Folder icon in a hierarchical tree
Hello, I don't know how can I put a folder icon in a hierarchical tree.
I have this query, and I know I have to change the 4th column, but I don't know how to do it.
SELECT -1,level,d_carpeta, null, id_carpeta
FROM DOCUMENTUM.doc_carpetas
START WITH id_carpeta_padre is null
CONNECT BY id_carpeta_padre = prior id_carpeta
and in the trigger (WHEN-TREE-NODE-SELECTED) I have this code
declare
htree ITEM;
n_selected NUMBER;
current_node FTREE.NODE;
begin
htree := Find_Item('blk_arbol_detalle.arb_carpetas');
n_selected := Ftree.Get_Tree_Property(htree, Ftree.SELECTION_COUNT);
FOR j IN 1..n_selected LOOP
current_node := Ftree.Get_Tree_Selection(htree, j);
if Ftree.Get_Tree_Node_Property(htree,
:SYSTEM.TRIGGER_NODE,Ftree.NODE_DEPTH) > 0 then
:blk_detalle.id_carpeta := Ftree.Get_Tree_Node_Property(htree,
:SYSTEM.TRIGGER_NODE, Ftree.NODE_VALUE);
else
:blk_detalle.id_carpeta := null;
end if;
END LOOP;
end;
Jesús,
just give it the name of an icon without the '.ico' extension. If you run it on the Web then the icon must be available in a gif format. Just the name nothing else. Make sure that in c/s the icon is in a directory mapped by the UI_ICON variable in of the Window Registry. For configuring icons on teh Web, have a look at this paper
http://otn.oracle.com/products/forms/pdf/webicons.pdf
If you need different folder icons on different tree levels, then instead of using a query, use a record group to populate the tree.
Frank
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If someone's answer is helpful or correct please mark it accordingly! -
I'm using Forms 6i and need to use Hierarchial trees. I've never worked on tree items. I have somehow populated data to the tree but my problem now is i'm not able to display a folder icon for the nodes. I would be very grateful if someone could explain me from the basics, of how to show a folder icon in the nodes, also the icon should be different when a node is expanded ie. folder to be opened when node expanded and closed when node collapsed.
Anitha,
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DECLARE
htree ITEM;
current_node FTREE.NODE;
find_node FTREE.NODE;
BEGIN
-- Find the tree itself.
htree := FIND_ITEM('tree_block.htree3');
-- Change the icon of the clicked node. The icon name
-- is "Open"
FTREE.SET_TREE_NODE_PROPERTY(htree, :SYSTEM.TRIGGER_NODE, Ftree.NODE_ICON, 'Open');
If you running in client/server, the icons need to be in the directory specified by the UI_ICONS registry variable. On the Web the icons must be in a gif format and in the same directory or archive you use for the iconic buttons
see: http://otn.oracle.com/products/forms/pdf/webicons.pdf
Frank
Frank
END; -
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Hierarchical Tree Node icon ?
Hi
How to create a icon on Hierarchical tree
Regards
ShahzaibThanks for your reply and i am sorry for not clear my developer version
My developer version is 6I
Database express addition
Well i write the trigger when tree node activate
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:system.trigger_node,
ftree.node_value);
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current_node FTREE.NODE;
find_node FTREE.NODE;
BEGIN
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find_node := :SYSTEM.TRIGGER_NODE;
ftree.set_tree_node_property(htree, find_node, ftree.NODE_ICON, 'D:\ico\Ico\favorite.ico');
END;
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declare
al_button number;
pl_id ParamList;
v_emp_id number;
e_child_rec exception;
pragma exception_init(e_child_rec, -02292);
len number := 3; --variable which tells till what length from last not to copy from first string
begin
v_emp_id := ftree.get_tree_node_property(find_item('Block28.tree8'),
:system.trigger_node,
ftree.node_value);
SET_BLOCK_PROPERTY('block3', DEFAULT_WHERE, 'acc_id = ''' || V_emp_id|| '''');
go_block('block3');
EXECUTE_QUERY;
exception
when e_child_rec then
Message ('Go Kimi Go');
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Regards
Shahzaib ismail -
Can Tree's folder icon node changed to different icon?
