Hierarchical Tree Icon Alignment

Hi
I am able to create and display a hierarchical tree with icons in the nodes okay. The default is that the icon is placed at the left of the node (like a folder icon on windows explorer). Is there any option to display icon at right side of node? I am unable to find any such option, but wish to confirm or seek other ideas.
Thanks

I think there is no option to display the icon in right side of the node. Even i tried to display only the icon without node label. And big icon (more then 16*16 pixel) with minimum of node label. If I succeed above two options then I might make an icon and label as a single image (even left icon right label or left label and right icon) and show it for a node.
So by default for hierarchical tree icon will be displayed left side with Dimensions: 16 (height) * 16 (width) pixels.
Regards
Balaji.M

Similar Messages

Hierarchical Tree not showing using a record group to populate

Hi, I am trying to set up an hierarchical tree. Can someone please give me the exact steps I need to take to get this right.
I am trying to create a hierarchical tree to behave like a menu on a Main form from where I will call the other forms of my application.
I have done the following
select 1, level, null, form_name, form_name
from iso_forms
connect by prior form_name=action
start with action is null
and get this when I run the statement in pl/sql
1 LEVEL NULL FORM_NAME FORM_NAME
1 1 Edit Edit
1 2 Holder Holder
1 2 Isotopes Isotopes
1 2 Laboratories Laboratories
1 2 Personal Personal
1 2 Incident Incident
1 2 Equipment Equipment
1 2 Over Exposure Over Exposure
1 2 Archive Archive
1 1 Print Print
1 1 Queries Queries
My tree on my main form is still blank, I have checked that the tree is the only item in the block but I am not sure how to confirm that it is a control block. I created the tree in layout editor by clicking on the Hierarchical Tree icon on the left and then dragging out a block, so I am assuming that the block is of the correct type.
Thank you for your assistance
Michael

a control block is one not based on a table/view/procedure . check the block's query data source name. its must be blank.
I suggest you create a procedure where you create the record_group using
CREATE_GROUP_FROM_QUERY,populate_group and ftree.set_tree_property
Here is my code that I i used to populate my tree .it works:
PROCEDURE populate_the_tree IS
grp recordgroup;
error_number number;
grpname varchar2(20) :='rg_group';
tree_id item :=find_item('ctrl.tree');
grp_qry2 varchar2(500) :='select -1,level,ename,null,empno from emp start with mgr is null connect by prior empno=mgr';
begin
     grp := find_group(grpname);
     if not id_null(grp)
          then delete_group(grp);
     end if;
--     grp := create_group_from_query(grpname,grp_qry1||grp_qry2);
     grp := create_group_from_query(grpname,grp_qry2);
     error_number:=populate_group(grpname);
     if error_number <> 0
          then message('Error while populating tree');
          raise form_trigger_failure;
     end if;
     ftree.set_tree_property(tree_id,ftree.record_group,grp);
END;
Message was edited by:
lewismak2000

Can i have a check box in the hierarchical tree in the icons place, urgent!!! please

Hi,
I'am working on the Hierarchical Tree structure which should have three levels, I need to have a check box in the place of the icon & if i select a node that node & the child nodes should get selected.
After this when i say move selected ( i'am trying to use picklist class also) the entire checked tree has to move to the display area to the right & should display as tree structure & after this if i save then the checked records which are moved to another text area should get saved!!
How to achieve this? I have the tree structure ready but the check box part is the worrying factor! & then moving the checked records to the right using picklist class is the second problem & finally saving records to database.
Any help in this regard will be deeply appreciated:)
If check box is not possible then i will have to look at other methods, will the tree structure allow checkboxes????
Thanks
Mahesh

No the tree will not allow checkboxes

Hierarchical tree with iconic nodes

hi i'm using database - 10g, developer suite - 10g; created a hierarchical tree and the icons are displaying along side the nodes when they are being selected or activated.
problem - i've stored the icons in g:\ICONS (all gif icons). but when i run the form it is picking up the icons from the following location - C:\Documents and Settings\development\Oracle Jar Cache\frmall_jinit.jar-63ace618-1160d49b\oracle\forms\icons. I've a button in the same form and the icon showing on it is from the location G:\ICONS(as desired); but in case of tree it's from the location which is not desirable.
any help.

