otherwise, it will be the 1st Monday of the year.
For the 2nd Monday after New Year's Day, add 7 to the expression above.

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Hi ,
I hAVE TABLE FOR EXAMPLE,
emp sal Arrivaldate
111 200 03-mar-2011
100 200 03-mar-2008
150 200 06-mar-2012
170 200 03-mar-2003
178 200 03-mar-2004
112 200 12-jun-2012-------------------->For Example THIS IS TABLE WE HAVE LOT OF RECORDS
I need querry to get based on this condition:Arrival Date is between Previous Year First Day Same Month And Current day.
Any one help me on this.....

Hi,
To get the records between Previous Year First Day Same month to Current day..
SELECT TRUNC (ADD_MONTHS (SYSDATE, -12), 'MM') AS last_yr_first_date, TRUNC(SYSDATE) AS PRESENT_DATE
FROM DUAL;Which Outputs to:
LAST_YR_FIRST_DATE     PRESENT_DATE
6/1/2011                   6/13/2012When you give TRUNC(sysdate) It will removes the Time part of the SYSDATE.
For Ex :
TRUNC(SYSDATE) means that is 6/13/2012 which doesn't give the time part in the query.
Which takes into account the day start that is from 12:00 A.M to today midnight 11.59 P.M.
And, One thing is that
emp sal Arrivaldate
111 200 03-mar-2011
100 200 03-mar-2008
150 200 06-mar-2012
170 200 03-mar-2003
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112 200 12-jun-2012The arrivaldate is in Character format so you need to convert to date type as
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Hi All,
i want to get first day of the given year based on 12-month financial year.
i'e if i entered '21-Sep-2014' as a given date then expected output is '01-Oct-2013'
Could you please suggest best way to get this done.
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Dan thanks for your reply.
am adding more description below to my post:
The thing is for a given date i needs to find out
Year Start Date , Year
End Date.
For this am using below scripts respectively
SELECT DATEADD(yy, DATEDIFF(yy, 0, GETDATE()), 0);
SELECT DATEADD(DD, -1 ,DATEADD(yy, DATEDIFF(yy, 0, GETDATE()) + 1, 0));
Here , the problem is , now its giving the current year first day and Last day.
But what i want is Year first day should be based on (minus 12 month) i'e '01-OCT-2013'
and Year End Day should be '30-SEP-2014'
i hope now the requirement is more clear.
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Try like this
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Function TODATE. Distinct first day of year

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Hi Kelvin,
There's an in-built SQL function to do this.
Function Name: TRUNC
SQL> SELECT TRUNC(TO_DATE('17-DEC-2001'),'YEAR') "First Day" FROM Dual;
First Day
01-JAN-01
SQL> SELECT TRUNC(SysDate,'YEAR') "First Day" FROM Dual;
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http://otn.oracle.com/docs/products/oracle9i/doc_library/901_doc/server.901/a90125/functions152.htm#79763
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I have a table
create table eresults
(student_name varchar2(20),
section_name varchar2(4),
exam_id NUMBER (4))
marks NUMBER (3))
Begin
insert into eresults values ('MOEED', 'A', 1, 20);
insert into eresults values ('SARAH', 'A', 1, 30);
insert into eresults values ('SAM', 'A', 1, 24);
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I hope I've been able to clear my requiment.
I will appreciate the shortest and simplest possible query to achieve since I've a large data and then I also need to take average of first 50% sum marks divided by 50% of the exams.
Thanks in advance.
regards
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Edited by: Hamza on May 25, 2011 12:46 AM

TRy this
/* Formatted on 2011/05/24 16:23 (Formatter Plus v4.8.8) */
SELECT student_name, section_name, marks,
       SUM (marks) OVER (PARTITION BY student_name, section_name) sum_marks,
       CASE
          WHEN exam_id = 1
             THEN   marks
                  +   LEAD (marks, 1, 0) OVER (PARTITION BY student_name, section_name ORDER BY exam_id)
                    / 2
          WHEN exam_id = max_id_exam
             THEN   marks
                  +   LAG (marks, 1, 0) OVER (PARTITION BY student_name, section_name ORDER BY exam_id)
                    / 2
          ELSE marks
       END res
FROM (SELECT student_name, section_name, exam_id, marks,
               MAX (exam_id) OVER (PARTITION BY student_name, section_name)
                                                                  max_id_exam
          FROM eresults)
STUDENT_NAME         SECT      MARKS SUM_MARKS        RES
MOEED                A            20        119       52.5
MOEED                A            65        119         65
MOEED                A            34        119       66.5
SAM                  A            24        167         26
SAM                  A             4        167          4
SAM                  A            40        167         40
SAM                  A            99        167        119
SARAH                A            30        173         80
SARAH                A           100        173        100
SARAH                A            10        173         10
SARAH                A            33        173         38
11 rows selected.Edited by: Salim Chelabi on 2011-05-24 13:23

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case i_vnam.
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clear : e_t_range,
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DATA DAT(8)TYPE D.
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IS THERE A DICREPENCY IN THE CODE?
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PLZ LET ME KNOW.
THANK U ALL

Hi,
my mail bounced back. send vaild mail id.
try this.
1) create one customer exit variable say zcuvar
2) create a USER entry variable Keydate 0date.
3) in CMOD, in I_STEP = 1 of zcuvar, make it default value ad 01/01/2006 as you have done.
4) in use as range in Selection restrict.
zcuvar;0date.
hope i m clear.
regards,
San!

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Bill
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First day of year and next monday of the year

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