Hi,
Currently, the tree and tree table node's icon is a "folder" icon. Can this be customized to different icons? We would like to have different icons for the nodes for different level in the tree/tree table. For example, level 1's node is icon A; level 2's node is icon B, etc...
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-MinaHi,
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level1 af|tree...{}
level2 af|tree...{}
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Frank -
Make an hierarchical Tree in oracle Forms 6i
Hi everybody,
I want to make an hierarchical tree. I work in Forms 6i
I create one non database block e.g. 'Bloc2' then
add hierarchical control item in that. e.g 'Menu'.
I create a record group named 'RG_DATA_TEST'
Before I use a table in this record_group.
I want a tree as this :
- Menu1
Menu1 option1
Menu1 option2
- Menu1 option3
Menu option3 Sub opt 3
+ Menu2
the table 'Menu_tree' is described' :
CREATE TABLE MENU_tree
ID NUMBER(5),
LABEL VARCHAR2(128 BYTE),
ICON VARCHAR2(40 BYTE),
MASTER NUMBER(5),
STATUS NUMBER(1) DEFAULT 1,
VALUE VARCHAR2(128 BYTE)
Here the data in the table :
INSERT INTO MENU_tree ( ID, LABEL, ICON, MASTER, STATUS, VALUE ) VALUES (1, 'Menu1', 'mainmenu', NULL, 1, NULL);
INSERT INTO MENU_tree ( ID, LABEL, ICON, MASTER, STATUS, VALUE ) VALUES (
2, 'Menu1 Option 1', 'optionmenu', 1, 1, 'Dialog11');
INSERT INTO MENU_tree ( ID, LABEL, ICON, MASTER, STATUS, VALUE ) VALUES ( 3, 'Menu1 Option 2', 'optionmenu', 1, 1, dialog12');
INSERT INTO MENU_tree ( ID, LABEL, ICON, MASTER, STATUS, VALUE ) VALUES (4, 'Menu1 Option 3', 'optionmenu', 1, 1, NULL);
INSERT INTO MENU_tree ( ID, LABEL, ICON, MASTER, STATUS, VALUE ) VALUES ( 5, 'Menu1 Opt 3 Sub Opt 3', 'suboptionmenu', 4, 1, 'Dialog131');
INSERT INTO MENU_tree ( ID, LABEL, ICON, MASTER, STATUS, VALUE ) VALUES ( 6, 'Menu2', 'mainmenu', NULL, -1, NULL);
INSERT INTO MENU_tree ( ID, LABEL, ICON, MASTER, STATUS, VALUE ) VALUES ( 7, 'Menu2 Option1', 'optionmenu', 6, 1,'Dialog21');
The record_group use this instruction SELECT :
SELECT STATUS, LEVEL, LABEL, ICON, VALUE
FROM MENU_tree
CONNECT BY PRIOR ID = MASTER
START WITH MASTER IS NULL
And At the trigger When_new_form_instance , i do this code :
DECLARE
htree ITEM;
V_IGNORE number;
BEGIN
HTREE := FIND_ITEM('BLOC2.MENU');
V_IGNORE := POPULATE_GROUP('RG_DATA_TEST');
FTREE.POPULATE_TREE(htree);
END;
When i run the forms, It don't give me a structure of node.
It give me only a icon with two arrows.
Where is the problem ?
Must I add code somewhere ?
Help me for your ideas.
Regards.
Edited by: 794982 on 17 sept. 2010 04:55
Edited by: 794982 on 17 sept. 2010 05:01
Edited by: 794982 on 17 sept. 2010 05:04
Edited by: 794982 on 17 sept. 2010 05:06
Edited by: 794982 on 17 sept. 2010 05:13
Edited by: 794982 on 17 sept. 2010 05:19
Edited by: 794982 on 17 sept. 2010 05:23Ok Francois Thanks for your response.