Hello,
You need to change the imagebase parameter to be documentbase instead of codebase.
When imagebase is set to codebase forms looks for Images in the jar files and then in the absolute path, otherwise it check direct path.
For details in deploying the Images please check:
http://docs.oracle.com/cd/B14099_19/web.1012/b14032/configure009.htm
Clear the Java cache and browser cache after the above changes!
Regards,
Alex
If someone's answer is helpful or correct please mark it accordingly!

Folder icon in a hierarchical tree

Hello, I don't know how can I put a folder icon in a hierarchical tree.
I have this query, and I know I have to change the 4th column, but I don't know how to do it.
SELECT -1,level,d_carpeta, null, id_carpeta
FROM DOCUMENTUM.doc_carpetas
START WITH id_carpeta_padre is null
CONNECT BY id_carpeta_padre = prior id_carpeta
and in the trigger (WHEN-TREE-NODE-SELECTED) I have this code
declare
htree ITEM;
n_selected NUMBER;
current_node FTREE.NODE;
begin
htree := Find_Item('blk_arbol_detalle.arb_carpetas');
n_selected := Ftree.Get_Tree_Property(htree, Ftree.SELECTION_COUNT);
FOR j IN 1..n_selected LOOP
current_node := Ftree.Get_Tree_Selection(htree, j);
if Ftree.Get_Tree_Node_Property(htree,
:SYSTEM.TRIGGER_NODE,Ftree.NODE_DEPTH) > 0 then
:blk_detalle.id_carpeta := Ftree.Get_Tree_Node_Property(htree,
:SYSTEM.TRIGGER_NODE, Ftree.NODE_VALUE);
else
:blk_detalle.id_carpeta := null;
end if;
END LOOP;
end;

Jesús,
just give it the name of an icon without the '.ico' extension. If you run it on the Web then the icon must be available in a gif format. Just the name nothing else. Make sure that in c/s the icon is in a directory mapped by the UI_ICON variable in of the Window Registry. For configuring icons on teh Web, have a look at this paper
http://otn.oracle.com/products/forms/pdf/webicons.pdf
If you need different folder icons on different tree levels, then instead of using a query, use a record group to populate the tree.
Frank

Hierarchical Tree Node icon ?

Hi
How to create a icon on Hierarchical tree
Regards
Shahzaib

Thanks for your reply and i am sorry for not clear my developer version
My developer version is 6I
Database express addition
Well i write the trigger when tree node activate
:parameter.current_emp := ftree.get_tree_node_property(find_item('Block28.Tree8'),
                                                      :system.trigger_node,
                                                      ftree.node_value);
DECLARE
htree         ITEM;
current_node FTREE.NODE;
find_node     FTREE.NODE;
BEGIN
htree := Find_Item('block28.tree8');
find_node := :SYSTEM.TRIGGER_NODE;
ftree.set_tree_node_property(htree, find_node, ftree.NODE_ICON, 'D:\ico\Ico\favorite.ico');
END;
Ftree.SET_tree_NODE_PROPERTY(htree, :SYSTEM.TRIGGER_NODE, Ftree.NODE_ICON, 'print');And also when mouse double click
declare
al_button number;
     pl_id ParamList;
     v_emp_id     number;
     e_child_rec exception;
     pragma exception_init(e_child_rec, -02292);
     len number := 3; --variable which tells till what length from last not to copy from first string
begin
     v_emp_id := ftree.get_tree_node_property(find_item('Block28.tree8'),
                                                         :system.trigger_node,
                                                            ftree.node_value);
SET_BLOCK_PROPERTY('block3', DEFAULT_WHERE, 'acc_id = ''' || V_emp_id|| '''');
go_block('block3');
EXECUTE_QUERY;
exception
     when e_child_rec then
          Message ('Go Kimi Go');
end;
Now when i double click the mouse its show tree icon
I want when i run my module its show me all node icon
Hope this time i clear my question
Regards
Shahzaib ismail

