Float precision

If I had a float that was equal to 0.30289307, how can I truncate it to be 0.3?
Thanks
Jay

i figured it out, the way you give your float, the program thinks it's a double, so he gives an error "possible loss of precision", now the solution is to put an f after your number so java will be forced to treat it as a float
like this:
import java.text.DecimalFormat;
public class Test
     public static void main(String a[])
          float number = 0.30289307f;
          DecimalFormat df = new DecimalFormat("0.0");
          System.out.println(df.format(number));
}

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