Just I pricise i work with oracle forms version 9.0.4.0.19 .
But I am putting this code in trigger When_New_form_Instance but it didn't work.
When I execute it just shows a line with two arrows but not a real tree.
Then I do a block-non based and a elemnt with type hierarticall tree and a canevas.
and i create a record_group. and in a palette property of the element i precise the canevas and the record_group
I don't khnow where is the problem ?
Any other suggestion ? please
Regards. -
Hierarchical Tree not showing using a record group to populate
Hi, I am trying to set up an hierarchical tree. Can someone please give me the exact steps I need to take to get this right.
I am trying to create a hierarchical tree to behave like a menu on a Main form from where I will call the other forms of my application.
I have done the following
select 1, level, null, form_name, form_name
from iso_forms
connect by prior form_name=action
start with action is null
and get this when I run the statement in pl/sql
1 LEVEL NULL FORM_NAME FORM_NAME
1 1 Edit Edit
1 2 Holder Holder
1 2 Isotopes Isotopes
1 2 Laboratories Laboratories
1 2 Personal Personal
1 2 Incident Incident
1 2 Equipment Equipment
1 2 Over Exposure Over Exposure
1 2 Archive Archive
1 1 Print Print
1 1 Queries Queries
My tree on my main form is still blank, I have checked that the tree is the only item in the block but I am not sure how to confirm that it is a control block. I created the tree in layout editor by clicking on the Hierarchical Tree icon on the left and then dragging out a block, so I am assuming that the block is of the correct type.
Thank you for your assistance
Michaela control block is one not based on a table/view/procedure . check the block's query data source name. its must be blank.
I suggest you create a procedure where you create the record_group using
CREATE_GROUP_FROM_QUERY,populate_group and ftree.set_tree_property
Here is my code that I i used to populate my tree .it works:
PROCEDURE populate_the_tree IS
grp recordgroup;
error_number number;
grpname varchar2(20) :='rg_group';
tree_id item :=find_item('ctrl.tree');
grp_qry2 varchar2(500) :='select -1,level,ename,null,empno from emp start with mgr is null connect by prior empno=mgr';
begin
grp := find_group(grpname);
if not id_null(grp)
then delete_group(grp);
end if;
-- grp := create_group_from_query(grpname,grp_qry1||grp_qry2);
grp := create_group_from_query(grpname,grp_qry2);
error_number:=populate_group(grpname);
if error_number <> 0
then message('Error while populating tree');
raise form_trigger_failure;
end if;
ftree.set_tree_property(tree_id,ftree.record_group,grp);
END;
Message was edited by:
lewismak2000 -
I would like to Know concept of Hierarchical Tree of forms 6i. What query should be written in the record group to populate the tree and how to implement hierarchical tree to make the form act like Windows Explorer .
Thank You.Read the documentation. Here is a sample query to load the record group.