Make an hierarchical Tree in oracle Forms 6i

Hi everybody,
I want to make an hierarchical tree. I work in Forms 6i
I create one non database block e.g. 'Bloc2' then
add hierarchical control item in that. e.g 'Menu'.
I create a record group named 'RG_DATA_TEST'
Before I use a table in this record_group.
I want a tree as this :
- Menu1
Menu1 option1
Menu1 option2
- Menu1 option3
Menu option3 Sub opt 3
+ Menu2
the table 'Menu_tree' is described' :
CREATE TABLE MENU_tree
ID NUMBER(5),
LABEL VARCHAR2(128 BYTE),
ICON VARCHAR2(40 BYTE),
MASTER NUMBER(5),
STATUS NUMBER(1) DEFAULT 1,
VALUE VARCHAR2(128 BYTE)
Here the data in the table :
INSERT INTO MENU_tree ( ID, LABEL, ICON, MASTER, STATUS, VALUE ) VALUES (1, 'Menu1', 'mainmenu', NULL, 1, NULL);
INSERT INTO MENU_tree ( ID, LABEL, ICON, MASTER, STATUS, VALUE ) VALUES (
2, 'Menu1 Option 1', 'optionmenu', 1, 1, 'Dialog11');
INSERT INTO MENU_tree ( ID, LABEL, ICON, MASTER, STATUS, VALUE ) VALUES ( 3, 'Menu1 Option 2', 'optionmenu', 1, 1, dialog12');
INSERT INTO MENU_tree ( ID, LABEL, ICON, MASTER, STATUS, VALUE ) VALUES (4, 'Menu1 Option 3', 'optionmenu', 1, 1, NULL);
INSERT INTO MENU_tree ( ID, LABEL, ICON, MASTER, STATUS, VALUE ) VALUES ( 5, 'Menu1 Opt 3 Sub Opt 3', 'suboptionmenu', 4, 1, 'Dialog131');
INSERT INTO MENU_tree ( ID, LABEL, ICON, MASTER, STATUS, VALUE ) VALUES ( 6, 'Menu2', 'mainmenu', NULL, -1, NULL);
INSERT INTO MENU_tree ( ID, LABEL, ICON, MASTER, STATUS, VALUE ) VALUES ( 7, 'Menu2 Option1', 'optionmenu', 6, 1,'Dialog21');
The record_group use this instruction SELECT :
SELECT STATUS, LEVEL, LABEL, ICON, VALUE
FROM MENU_tree
CONNECT BY PRIOR ID = MASTER
START WITH MASTER IS NULL
And At the trigger When_new_form_instance , i do this code :
DECLARE
htree ITEM;
V_IGNORE number;
BEGIN
HTREE := FIND_ITEM('BLOC2.MENU');
V_IGNORE := POPULATE_GROUP('RG_DATA_TEST');
FTREE.POPULATE_TREE(htree);
END;
When i run the forms, It don't give me a structure of node.
It give me only a icon with two arrows.
Where is the problem ?
Must I add code somewhere ?
Help me for your ideas.
Regards.
Edited by: 794982 on 17 sept. 2010 04:55
Edited by: 794982 on 17 sept. 2010 05:01
Edited by: 794982 on 17 sept. 2010 05:04
Edited by: 794982 on 17 sept. 2010 05:06
Edited by: 794982 on 17 sept. 2010 05:13
Edited by: 794982 on 17 sept. 2010 05:19
Edited by: 794982 on 17 sept. 2010 05:23

Ok Francois Thanks for your response.
Just I pricise i work with oracle forms version 9.0.4.0.19 .
But I am putting this code in trigger When_New_form_Instance but it didn't work.
When I execute it just shows a line with two arrows but not a real tree.
Then I do a block-non based and a elemnt with type hierarticall tree and a canevas.
and i create a record_group. and in a palette property of the element i precise the canevas and the record_group
I don't khnow where is the problem ?
Any other suggestion ? please
Regards.

Forms 6 hierarchical Tree

I would like to Know concept of Hierarchical Tree of forms 6i. What query should be written in the record group to populate the tree and how to implement hierarchical tree to make the form act like Windows Explorer .
Thank You.

