ForLoop Square Root Calculator Program

* Programmer:      R McBride
* Date:           November 29, 2006
* Filename:     SquareRootForLoop.java
* Purpose:          This program uses for()loops to
*                    find the square root of a number
*                    up to four decimal places long.
import APCS.Keyboard;
class SquareRootForLoopTest1
     public static void main (String[]args)
          //define variables
          double SquareRoot = 0; //holds initial value
          double num1 = 0;
          boolean done = false;
          double tempReg1 = 0; //holds initial value of i
          double tempReg2 = 0; //holds
          double tempReg3 = 0;
          //while loop start
//          while (!done)
          //program input
          System.out.println("\t\t\tSQUARE ROOT CALCULATOR PROGRAM");
          System.out.println(""); //skip line
          System.out.println("Enter the number you would like to be square rooted or [0] to end the program.");
          System.out.print("");
          SquareRoot = Keyboard.readInt();
          System.out.println(""); //skip line
          System.out.println("You entered "+SquareRoot+".");
          System.out.println(""); //skip line
          //for loop function
          for(int i = 0; i < 999999; i++)
          tempReg1 = i * i;
          tempReg2 = i;
//          while (!done)
                    if(tempReg1 == SquareRoot)
                         System.out.println("The square root is "+tempReg2);
                         System.out.println("");
                    else
                         System.out.print("");
          //while loop check to finish
//          if(SquareRoot == 0)
//               done = true;
//          }//end while loop
}Here is my code for and of you who ever wants to use it. Our assignment was to make a square root calculator using ForLoop (a.k.a. no square root functions).
My question is, how would I make it increase by .0001 instead of 1 every loop? I need it to do that so I can find square roots of numbers of numbers that have decimals for squares.

* Programmer:      R McBride
* Date:           November 29, 2006
* Filename:     SquareRootForLoop.java
* Purpose:          This program uses for()loops to
*                    find the square root of a number
*                    up to four decimal places long.
import APCS.Keyboard;
class SquareRootForLoopTest1
     public static void main (String[]args)
          //define variables
          double SquareRoot = 0; //holds initial value
          double num1 = 0;
          boolean done = false;
          double tempReg1 = 0; //holds initial value of i
          double tempReg2 = 0; //holds
          double tempReg3 = 0;
          //while loop start
//          while (!done)
          //program input
          System.out.println("\t\t\tSQUARE ROOT CALCULATOR PROGRAM");
          System.out.println(""); //skip line
          System.out.println("Enter the number you would like to be square rooted or [0] to end the program.");
          System.out.print("");
          SquareRoot = Keyboard.readInt();
          System.out.println(""); //skip line
          System.out.println("You entered "+SquareRoot+".");
          System.out.println(""); //skip line
          //for loop function
          for(double i = 0; i < 999999; i+=.0001)
          tempReg1 = i * i;
          tempReg2 = i;
//          while (!done)
                    if(tempReg1 == SquareRoot)
                         System.out.println("The square root is "+tempReg2);
                         System.out.println("");
                    else
                         System.out.print("");
          //while loop check to finish
//          if(SquareRoot == 0)
//               done = true;
//          }//end while loop
}Still doesn't work. =[                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                   

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  • Calculating the square root...

    Hi all,
    let me shortly sketch the situation.
    I have a number of fields that I select from the database (coming from different queries)
    that I need to do calculations on...
    so far, I was able to do most of those calculations, but now I'm stuck.
    One of my calculations contains a square root.
    So I got something like:
    VARIABLE1 + VARIABLE2 + SQRT(3*VARIABLE1)
    with VARIABLE1 being a multiplication of several other fields.
    my question: is there an xsl or xdofx function to calculate the square root? Or any other solutions for my problem?
    Any help would be greatly appreciated :)
    Wkr,
    Filip

    You can use like this.
    <?xdoxslt:pow(10,2)?>
    <?xdoxslt:pow(10,3)?>
    <?xdoxslt:pow(10,4)?>

  • Square root formula in Calculated Characteristics

    Have a great days.
    There are two MIC in my inspection plan. first (0010) is for entering number and another (0020) is calculated characteristics. I want to calculate the square root of 0010 charateristics in 0020.
    What should be teh formula to put in 0020 char.
    Please guide. thanks in advance.
    Regards,
    Dipesh Bhavsar
    Edited by: dipeshbhavsar1982 on Jul 31, 2011 9:41 AM

    HI
    0020 MIC should be created with control indicator for formula tab(calc.characteristic)
    and in quality plan assign the first MIC as normal
    and assign second MIC then system will ask a formula ...
    there you can give the formula in terms of character
    example (0010)2
    Faisal

  • How to find square root, log recursively???