PROCEDURE prc_populate_record_group
IS
CURSOR g IS
SELECT groupnum,
groupnm
FROM merch_group
ORDER BY groupnm;
CURSOR c (l_groupnum NUMBER) IS
SELECT categorynum,
categorynm
FROM merch_group_category
WHERE groupnum = l_groupnum
ORDER BY categorynm;
i NUMBER;
l_rg_id RECORDGROUP;
l_init_state GROUPCOLUMN;
l_level GROUPCOLUMN;
l_label GROUPCOLUMN;
l_icon GROUPCOLUMN;
l_value GROUPCOLUMN;
l_node ftree.node;
l_next_node ftree.node;
l_tree_item ITEM;
BEGIN
l_rg_id := FIND_GROUP('PRC_GROUP_CAT');
IF NOT ID_NULL(l_rg_id)
THEN
DELETE_GROUP(l_rg_id);
END IF;
l_rg_id := CREATE_GROUP('PRC_GROUP_CAT');
l_init_state := ADD_GROUP_COLUMN(l_rg_id, 'init_state', NUMBER_COLUMN);
l_level := ADD_GROUP_COLUMN(l_rg_id, 'level', NUMBER_COLUMN);
l_label := ADD_GROUP_COLUMN(l_rg_id, 'label', CHAR_COLUMN, 40);
l_icon := ADD_GROUP_COLUMN(l_rg_id, 'icon', CHAR_COLUMN, 20);
l_value := ADD_GROUP_COLUMN(l_rg_id, 'value', CHAR_COLUMN, 40);
i := 1;
FOR g_rec IN g
LOOP
ADD_GROUP_ROW (l_rg_id, i);
SET_GROUP_NUMBER_CELL(l_init_state, i, -1);
SET_GROUP_NUMBER_CELL(l_level, i, 1);
SET_GROUP_CHAR_CELL(l_label, i, g_rec.groupnm| |' - '| |g_rec.groupnum);
SET_GROUP_CHAR_CELL(l_icon, i, NULL);
SET_GROUP_CHAR_CELL(l_value, i, g_rec.groupnum);
i := i + 1;
FOR c_rec IN c (g_rec.groupnum)
LOOP
ADD_GROUP_ROW (l_rg_id, i);
SET_GROUP_NUMBER_CELL(l_init_state, i, -1);
SET_GROUP_NUMBER_CELL(l_level, i, 3);
SET_GROUP_CHAR_CELL(l_label, i, c_rec.categorynm| |' - '| |c_rec.categorynum);
SET_GROUP_CHAR_CELL(l_icon, i, NULL);
SET_GROUP_CHAR_CELL(l_value, i, c_rec.categorynum);
i := i + 1;
END LOOP;
END LOOP;
--Find the tree
l_tree_item := find_item('CONTROL.TREE4');
-- Assign record group to item causing the data to display
ftree.set_tree_property(l_tree_item, ftree.record_group, l_rg_id);
-- Find the root node of the tree
l_node := ftree.find_tree_node(l_tree_item, '');
END;
null -
How do we create Hierarchical tree??
Can I get help on creating hirerchical tree with detailed description ?? I tried basing hierarchical item on query but it didn't work.Do i need to specifically give code for populating it ??
Also I need help on basing it on Record Group ??
Is there any rule for having specific no of columns for a tree ??You can create Hierarchical Tree in two ways.
One using "connect by prior" and another
by Adding columns and row to record group at run time.
If your table has Self reference Key then
you can create using connect by prior.
Otherwise you have to go for second one.
Go and check the navwiz.fmb in oracle demo files.
Following example is from navwiz.fmb
(open navwiz.pll and then check refresh_tree)
In this example they used both.For Emp they used connect by prior.