Read the documentation. Here is a sample query to load the record group.
PROCEDURE prc_populate_record_group
IS
CURSOR g IS
SELECT groupnum,
groupnm
FROM merch_group
ORDER BY groupnm;
CURSOR c (l_groupnum NUMBER) IS
SELECT categorynum,
categorynm
FROM merch_group_category
WHERE groupnum = l_groupnum
ORDER BY categorynm;
i NUMBER;
l_rg_id RECORDGROUP;
l_init_state GROUPCOLUMN;
l_level GROUPCOLUMN;
l_label GROUPCOLUMN;
l_icon GROUPCOLUMN;
l_value GROUPCOLUMN;
l_node ftree.node;
l_next_node ftree.node;
l_tree_item ITEM;
BEGIN
l_rg_id := FIND_GROUP('PRC_GROUP_CAT');
IF NOT ID_NULL(l_rg_id)
THEN
DELETE_GROUP(l_rg_id);
END IF;
l_rg_id := CREATE_GROUP('PRC_GROUP_CAT');
l_init_state := ADD_GROUP_COLUMN(l_rg_id, 'init_state', NUMBER_COLUMN);
l_level := ADD_GROUP_COLUMN(l_rg_id, 'level', NUMBER_COLUMN);
l_label := ADD_GROUP_COLUMN(l_rg_id, 'label', CHAR_COLUMN, 40);
l_icon := ADD_GROUP_COLUMN(l_rg_id, 'icon', CHAR_COLUMN, 20);
l_value := ADD_GROUP_COLUMN(l_rg_id, 'value', CHAR_COLUMN, 40);
i := 1;
FOR g_rec IN g
LOOP
ADD_GROUP_ROW (l_rg_id, i);
SET_GROUP_NUMBER_CELL(l_init_state, i, -1);
SET_GROUP_NUMBER_CELL(l_level, i, 1);
SET_GROUP_CHAR_CELL(l_label, i, g_rec.groupnm| |' - '| |g_rec.groupnum);
SET_GROUP_CHAR_CELL(l_icon, i, NULL);
SET_GROUP_CHAR_CELL(l_value, i, g_rec.groupnum);
i := i + 1;
FOR c_rec IN c (g_rec.groupnum)
LOOP
ADD_GROUP_ROW (l_rg_id, i);
SET_GROUP_NUMBER_CELL(l_init_state, i, -1);
SET_GROUP_NUMBER_CELL(l_level, i, 3);
SET_GROUP_CHAR_CELL(l_label, i, c_rec.categorynm| |' - '| |c_rec.categorynum);
SET_GROUP_CHAR_CELL(l_icon, i, NULL);
SET_GROUP_CHAR_CELL(l_value, i, c_rec.categorynum);
i := i + 1;
END LOOP;
END LOOP;
--Find the tree
l_tree_item := find_item('CONTROL.TREE4');
-- Assign record group to item causing the data to display
ftree.set_tree_property(l_tree_item, ftree.record_group, l_rg_id);
-- Find the root node of the tree
l_node := ftree.find_tree_node(l_tree_item, '');
END;
null

How do we create Hierarchical tree??

Can I get help on creating hirerchical tree with detailed description ?? I tried basing hierarchical item on query but it didn't work.Do i need to specifically give code for populating it ??
Also I need help on basing it on Record Group ??
Is there any rule for having specific no of columns for a tree ??