    I need to find the square root of a number entered recursively and log as well. Your help would be greatly appreciated. Thanks in advance!
    import java.io.*;
    /**Class provides recursive versions
    * of simple arithmetic operations.
    public class Ops2
         private static BufferedReader in = null;
         /**successor, return n + 1*/
         public static int suc(int n)
              return n + 1;
         /**predecessor, return n - 1*/
         public static int pre(int n)
              if (n == 0)
                   return 0;
              else
                   return n - 1;
         /**add two numbers entered*/
         public static int add(int n, int m)
              if (m == 0)
                   return n;
              else
                   return suc(add(n, pre(m)));
         /**subtract two numbers entered*/
         public static int sub(int n, int m)
              if (n < m)
                   return 0;
              else if (m == 0)
                   return n;
              else
                   return pre(sub(n, pre(m)));
         /**multiply two numbers entered*/
         public static int mult(int n, int m)
              if (m == 0)
                   return 0;
              else
                   return add(mult(n, pre(m)), n);
         /**divide two numbers entered*/
         public static int div(int n, int m)
              if (n < m)
                   return 0;
              else
                   return suc(div(sub(n, m), m));
         /**raise first number to second number*/
         public static int exp(int n, int m)
              if (m == 0)
                   return 1;
              else
                   return mult(exp(n, pre(m)), n);
         /**log of number entered*/
         public static int log(int n)
              if (n < 2)
                   return 0;
              else
                   return suc(log(div(n, 2)));
         /**square root of number entered*/
         public static int sqrt(int n)
              if (n == 0)
                   return 0;
              else
                   return sqrt(div(n, ));
         /**remainder of first number entered divided by second number*/
         public static int mod(int n, int m)
              if (n < m)
                   return 0;
              else
                   return mod(div(n, pre(m)), m);
         public static void prt(String s)
              System.out.print(s);
         public static void prtln(String s)
              System.out.println(s);
         public static void main(String [ ] args)
              prtln("Welcome to the amazing calculator");
              prtln("It can add, multiply and do powers for");
              prtln("naturals (including 0). Note that all the");
              prtln("HARDWARE does is add 1 or substract 1 to any number!!");
              in = new BufferedReader(new InputStreamReader ( System.in ) );
              int It;
              while ( (It = getOp()) >= 0)
                   prt("" + It + "\n");
            private static int getOp( )
            int first, second;
            String op;
            try
                System.out.println( "Enter operation:" );
                do
                    op = in.readLine( );
                } while( op.length( ) == 0 );
             System.out.println( "Enter first number: " );
                first = Integer.parseInt( in.readLine( ) );
                System.out.println( "Enter second number: " );
                second = Integer.parseInt( in.readLine( ) );
             prtln("");
             prt(first + " " + op + " " + second + " = ");
                switch( op.charAt( 0 ) )
                  case '+':
                    return add(first, second);
                  case '-':
                       return sub(first, second);
                  case '*':
                    return mult(first, second);
                  case '/':
                       return div(first, second);
                  case '^':
                    return exp(first, second);
                  case 'v':
                       return log(first);
                  case 'q':
                       return sqrt(first);
                  case '%':
                       return mod(first, second);
                  case 's':
                       return suc(first);
                  case 'p':
                       return pre(first);
                  default:
                    System.err.println( "Need +, *, or ^" );
                    return -1;
            catch( IOException e )
                System.err.println( e );
                return  0;
    }

    Hi,
    Is there any one to make a program for me in Turbo
    C++ for Dos, which can calculate the square root of
    any number without using the sqrt( ) or any ready
    made functions.
    The program should calculate the s.root of the number
    by a formula or procedure defined by the user
    (programmer).
    Thanks.This is a Java forum!
    If you want Java help:
    1. Start your own thread.
    2. Use code tags (above posting box) if you post code.
    3. No one will write the program for you. We will help by answering your questions and giving advice on how to fix problems in code you wrote.
    4. The formula you need to implement is given above by dizzy.