PROCEDURE refresh_trees(p_view VARCHAR2) IS
cursor cursor_dept is
select dname, deptno
from dept
order by dname;
cursor cursor_emp(p_dno number) is
select ename, empno
from emp
where deptno = p_dno
order by ename;
v_i number;
v_ignore number;
rg_emps recordgroup;
rg_depts recordgroup;
v_init_state groupcolumn;
v_level groupcolumn;
v_label groupcolumn;
v_icon groupcolumn;
v_value groupcolumn;
begin
if p_view = 'EMP' then
--the emps hierarchy
rg_emps := find_group('EMPS');
if not id_null(rg_emps) then
delete_group(rg_emps);
end if;
rg_emps := create_group_from_query('EMPS',
'select 1, level, ename, NULL, to_char(empno) ' | |
'from emp ' | |
'connect by prior empno = mgr ' | |
'start with mgr IS NULL');
v_ignore := populate_group(rg_emps);
ftree.set_tree_property('navigator.nav_display', ftree.record_group, rg_emps);
else
--the organization
rg_depts := find_group('DEPTS');
if not id_null(rg_depts) then
delete_group(rg_depts);
end if;
rg_depts := create_group('DEPTS');
v_init_state := add_group_column(rg_depts, 'init_state', number_column);
v_level := add_group_column(rg_depts, 'level', number_column);
v_label := add_group_column(rg_depts, 'label', char_column, 40);
v_icon := add_group_column(rg_depts, 'icon', char_column, 20);
v_value := add_group_column(rg_depts, 'value', char_column, 5);
v_i := 1;
for deptrec in cursor_dept loop
add_group_row(rg_depts, v_i);
set_group_number_cell(v_init_state, v_i, 1);
set_group_number_cell(v_level , v_i, 1);
set_group_char_cell (v_label , v_i, deptrec.dname);
set_group_char_cell (v_icon , v_i, NULL);
set_group_char_cell (v_value , v_i, to_char(deptrec.deptno));
v_i := v_i + 1;
for emprec in cursor_emp(deptrec.deptno) loop
add_group_row(rg_depts, v_i);
set_group_number_cell(v_init_state, v_i, 1);
set_group_number_cell(v_level , v_i, 2);
set_group_char_cell (v_label , v_i, emprec.ename);
set_group_char_cell (v_icon , v_i, NULL);
set_group_char_cell (v_value , v_i, to_char(emprec.empno));
v_i := v_i + 1;
end loop;
end loop;
ftree.set_tree_property('navigator.nav_display', ftree.record_group, rg_depts);
end if;
My query******
procedure refresh1 is
v_i number;
v_ignore number;
Rg_Menus recordgroup;
rg_depts recordgroup;
Begin
Rg_Menus := find_group('MENUS');
If not id_null(Rg_Menus) then
delete_group(Rg_Menus);
End If;
Rg_Menus := create_group_from_query('MENUS',
'select 1, level, item_name, NULL, item_id ' | |
'from Item_all '
| |' where Item_id in (select Item_id from Item_access_all where role_id in
(select role_id from org_access_all where user_id =
(select gsp_user_id from users_all where upper(user_name) = upper(USER))
and code = :global.code) )
and item_id not in (select item_id from item_Exception where Code = :Global.Code)' | |
'connect by prior item_name = main_name ' | |
'start with item_name = ''MAIN''');
v_ignore := populate_group(Rg_Menus);
ftree.set_tree_property('tree_blk.tree_menu', ftree.record_group,Rg_Menus);
Exception
When Others then
Bell;
Message('You cannot Access any menu item...');
Raise Form_trigger_Failure;
End;
viji.
null -
Hi,
This is the first thread am posting. I searched ur discussions for "How to show the hierarchical tree in forms 10g with different colours and in different fonts weigth for different nodes". But i found nothing.
Hopefully looking forward for your replies.You should use a less specific search string if you don't find anything first time but in this case it won't have helped you.
You can set an icon for each node in the tree, which might be an acceptable alternative to writing lots of java.
The icon can be set as a property
http://www.oracle.com/webapps/online-help/forms/10g/topics/f1_help/builts/set_tree_node_property_built_in.html?tp=true
or it can be built into the select statement that creates the tree (if your tree is query-driven).
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Folders and documents on desktop
when i was in 10.3.9 the items on my desk top were neatly lined up in two columns on the right of my desk top with the icons in the columns about 4 cms apart. moving to 10.4 has made them about 8 cms apart. how can i get them close together again? an
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Color Finesse 3 & Premier CS6 ?
Hello i have Production Premium CS6 on my Win 7 x64, i am still new to editing, just learning, but what i noticed is that i have in my AE - Color Finesse 3, but for now AE is too complicated for me and i dont like working in AE as when i import my
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I cant add mp4 to my Imovie Help to convert mp4 to mp3 ot update imovie
I am having a big head ache trying to add an music song to my IMOVIE I have an older song on there that was an mp3 but all of teh new songs on my I tunes are locked in to mp4 I want to add these songs to the slide show for my Fiancee Thanks Kazoo