You can create Hierarchical Tree in two ways.
One using "connect by prior" and another
by Adding columns and row to record group at run time.
If your table has Self reference Key then
you can create using connect by prior.
Otherwise you have to go for second one.
Go and check the navwiz.fmb in oracle demo files.
Following example is from navwiz.fmb
(open navwiz.pll and then check refresh_tree)
In this example they used both.For Emp they used connect by prior.
PROCEDURE refresh_trees(p_view VARCHAR2) IS
cursor cursor_dept is
select dname, deptno
from dept
order by dname;
cursor cursor_emp(p_dno number) is
select ename, empno
from emp
where deptno = p_dno
order by ename;
v_i number;
v_ignore number;
rg_emps recordgroup;
rg_depts recordgroup;
v_init_state groupcolumn;
v_level groupcolumn;
v_label groupcolumn;
v_icon groupcolumn;
v_value groupcolumn;
begin
if p_view = 'EMP' then
--the emps hierarchy
rg_emps := find_group('EMPS');
if not id_null(rg_emps) then
delete_group(rg_emps);
end if;
rg_emps := create_group_from_query('EMPS',
'select 1, level, ename, NULL, to_char(empno) ' | |
'from emp ' | |
'connect by prior empno = mgr ' | |
'start with mgr IS NULL');
v_ignore := populate_group(rg_emps);
ftree.set_tree_property('navigator.nav_display', ftree.record_group, rg_emps);
else
--the organization
rg_depts := find_group('DEPTS');
if not id_null(rg_depts) then
delete_group(rg_depts);
end if;
rg_depts := create_group('DEPTS');
v_init_state := add_group_column(rg_depts, 'init_state', number_column);
v_level := add_group_column(rg_depts, 'level', number_column);
v_label := add_group_column(rg_depts, 'label', char_column, 40);
v_icon := add_group_column(rg_depts, 'icon', char_column, 20);
v_value := add_group_column(rg_depts, 'value', char_column, 5);
v_i := 1;
for deptrec in cursor_dept loop
add_group_row(rg_depts, v_i);
set_group_number_cell(v_init_state, v_i, 1);
set_group_number_cell(v_level , v_i, 1);
set_group_char_cell (v_label , v_i, deptrec.dname);
set_group_char_cell (v_icon , v_i, NULL);
set_group_char_cell (v_value , v_i, to_char(deptrec.deptno));
v_i := v_i + 1;
for emprec in cursor_emp(deptrec.deptno) loop
add_group_row(rg_depts, v_i);
set_group_number_cell(v_init_state, v_i, 1);
set_group_number_cell(v_level , v_i, 2);
set_group_char_cell (v_label , v_i, emprec.ename);
set_group_char_cell (v_icon , v_i, NULL);
set_group_char_cell (v_value , v_i, to_char(emprec.empno));
v_i := v_i + 1;
end loop;
end loop;
ftree.set_tree_property('navigator.nav_display', ftree.record_group, rg_depts);
end if;
My query******
procedure refresh1 is
v_i number;
v_ignore number;
Rg_Menus recordgroup;
rg_depts recordgroup;
Begin
Rg_Menus := find_group('MENUS');
If not id_null(Rg_Menus) then
delete_group(Rg_Menus);
End If;
Rg_Menus := create_group_from_query('MENUS',
'select 1, level, item_name, NULL, item_id ' | |
'from Item_all '
| |' where Item_id in (select Item_id from Item_access_all where role_id in
(select role_id from org_access_all where user_id =
(select gsp_user_id from users_all where upper(user_name) = upper(USER))
and code = :global.code) )
and item_id not in (select item_id from item_Exception where Code = :Global.Code)' | |
'connect by prior item_name = main_name ' | |
'start with item_name = ''MAIN''');
v_ignore := populate_group(Rg_Menus);
ftree.set_tree_property('tree_blk.tree_menu', ftree.record_group,Rg_Menus);
Exception
When Others then
Bell;
Message('You cannot Access any menu item...');
Raise Form_trigger_Failure;
End;
viji.
null

Colourful Hierarchical Tree

Hi,
This is the first thread am posting. I searched ur discussions for "How to show the hierarchical tree in forms 10g with different colours and in different fonts weigth for different nodes". But i found nothing.
Hopefully looking forward for your replies.

You should use a less specific search string if you don't find anything first time but in this case it won't have helped you.
You can set an icon for each node in the tree, which might be an acceptable alternative to writing lots of java.
The icon can be set as a property
http://www.oracle.com/webapps/online-help/forms/10g/topics/f1_help/builts/set_tree_node_property_built_in.html?tp=true
or it can be built into the select statement that creates the tree (if your tree is query-driven).