  • Square root of an interval using Newton's method

    Hello!
    I am trying to create a method that calculates the square root of an interval, and I am having trouble with both the actual calculation part, as well as the base case for the recursion. I implemented a simple counter for the recursion, but was not seeing any kind of pattern for the values. (I am pretty sure the "better" values should converge to 0).
    I was wondering if anybody wanted to take a swing at it and help me out. :)
    Here is the code for my program, followed by the code for Newton's method for calculating square roots of doubles. I am supposed to use it as a reference.
    I made the simple arithmetic methods with the help of http://en.wikipedia.org/wiki/Interval_arithmetic . They seem to work fine, so I am having issues with troubleshooting!
    Thanks!
    public class Interval {
         double x1;
         double x2;
         public Interval(double newx1, double newx2){
              x1 = newx1;
              x2 = newx2;
         public String toString(){
              return "[" + this.x1 + ", " + this.x2 + "]";
         //Add an interval to the current one.
         public Interval add(Interval j){
              double tempx1 = this.x1 + j.x1;
              double tempx2 = this.x2 + j.x2;
              Interval tempInterval = new Interval(tempx1, tempx2);
              return tempInterval;
         //Subtract an interval from the current one.
         public Interval sub(Interval j){
              double tempx1 = this.x1 - j.x2;
              double tempx2 = this.x2 - j.x1;
              Interval tempInterval = new Interval(tempx1, tempx2);
              return tempInterval;
         //Multiply an interval with the current one.
         public Interval mul(Interval j){
                   double minx1 = Math.min(this.x1*j.x1, this.x2*j.x2);
                   double minx2 = Math.min(this.x1*j.x2, this.x2*j.x1);
                   double maxx1 = Math.max(this.x1*j.x1, this.x2*j.x2);
                   double maxx2 = Math.max(this.x1*j.x2, this.x2*j.x1);
                   double tempx1 = Math.min(minx1, minx2);
                   double tempx2 = Math.max(maxx1, maxx2);
                   Interval tempInterval = new Interval(tempx1, tempx2);
                   return tempInterval;
         //Divide the current interval by a new one.
         public Interval div(Interval j){
                   double minx1 = Math.min(this.x1/j.x1, this.x2/j.x2);
                   double minx2 = Math.min(this.x1/j.x2, this.x2/j.x1);
                   double maxx1 = Math.max(this.x1/j.x1, this.x2/j.x2);
                   double maxx2 = Math.max(this.x1/j.x2, this.x2/j.x1);
                   double tempx1 = Math.min(minx1, minx2);
                   double tempx2 = Math.max(maxx1, maxx2);
                   Interval tempInterval = new Interval(tempx1, tempx2);
                   return tempInterval;
         static Interval step(Interval x, Interval y) {
              // Compute a "better" guess than x for the square root of y:
              // Code for doubles: Interval better = x - (x*x - y)/(2*x);
              Interval two = new Interval(2.0, 2.0);
              Interval better = x.sub( ( (x.mul(x)).sub(y) ).div(two.mul(x)) );
              // For doubles:
              if ( Math.abs(better.x2 - better.x1) < 0.001 ) { // base case
                   System.out.println(better.toString());
                   return better;
              else {
                   return step(better, y); // try to get even better...
         static Interval sqrt(Interval y) {
              return step(y, y); //: start guessing at the square root
         public static void main(String args[]){
              Interval i = new Interval(4.0, 8.0);
              Interval j = new Interval(4.0, 8.0);
              Interval addij = i.add(j);
              Interval subij = i.sub(j);
              Interval mulij = i.mul(j);
              Interval divij = i.div(j);
              Interval sqrtj = i.sqrt(j);
              System.out.println("Intervals:");
              System.out.println(i.toString());
              System.out.println(j.toString());
              System.out.println("Add: " + addij.toString());
              System.out.println("Sub: " + subij.toString());
              System.out.println("Mul: " + mulij.toString());
              System.out.println("Div: " + divij.toString());
              System.out.println("Sqrt: " + sqrtj.toString());
    }and newton's root finder for doubles:
    public class SquareRoot {
         static final double ALLOWED_ERROR = 0.001;
          * Newton's method for finding square roots.
         static double step(double x, double y) {
              // Compute a "better" guess than x for the square root of y:
              double better = x - (x*x - y)/(2*x);
              // Are we close enough?
              if ( Math.abs(x - better) < ALLOWED_ERROR ) { // => stop: base case
                   return better;
              else {
                   return step(better, y); // try to get even better...
         static double sqrt(double y) {
              return step(y, y); //: start guessing at the square root
         public static void main(String[] args) {
              System.out.println(Math.sqrt(1234));
              System.out.println(sqrt(1234));
              // NOTE: you may need to adjust the error bound for these two to agree
    }

    Nathron wrote:
    Here is the code for my program, followed by the code for Newton's method for calculating square roots of doubles. I am supposed to use it as a reference.The only thing I can see that looks suspicious is the call to step(better, y) in your reference code.
    Are you sure it shouldn't be step(y, better) or step(better, x))? Newton-Rhapson is supposed to be a progressive method, but as far as I can see the value of y can never change with the way you've got it. And if you've copied that to your new code, it might explain the problem.
    Winston

  • Fast Inverse Square Root

    I expect no replies to this thread - because there are no
    answers, but I want to raise awareness of a faculty of other
    languages that is missing in Flash that would really help 3D and
    games to be built in Flash.
    Below is an optimisation of the Quake 3 inverse square root
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