Hierarchical Tree Node Attributes

Hi,
I know that Oracle' official answer to this is no, but is there a way to specify attributes for specific nodes in a hierarchical tree? I would like to display specific nodes in bold and specific nodes in a different color.
Any idea welcomed.
Monica

If this were possible then you would have to use the FTree package and probably the FTree.Set_Tree_Node_Property procedure, so check those in the help system. But I'm 99.99% sure you'd be wasting your time.
You might be able to do it with a JTree in a bean (it looks like it's not possible to extend an htree item in a pjc) but in forms the best you can do is assign icons to the nodes.

How to go to a particular node in a hierarchical tree?

I want to do this simple thing with a Forms hierarchical tree.
Since tree has lots of levels and branches I want to give a search box.
User types the label and press a button. The form then has to query the tree node and expand ONLY the path where the node is (if found) and highlight it. If a node with a label is NOT found I give an error message to the user.
I got hold of a code segment to explode a tree and modified it, but it does not work. The entire tree is expanded and you don't know where you are.
Any help will be greatly appreciated?
PROCEDURE Expand_All_Nodes_in_Tree IS
     node ftree.node;
     htree ITEM;
     state varchar2(30);
BEGIN
     -- Search the tree identifiant --
     htree := Find_Item('menu.tree');
     -- Search the root --
     node := Ftree.Find_Tree_Node(htree, '');
     -- Expand all nodes --
     WHILE NOT Ftree.ID_NULL(node) LOOP
     state := Ftree.Get_Tree_Node_Property(htree, node, Ftree.NODE_STATE);
     IF state = Ftree.COLLAPSED_NODE THEN
     Ftree.Set_Tree_Node_Property(htree, node, Ftree.NODE_STATE, Ftree.EXPANDED_NODE);
     END IF;
     node := Ftree.Find_Tree_Node(htree, '', ftree.find_NEXT,Ftree.NODE_LABEL,'', node);
IF Ftree.Get_Tree_Node_Property(htree, node, Ftree.NODE_LABEL) = :ctrl.node_lable_to_search THEN
EXIT;
END IF;
     END LOOP;
END;

Hi Channa,
Try this code with you tree i am using the same situation and this code is working perfect with me.
PROCEDURE find_node_in_tree(search_string varchar2, find_type varchar2) IS
htree ITEM;
search_start_node ftree.node;
find_node ftree.node;
BEGIN
htree := Find_Item('blk_tree.main_tree');
     search_start_node := nvl(ftree.get_tree_selection(htree,1),ftree.root_node);
     find_node := ftree.find_tree_node(htree,upper(search_string)||'%',ftree.find_next,ftree.node_label,ftree.root_node,search_start_node-1);
     if find_node = 0 then
          find_node := 1;
end if;
Ftree.Set_Tree_selection(htree, find_node, Ftree.SELECT_ON);
exception
     when others then
          NULL;
END;
-Ammad

URGENT *** Hierarchical Tree in Forms 9i *** URGENT

Hello everybody,
for my company I need to build a hierarchical tree item, that will display static data over three levels. Let's say: departments, employees and employee projects.
How do I fill the Item?
When do I fill the Item?
Where do I fill the Item?
What are the elements of the SQL query, that fills the hierarchical tree?
Any help will be appreciated
[email protected]

Note:210663.1 helped a bit.
I used the database column as the third element in the select part and put NULL as the fifth element. Then it worked.
Now I am looking for the way to add the employees, when the user selects / activates a department node.

Hierarchical Tree error - fighting for over a year

For over a year now, our Oracle forms have presented an elusive problem with Hierarchical Trees. First some core information:
We are running Developer 6i, patchset 8, on a Sun host and an Oracle 8i database. Our forms are deployed over the web on the
Oracle Application Server using J-Initiator 1.1.7.27.
Now, only on our Production platform, and only during busy times of the day, we randomly get the error "Invalid Query for Hierarchical
Tree" when one of our tree-based forms populates the tree. This error is sometimes followed by the infamous
FRM-92100 "connection has been terminated" error. This happens whether building the tree with a single Selec and Populate Treet,
or via a systematic series of Add Tree Node calls.
We have tried rebuilding the form logic to eliminate form corruption, (form corruption - happens if you open a large FMB in the
forms developer without first being connected to the database, manifests itself as random and odd form behaviour,
or FRM-92100 errors, Oracle product support denies it really happens), we have added debug code, we've even tried generating
the FMX on the Production platform as part of our deployment (normally we generate FMX files on our Integration platform
which mirrors Production).
We are not scheduled to upgrade for Forms 9i and the 9IAS for several more months, so upgrading isn't an immediate option for us.
Any and all ideas welcome.
Jeff Cline

Hi Nigel,
Two questions:
1. When the publisher sends the access permission to the subcriber by:
netStream.send("|RtmpSampleAccess", true, true)
, on the subscriber side, what event or function can handle the guaranteed receipt of the access permission? Currently it is possible to draw the incoming stream video upon receiving NetStream.Play.Star and waiting for 5 seconds or so:
public class MyWebcamSubscriber extends WebcamSubscriber {
override protected function layoutCameraStreams():void
// trying the event listener seems to work here.
_streamManager.addEventListener(NetStatusEvent.NET_STATUS, onNetStatus);
override protected function onNetStatus(e:NetStatusEvent):void
super.onNetStatus(e);
case "NetStream.Play.Start":
setTimeout(function():void {
// draw the video from the incoming stream here.
}, 5000);
The questions is, which event can let the subscriber know that it has the access permission to the video stream?
2. In WebcamPublisher, why is that the access permission is sent 3 times?
a. Once on receiving NetStream.Connect.Success with 0.5 second delay, as in below.
b. Once immediately upon receiving NetStream.Connect.Success, as in below.
protected function onNetStatus(p_evt:NetStatusEvent):void
if (p_evt.info.code=="NetStream.Connect.Success") {
setTimeout(sendSnapShotPermission, 500);
_stream.send("|RtmpSampleAccess", true, true);
protected function sendSnapShotPermission():void
_stream.send("|RtmpSampleAccess", true, true);
c. Once in onConnectionTypeChange() with 2 seconds delay:
protected function onConnectionTypeChange(p_evt:StreamEvent):void
if ( _streamManager.isP2P) {
_stream= new NetStream(_connectSession.sessionInternals.session_internal::connection as NetConnection,NetStream.DIRECT_CONNECTIONS);
setTimeout(sendSnapShotPermission, 2000);

It's possible to make Hierarchical Tree from multiple tables ?

the famous example for Hierarchical Tree is about employee_id and manager_id field in employees table ............ so I was wondering it's possible to make[b] Hierarchical Tree from multiple tables ? and How ??
if the answer associate with example that will be so kind of you :D
and thanks in advance.

HI
use curose in when new form instance or procedure then u can got data more then one table like that
DECLARE
htree ITEM;
top_node FTREE.NODE;
new_node FTREE.NODE ;
child_node ftree.node ;
item_value VARCHAR2(30);
cursor prime_cur is select main_desc mgr_name, main_code dept
from pur_item_group_mst;
cursor child_cur(v_dept number) is select sub_desc,sub_code
from pur_item_group_dtl where main_code = v_dept ;
BEGIN
htree := Find_Item('tmp.tree4');
for dummy in prime_cur loop
new_node := Ftree.Add_Tree_Node(htree,
ftree.root_node,
Ftree.PARENT_OFFSET,
Ftree.LAST_CHILD,
Ftree.EXPANDED_NODE,
dummy.mgr_name,
'D:\ORYX_POLYBAGS\accept',
dummy.dept);
for child in child_cur(dummy.dept) loop
child_node := Ftree.Add_Tree_Node(htree,
new_node,
Ftree.PARENT_OFFSET,
Ftree.LAST_CHILD,
Ftree.EXPANDED_NODE,
child.sub_desc||' '||'('||child.sub_code||' '||')',
'D:\ORYX_POLYBAGS\next',
child.sub_code);
end loop;
end loop;
END;
Rizwan Shafiq
www.rizwanshafiq.blogspot.com

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